Answer:
.41
Step-by-step explanation:
Take what 2/3 and make it into a decimal. Then do the same with the 1/4. Then you minus the biggest number from the smallest number then it gives you .41.
Two forces are acting on an object at the same point. Determine the angle between the two forces. (-2,7) and (3,-1)
Answer:
It is 124 degrees.
Step-by-step explanation:
You square each coordinate like this:
sqrt(x^2+y^2 )
You will end up getting sqrt(53 and sqrt(10.
Then find the dot product which is -6+-7=-13.
Then cos^-1(-13/sqrt53*sqrt10)
=124 degrees
Anyone knows the answer?
Answer:
E
Step-by-step explanation:
so you put the square root of 10 and then it will give you a decimal
Answer:
F
Step-by-step explanation:
when you put in 10 you get
3.16227766017 to the nearest number is 3.2
The owner of an automobile repair shop studied the waiting times for customers who arrive at the shop for an oil change. The following data with waiting times in minutes were collected over a one-month period. 2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3 (a) Develop a frequency distribution using classes of 0-4, 5-9, 10-14, 15-19, and 20-24.
Answer:
Step-by-step explanation:
Developing a frequency distribution of the ungrouped data simply means creating a structure (table) for the data. It is a method of converting an ungrouped data into a grouped data for proper analysis of the data.
The table will contain the values, their frequency (this means the number of times individual values occurs based on the classes) and the tally.
Check the attachment for the table.
Given the ungrouped data 2 5 10 12 4 4 5 17 11 8 9 8 12 21 6 8 7 13 18 3. The total number of data collected is 20. From the frequency distribution table, it can be seen that the total frequency is 20 which shows that all the values have been catered for.
Assume the average weight of an American adult male is 180 pounds with a standard deviation of 34 pounds. The distribution of weights follows a normal distribution. What is the probability that a man weighs somewhere between 120 and 155 pounds?
Answer:
Step-by-step explanation:
Find a-score of both
z-score = (x-mean)/SD
for 120
z =( 120- 180)/34 = -1.765
For 155
z = (155-180)/34 = -0.735
The probability to look for using z-score table is;
P(-1.765<z<-0.735) = 0.19239
Solve for a,b,and/or c
Help solve ASAP!
Answer:
a=90-67=23°
.................
Tuli is 10 years younger than Emily. The product of their
ages 2 years ago was 39. Let the present age of Emily
be A. Which of the following quadratic equations does A
satisfy?
Answer:
a² - 14a - 15 = 0 (quadratic equation)
Emily's age = 15 years
Tuli's age = 15 - 10 = 5 years
Step-by-step explanation:
let
Emily age = a
Tuli age = a - 10
Two years ago their ages will be as follows.
Emily's age = a - 2
Tuli's age = a - 10 - 2 = a - 12
The product of their ages 2 years ago is 39.
(a - 2)(a - 12) = 39
a² - 12a - 2a + 24 - 39 = 0
a² - 14a - 15 = 0 (quadratic equation)
To get a
a² + a - 15a - 15 = 0
a(a + 1) - 15(a + 1)
(a + 1)(a - 15)
a = -1 or 15
we can only use 15 as it is positive.
40/27 ,20/9, 10/3 what is the next term in the geometric sequence ?
Answer:
5/1
Step-by-step explanation:
40/27
20/9
10/3
5/1
divided by 2 and 3 each other!
Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is the height of the particle. (a) What is tt when the particle has height 2020? t=t= (b) What is the velocity of the particle when its height is 2020? v⃗ =v→= (c) When the particle has height 2020, it leaves the helix and moves along the tangent line at the constant velocity found in part (b). Find a vector parametric equation for the position of the particle (in terms of the original parameter tt) as it moves along this tangent line.
Answer:
a) t = 4
b) v = pi j + 5 k
c) rt = 1i + (pi t) j + (20 +5t )k
Step-by-step explanation:
You have the following vector equation for the position of a particle:
[tex]r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}[/tex] (1)
(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.
For a height of 20 you have:
[tex]5t=20\\\\t=\frac{20}{5}=4[/tex]
(b) The velocity of the particle is the derivative, in time, of the vector position:
[tex]v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}[/tex] (2)
and for t=4 (height = 20):
[tex]v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}[/tex]
(c) The vector parametric equation of the tangent line is given by:
[tex]r_t(t)=r_o+vt[/tex] (3)
ro: position of the particle for t=4
[tex]r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}[/tex]
Then you replace ro and v in the equation (3):
[tex]r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}[/tex]
Part(a): The value of [tex]t=4[/tex]
Part(b): Required vector [tex]L(t)=(1\widehat{i}+0\widehat{j}+10\widehat{k})+(t-4)(0\widehat{i}+\pi \widehat{j}+5\widehat{k})[/tex]
Given vector equation is,
[tex]r(t)=cos(\pi t)\widehat{i}+sin(\pi t)\widehat{j}+5t\widehat{j}[/tex]
Vector equation:
A vector is an object that has both a magnitude and a direction. Geometrically, we can picture a vector as a directed line segment, whose length is the magnitude of the vector, and with an arrow indicating the direction.
