171) a force of 16.88 n is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular 171) acceleration of 1.20 rad/s2. calculate the rotational inertia of the wheel.

Answers

Answer 1

The rotational inertia of the wheel which has a radius of 0.34 m is 4.782 kgm²

The force applied tangentially to the wheel = 16.88 N

The radius of the wheel = 0.340 m

The angular acceleration of the well = 1.20 rad /s²

The rotational inertia can be found using the formula,

             I = F x r / α

where I is the rotational inertia

          F is the force applied

          r is the radius of the wheel

          α is the angular acceleration

Let us substitute the known values in the above equation, we get

              I = 16.88 x 0.34 / 1.20

                = 5.7392 / 1.20

                = 4.782 kgm²

Therefore, the rotational inertia is 4.782 kgm²

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Related Questions

disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.

Answers

If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.

Which definition of distance suits you best?

How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

s = 1.925 meters

What is the definition of a distance?

In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."

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A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?

Answers

Answer:

5 m

Explanation:

Displacement is the straight-line distance from the starting point to the end point.  Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).  

d² = 3² + 4² = 25

d = [tex]\sqrt{25}[/tex] = 5 m

Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)

9. A piece of iron with a mass of 9.8 g has an initial temperature of 32.6°C. As it is heated, it absorbs 365J of energy. What is the final temperature of the iron? (The specific heat of iron is .46 J/g °C)

Answers

The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.

What is Specific heat capacity?

The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).

The specific heat capacity of a material can be calculated by the formula:

Q = m × c × ΔT

where, Q = heat energy,

m = mass of the material,

c = specific heat capacity,

ΔT = change in temperature

The final temperature of the piece of iron can be calculated by the formula:

Q = m × c × ΔT

ΔT = (Final temperature - initial temperature)

365J = 9.8 × 0.46 × ΔT

365J = 4.508 × ΔT

ΔT = 80.96

ΔT = Final temperature = initial temperature

ΔT = (T - 32.6)

80.96 = (T - 32.6)

T = 80.96 + 32.6

T = 113.56°C

Therefore, the final temperature of the piece of iron is 113.56°C.

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9) During a game of bowling, which of the following describe the ball's motion?(SELECT ALL ANSWERS THAT APPLY)

A) The ball is accelerated while it is pushed by the student's hand due to an
unbalanced force.
B) The ball slows down as it rolls because friction exerts an unbalanced force.
C) The ball is accelerated while it is held in the student's hand due to balanced
Forces.
D) The ball does not change its motion as it rolls because of the balanced force
provided by friction.
E) The ball does not change its motion while it is held in the student's hand due to
balanced forces.

Answers

During a game of bowling the ball's motion:

The ball is accelerated while it is pushed by the student's hand due to an unbalanced force.The ball slows down as it rolls because friction exerts an unbalanced force.The ball does not change its motion while it is held in the student's hand due to balanced forces.

The correct options are A,B and E.

Description of a bowling ball's motion

Bowling ball motion is commonly divided into sequential skid, hook, and roll phases. When the ball moves down the lane in the skid and hook phases, frictional contact with the lane causes the ball's forward (translational) speed to continually decrease, but to continually increase its revolution rate (rotational speed).

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a pendulum is pulled to a height of 1.28 m above the lowest position and released. what is its speed at the level of the lowest position?

Answers

The speed at the level of the lowest position is 5.01m/s.

How do you conserve energy?

Energy cannot be created or destroyed; it can only be changed from one form of energy to another, according to the law of conservation of energy. This implies that a system always has the same amount of energy, barring external energy addition.

To reduce expenses and protect the resources for future use, energy conservation is necessary. The environment is contaminated by the harmful gases released into the atmosphere by conventional energy sources. Traditional energy sources are finite and could run out one day.

This is a typical energy conservation question, Set the kinetic energy at the bottom and the potential energy at the height to be equal.

mgh = 1/2mv²

gh = v²/2

v = √2gh

v = √2×9.8×1.28m/s

v = 5.01m/s.

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there must be equal amounts of mass on both side of the center of mass of an object.T/F

Answers

An object's centre of mass must be surrounded by an equal amount of mass on both sides. It is untrue.

Does an object's centre of mass have to be located there?

The centre of mass of an item typically, but not always, sits within the thing itself. For instance, a ball's centre of mass is located in its exact centre, while a book's centre of mass is located in its middle.

