1
1
A baseball weighs approximately
3
pound. A golf ball weighs about pound.
10
What expression can be used to find the combined weight of a baseball and a golf ball?​

Answers

Answer 1

Answer:

6 pounds 10 ounces

Step-by-step explanation:

I take this to mean "a baseball weighs approximately 3 pounds and a golf ball three pounds ten ounces."

Adding these two weights together, we get 6 pounds 10 ounces.


Related Questions

Lines a and b are parallel. If the slope of line a is , what is the slope of line b?



A.
-

B.
4

C.


D.
-4

Answers

Answer:

C. 1/4

Step-by-step explanation:

Parallel lines always have the same slope.

Answer:

  C.  1/4

Step-by-step explanation:

Parallel lines have the same slope. If line b is parallel to line a, and line a has slope 1/4, then line b has slope 1/4.

Following are the outcomes that are possible when a couple has three children. Refer to that list, and find the probability of each event.
1st 2nd 3rd
Boy Boy Boy
Boy Boy Girl
Boy Girl Boy
Boy Girl Girl
Girl Boy Boy
Girl Boy Girl
Girl Girl Boy
Girl Girl Girl
a. Among three children, there are exactly 2 boys.
b. Among three children, there are exactly o girls.
c. Among three children, there is exactly 1 girl.
1. What is the probability of exactly 2 boys out of three children?
2. What is the probability of exactly 0 girls out of three children?
3. What is the probability of exactly 1 girl out of three children?

Answers

Answer:

a.0.375

b.0.125

c.0.375

1.0.375

2.0.125

3.0.375

Step-by-step explanation:

a.

The total events in a sample space are n(S)=8

The events that contains exactly two boys

Boy Boy Girl,Boy Girl Boy,Girl Boy Boy.

Let A be the event that there are exactly two boys. Thus, n(A)=3.

So, probability of exactly 2 boys is P(A)=n(A)/n(S)=3/8=0.375.

b.

The event that contains exactly 0 girls.

Boy Boy Boy

Let B be the event that contains exactly 0 girls. Thus, n(B)=1.

So, probability of exactly 0 girls is

P(B)=n(B)/n(S)=1/8=0.125.

c.

The events that contains exactly 1 girl.

Boy Boy Girl,Boy Girl Boy,Girl Boy Boy

Let C be the event that contains exactly 1 girl. Thus, n(C)=3.

So, probability of exactly 1 girl is

P(C)=n(C)/n(S)=3/8=0.375.

Q1 is same as part a.

Q2 is same as part b.

Q3. is same as part c

Stefan rode 32.95 miles.
Ben rode 25 4/5 miles. How many more miles did stefan ride than ben?​

Answers

Answer:

7.15 miles

Step-by-step explanation:

4/5 of a mile is equivalent to .8 miles.

32.95

-25.8

7.15

Answer:

Step-by-step explanation:

39.95 - 25.80 = 7.15 miles

While walking from the car into your dormitory you dropped your engagement ring somewhere in the snow. The path is 30 feet long. You are distraught because the density of its location seems to be constant along this 30-foot route. a) What is the probability that the ring is within 12 feet of your car

Answers

Answer:

0.4

Step-by-step explanation:

we are required to find the probability that the ring is within 12 meters from nthe car.

we start by defining a random variable x to be the distance from the car. the car is the starting point.

x follows a normal distribution (0,30)

[tex]f(x)=\frac{1}{30}[/tex]

[tex]0<x<30[/tex]

probabilty of x ≤ 12

= [tex]\int\limits^a_ b{\frac{1}{30} } \, dx[/tex]

a = 12

b = 0

[tex]\frac{1}{30} *(12-0)[/tex]

[tex]\frac{12}{30} = 0.4[/tex]

therefore 0.4 is the probability that the ring is within 12 feet of your car.