Part(a):
When the particle has a height of 20
[tex]5t=20\\t=4[/tex]
Part(b):
The point on the curve is [tex](cos(4\pi),sin(4\pi),20) =(1,0,20)[/tex]
Differentiating the given equation with respect to [tex]t[/tex].
[tex]r'(t)=- \pi sin(\pi t)\widehat{i}+\pi cos(\pi t)\widehat{j}+5\widehat{k}\\r'(t)=- \pi sin(4\pi t)\widehat{i}+\pi cos(4\pi t)\widehat{j}+5\widehat{k}\\r'(4)=0\widehat{i}+\pi \widehat{j}+5\widehat{k}\\L(t)=r(4)+(t-4)r'(4)\\L(t)=(1\widehat{i}+0\widehat{j}+10\widehat{k})+(t-4)(0\widehat{i}+\pi \widehat{j}+5\widehat{k})[/tex]
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Which of these are characteristics of good experimental design? Check all that apply. Good experimental design uses different methods for trials in an experiment. Good experimental design allows scientists to replicate experiments. Good experimental design tests only one variable at a time. Good experimental design plans how to record data so the data can be published. Good experimental design involves only one trial in an experiment. Good experimental design includes logging every step and data point of the experiment.
Answer:21
Step-by-step explanation:9+10
Answer:
B,C,D.F
Step-by-step explanation:
!!!!!!WILL MARK BRAINLIEST I need answer quickly!!!!!!!!
For males in a certain town, the systolic blood pressure is normally distributed with a mean of 105 and a standard deviation of 5. Using empirical rule, determine the interval of systolic blood pressures that represent the middle 99.7 of males
Answer:
Average systolic blood pressure = x = 130
Standard deviation = s = 6
Step-by-step explanation:
We are to find interval that represents the systolic blood pressure of middle 99.7% of the males.
According to the empirical rule:
a) 68% values lie within 1 standard deviation of the mean
b) 95% values lie within 2 standard deviation of the mean
c) 99.7% values lie within 3 standard deviation of the mean
So, 99.7% value will lie within 3 standard deviations from the mean.
We can express this range as:
( x - 3s, x + 3s)
= (130 - 3(6), 130 +3(6))
= ( 130 - 18, 130 + 18)
= ( 112, 148 )
Thus the interval from 112 to 148 contains the systolic blood pressure of middle 99.7% of the males in the certain town
Hope this helps!!!
The interval of systolic blood pressures that represent the middle 99.7 of males is (90, 120).
What is Empirical Rule?Empirical rule is a rule for normally distributed data which defines that almost all the data observed ranges between three standard deviations from the mean.
Given that,
For males in a certain town, the systolic blood pressure is normally distributed.
Mean, μ = 105
Standard deviation, σ = 5
Using empirical rule, we can say that 99.7% of males having the systolic blood pressures observed following a normal distribution lies within 3 standard deviations of the mean.
So the interval is (μ ± 3σ).
That is, (105 - 3×5, 105 + 3×5) = (90, 120)
Hence the required interval is (90, 120).
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Mariah is studying the life cycle of the monarch butterfly. She must choose one stage in the cycle to present in science class: egg, caterpillar, chrysalis, or adult. She plans to make her choice randomly using a custom spinner divided into four sections. First, however, she spins the spinner 50 times to see the frequencies it generates.
Stage Times Landed On
egg 10
caterpillar 12
chrysalis 15
adult 13
The relative frequency of landing on egg is .
The relative frequency of landing on caterpillar is .
The relative frequency of landing on chrysalis is .
The relative frequency of landing on adult is .
All the outcomes be considered equally likely.
The relative frequency of landing on an egg, caterpillar, chrysalis and adults are 0.2, 0.24, 0.3 and 0.26.
What is the relative frequency?"Relative frequency represents the ratio of the number of times a value of the data occurs in a dataset".