When two masses are equivalent, what happens?

When two objects of equivalent mass and speed approach one another, they stay together. After staying together, the two surfaces come to rest while retaining motion but losing kinetic energy. several of the energy of motion gets converted to thermal energy, or heat.

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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.

Answers

The volume of the toy is 80 ml.

To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.

In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.

The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.

It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.

Answer:

Volume of the toy: [tex]80\; {\rm mL}[/tex].

Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)

Explanation:

The graduated cylinder initially measures the volume of water in this cylinder:

[tex]V(\text{water}) = 70\; {\rm mL}[/tex].

Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:

[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].

Rearrange to find the volume of the toy:

[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].

To find the average density of this toy, divide mass by volume:

[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].

WILL GIVE BRAINLY IF RIGHT
what would happen if you dropped, at the same time, particles of different shapes from a boat into still water

Answers

Explanation:

If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.

1. A car moving 11 m/s accelerates at 1.5 m/s². How fast is it moving after it accelerates for 50
seconds?
Type a response (show work please)

Answers

We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.

what an acceleration is?

acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.

What prompts accelerating?

An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.

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Where does the depenent variable go on a graph?

Answers

The dependent variable go on the Y-axis on a graph.

what is a dependent variable?

The dependent variable is described as the variable that is being measured or tested in an experiment.

Dependent variable can be explained using the example where a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.

The independent variable is found on the x-axis (horizontal line) of the graph and the dependent variable is displayed on the y-axis.

The difference between independent variable and the dependent variable is that in an experiment, the independent variable is the variable that is varied or manipulated by the researcher.

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a 65 kg person dives into the water from the 10 m platform. a. what is her speed as she enters the water?

Answers

The speed of the person as she enters the water is 14.2 m/s.

What is kinetic energy?

Kinetic energy is the energy of motion. It is the energy that an object has due to its motion. This energy can be transferred from one object to another or converted into other forms of energy. Kinetic energy is dependent on an object's mass and its velocity. The greater an object's mass or velocity, the more kinetic energy it has. Kinetic energy can be used to do work, such as powering a machine or vehicle. It can also be used to generate electricity or to heat up objects.

The speed of the person as she enters the water can be calculated using the equation for kinetic energy:
KE = ½mv²
Where m is the mass of the person (65 kg) and v is the speed.
Solving for v, we get:
v = √(2KE/m)
Since the potential energy of the person just before she enters the water is equal to the kinetic energy of the person just after she enters the water, we can calculate the kinetic energy as:
PE = mgh
KE = mgh
Where m is the mass of the person (65 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the platform (10 m).
Plugging this into the equation for v, we get:
v = √(2mgh/m)
v = √(2gh)
v = √(2*9.8*10)
v = 14.2 m/s

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a dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to a frequency of 15 rpm in 10.0 s. assume the merry-go-round is a uniform disk of radius 2.5 m and has a mass of 330 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. calculate the torque required to produce the acceleration, neglecting frictional torque. what force is required at the edge?

Answers

Refer to the photo taken.

suppose that experiment 1 and experiment 2 are conducted at the same time; one student drops the ball from rest at the same instant that a second student horizontally rolls an identical off the table. after both balls have traveled half their vertical distance to the floor, what is the acceleration of the center of mass of the two-ball system relative to earth?

Answers

The two-ball system's center of mass will accelerate at a rate of "g" with respect to the earth.

What is a system's center of mass?

It represents the system's average location as weighted by each component's mass. The center of mass for straightforward stiff objects with homogeneous density is found at the centroid.

How can the center of mass of a symmetrical object be determined?

Finding the center of mass for symmetrical objects is significantly easier because symmetrical points on one side of the item will negate those same points on the other. Consider a uniform cylinder that is upright as an illustration.

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a point at an antinode of the standing wave on the wire travels from its maximum upward displacement to its maximum downward displacement in 8.40 msms . what is the wire'??s mass?

Answers

The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]

[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]

for t in the above expression.

[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]

The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]

[tex]v=\frac{\lambda_3}{T_3}[/tex]

Here,

[tex]$$\lambda_3$$[/tex]

is the frequency of third harmonics and

[tex]$$T_3$$[/tex]

is the time-period of third harmonics.

Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for

[tex]$$\lambda_3$$[/tex]

and

[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]

[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]

The expression of the wave velocity is given by the following expression.

