1. Briefly explain some examples of convergence in the wireless market.​

Answer:

Follow these steps to create your own app:

1)Choose your app name.

2)Select a color scheme.

3)Customize your app design.

4)Choose the right test device.

5)Install the app on your device.

6)Add the features you want (Key Section)

7)Test, test, and test before the launch.

8)Publish your app.

Explanation:

(!!_!!)

Answer:

the use of criminal thought by the name of education

Answer:

Explanation:

The following program is written in Python. It simply creates an endless loop that continously asks the user for an input. If the input is not -1 then it outputs the same input, otherwise it exists the program correctly. A test output can be seen in the attached image below.

while True:

   answer = input("Enter a value: ")  

   if answer != "-1":

       print(answer)

   else:

       break

Answer:

1.)

def two(a, b) :

print(a+b)

print(a*b)

2.)

a = int(input('enter an integer values '))

b = int(input('Enter another integer value' ))

print(a+b)

print(a*b)

3.)

Take side of a square from user and print area and perimeter of it.

def square(a):

area = a**2

perimeter = 4*a

print(area, perimeter)

Explanation:

Code written in python :

The first function named two, takes to arguments a and b ;

The sum of integers a and b is taken and displayed using ; print(a+b)

The product of integers a and b is taken and displayed using ; print(a*b)

2.)

User can enter an input and converted to an integer value using the command ;

int(input()) ; the sum and product of these values are displayed using :

print(a*b) and print(a+b)

The Area and perimeter of a square requires the side length, which is taken as the argument a in the square function defined.

Area of square = a² = a**2

Perimeter = 4 * a

Answer: 2.125

Explanation

Answer:

The capacitive reactance will be "100Ω" and RMS value of current is "2.2 A". A further explanation is provided below.

Explanation:

Given:

[tex]C =\frac{10^2}{\pi}\times 10^{-6} \ F[/tex]

[tex]V_{RMS}=220 \ V[/tex]

[tex]f = 50 \ Hz[/tex]

Now,

The capacitive reactance will be:

⇒ [tex]X_c=\frac{1}{\omega C} =\frac{1}{2 \pi f C}[/tex]

                   [tex]=\frac{1}{2\times \pi\times 50\times \frac{10^{-4}}{\pi} }[/tex]

                   [tex]=100 \ \Omega[/tex]

RMS value of current will be:

⇒ [tex]I_{RMS}=\frac{V_{RMS}}{X_c}[/tex]

             [tex]=\frac{220}{100}[/tex]

             [tex]=2.2 \ A[/tex]

So that,

⇒ [tex]V_m=220\times \sqrt{2}[/tex]

         [tex]=311 \ V[/tex]

⇒ [tex]I_m=2.2\times \sqrt{2}[/tex]

         [tex]=3.1 \ A[/tex]

hence,

The equation will be:

⇒ [tex]\nu=311 sin31 \ 4t[/tex]

and,

⇒ [tex]i=3.1 sin(314t+\frac{\pi}{2} )[/tex]

Answer:A

Explanation:i need points

Answer: A keyframe is a location on a timeline which marks the beginning or end of a transition. So for example, you have a movie and it transitions to another scene, keyframes tell it when and where to start the transition then when and where to stop the transition.

Answer:

D

Explanation:

, . , .

Explanation:

Answer:

a) a plotting object like point, line, or other shape

Explanation:

A geom in the ggplot2 system is "a plotting object like point, line, or other shape."

A Geom is used in formulating different layouts, shapes, or forms of a ggplot2 such as bar charts, scatterplots, and line diagrams.

For example some different types of Geom can be represented as geom_bar(), geom_point(), geom_line() etc.

(a) mkdir /d D:\utilities\recover    

     or

    mkdir D:\utilities\recover    

(b) rd  /s  D:​\software​\arch98

(a) To make a new directory we use the md or mkdir command followed by the name of the directory as follows;

mkdir [name_of_directory]

The name of the directory could also be a relative or absolute path depending on the request.

In the task, the specified directory uses an absolute path given as D:​\​utilities​\​recover. This path is in a drive D. Therefore, if you are in another drive different than D, to run this command, it is a great idea to do that with the /d switch.