A low-noise transistor for use in computing products is being developed. It is claimed that the mean noise level will be below the 2.5-dB level of products currently in use. It is believed that the noise level is approximately normal with a standard deviation of .8. find 95% CI

Answers

Answer:

The 95% CI is   [tex]2.108 < \mu < 2.892[/tex]

Step-by-step explanation:

From the question we are told that

   The  population mean [tex]\mu = 2.5[/tex]

    The standard deviation is  [tex]\sigma = 0.8[/tex]

Given that the confidence level is  95% then the level of confidence is mathematically evaluated as

          [tex]\alpha = 100 - 95[/tex]

   =>  [tex]\alpha = 5\%[/tex]

  =>    [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table, the values is  [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically evaluated as

          [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }[/tex]

here we would assume that the sample size is  n =  16 since the person that posted the question did not include the sample size

  So    

               [tex]E = 1.96* \frac{0.8}{\sqrt{16} }[/tex]

               [tex]E = 0.392[/tex]

The  95% CI is mathematically represented as

              [tex]\= x -E < \mu < \= x +E[/tex]

substituting values

              [tex]2.5 - 0.392 < \mu < 2.5 + 0.392[/tex]

substituting values

              [tex]2.108 < \mu < 2.892[/tex]

       

A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 210 students who averaged 28 texts per day. The standard deviation was 21 texts.A. The sampling distribution follows a_______.1. "F"2. "normal"3. "T"4. "Chi-square" B. With 95% confidence the population mean number of texts per day of is between_______and______texts. A. 1. "24.92"2. "25.79"3. "27.37"4. "25.14"B. 1. "31.19"2. "31.20"3. "29.28"4. "30.86" C. If many groups of 210 randomly selected students are studied, then a different confidence interval would be produced from each group. About_______% of these confidence intervals will contain the true population mean number of texts per day and about______% will not contain the true population mean number of texts per day.A. 1. "5"2. "95"3. "1"4. "99"B. 1. "95"2. "99"3. "5"4. "1"

Answers

Answer: A. The sampling follows a normal distribution.

              B. Between 25.14 and 30.86

              C. About 95% will contain the true mean and about 5% won't

Step-by-step explanation: A. The sampling is normally distributed because:

it has a symmetric bell shape, mean and median are both the same and located at the center of graphic, approximately 68% of the data falls within one standard deviation;95% falls within two standard deviations;99.7% within 3 standard deviations;

B. For a 95% confidence interval: α/2 = 0.025

Since n = 210, use z-score = 1.96

To calculate the interval:

mean ± [tex]z.\frac{s}{\sqrt{n} }[/tex]

Replacing for the values given:

28 ± [tex]1.96.\frac{21}{\sqrt{210} }[/tex]

28 ± [tex]1.96*1.45[/tex]

28 ± 2.84

lower limit: 28 - 2.84 = 25.14

upper limit: 28 + 2.84 = 30.86

Confidence Interval is between 25.14 and 30.86.

C. Confidence Interval at a certain percentage is an interval of values that contains the true mean with a percentage of confidence. In the case of number of times per day students text, 95% of the interval will contain the true mean, while 5% will not contain it.

Assume a bank loan requires an interest payment of $85 per year and a principal payment of $1,000 at the end of the loan's eight-year life. What would be the present value of this loan if it carried a 10% interest rate?

Answers

Answer:

The present value is  [tex]PV = \$ 396,987[/tex]

Step-by-step explanation:

From the question we are told that

   The  interest payment per year is  [tex]C = \$ 85[/tex]

    The principal payment is  [tex]P = \$ 1000[/tex]

     The  duration is  n =  8   years

      The  interest rate is  [tex]r = 10\% = 0.10[/tex]

The present value is  mathematically represented as

      [tex]PV = [ \frac{C}{r} * [1 - \frac{1 }{ (1 +r)^n} ] + \frac{P}{(1 + r)^n} ][/tex]

substituting values

      [tex]PV = [ \frac{85}{0.10} * [1 - \frac{1 }{ (1 +0.10)^8} ] + \frac{1000}{(1 + 0.10)^ 8} ][/tex]

      [tex]PV = \$ 396,987[/tex]

How many multiples of 4, that are smaller than 1,000, do not contain any of the digits 6, 7, 8, 9 or 0? I really need a answer.