For the given situation,
Number of times egg landed on spin, x1 = 10
Number of times caterpillar landed on spin, x2 = 10
Number of times chrysalis landed on spin, x3 = 15
Number of times adult landed on spin, x4 = 13
Total number of times, n = 50
The formula for relative frequency = [tex]\frac{x}{n}[/tex]
The relative frequency of landing on an egg = [tex]\frac{10}{50}[/tex]
⇒ [tex]0.2[/tex]
The relative frequency of landing on caterpillar = [tex]\frac{12}{50}[/tex]
⇒[tex]0.24[/tex]
The relative frequency of landing on chrysalis = [tex]\frac{15}{50}[/tex]
⇒ [tex]0.3[/tex]
The relative frequency of landing on adults = [tex]\frac{13}{50}[/tex]
⇒ [tex]0.26[/tex]
Hence we can conclude that the relative frequency of landing on an egg, caterpillar, chrysalis, and adults are 0.2, 0.24, 0.3 and 0.26.
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Answer:
The relative frequency of landing on egg is 0.2.The relative frequency of landing on caterpillar is 0.24.The relative frequency of landing on chrysalis is 0.3.The relative frequency of landing on adult is 0.26.All the outcomes can be considered equally likely.Step-by-step explanation:
Ready to help you all any time
(07.06)
Number line with open circle on 9 and shading to the left.
Which of the following inequalities best represents the graph above? (3 points)
x < 9
x > 9
x ≤ 9
x ≥ 9
Answer:
I think it's number two
Answer:
A, first one
Step-by-step explanation:
Can y’all answer this or not !?
Answer:
b
Step-by-step explanation:
Answer:
x=417.6
Step-by-step explanation:
Let's solve your equation step-by-step.
0.5x+78.2=287
Step 1: Subtract 78.2 from both sides.
0.5x+78.2−78.2=287−78.2
0.5x=208.8
Step 2: Divide both sides by 0.5.
0.5x divided by 0.5
208.08 divided by 0.5
Find the length of the right triangle’s other leg. Round to the nearest tenth.
leg = 10 ft
hypotenuse = 12 ft
Answer: 17.32
Step-by-step explanation:
HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing. Check ALL that apply
Answer:
A, B
Step-by-step explanation:
After being simplified and put in standard form, the equations are ...
A. 3x² +8x -13 = 0 . . . a quadratic
B. 3x² -x -30 = 0 . . . . a quadratic
C. 4x = -16 . . . . . . . . . a linear equation, not quadratic
D. 3x⁴ -5x -6 = 0 . . . . a quartic equation, not quadratic
Both of the quadratic equations can be solved using the quadratic formula.
Tyrianne next solved a quadratic equation her work shown below in which step did Tyrianne make an error 1/2(x+4)^2-3=29
Step 1
Answer:
step 2
Step-by-step explanation:
khan academy
Suppose the following set of random numbers is being used to simulate the event of a basketball player making 3 free throws in a row. How should the numbers be arranged?
Answer:
860 583 785 814 010 122 337 198 621 549 034 076 796 495 978 078 433 330 333 153
Step-by-step explanation:
a p e x :))
Answer: 860 583 785 814 010 122 337 198 621 549 034 076 796 495 978 078 433 330 333 153
Step-by-step explanation:
Need Help ASAP !!!!!
Answer:
Luke worked 7 hours and Joshua worked 4 hours
Step-by-step explanation:
Let's call the number of hours that Luke worked l, and the number of hours that Joshua worked j. Since we know that Luke worked for 3 more hours than Joshua, we can express the amount of hours he worked as (j+3). Now, you can set up the following equation:
25j+35(j+3)=345
Expand parentheses:
25j+35j+105=345
Subtract 105 from both sides and combine like terms:
60j=240
j=4
Since Luke worked 3 more hours, he worked 7 hours. Hope this helps!
Find the volume of the cylinder. Round your answer to the nearest tenth.
Please help!
Answer:1236.4 ft^3
Step-by-step explanation:
height=h=7ft
Diameter=15ft
Radius=r=15/2=7.5ft
Volume of cylinder=π x r^2 x h
Volume of cylinder=3.14 x (7.5)^2 x 7
Volume of cylinder=3.14x7.5x7.5x7
Volume of cylinder=1236.375
Volume of cylinder=1236.4 ft^3
Which of the following are perfect squares? Check all that apply.
Answer: 16, 64, and 49
Step-by-step explanation: Perfect squares are products made by squaring or multiplying a whole number by itself twice.
11 is not a perfect square since nothing can
be multiplied by itself to give us 11.
The same is true for 62 and 15.
16 is a perfect square since it's possible to find a whole number that can be multiplied by itself to give us 16.
That number is 4 since 4 × 4 = 16.
64 is also one since 8 can be multiplied by itself twice to give us 64.
49 is also one since 7² or 7 × 7 is 49.