[tex]v=\sqrt{\frac{T}{m / L}}[/tex]

Rearrange the above expression for

[tex]$$m$$[/tex]

[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]

[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]

The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.

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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:

Answers

The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

How to find velocity ?

To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:

Mass flow rate = Density * Flow rate

= Density * (Area * Velocity)

Where:

Density is the density of the fluid

Flow rate is the volume flow rate, or the rate at which volume flows through the pipe

Area is the cross-sectional area of the pipe

Velocity is the velocity of the fluid

The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.

The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:

A = pi * r^2

Where:

A is the cross-sectional area of the pipe

r is the radius of the pipe

The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:

A = pi * (1.5 cm)^2

= 7.07 cm^2

The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:

A = pi * (3 cm)^2

= 28.27 cm^2

Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:

(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)

Solving for v, the velocity on the narrow side, you get:

v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)

= 11.6 m/s

The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.

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what is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then released from rest, and whose period is 0.66 s ? assume that the displacement at the start of the motion is positive.

Answers

Answer:

x = A cos ω t          at t = zero, x displacement equals amplitude

x = .088 m cos ω t             describes the motion

We need yet to find ω in terms of P which is given

ω = √(k / m)        

P = 1 / f      and f = ω / (2 π)

Thus ω = 2 π f = 2 π / P       since 1 / f = P

This gives us

x = .088 m cos 2 π / .66 * t    

determine the energy levels and the corresponding eigenstates for a par- ticle of mass m, subject to a potential energy v (x) g

Answers

An energy eigenstate can always be written as (x,t) = (x)e-iEt/1. Probability density is equal to |(x,t)|2 (x,t) (x)e-iEt/1 * (x,t) ψ*(x)e+iEt/1 = ψ (x) The wave function *(x) = |(x)|2 exhibits time-dependent phase.

V's role in the Schrodinger equation?

For the system of a particle or particles interacting with a set of constraints, V(x) is a potential energy function. These restrictions can be compared to fields that exert a force on the desired particle or particles.

What is the energy eigenvalue?

The term "energy eigenvalues," which comes from the German word eigen, which means "characteristic" or "unique," refers to such particular discontinuous (step-like) energies. We refer to these energies as discrete energy eigenvalues or as quantized energies.

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The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation.

What is potential energy?

Potential energy is energy that is stored and can be released in the future. It is the energy of position or condition, as opposed to kinetic energy which is energy in motion. Potential energy can be stored in many forms such as gravitational, chemical, elastic, nuclear, and electromagnetic. Gravitational potential energy is the energy stored in an object due to its position in a gravitational field, while chemical potential energy is the energy stored in the bonds of chemical compounds. Elastic potential energy is energy stored in objects that can be stretched or compressed, such as a spring, while nuclear potential energy is the energy stored in the nucleus of an atom. Electromagnetic potential energy is the energy stored in the electric and magnetic fields of an object.

The energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation:
Hψ = Eψ
Where H is the Hamiltonian operator, ψ is the wavefunction, and E is the energy. For a particle of mass m subject to a potential energy v(x) g, the Hamiltonian can be written as:
H = -(h2/2m)*d2/dx2 + v(x) g
The solution of the Schrodinger equation for this Hamiltonian yields the energy levels E and the corresponding wavefunctions ψ. The energy levels are determined by solving the equation:
E - v(x) g = 0
This equation can be solved for the different energy levels E, and the corresponding wavefunctions can then be determined by solving the Schrodinger equation. The wavefunctions represent the probability distribution of the particle, and are determined by the boundary conditions imposed by the potential energy.
In summary, the energy levels and the corresponding eigenstates of a particle of mass m subject to a potential energy v(x) g can be determined by solving the time-independent Schrodinger equation. The energy levels are found by solving the equation E - v(x) g = 0, and the corresponding wavefunctions are found by solving the Schrodinger equation.

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- Determine the tension in each cable in the diagram to the right.

Answers

Tension of the three cables connecting the  celling, 7 kg ball, 4 kg ball,  5 kg ball respectively 156.8 N,  88.2 N and 49 N.

What is tension?

The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.

Tension of the cable connecting the  celling and 7 kg ball:

= (7 kg + 4 kg + 5Kg) × 9.8 m/s²

= 156.8 N.

Tension of the cable connecting the  7kg ball and 4 kg ball:

= (4 kg + 5Kg) × 9.8 m/s²

= 88.2 N.

