100POINTS! ANSWER ALL 3 PARTS (look at the picture)

100POINTS! ANSWER ALL 3 PARTS (look At The Picture)

Answers

Answer 1

Answer:

Part 1-B

Part 2-D

Part 3-A

Answer 2

Answer:

1.B

2.D

3.A

Explanation:

.......................


Related Questions

Increasing the force on an object _________ its acceleration, if the mass of the object stays the same

Answers

Increases fill in the blank

How many moles are in 2.5 g of N2?
0.089 moles
KD 0.18 moles
1.3 moles
11 moles

Answers

Answer:

0.089

Explanation:

2.5/ 14= .178 then 0.178/ 2 again and you get 0.089

The moles of nitrogen in 2.5 grams of the compound is 0.089 moles. Thus option A is correct.

Moles can be calculated as the ratio of mass to molecular mass.

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

The mass of Nitrogen = 14 g/mol

The mass of diatomic nitrogen = 2 [tex]\times[/tex] mass of nitrogen

The mass of diatomic nitrogen = 2 [tex]\times[/tex] 14 g/mol

The mass of diatomic nitogen = 28 g/mol

The molecular weight of Nitrogen = 28g/mol

Given, the mass of Nitrogen = 2.5 g

Moles of nitrogen = [tex]\rm \dfrac{2.5}{28}[/tex]

Moles of Nitrogen = 0.089 moles.

The moles of nitrogen in 2.5 grams of the compound is 0.089 moles. Thus option A is correct.

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How many moles are in 4.3 x 10 ^22 molecules of Na3PO4

Answers

Answer:

0.071 moles of Na₃PO₄ .

Explanation:

Given data:

Number of molecules of Na₃PO₄ = 4.3× 10²² molecules

Number of moles = ?

Solution:

1 mole contain 6.022 × 10²³ molecules

4.3× 10²² molecules × 1 mol / 6.022 × 10²³ molecules

0.71× 10⁻¹ mol

0.071 mol

The number 6.022 × 10²³ is called Avogadro number.

"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"

(9) How many moles of oleum in 1780. g of oleum? - Write an equation to summarize the process.

Answers

Answer:

1. 10moles

2. Find the summarized equation below

Explanation:

Mole = mass ÷ molar mass

Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)

= 2 + 64 + 112

= 178g/mol

According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:

Mole = 1780/178

Mole = 10moles

2. The summarized equation of the contact process is:

1) S + O2 → SO2

2) 2SO2 + O2 → 2SO3

3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7

4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)

aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Supposed 6.93 g of hydrochloric acid is mixed with 2.4 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits. g

Answers

Answer:

Explanation:

HCl    + NaOH     =    NaCl    +     H₂O.

1 mole   1 mole           1 mole          1 mole

6.93  g of hydrochloric acid = 6.93 / 36.5 = .189 mole of HCl

2.4 g of NaOH = 2.4 / 40 =  .06 mole of NaOH

NaOH is in short supply so it is the limiting reagent .

1  mole of NaOH reacts with 1 mole of HCl to give 1 mole of Water

.06 mole of NaOH will react with .06 mole of HCl to give .06 mole of water

Water formed = .06 mole

= .06 x 18 = 1.08 g

= 1.1 g

According to Image 2, which tectonic plate is composed of the largest percentage of oceanic lithosphere?
A. African Plate
B. Eurasian Plate
C. Indian Plate
D. Nazca Plate

Answers

I think it would be African plate

Answer:

I think the answer is A the Afracan plate

Explanation:

hope this helps:)

The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process.
2N2O5(g) = 4NO2(g) + O2
[N2O5] Time (s)
0.100 0.00
0.066 200.00
0.044 400.00
a) Find the rate of disappearance of N2O5 from t=0 s to t=200s
b) Find the rate of appearance of NO2 from t=0 s to t =200s

Answers

Answer: a) [tex]1.7\times 10^{-4}[/tex]

b) [tex]3.4\times 10^{-4}[/tex]

Explanation:

The reaction is :

[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]

Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]

Rate =  [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]

a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]

Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

b) Rate of appearance of [tex]NO_2[/tex] =  [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]

A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s

[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]

B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s

According to rate law,

[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]

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A student collected a 1.28 g sample of Magnesium. How many atoms of Mg are in his sample?