Answer:D,E and F
Step-by-step explanation:
Perfect squares are numbers in which their square roots are whole numbers.
From the options
√16 =4
√64 =8
√49 =7
What type of ratio can be a fraction?
a
part to whole
b
whole to part
c
part to part
d
part to total
Answer:
Your answer is A . part to whole .
Step-by-step explanation:
hope it helps!
Can I get brainliest !
12 divided by 9 tenths and hundredths
A child is laying on the ground relaxing and looking up at a plane that is passing by. If the plane’s altitude is 33,500 feet and the child’s eyes are located 8,200 feet away from a point on the ground directly beneath the plane, what is the angle of elevation for the child’s line of sight to the plane?
Answer:
about 76.2°
Step-by-step explanation:
The geometry can be modeled by a right triangle with the given dimensions being the side opposite the angle (height = 33,500 ft) and the side adjacent to the angle (8,200 ft). The fact that you know these two sides suggests the inverse of the tangent function may be useful.
Tan = Opposite/Adjacent
tan(angle) = (33,500/8,200)
angle = arctan (335/82) ≈ 76.246°
The angle of elevation is about 76.2°.
Which expression is equivalent to 5(2+7)
A. 2(5+7)
B. 2+7(5)
C. 5(2)+7
D.5(2)+5(7)
Answer:
D
Step-by-step explanation:
So 5(2+7) equals 45
A. 2(5+7)=24
B. 2+7(5)=37
C. 5(2)+7=17
D.5(2)+5(7)=45
Only D equals 45
Hope I helped :D
A random sample of 150 donations at a certain blood bank reveals that 70 were Type A blood. Does this suggest that the actual percentage of Type A donations differs from 40%, the percentage of the population having Type A blood? Carry out a test of hypotheses using a significance level of 0.01. Would your conclusion have been different if significance level of 0.05 had been used? Use only the P-Value Approach. State H0 and Ha. (20 pts)
Answer:
[tex]z=\frac{0.467 -0.4}{\sqrt{\frac{0.4(1-0.4)}{150}}}=1.675[/tex]
Now we can calculate th p value using the alternative hypothesis with the following probability:
[tex]p_v =2*P(z>1.675)=0.0939[/tex]
Since the p value is higher than the significance level given of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion of Type A donations is not significantly different from 0.4 or 40% at 5% of significance.
Step-by-step explanation:
Information given
n=150 represent the random sample taken
X=70 represent the samples with Type A blood
[tex]\hat p=\frac{70}{150}=0.467[/tex] estimated proportion of samples with Type A blood
[tex]p_o=0.4[/tex] is the value to verify
[tex]\alpha=0.05[/tex] represent the significance level
zwould represent the statistic
[tex]p_v[/tex] represent the p value
System of hypothesis
We want to verify if the actual percentage of Type A donations differs from 40%, then the system of hypothesis are:
Null hypothesis:[tex]p=0.4[/tex]
Alternative hypothesis:[tex]p \neq 0.4[/tex]
The statistic is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{0.467 -0.4}{\sqrt{\frac{0.4(1-0.4)}{150}}}=1.675[/tex]
Now we can calculate th p value using the alternative hypothesis with the following probability:
[tex]p_v =2*P(z>1.675)=0.0939[/tex]
Since the p value is higher than the significance level given of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true proportion of Type A donations is not significantly different from 0.4 or 40% at 5% of significance.
The estimate obtained from a sample of which of the following sizes would most likely be closest to the actual parameter value of a population?
A.15
B. 75
c. 45
d. 150
Answer:
d 150
Step-by-step explanation:
Answer:
150
Step-by-step explanation:
Need help solving this
Answer:
c: no solution
Step-by-step explanation:
State the domain and range for the function. f(x)= -tan x
Answer:
domain: (-∞, ∞) \ (kπ+π/2 for integers k)range: (-∞, ∞)Step-by-step explanation:
The tangent function is undefined at odd multiples of π/2. It can take on any value.
The domain is all real numbers except odd multiples of π/2.
The range is all real numbers.
Answer: it’s b
Step-by-step explanation:
edge
An instructor at a major research university occasionally teaches summer session and notices that that there are often students repeating the class. On the first day of class, she counts 105 students enrolled, of which 19 are repeating the class. The university enrolls 15,000 students.
1. An estimate of the population proportion repeating the class is given by:
a) 0.0013.
b) 0.007.
c) 0.181.
d)0.046.
2. The instructor wishes to estimate the proportion of students across campus who repeat a course during summer sessions and decides to do so on the basis of this class. Would you advise the instructor against it and why:
a) No, because 105 students is a pretty large class.
b) Yes, because this class is too small.
c) No, because it is completely arbitrary who takes this class.
d) Yes, because this class is not a random sample of students.