In summary:

i. if in drive D, to make a directory D:\utilities\recover, type the following command;

mkdir  D:\utilities\recover    

ii. if otherwise in a different drive, type the following command.

mkdir /d D:\utilities\recover

(b) To delete a directory, we use the rd or rmdir command. If the directory has contents that also need to be deleted, we use the switch /s alongside the rd or rmdir.

In the task given, the directory to be deleted is D:\software\arch98. This includes deleting all of its files too. To do this, type the following command;

rd /s D:\software\arch98

Answer:

Following are the code to the given question:

def getSAOneSide(edge):#defining a method that getSAOneSide that takes edge patameter

   return edge * edge#use return to calculate the edge value

def getSA(SA_one_side):#defining a method that getSA that takes SA_one_side patameter

   return 6 * SA_one_side#use return to calculate the SA_one_side value

def volume(edge):#defining a method that volume that takes edge patameter

   return edge * edge * edge#use return to calculate edge value

edge = int(input("Enter the length of edge of the cube:\n"))#defining edge variable that input value

SA_one_side = getSAOneSide(edge)#defining SA_one_side that holds getSAOneSide method value

print("Surface area of one side of the cube:", SA_one_side)

surfaceArea = getSA(SA_one_side)#defining a surfaceArea that holds getSA method value

print("Surface area of the cube:", surfaceArea)#print surfaceArea value

vol = volume(edge)#defining vol variable that holds Volume method value

print("Volume of the cube:", vol)#print vol Value

Output:

Please find the attached file.

Explanation:

In the code three method "getSAOneSide, getSA, and volume" method is declared that takes a variable in its parameters and use a return keyword that calculates and return its value.

In the next step,edge variable is declared that holds value from the user and defines three variable that holds method value and print its value with the message.

Answer: PROXY

Explanation:

The basic objective of the web server is to store, process and deliver web pages to the users.

FTP server is to allow users to upload and download files. An FTP server is a computer that has a file transfer protocol (FTP) address and is dedicated to receiving an FTP connection. FTP is a protocol used to transfer files via the internet between a server (sender) and a client (receiver)

pop provides access via an Internet Protocol (IP) network for a user client application to a mailbox (maildrop) maintained on a mail server

proxy server is a system that isolates internal clients from the servers by downloading and storing files on behalf of the clients. it intercepts requests for web-based or other resources that come from

Answer:

We assume that the NFA for the expression S is theorem by using the expressions given below.

Cases as

Thompson's Construction Algorithm proves that any expression can be expressions in the NFA's.

Answer:

Following are the program to the given question:

#include<iostream>//defining header file  

using namespace std;

float temperatures()//defining a method temperatures

{

int a[10],i,j,n,min,max,sum=0,temp;//defining integer variable

float avg;//defining floating point variable

cout<<"Please input the number of temperatures to be read: ";//print message

cin>>n;//input integer value

if(i>10)//use if to check array length greater than 10

return -1;//return integer value -1

for(j=0;j<n;j++)//defining loop to input value

{

cout<<"Input temperature: "<<endl;//print message

cin>>a[j];//holding value in loop

}

for(i=0;i<n-1;i++)//defining loop to compare array value

{

for(j=i+1;j<n-1;j++)//defining loop to compare array value

{

if(a[i]>a[j])//use if to compare array values

{

   //swapping

temp=a[j];//holding array value in temp

a[j]=a[i];//holding value in first index of array  

a[i]=temp;//holding temp value

}

}

}

max=min=a[0];//holding max value  

for (i = 0; i < n; i++)//defining loop to compare array value

{

if (a[i] > max)//use if to compare max array value

{

max = a[i];//holding max array value

}

else if (a[i] < min)//use else if to compare min array value

{

min = a[i];//holding min array value

}

}

for(i=0;i<n;i++)//use loop to add array value

sum=sum+a[i];//adding array value

avg=(float) sum/n;//calculating avg of the array

std::cout.setf(std::ios::fixed);//using namespace

std::cout.precision(2);//using precision method

cout<<"The average temperature is: "<<avg<<endl;//print avg value with message

cout<<"The highest temperature is: "<<max<<endl;//print max value with message

cout<<"The lowest temperature is: "<<min<<endl;//print min value with message

return avg;//return avg value

}

int main()//defining main method

{

float k;//defining float variable

k=temperatures();//calling method  

}

Output:

Please find the attached file.