Tension of the cable connecting the  4kg ball and 5 kg ball:

= 5Kg× 9.8 m/s²

= 49 N.

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Uing two billiard ball and 3 to 4 entence decided experiment to demontrate the law of conervation of momentum. (4 point)

Answers

So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.

What is momentum?Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop. Momentum is a physics term; it refers to the quantity of motion that an object has. A sports team that is on the move has the momentum. If an object is in motion (on the move) then it has momentum.Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.

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1. Find the force due to gravity if the mass of the object is 2300 kg
and the mass of the other object is 4000 kg. The distance
between the two objects is 0.150 m.

Answers

The force due to gravity will be 0.0272 Newtons.

What exactly does gravitational force signify?

The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.

How to calculate gravitational force in the above question?

Despite being weak and appealing, gravitational forces exist.

Given, mass of one object= 2300 kg

mass of another object= 4000 kg

distance between the two objects= 0.150 m

value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]

the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]

                       [tex]F=0.0272 N[/tex]

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find the maximum transverse speed of a point on the string. (f) what would be the equation y1x, t2 for this string if it were vibrating in its eighth harmonic?

Answers

In a one-dimensional string, a harmonic wave has a maximum transverse velocity and maximum transverse acceleration of 1ms-1 and 1ms-2, respectively.

What is maximum transverse speed of a point on the string?

We have attached a harmonic wave with a frequency of 80 Hodge to the string. Additionally, a positive extraction travels at a speed of 12 m/s with an amplitude of 0.025 m. Next, we must create a proper wave function for this wave in the first. In light of this.

we have established that the frequency F is the hurt amplitude is 0.025 m, and the speed is 12 m/s. As a result, given that we are aware of the wave function's writing, we may determine whether or not the sign K x minus omega T applies. Omega, which equals two pi into, is the angular frequency in this case. Thus, we can say that this word has been introduced. 80 is to be purchased That makes 160 by, too.

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when you look at a single slit diffraction pattern produced on a screen by light of a single wavelength, you see a bright central maximum and a number of maxima on either side, their intensity decreasing with distance from the central maximum. if the wavelength of the light is increased:_____.

Answers

The pattern gets bigger as the light wave length gets longer. other maxima are further from the central one and are wider.

What wavelength does it have?

A wavelength is the distance between two identical locations (adjacent crests) in successive cycles in a waveform signals that is transmitted by a wire or in space. Typically, this length is expressed in feet (m), millimeters (cm), or millimeters (mm) in wireless systems (mm).

What do wavelengths and frequencies refer to?

The distance that separates two wave crests is known as the wavelength, and it also applies to troughs. The number of vibrations that pass across a certain area in a second, or 60hz (Hz), is the unit of measurement for frequency (Hertz).

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the force between between two objects increases by what factor if the distance between them is changed 4.5 times the original separation?

Answers

The new gravitational force between the object will be 1/20.25 times of the original force.

The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,

F = GMm/R²

Here,

G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.

As per the given question the distance between the object is increased 4.5 times the original separation.

R' = 4.5R.

The new force of attraction between the object will be,

F' = GMm/(R')²

F' = GMm/(4.5R)²

F' = GMm/20.25R²

F' = F/20.25

So, the new force of attraction between the two objects will become 1/20.25 times of original force.

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ernie is trying to swim directly across a rushing river. ernie can swim at a rate of 6.2 m/s. the river's current is moving at a rate of 10.7 m/s. calculate the magnitude of ernie's resultant velocity?

Answers

The magnitude of Ernie's resultant velocity is    [tex]V=8.72m/s[/tex].

Velocity:

Velocity is the direction in which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.

Given,

Ernie's swimming rate with respect to the river   [tex]V_{ER} =6.2 m/s[/tex]

River's current rate [tex]V_{R}=10.7 m/s[/tex]

Hence,

         The magnitude of Ernie's resultant velocity

                                               [tex]V[/tex] = [tex]V_{R} -V_{ER}=10.7i - 6.2j[/tex]

                                              [tex]V=\sqrt{(10.7)^{2}-(6.2)^{2} }[/tex]

                                              [tex]V=8.72m/s[/tex]

Hence,

           The magnitude of Ernie's resultant velocity is  [tex]V=8.72m/s[/tex].

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which deductible level would result in the lowest premium for automobile insurance?