A student did an experiment that called for 1.24 x 1024 molecules of CaO. What is the mass of her reactant?

A student reacted 0.0405 g of glucose (C6H12O6). How many molecules of glucose did he react?

Answers

All you haft to do is mutiply and see how many points there are

Assuming a 25% efficiency, how many Calories would a horse need to consume to work at 1.0 hp for 2.0 hh ?

Answers

Answer:

E = 7.11 × [tex]10^{-7}[/tex]  Cal

Explanation:

given data

efficiency = 25 %

solution

first we get here E by the power that is express as

p = [tex]\frac{E}{t}[/tex]     ...........1

E = p × t

E = 1 ×  2 × [tex]\frac{1hp}{746w} \times \frac{1hr}{3600 s}[/tex]  

E = 7.447 × [tex]10^{-7}[/tex] J

and

Ein is get by efficiency

Ein = [tex]\frac{Eout}{\eta }[/tex]        ..................2

Ein = [tex]\frac{7.447 \times 10^{-7}}{.25 }[/tex]

Ein = 29.788 × [tex]10^{-7}[/tex]  J

so required energy is

E = 29.788 × [tex]10^{-7}[/tex]  ×  [tex]\frac{1Cal}{4.184J}[/tex]

E = 7.11 × [tex]10^{-7}[/tex]  Cal

A compound is found to contain 7.962 % silicon , 20.10 % chlorine , and 71.94 % iodine by mass.

a. The empirical formula for this compound is_______ .
b. The molar mass for this compound is 352.8 g/mol. The molecular formula for this compound is:_____

Answers

Answer:

A. Empirical formula => SiCl₂I₂

B. Molecular formula = SiCl₂I₂

Explanation:

From the question given above, the following data were:

Silicone (Si) = 7.962 %

Chlorine (Cl) = 20.10 %

Iodine (I) = 71.94 %

Molar mass of compound = 352.8 g/mol

Empirical formula =?

Molecular formula =?

A. Determination of the empirical formula of the compound.

Si = 7.962 %

Cl = 20.10 %

I = 71.94 %

Divide by their molar mass

Si = 7.962 / 28 = 0.284

Cl = 20.10 / 35.5 = 0.566

I = 71.94 / 127 = 0.566

Divide by the smallest

Si = 0.284 / 0.284 = 1

Cl = 0.566 / 0.284 = 2

I = 0.566 / 0.284 = 2

Empirical formula => SiCl₂I₂

B. Determination of the molecular formula of the compound.

Empirical formula => SiCl₂I₂

Molar mass of compound = 352.8 g/mol

Molecular formula =?

Molecular formula = [SiCl₂I₂]ₙ

[SiCl₂I₂]ₙ = 352.8

[28 + (2×35.5) + (2×127)]n = 352.8

[28 + 71 + 254]n = 352.8

353n = 352.8

Divide both side by 353

n = 352.8 / 353

n = 1

Molecular formula = [SiCl₂I₂]ₙ

Molecular formula = [SiCl₂I₂]₁

Molecular formula = SiCl₂I₂

Tim and Jose are moving furniture. Tim pushes a 150 kg sofa with 300N
force. As a result, Sofa’s acceleration was __________ according to Newton’s
Second Law of motion. (F = ma)

Answers

Answer:

a = 2m/s²

Explanation:

Given data:

Mass of sofa = 150 Kg

Force applied = 300 N

Acceleration = ?

Solution:

Formula:

F = ma

F = force

m = mass

a = acceleration

by putting values,

300 N = 150 Kg × a

a =  300 N /150 Kg

a = 300 Kg m/s² / 150 Kg   ( N = Kgm/s²)

a = 2m/s²

Which atom is most likely to partake in chemical bonding given the number of valence electrons?

