13) Un móvil A parte de una ciudad a las 12 horas, con una velocidad de 40 Km/h. 2 horas después parte otro con una velocidad de 60 Km/h. Averiguar a qué hora se encuentran y a que distancia de la ciudad

Answers

Answer 1

Answer:

¿Podrías poner la pregunta en inglés por favor?

Explanation:


Related Questions

Directions. Read and understand each item carefully. Write your answers on the space provided.
1. Create a graphic representation based on the following data tabulated on Table 2 and make an interpretation of
the graph. Make sure to coordinate points correctly and trace line to show motion of the object.
Table 2. The distance travelled by a car in a given time.

(Dudes I need this today, pls answer this correctly)​

Answers

Answer:

Please find attached the required graph of the data points

The graph can be interpreted as showing that which was at rest starts  moving at a constant speed of 2 km/min

Explanation:

The table is presented as follows;

[tex]\begin{array}{lcl}Time \ (min)&& Distance \ (km)\\0&&0\\5&&10\\10&&20\\15&&30\\20&&40\\25&&50\\30&&60\end{array}[/tex]

The graphic representation of the above data can be created by plotting the Time on the x-axis and the Distance on the y-axis on a graph paper

The graph of the data can be created also using a spreadsheet application such as MS Excel by using the Chart function under the Insert menu, after selecting the points input into cells on the spreadsheet as shown in the attached drawing

The distance travelled by the car in a given time is found by obtaining the rate of change of the values of the graph, m, as follows;

[tex]m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Where (y₁, x₁), and (x₂, y₂) are a pair of chosen points on the given line

When, the chosen points are (y₁, x₁) = (0, 0), and (x₂, y₂) = (30, 60), we get;

[tex]m =\dfrac{60 \, km-0 \, km}{30 \, min-0 \, min} = 2 \, km/min[/tex]

The graph can be interpreted as showing that the rate of change of the distance travelled by the car per  unit time which is the speed of the car starting from rest is 2 km/min

rocks from volcanoes are used by scientists to study the interior of the earth

TRUE OR FALSE​

Answers

I think it’s false bc A volcano is not in the interior of the earth
True, rocks are made from hardened magma from the Earth’s interior. By studying them you can find out a lot about the interior.

I had a carved lava rock necklace when I was a kid & lived in Hawaii. My sister & I developed a rash from wearing the lava rock pendant. We think it was because there was a high level of sulfur in the lava rock.

If you have ever been near an active volcano, the smoke/ steam gives off a smell of sulfur, which smells like rotten

3 Draw energy transfer diagrams
for:
a) winding up a clockwork car
b) letting a clockwork car run
c) letting a battery-powered car
run.

Answers

Answer:

The outline of the energy transfer are;

a) Kinetic energy → Clockwork spring → Potential energy

b) Potential energy in clockwork car → Clockwork spring coil unwound → Clockwork car run

c) Chemical potential energy → Batteries in the car → Electric motors → Kinetic energy

Please find attached the drawings of the energy transfer created with MS Visio

Explanation:

The energy transfer diagrams are diagrams that can be used to indicate the part of a system where energy is stored and the form and location to which the energy is transferred

a) The energy transfer diagram for the winding up a clockwork car is given as follows;

Mechanical kinetic energy is used to wind up (turn) the clockwork car such that the kinetic energy is transformed into potential energy and stored in the wound up clockwork as follows;

Kinetic energy → Clockwork spring → Potential energy

b) Letting a wound up clockwork car run results in the conversion of mechanical potential energy into kinetic (energy due tom motion) energy as follows;

Potential energy in clockwork car → Clockwork spring coil unwound → Clockwork car run

c) The energy stored in the battery of a battery powered car is chemical potential energy. When the battery powered car runs, the chemical potential energy produces an electromotive force which is converted into kinetic energy as electric current flows from the batteries

Therefore, we have;

Chemical potential energy → Batteries in the car → Electric motors → Kinetic energy

Which best compares radiation and conduction?
C Both transfer thermal energy from warm objects to cooler objects.
O Both can transfer energy through empty space.
O Both transfer thermal energy by electromagnetic waves.
O Both involve the transfer of energy through direct contact.

Answers

Answer:

The statements that best compares radiation and conduction are the following: both transfer thermal energy from warm objects to cooler objects and both can transfer energy through matter. The difference is that conduction is through direct heat transfer; whereas, radiation transfers heat through waves.

