11. Samantha was asked to measure out 10 g of salt in a lab. She mistakenly measures out 15 g instead. Calculate
the percent error. Make sure your answer has the correct number of significant figures!

11. Samantha Was Asked To Measure Out 10 G Of Salt In A Lab. She Mistakenly Measures Out 15 G Instead.

Answers

Answer 1

Answer:

50%

Explanation:

Expected measurement required = 10g

Actual measurement observed = 15g

The percentage error is given as proportion the difference between the actual and expected measurement or values and the expected value value expressed as a percentage.

[(Actual - Expected) / Expected] × 100%

[(15 - 10) / 10)] × 100%

(5 / 10) × 100%

0.5 × 100%

50%

Therefore, the percentage error in the measurement is 50%


Related Questions

Given that the density of air is 14.4, then the vapour of sulphur IV oxide is A. 16 B. 32 C. 64 D. 128
Thank you.

Answers

Answer:

32

Explanation:

The vapour density of a gas is the number of times a given volume of gas or vapour is as heavy as the same volume of hydrogen at a particular temperature and pressure.

Vapour density = 2 × relative molecular mass of the gas or vapour

Relative molecular mass of SO2 = 32 + 2(16) = 64

Hence;

Vapour density of SO2 = 64/2

Vapour density of SO2 = 32

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