A. Krypton
B. Argon
C. Xenon
D. Boron

Need help****

Answers

Answer:

D

Explanation:

I hope this helps and have a great day

how many electrons does a covelent bond consist of?

Answers

Answer: 2 electrons

Explanation: Good luck! :D

What is the formula for the ionic compound formed between sodium and oxygen?

Answers

Answer:

Na2O (the 2 is small the o is not a 0 but and OOh)

Explanation:

Hey there, The formula for the compound formed between sodium and oxygen will be Na2O

Though since sodium is a metal and oxygen is a nonmetal, Na2O is expected to be ionic.

What is an ionic compound?

An ionic compound is a chemical compound made up of ions held together by electrostatic forces known as ionic bonding.

To determine an ionic compound's formula, first identify the cation and record its symbol and charge.

After that, identify the anion and record its symbol and charge. Finally, mix the two ions together to make an electrically neutral compound.

After two or more atoms lose or gain electrons to form an ion, an ionic bond can form.

Ionic bonds form when metals lose electrons and nonmetals gain electrons. Ions with opposite charges attract each other, forming an ionic bond.

The symbol for sodium is Na+, and the symbol for oxygen is O2. The resulting compound here in the given condition is Na2O.

Thus, this is the formula for the ionic compound formed between sodium and oxygen.

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How do I round 74,000 to have only one significant figure?

Answers

Answer:

7x10⁴.

Explanation:

Hello!

In this case, when rounding big number to a representation with less significant figures than it, we need to make sure we remove the spare figures and round up whether the next digit is five or more.

In such a way, for 74,000, we notice that 4 is not enough to round up the 7, that is why the number would contain a 7 only; moreover, to get rid of the thousand places, we need to introduce an exponent in 4 places, which means that the result would be:

7x10⁴.

Best regards!

Which of the statements about liquids and gases are true?
Both liquids and gases have a definite volume.
O The particles in liquids and gases can move past one another
freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.

Answers

Question:

Which of the statements about liquids and gases are true?

Answer:

The particles in liquids and gases can move past one another freely.

#CARRYONLEARNING #STUDYWELL
Question:

Which of the statements about liquids and gases are true?

Choosing:

Both liquids and gases have a definite volume.

The particles in liquids and gases can move past one another freely

Both liquids and gases have a definite shape.

Neither liquids nor gases have a definite shape.

Answer:

The particles in liquids and gases can move past one another freely.

#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELL

What is the coefficient, subscript for V, and subscript for O in V2O5

Answers

Answer: Coefficient 0

subscript for V 2

subscript for O 5

Explanation: yes

There is no coefficient in V₂O₅ and the subscript of vanadium V is 2 and the subscript of oxygen is 5.

What is vanadium pentoxide ?

Vanadium pentoxide is an ionic compound formed by donating electrons from the vanadium metal to oxygen.  The chemical formula of vanadium pentoxide is V₂O₅.

The chemical formula of a compound is written in terms of the chemical symbol of each constituent elements and the number of their atoms. The number of atoms is written as subscript for the chemical symbols.

In V₂O₅, there are are 2 vanadium atoms and 5 oxygen atoms. Coefficients are numbers prior to the formula in reaction. Here there is no coefficient and the subscript for V is 2 and that of O is 5.

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A nucleus with four protons has total positive charge

Answers

It would have a charge of 4+
It would be 4 Bc Protons are positive charges

The element in Period 4 and Group 14 of the Periodic Table would be classified as a

Answers

Answer:

Chalcogen

Explanation:

what can scientists learn from index fossils?

Answers

Answer:

dating and correlating the strata in which it is found

Explanation:

Answer:

The correct answer is A:The age of an unfamiliar layer of rock

Explanation:

I promise that I got it correct on A P E X <3

Jill graphs the speed of a model train that is travelling at a speed of 15 kilometers per hour. Which graph shows the speed of the model train?

Answers

Answer:c

Explanation:

50POINTS!
Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k

If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?

A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles

Answers

Answer:

A. 1.02 moles .

Explanation:

Hello!