The last option is the right

Calculate the man’s mass. (Use PE = m × g × h, where g = 9.8 N/kg.)
A man climbs a wall that has a height of 8.4 meters and gains a potential energy of 4,620 joules. His mass is about
kilograms

Answers

Answer:

mass=56.12kg

Explanation:

PE=mgh

4620=m×9.8×8.4

make m subject of the formula...

m =4620/(9.8×8.4)

m=4620/82.32

m=56.12kg

describe 2 ways you could increase the efficiency of a household central heating system

Answers

Answer:

Arrange an annual service. Treat your boiler like your car. ...

Keep your boiler clean. ...

Bleed your radiators. ...

Top up the pressure. ...

Use a Powerflush. ...

Insulate your pipes. ...

Turn the heating on. ...

If all else fails…

Explanation:

Define second class lever​

Answers

Answer:

Please find detailed explanation of second class levers below

Explanation:

Levers are one of the classes of machine that possesses three levels namely: first class, second class and third claas. A second class lever is the level of levers in which the load (L) is in between the pivot (F) and the effort (E).

Examples of second class levers include; wheelbarrow, a bottle opener etc. In the bottle opener for example, the bottle lid (load) is in between the pivot of the opener and the hand opening it (effort).

A bicyclist rides 2.93 km due east, while the resistive force from the air has a magnitude of 8.65 N and points due west. The rider then turns around and rides 2.93 km due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 8.65 N and points due east. Find the work done by the resistive force during the round trip. Number Type your answer here Units Choose your answer here

Answers

Answer:

-50.6 kJ

Explanation:

The work done (W) on an object is given by:

W = (Fcosθ) * S

where F is the force, S is the displacement and θ is the angle between the force and displacement.

i) During the first trip riding east, S₁ = 2.93 km = 2930 m, F₁ = 8.65 N.

The displacement is due east and the force is due west, hence θ₁ = 180°. Therefore:

W₁ = (F₁ * cosθ₁)S₁ = (8,65 * cos(180))2930 = -25.3 kJ

ii) i) During the second trip riding west, S₂ = 2.93 km = 2930 m, F₂ = 8.65 N.

The displacement is due west and the force is due east, hence θ₂ = 180°. Therefore:

W₂ = (F₂ * cosθ₂)S₂ = (8,65 * cos(180))2930 = -25.3 kJ

work done by the resistive force during the round trip is:

W = W₁ + W₂ = -25.3 kJ + (-25.3 kJ) = -50.6 kJ

Write the equation which links gravitational potential energy,height and mass.

Answers

Answer:

PE = mgh

Explanation:

The equation of potential energy is mgh.

What is the activity of a source that emits 1,200 particles per minute?
A. 1,200 Bq

B. 20 Bq

C. 72,000 Bq

Answers

What is the activity of a source that emits 1,200 particles per minute?

[tex]\boxed{ B. \:20 \:Bq }[/tex]

Explanation:

20 Bq is the activity of a source that emits 1,200 particles per minute. Activity is the number of decays per second. The SI unit for activity is becquerel (Bq).

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

Answer:

B) 20 Bq

The activity of a source that emits 1,200 particles per minute is 20 Bq.

-------------------------

☆hope it helps

☆have a great day!!

there is no gain in mechanical advantage in a single fixed pulley but they are used​

Answers

Answer:

A single fixed pulley is used to lift load by changing the direction of the lifting force. Even though a single fixed pulley has no mechanical gain in that, the effort applied is greater than the load, it is preferred in use since you do not have to pull or push the pulley up and down.

Explanation:

The answer itself speaks

HELPPP THIS IS IMPORTANT NOWW OMGG HELPPPP PLEASEE

Answers

Answer:

The correct answer is -

19 - C) parasitism

20- B) commensalism

Explanation:

Parasitism is a type of symbiotic relationship among two different organisms where one is benefited and the other is harmed. The harmed organism known as the host and the benefitted organism called the parasite. For instance, tapeworms are parasites in the human body.

Commensalism is also a symbiotic relationship but in this relationship, one symbiont is benefitted but another one neither benefitted nor harmed. For instance, Hermit crabs use the shells of dead snails for homes.

hey what is magnetic field






Answers

Answer:

a region around a magnetic material or a moving electric charge within which the force of magnetism acts.

Explanation:

The definition of a magnetic field is a place in space near a magnet or an electric current where a physical field is created from a moving electric charge that creates a force on another moving electric charge. An example of a magnetic field is the Earth's magnetic field.

a) How much electrical energy, in joules, does a 1000W space heater consume when it runs for 8h? (b) How much energy is that in kilowatt hours? (c) Calculate the cost of using this heater if 1kWh costs 0.5 dollars.

Answers

Answer:

a. Energy = 28800000 Joules

b. Energy = 8 Kwh

c. Cost = $4

Explanation:

Given the following data;

Power = 1000 Watts

Time = 8 hours

Cost = $0.5 per KWh

Conversion:

1 hour = 60 * 60 = 3600 seconds

8 hour = 8 * 3600 = 28800 seconds

a. To find much electrical energy, in joules;

Energy = power * time

Energy = 1000 * 28800

Energy = 28800000 Joules

b. To find how much energy is that in kilowatt hours;

Energy = power * time

Energy = 1000 * 8

Energy = 8000 Watt-hour = 8000/1000 = 8 Kwh (1 Kilowatts is equal to 1000 watts).

c. To calculate the cost of using this heater;

Cost = 8 * 0.5

Cost = $4

HELP
What is the momentum of a 50-kg ice skater gliding across the ice at a speed of 5 m/s?

Answers

Answer:

250 kgm/s

Explanation:

To calculate momentum, simply take the product of the mass and velocity.

Two cups having different liquids at a temperature of 20°c and 68°c lose heat energy to the environment. To measure the temperature difference between the two cups of liquid, you would use a ____

Answers

Answer:

youd use a thermometer. this can be used to measure the temperature of a solid such as food, a LIQUID such as water, or a gas such as air.

Explanation:

Gold at 100.0°C is placed in 2.00×10^2 g of water at 20.0°C. The mixture reaches equilibrium at 21.2°C. the specific heat of gold is 0.129 (J/g°C) What is the mass of the gold? Specific heat of water is 4.18 (J/g°C) .

Answers

Answer:

there it is fella atleast i tried

1) Un cuerpo se mueve desacelerando a razón de 8m/s2, calcula: a) La velocidad que tenía 5 segundos antes de detenerse. b) La distancia recorrida los últimos 5 segundos de su trayectoria.

Answers

Answer:

Initial velocity (u) = 40 m/s

Distance travel in last 5 seconds = 100 m

Explanation:

Given:

Acceleration (a) = 8 m/s²

Final velocity (v) = 0 m/s

Find;

1] Initial velocity before 5 sec

2] Distance travel in last 5 seconds

Computation:

1] Initial velocity before 5 sec

v = u + at

0 = u + (-8)(5)

u - 40 = 0

Initial velocity (u) = 40 m/s

2] Distance travel in last 5 seconds

s = ut + (1/2)(a)(t²)

s = (40)(5) + (1/2)(-8)(5²)

s = 200 - 100

Distance travel in last 5 seconds = 100 m

Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path.
A. 0.60 N, along the line tangent to the circle
B. 0.015 N, along the line tangent to the circle
C. 0.60 N, toward the center of the circle
D. 0.015 N, toward the center of the circle

Answers

Answer:

Option C

Explanation:

From the question we are told that:

Mass [tex]m=0.015kg[/tex]

Radius [tex]r=0.5m[/tex]

Time [tex]t=0.70[/tex]

Generally the equation for Tension is mathematically given by

 [tex]T=\frac{4mr}{t^2} \pi[/tex]

 [tex]T=\frac{4*0.015*0.5}{(0.70)^2} (3.142)[/tex]

 [tex]T=0.60N[/tex]

Therefore

[tex]T=0.60 N[/tex], toward the center of the circle

Option C

Answer:

0.60 N, toward the center of the circle

Explanation:

Got it right on the test.

If a driver makes contact with a steering wheel during a 35 mph crash, she comes to rest in about Δ=15 ms. If, during an identical crash, the driver makes contact with an air bag, she comes to rest in about Δ=110 ms. What is the ratio of the force exerted by the steering wheel to the force exerted by the air bag on the driver?

Answers

Answer:

The ratio of forces is 22 : 3.

Explanation:

Case I:

initial velocity, u = 35 mph

final velocity, v = 0

time, t = 15 ms

Case II:

initial velocity, u = 35 mph

final velocity, v = 0

time, t' = 110 ms

let the mass is m.

According to the Newton's second law, the force is given by the rate of change of momentum.

So

[tex]F =\frac{m(v-u)}{t}\\\\F'= \frac{m(v-u)}{t'}\\\\So, \frac{F}{F'} =\frac{t'}{t}\\\\\frac{F}{F'}=\frac{110}{15}=22:3[/tex]

which force is responsible for the moon revolving around the sun?​

Answers

Gravitational attraction

Uma bola é lançada para cima com a velocidade inicial de 20m/s. A sua aceleração é constante e igual a 10m/s² para baixo. Quanto tempo permanece a bola no ar? Qual é a maior altura atingida pela bola? Quando a bola está a 15 m de altura em relação ao solo?