3. The standard error for the estimated sample proportion is given by:
a) 0.025.
b) 0.0014.
c) 0.0376.
d) 0.005.
4. A 95% confidence interval is given by:
a) 0.15, 0.23.
b) 0.345, 0.453.
c) 0.107, 0.255.
d) 0.09, 0.272.
5. She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are:
a) H0:p? =0.181 vs. H?:p=0.1 .
b) H0:p=0.1 vs. H?:p?0.18 .
c) H0:p=0.1 vs. H?:p? =0.181 .
d) H0:p=0.1 vs. H?:p?0.1 .
6. The test statistic for this hypothesis is given by:
a) 2.575.
b) 2.332.
c) 2.765.
d) 1.96.
7. The P?value for this test is:
a) 0.05>P>0.01 .
b) P>0.05 .
c) 0.01>P>0.005 .
d) 0.005>P .
8. Based on the p-value found:
a) we have convincing proof that the proportion of students repeating a class during summer sessions is not 10%.
b) we have strong evidence that the proportion of students repeating a class during summer sessions is not 10%.
c) we have strong evidence that the proportion of students repeating a class during summer sessions is 10%.
d) we have no doubt that the proportion of students repeating a class during summer sessions is not 10%.
Answer:
Check the explanations
Step-by-step explanation:
According to given information, an instructor at a major research university occasionally teaches summer session and notices that that there are often students repeating the class. On the first day of class, she counts 105 students enrolled, of which 19 are repeating the class. The university enrolls 15,000 students.
Therefore the number of observation n 105 and enrolled x=19
1. An estimate of the population proportion repeating the class is given by:
c) 0.181.
Explanation:
19 --0.18090,181 n 105
2. The instructor wishes to estimate the proportion of students across campus who repeat a course during summer sessions and decides to do so on the basis of this class. Would you advise the instructor against it and why:
d) Yes, because this class is not a random sample of students.
3. The standard error for the estimated sample proportion is given by:
c) 0.0376.
Explanation:
SE [tex](\hat{p})=\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}[/tex]
0.181 × (1-0.181) 105
0,0376 0.0376
4. A 95% confidence interval is given by:
c) 0.107, 0.255.
Explanation:
In order to determine the 95% confidence interval we follow the following step:
Where the z value is determined from the standard normal table as ~ 1.96
[tex]\hat{p}\pm \left [z\times SE(\hat{p}) \right ][/tex]
0.181 ± (1.96 × 0.0376)
0.181 ± 0.0737
Therefore the lower confidence interval is
LCI= 0.181- 0.0737
LCI= 0.107
Therefore the upper confidence interval is
UCI = 0.181 + 0.0737
UCI0.255
Therefore 95% confidence interval is
[tex]\left (0.107,0.255 \right )[/tex]
5. She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are:
d)[tex]0 :P = 0.10 and H_{a}:p\neq 0.10[/tex]
Explanation:
She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are defined on the basis of observation,
Null hypothesis as:
[tex]H_{0}[/tex]:p= 0.10
and alternative hypothesis as:
[tex]H_{a}:p\neq 0.10[/tex]
6. The test statistic for this hypothesis is given by:
c) 2.765.
Explanation:
In order to determine the z test statistics as:
Z=[tex]\frac{\hat{p}-p_{0}}{\sqrt{\frac{p_{0}(1-p_{0})}{n}}}[/tex]
0.181 - 0.10 0.10x (1-0.10)
=2.765
7. The P value for this test is:
c) 0.01>P>0.005 .
Explanation:
P value is calculated as:
P(Z > 2.765) 0.002845 for one tail test and
P(Z > 2.765) 0.005692 for two tail test.
8. Based on the p-value found:
b) we have strong evidence that the proportion of students repeating a class during summer sessions is not 10%.
Explanation:
As the z observed is more than the tabulated z value at 95% as:
[tex]Z_{observed}=2.765> Z_{tabulated}=1.96[/tex]
and also P value is less than the [tex]\alpha =1-0.95=0.05[/tex]
[tex]P(Z\geq 2.765)=0.005692< \alpha =0.05[/tex]
Therefore we accept the alternative hypothesis and we may conclude that we have strong evidence that the proportion of students repeating a class during summer sessions is not 10%.
Which statement about the relationship between different types of triangles is true?
An equilateral triangle is never an obtuse triangle.
An equilateral triangle is never an isosceles triangle.
A right triangle is always an isosceles triangle.
An obtuse triangle is always an acute triangle.
Answer:
its "A" because i got it right on my test
Step-by-step explanation:
