17.
What is the value of the expression
2a + 5b + 3c for a = 12, b = 6, and
C=3?
A 10
B 21
C49
D 63

Answer:

352

Step-by-step explanation:

512 - 256 + 128 - 64 + 32 = 352

Answer:

Perpendicular bisector

Answer:

perpendicular bisector

Answer:

tan 43 =.93

cos 67=.39

sin 39=.63

Step-by-step explanation:

tan 43 = .932515086=.93

cos 67=.390731128=.39

sin 39=.629320391=.63

Answer:

80x⁴

Step-by-step explanation:

[tex](\frac{1}{ax} + 2ax^2)^5 = 5C_0(\frac{1}{ax})^5(2ax^2)^0 + 5C_1(\frac{1}{ax})^4(2ax^2)^1 + 5C_2(\frac{1}{ax})^3 (2ax^2)^2[/tex]

                           [tex]+ 5C_3 (\frac{1}{ax})^2(2ax^2)^3 + 5C_4(\frac{1}{ax})^1(2ax^2)^4 + 5C_5(\frac{1}{ax})^0(2ax^2)^5[/tex]

[tex]5C_0(\frac{1}{ax})^5(2ax^2)^0 =1 \times (\frac{1}{ax})^5 \times 1 = \frac{1}{a^5x^5}\\\\5C_1(\frac{1}{ax})^4(2ax^2)^1 = 5 \times (\frac{1}{ax})^4 \times (2ax^2)^1 = 10 ax^2 \times \frac{1}{a^4x^4} = \frac{10}{a^3x^2}\\\\5C_2 (\frac{1}{ax})^3 (2ax^2)^2= 10 \times (\frac{1}{ax})^3 \times (2ax^2)^2 = 10 \times \frac{1}{a^3x^3} \times 4a^2x^4 = \frac{40x}{a}\\\\5C_3 (\frac{1}{ax})^2 (2ax^2)^3 = 10 \times (\frac{1}{ax})^2 \times (2ax^2)^3 = 10 \times \frac{1}{a^2x^2} \times 8a^3 x^6 = 80ax^4\\\\[/tex]

[tex]5C_4(\frac{1}{ax})^1(2ax^2)^4 = 5 \times \frac{1}{ax} \times 16a^4x^8 = 80a^3x^7\\\\5C_5(\frac{1}{ax})^0(2ax^2)^5 = 1 \times 1 \times 32a^5x^{10}[/tex]

The fourth term of the expansion has the constant a,

the coefficient of a is 80x⁴

Answer:

maybe u missplaced it somehow and it also would depend if you trust that person or not. some times that 'friend' can turn out to be fake but i don't mean it about ur friend. for now, u should just ask, there's no harm in that.

[tex]h(-3) - h( - 2) = - \frac{5}{ 8} \\ \\ [/tex]

Step-by-step explanation:

[tex]\boxed{h(x) = \frac{2 {x}^{2} - x + 1}{3x - 2}}[/tex]

[tex]h(2) = \frac{2 {(2)}^{2} - (2) + 1}{3(2) - 2} [/tex]

[tex]h(2) = \frac{2 {(4)} - 2 + 1}{6 - 2} [/tex]

[tex]h(2) = \frac{ 8 - 1}{4} [/tex]

[tex]h(2) = \frac{7}{4}[/tex]

[tex]h( - 3) = \frac{2 {( - 3)}^{2} - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) = \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) = \frac{18 + 4}{ - 11} \\ h( - 3) = \frac{22}{ - 11} \\ h(-3) = -2[/tex]

[tex]h( - 2) = \frac{2 {( - 2)}^{2} - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) = \frac{2 (4) + 2+ 1}{- 6 - 2} \\ h( - 2) = \frac{8 + 3}{- 8} \\ h( - 2) = \frac{11}{- 8} [/tex]

[tex]h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8} [/tex]

This question is incomplete, the complete question;

At 11:30 a.m. the angle of elevation of the sun for one city is 55.7°. If the height of a monument is approximately 555 ft, what is the length of the shadow it will cast at that time? Round to the nearest foot.