In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:

[tex]n=\frac{PV}{RT}[/tex]

Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:

[tex]n=\frac{1.00atm*22.9L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.02mol[/tex]

Therefore, the correct answer is A. 1.02 moles

Best regards!

Marine chemist exam in the mass percent composition of manganese sulfide compound from ocean floor he determined that 60.2% of this compound is sulfur determine the mole ratio between manganese and sulfur

Answers

Explanation:

Let the mass of the compound be 100g.

There are 60.2g of sulfur.

Moles of sulfur

= 60.2g / (32.07g/mol) = 1.877mol

There are 100g - 60.2g

= 39.8g of manganese.

Moles of manganese

= 39.8g / (54.94g/mol) = 0.724mol

Mole ratio of manganese to sulfur

= 0.724mol : 1.877mol = 1 : 2.5.

[2071]State and explain Kohlrusch's law.
(2071]Why does the specific conductance decreases and equivalent conductance increase
with dilution of a solution of electrolyte?
ito unit How does it Vary with dilution?
1101​

Answers

I have no idea how about it lol I t

A parallel circuit contains four identical lamps. The current through the energy source is 4 A. The total resistance of the circuit is 10 Ω. What is the voltage across the energy source and across each lamp

Answers

Answer:

a parallel circuit has two or more paths for current to flow through voltage is the same across each component of the parallel circuit the sum of the current through each path is equal to the total current that follows from the source another definition is in a parallel circuit all components are connected across each other formally exactly two sets of electricity common points a branch in a parallel circuit in a path of electricity current formed by one of the load component

Dribbling a basketball harder into the floor makes it bounce higher is an example of what newton's law?

Answers

newton’s third law, because a person(a) is acting upon the ball(b) by dribbling the ball on the floor

A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the temperature of the water starts off at . When the temperature of the water stops changing it's . The pressure remains constant at . Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits.

Answers

Answer:

Therefore, the specific heat capacity of the iron is 0.567J/g.°C.

Note: The question is incomplete. The complete question is given as follows:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

Explanation:

Using the formula of heat, Q = mc∆T  

where Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)

When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water

mass of iron  = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C

∆T = 85.0 °C - 27.6 °C = 57.4 °C

mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C

∆T = 27.6°C - 23.0°C = 4.6 °C

Substituting the values above in the equation; Heat lost by Iron = Heat gained by water

59.1 g * c * 57.4 °C  = 100.0 g * 4.184 J/g.°C * 4.6 °C

c = 0.567 J/g.°C

Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.

100 Points PLZ HELP!

Using the ideal Gas Law (PV=nRT), solve for the missing variable. R=0.08206 atm*L/mol*k


At what temperature will 0.654 moles of neon gas occupy 15.66 liters and 0.899 atmospheres?

Answers

Answer:

C

Explanation:

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure Y---:X:------Y could be abbreviated as XY2Z2.Classify these structures by the hybridization of the central atom. XY4Z2, XY4Z, XY5Z, XY2Z3, XY2Z, XY3Z, XY2Z2, XY3Z2,XY2,XY3,XY4,XY5,XY6

Answers

Answer:

XY4Z2- dsp2

XY4Z- sp3d

XY5Z- sp3d2

XY2Z3- sp3d

XY2Z- sp2

XY3Z- sp3

XY2Z2- sp3

XY3Z2- sp3d

XY2 - sp

,XY3- sp2

XY4- sp3

,XY5- sp3d

XY6- sp3d2

Explanation:

In the answer box I have shown the hybridization patterns of the various arrangement of bond pairs and lone pairs.

Hybridization was put forward to explain the shapes of molecules under the valence bond theory. All molecules having the same hybridization pattern are based on the same geometry. Deviations from the expected geometry may arise due to the presence of lone pairs.

What is CaF2(aq) + Rb

Answers

Answer:

RbF2 + Ca

Explanation:

Since Rb is located in IIA as well as Ca, Rb has ion form Rb2+

Hence CaF2 + Rb → RbF2 +Ca

Please be reminded, this answer may not be 100% correct

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