Answers

The deductible level that would result in the lowest premium for automobile insurance is from  $250 or $500

Is a greater or lower deductible preferable?

For those who anticipate needing expensive medical care or continuous medical treatment, a plan without a deductible typically offers good coverage and is a wise decision.

In most circumstances, a plan's premium will be lower the larger its deductible. You save money on what you pay each month when you're willing to pay more up front when you need care.

The typical range for a comprehensive deductible suggested by insurance agents is between $100 and $500. It makes sense to have a smaller deductible for comprehensive claims because they often involve less damage than collision claims.

High-deductible health plans typically have cheaper premiums but need greater upfront payments before insurance will cover medical expenses. Meanwhile, higher premiums are typically associated with health insurance plans with lower deductibles since they provide more predictable expenses and frequently more robust coverage.

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Can someone please help me with this calculation? It's a bit confusing for me.

You are calculating the average speed, velocity, and acceleration of a toy car.

I'm not sure what the speed of the toy car was or the acceleration. I only have the times of the meters.
first meter: 2.00, second meter: 4.00, third meter: 6.20, fourth meter: 8.01, fifth meter: 10:13, sixth meter: 12:13, seventh meter: 14:13, eighth meter: 16:14, ninth meter 18:18 and tenth meter: 20:00.

Answer the following questions.
Did the car travel at a constant speed? (Hint: you must calculate the speed at every meter)
What was the average speed of the car?
Describe the overall motion of the car.
What are some practical applications for determining the motion of an object?

Answers

Answer: See Explanation

Explanation:

Did the car travel at a constant speed?

This means "Is the speed at each interval the same?"

There are 10 intervals for which to calculate from.

For each one, the speed is the distance traveled divided by the time.

Each interval is 1 meter long (distance).

1st: 1 meter / 2.00 s = 0.5 m/s

2nd: 1 meter / (4.00 - 2.00) s = 0.5 m/s

3rd: 1 meter / (6.2 - 4.0) s = 0.454 m/s

Right here you can see that the speed is different, NO is the answer.

Average Speed = total distance divided by total time

v = d / t     v = (10 m) / (20:00 s) = 0.5 (m/s)

Describe the overall motion: (continue on with step one to see the total motion over the 10 meters)

4th: 0.552

5th: 0.472

6th: 0.5

7th: 0.5

8th: 0.4975

9th: 5.39

10th: 0.55

Overall motion stayed steady from 0-2 meters, slowed for the 3rd meter, sped up for the 4th, slowed down the 5th, stayed steady until slowing down in the 8th meter, then increased speed til the 10th meter.

Races would be practical applications to see where people/cars pace themselves, push themselves, etc.

Question 8 of 20
You heat a pot of water on a gas stove. Not all the energy from the
combustion of the gas is transformed into thermal energy. What happens to
the rest of the energy released when the gas burns?
OA. It is transformed into light energy.
OB. It is transformed into chemical energy.
C. It is transformed into electrical energy.
OD. It is transformed into nuclear energy.
SUBMIT

Answers

Answer:

None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.

Explanation:


A 20 kg wagon is pulled along the level ground by a rope inclined 30 degrees above the horizontal (friction is
negligible) (A) How large is the pulling force is the wagon accelerates of .40 m/s²? (B) What is the normal force of
the wagon?

Answers

Answer:

(A)   9.2 Newtons

(B)   200.8 Newtons

Explanation:

Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.

a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?

Answers

The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.

To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.

Now, we know that momentum =mass × velocity

So, initial momentum of first object=6.2×3=18.6Kg-m/sec

Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec

Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg

Now, both objects are moving with common velocity, so assume both have velocity v

=>So, final momentum of both objects is =14.2×v

according to law of conservation of momentum

=>18.6+25=14.2v

=>43.6=14.2v

=>v=43.6/14.2

=>v=3.07m/sec

Hence, final velocity of objects are 3.07m/sec.

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a 1,402-kg car rounds an unbanked curve with a radius of 53 m at a speed of 9.9 m/s. what minimum coefficient of friction must exist between the road and tires to prevent the car from slipping?

Answers

To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.

The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.

Here m= 1402 kg

r=53

v= 9.9 m/s

g=9.8

coefficient = (v^2) / rg

coefficient = (9.9^2) / (53*9.8)

coefficient = 98.01/519.4

coefficient = 0.188

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