Answer:

the length of the shadow will be 379 ft

Step-by-step explanation:

Given the data in the question and as represented in the diagram below;

height of monument = 555 ft

angle of elevation = 55.7°

From the image below, this makes a right angled triangle

we know that the some of the interior angles of a triangle is 180

so

∠ABC + ∠BCA + ∠CAB = 180°

90° + 55.7° + ∠CAB  = 180°

∠CAB = 180° - 145.7°

∠CAB = 34.3°

Now, using sine rule;

BC / sinA = AB / sinC

so we substitute

BC / sin( 34.3°) = 555 / sin( 55.7° )

BC / 0.563526 = 555 / 0.826098

we cross multiply

BC × 0.826098 = 0.563526 × 555

BC × 0.826098 = 312.75693

BC = 312.75693 / 0.826098

BC = 378.595 ≈ 379 ft

Therefore, the length of the shadow will be 379 ft

Answer:

??????????????????????????

9514 1404 393

Answer:

  3/(√(3(x+h)) +√(3x))

Step-by-step explanation:

The conjugate of a binomial is the same sum, but with the sign changed. That is (a +b) and (a -b) are a conjugate pair: each is the conjugate of the other.

The purpose of multiplying expressions involving roots or complex numbers by their conjugate is to take advantage of the relation ...

  (a +b)(a -b) = a² -b²

Here. you want to eliminate the h from under the radical, so squaring the radical containing h is useful for the purpose. Hence the conjugate gets involved.

"Multiply by the conjugate" means multiply both the numerator and the denominator by the conjugate. (Effectively, multiply by 1.)

__

  [tex]\displaystyle\frac{f(x+h)-f(x)}{h}=\frac{\sqrt{3(x+h)}-\sqrt{3x}}{h}\\\\=\frac{(\sqrt{3(x+h)}-\sqrt{3x})(\sqrt{3(x+h)}+\sqrt{3x})}{h(\sqrt{3(x+h)}+\sqrt{3x})}=\frac{3(x+h)-3x}{h(\sqrt{3(x+h)}+\sqrt{3x})}\\\\=\frac{3h}{h(\sqrt{3(x+h)}+\sqrt{3x})}=\boxed{\frac{3}{\sqrt{3(x+h)}+\sqrt{3x}}}[/tex]

_____

Additional comment

In the end, you will want the limit as h → 0, which will be 3/(2√(3x)). You will notice that h=0 no longer makes the denominator zero, so the limit is found by simple evaluation.

When the "binomial" is a complex number of the form a+bi, its conjugate is a-bi, regardless of the sign of b. That is, the conjugate of a complex number is found by negating its imaginary part. The sign of the real part is left alone.

Answer:

15

Step-by-step explanation:

Because 3/4 of 20 or 75% of 20 is 15

Answer:

11 because <.5 is rounded to the next ten

Answer:

I thinks they take 5 hours to meet each other

Answer: K941,200,000

Step-by-step explanation:

From the question, we are to calculate the amount of earning that PNG can make in a year in cocoa export of 400 000 tonnes at K2 353 per tonne.

This will be:

= Number of tonnes × Amount per ton

= 400000 × k2353

= K941,200,000

Therefore, the answer is K941,200,000

Answer:

7

Step-by-step explanation:

This is correct answer bro...

Answer:

7

Step-by-step explanation:

So first off, two numbers that are to the same root can be combined.

In this case we can combine these two values, since they are to the 5th root and are both 7:

[tex]\sqrt[5]{7*7^4}[/tex]

=

[tex]\sqrt[5]{49^4}[/tex]

This can be broken down into 7^2

This gets us [tex]\sqrt[5]{7^5}[/tex]

Remember that we add exponents, together, so in this case it adds up to 5.

You might be wondering...well if its 7^2 and 7^4, wouldnt it be 7^6?

Well, remember this. One of the 7s in 7^2 is from the 7^4, so tecnically it is 7^3 + 7^2, which is 7^5

Anyway, now we have:

[tex]\sqrt[5]{7^5}[/tex]

When you root a exponent, it works like subtraction.

In this case we have a exponent of 5, and a root of 5.

This is 5-5 = 0

So it will just be 7. Because the square and root cancel each other out, leaving us with 7.

Hope this helps!

Also, I  just watched you waste someone elses answer so you could ask your own question. Instead of wasting other peopes answers, message me on one of my questions or answers, I will help you for free. :D

Answer:

x = 28

Step-by-step explanation:

HFG = EFI

6x - 4 = 164

6x = 164 + 4

6x = 168

x = 168/6

x = 28

Answer:

2/3

Step-by-step explanation:

2/3 is 66 2/3%

Answer:

B, 4x6x7 and 1x3x3.

Step-by-step explanation:

First, remember the formula: V=LWH (Volume equals length times width times height). Lastly, find the equations that match that formula, therefor B, 4x6x7 and 1x3x3 matches the formula, so B  is your correct answer.

Answer:

option A

Step-by-step explanation:

since the given triangle is an isosceles triangle it's two remaining sides are equal

let the length of missing side be x

using pythagoras theorem

a^2 + b^2 = c^2

x^2 + x^2 = 22^2

2x^2 = 484

x^2 = 484/2

x = [tex]\sqrt{242}[/tex]

x = [tex]11\sqrt{2}[/tex]

Answer:

Step-by-step explanation:

Distance = 48 * 4

Distance = 192

~~~~~~~~~~~~~~~

3*50 = 150

192 - 150 = 42

42 MPH for the last hour

Answer:

2.3 =x

Step-by-step explanation:

We know the opposite and adjacent sides.

Since this is a right triangle, we can use trig functions

tan 38 = opp/ adj

tan 38 = x/3

3 tan 38 = x

2.34385688= x

To the nearest tenth

2.3 =x

Answer:

x ≈ 3.9

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 38°

Opposite Leg = x

Adjacent Leg = 5

Step 2: Solve for x

Answer:

x = 18

Step-by-step explanation:

JM = LM

8x - 3 = 141

8x = 141 + 3

8x = 144

x = 144/8

x = 18

Answer:

since its a square each side is equal so

8x-3=141

8x=144

x=18

so

A: x=18

Hope This Helps!!!

Answer:

c

Step-by-step explanation:

Answer:

82.31

Step-by-step explanation:

I believe this is correct, if it isn't feel free to let me know and I will fix it. I'm sorry in advance if this is incorrect.

============================================================

Explanation:

The y intercept of the blue curve f(x) is (0,5)

The y intercept of the red curve g(x) is (0,2)

We see that the y intercept has been shifted down 3 units when going from f(x) to g(x). Overall, the entire f(x) curve has been shifted down 3 units to get the g(x) curve.

Based on that, we would say

g(x) = f(x) - 3

g(x) = (5-x^2) - 3

g(x) = -x^2 + (5 - 3)

g(x) = -x^2 + 2

g(x) = 2 - x^2 ..... answer is choice C

Answer:

2-x^2

Step-by-step explanation:

Answer:

sssssssss

Step-by-step explanation:

ssssssss

Answer:

Miguel's account

Step-by-step explanation:

Miguel's account savings are doubled every month. Hence, they will eventually surpass the savings of Anita, even though Anita's account has more money atm.

Answer:

Miguel's account

Step-by-step explanation:

Even though Anita had more money at first compared to Miguel, Miguel savings will double each month while Anita will get only $200 each month. As a result, Miguel's account will grow faster compared to Anita's.

yes

Substitute x and y into the

equation  we have

0+4 .(-5)=-20

<=>-20=-20

satisfy the condition

Answer:

[tex]CI =0.894%[/tex]

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=4[/tex]

Standard deviation [tex]\sigma=0.76\% of \=x[/tex]

Confidence level [tex]\mu =90\%=0.90[/tex]

Degree of Freedom [tex]Df=n-1=3[/tex]

Therefore

Test T from table is given

 [tex]t=2.353[/tex]

Generally the equation for Confidence interval CI is mathematically given by

 [tex]CI =t*\frac{\sigma}{\sqrt{n}}[/tex]

 [tex]CI =2.353*\frac{0.76}{\sqrt{4}}[/tex]

 [tex]CI =0.894%[/tex]