Explanation:

In this code, a method "temperatures" is declared that defines the integer and float variable in which "n, array" is used to store the array value and inside the method min and max variable is declared that use the conditional statement to store its value.

Outside the main method, a floating-point variable "k" is declared that calls the method and stores its value.  

Answer:

British Broadcasting Corporation Microcomputer System

Explanation:

The British Broadcasting Corporation Microcomputer System, or BBC Micro, is a series of microcomputers and associated peripherals designed and built by the Acorn Computer company in the 1980s for the BBC Computer Literacy Project.

Answer:

British Broadcasting Corporation

Explanation:

This is a UK company which provides television and radio news in over 40 languages. This is the computer related meaning, there are other meanings to the abbreviation but they seem irrelevant in this case.

Hope this information was of any help to you. (:

Answer:

a bit

Explanation:

<3

Answer:

4 * 10^9

2.7 * 10^-8

6.776 * 10^7

9.05*10^4

5.409*10^5

9.04 * 10^-3

3.2 * 10^-2

5.12 * 10^8

Explanation:

1. 4,000,000,000

4 * 1,000,000,000 = 4 * (10*10*10*10*10*10*10*10*10) = 4 * 10^9

2. 0.000000027

27 * 10^-9 = 2.7 * 10^-8

0.000000027 = 2.7 * 10^-8

3. 67,760,000 = 6776 * 10000

6776 * 10000 = 6776 * 10^4

6776 * 10^4 = 6.776 * 10^3 * 10^4 = 6.776 * 10^7

4. 90,500

905 * 100 = (9.05 * 100) * 100

(9.05*100) * 100 = 9.05 * 10^2 * 10^2 = 9.05*10^4

5. 540,900

5409 * 100 = (5.409 * 1000) * 100

(5.409*1000)*100 = 5.409*10^3 * 10^2

5.409*10^3 * 10^2 = 5.409*10^5

6.) 0.00904

0.00904 = 904 * 10^-5

904 * 10^-5 = 9.04 * 10^-3

7. 0.032

32 * 10^-3 = 3.2 * 10^-2

8. 512,000,000

512 * 1000000

512 * 10^6 = 5.12 * 10^2 * 10^6 = 5.12 * 10^8

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

public static void main(String[] args) {

 int n, num;

 Scanner input = new Scanner(System.in);

 System.out.print("Number of inputs: ");

 n = input.nextInt();

 LinkedList<Integer> myList = new LinkedList<Integer>();

 for(int i = 0; i<n;i++){

     System.out.print("Input Integer: ");

     num = input.nextInt();

     while (num > 0) {

     myList.push( num % 10 );

     num/=10;

     }

     while (!myList.isEmpty()) {

         System.out.print(myList.pop()+" ");

     }

     System.out.println();

     myList.clear();

 }

}

}

Explanation:

This declares the number of inputs (n) and each input (num) as integer

 int n, num;

 Scanner input = new Scanner(System.in);

Prompt for number of inputs

 System.out.print("Number of inputs: ");   n = input.nextInt();

The program uses linkedlist to store individual digits. This declares the linkedlist

 LinkedList<Integer> myList = new LinkedList<Integer>();

This iterates through n

 for(int i = 0; i<n;i++){

Prompt for input

     System.out.print("Input Integer: ");

This gets input for each iteration

     num = input.nextInt();

This while loop is repeated until the digits are completely split

     while (num > 0) {

This adds each digit to the linked list

     myList.push( num % 10 );

This gets the other digits

     num/=10;

     }

The inner while loop ends here

This iterates through the linked list

     while (!myList.isEmpty()) {

This pops out every element of thelist

         System.out.print(myList.pop()+" ");

     }

Print a new line

     System.out.println();

This clears the stack

     myList.clear();

 }