Answers

Answer:

sorry but i cannot understand your language, can you speak in english

Use the equation d = st, where d = distance, s = speed, and t = time. If you jog
at a speed of 1.5 m/s for 20 seconds, how far do you travel?
A. 13.3 m
B. 30 m
C. 5 m
D. 21.5 m

Answers

Answer:

Distance = 30 meters

Explanation:

Given the following data;

Speed = 1.5 m/s

Time = 20 seconds

To find the distance travelled;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex] Distance = speed * time [/tex]

Substituting into the above formula, we have;

[tex] Distance = 1.5 * 20 [/tex]

Distance = 30 meters

The pressure difference, , across a partial blockage in an artery (called a stenosis) is approximated by the equation where is the blood velocity, the blood viscosity , the blood density , the artery diameter, the area of the unobstructed artery, and the area of the stenosis. Determine the dimensions of the constants and . Would this equation be valid in any system of units

Answers

The question is incomplete. The complete question is  :

The pressure difference, Δp, ac[tex]K_u[/tex]ross a partial blockage in an artery (called a stenosis) is approximated by the equation :

[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]

Where V is the blood velocity, μ the blood viscosity {FT/L2}, ρ the blood density {M/L3}, D the  artery diameter, [tex]A_0[/tex] the area of the unobstructed artery, and A1 the area of the stenosis.  Determine the dimensions of the constants [tex]K_v[/tex] and [tex]K_u[/tex]. Would this equation be valid in any  system of units?

Solution :

From the dimension homogeneity, we require :

[tex]$\Delta p=K_v\frac{\mu V}{D}+K_u\left(\frac{A_0}{A_1}-1\right)^2 \rho V^2$[/tex]

Here, x means dimension of x. i.e.

[tex]$[ML^{-1}T^{-2}]=\frac{[K_v][ML^{-1}T^{-1}][LT^{-1}]}{[L]}+[K_u][1][ML^{-3}][L^2T^{-2}]$[/tex]

                    [tex]$=[K_v][ML^{-1}T^{-2}]+[K_u][ML^{-1}T^{-2}]$[/tex]

So, [tex]$[K_u]=[K_v]=[1 ]=$[/tex] dimensionless

So, [tex]K_u[/tex] and [tex]K_v[/tex]  are dimensionless constants.

This equation will be working in any system of units. The constants [tex]K_u[/tex] and [tex]K_v[/tex] will be different for different system of units.

Amigos necesito que me ayuden a resolver esta gráfica :').

Answers

Answer:

ANO BA TO?(;-;)

Explanation:

miss the rage??

Which of the following are correct statements about the way an atom is put
together?
Check all that apply.
A. The valence shell is the innermost shell of electrons in an atom.
B. Electrons are found in the nucleus of an atom.
O C. There are two electrons in all electron shells.
O D. Electrons are in layers around the nucleus.
***** multiple choice ******

Answers

Answer:

valenc e shell

Explanation:

a car travelled at 50km/hr for 3 hours, how far did the car travel

Answers

Answer:

The answer answer is 150 km

Answer:

Explanation:

Distance =Speed×time

Speed=50km/hr

Time=3hours

Hence the Distance will be(50km/hr×3hours)

The answer is 150km

five scientist who travelled to space​

Answers

Answer:

The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...

Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...

Nicolaus Copernicus. Public Domain. ...

Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...

Galileo Galilei. NASA

Solve this question please sqdancefan​

Answers

Answer:

  (D) 4×10⁻³

Explanation:

The difference is ...

  0.2050 -0.2014 = 0.0036 = 3.6×10⁻³

The number 0.205 is expressed to a precision of 1×10⁻³, so the result of the subtraction operation cannot be considered to be more precise. It must be expressed as ...

  4×10⁻³ . . . . matches choice D

_____

Additional comment

This is physics, not math. In the physical sciences, most numbers must be considered to be measurements. (A few are definitions.) Hence, the rules of significant figures and precision apply to the results of arithmetic operations. This problem is a good illustration of what happens when computing small differences of large numbers. We start with 3 significant figures in 0.205, and end up with 1 significant figure in 0.004.

The isotope used to remove cancer malignancy cell the given options are a. Strontium 89 b. Uranium 238 c. Carbon 14 d. Chlorine 37.......... can anyone tell me the ans plzz​

Answers

Answer:

B. Uranium 238.

Explanation:

It is radioactive and can be used to treat cancer in the form of radiotherapy

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