Answers

Answer:

Step-by-step explanation:

We could start by listing multiples of 4 and looking for patterns. Do  

you know what a multiple of a number is?  It's that number multiplied  

by another number. So the first multiple of 4 is 4x1, the second  

multiple of 4 is 4x2=8, the third multiple of 4 is 4x3=12, etc.  

Let's make a table of multiples of 4 from 1 to 100, with columns A-E  

across the top and rows 1-5 down the left-hand side:

    A      B      C      D      E

1    4      8     12     16     20

2   24     28     32     36     40

3   44     48     52     56     60

4   64     68     72     76     80

5   84     88     92     96    100

Now let's look at these multiples, remembering that there will be nine  

more tables like this one from 101-1000.

Let's look for 6,7,8,9, and 0 in the columns first. Aha! We can erase  

all of columns B, D, and E because there's a 6 or an 8 or a 0 in each  

number in those columns.  Now we're left with just:

    A      C  

1    4     12  

2   24     32  

3   44     52  

4   64     72  

5   84     92  

Now let's look at the rows. Wow! We can eliminate rows 4 and 5 because  

they have 6, 7, 8, or 9, leaving:

    A      C  

1    4     12  

2   24     32  

3   44     52  

Just 6 numbers left!

So if from 1-100 there are 6 multiples of four that do not contain any  

of the digits 6, 7, 8, 9, or 0, how many multiples of four like this  

are there from 1-1000?

A salesperson earns $99 per day, plus a 9% sales commission. Find a function that
expresses her earnings as a function of sales, and use it to compute her earnings if the
total sales were $999. The salesperson would take home $___ for the day?
$188.00
$188.91
$188.99
$189.99

Answers

Answer:

$188.91

Step-by-step explanation:

$999*.09=$89.91

$89.91+$99=$188.91

Consider the following. (Assume that the coins are distinguishable and that what is observed are the faces or numbers that face up.) Three coins are tossed; the result is at most one head. Which of the following sets of elements are included in the sample space
HHTHTTTTHTTTTHTHHHTHHHTH
List the elements of the given event. (Select all that apply.)
HHT
HTT
TTH
TTT
THT
HHH
THH
HTH
List the elements of the given event. (select all that apply)
HTT
TTH
HTH
THH
THT
HHH
TTT
HHT

Answers

Answer:

Even set = {HTT, THT, TTH, TTT}

Step-by-step explanation:

We are given that three coins are tossed; the result is at most one head.

And we have to find the sets of elements that are included in the sample space.

Firstly, as we know that when three coins are tossed, the total number of cases formed is 8.

Let Head on the coin be represented by 'H' and the Tail on the coin be represented by 'T'.

So, the sample space so formed is;

S = {HHH, HTH, HHT, THH, THT, TTH, HTT, TTT}

Now, our event is at most one head. So, the sample space for the favorable event is given by;

Even set = {HTT, THT, TTH, TTT}

In this, three cases are of head occurring only once and one case is of head not appearing in three tosses of a coin.

In the following studies, state whether you would use a one-sample t test or a two-independent-sample t test.
A. A study testing whether night-shift workers sleep the recommended 8 hours per day.
B. A study measuring differences in attitudes about morality among Democrats and Republicans.
C. An experiment measuring differences in brain activity among rats placed on either a continuous reward schedule (rewarded every time behavior is exhibited) or an intermittent reward schedule (rewarded after every few times behavior is exhibited).

Answers

Answer:

A) one-sample t-test

B) two sample t-test

C) two sample t-test

Step-by-step explanation: The one - sample t-test is used to determine the existence of a statistical difference between a sample mean and a given population mean. The one sample t test is only capable of making comparison between a singular sample mean and an established value. Such is the case in (A) where the aim is to determine if a group of night workers sleep for 8 hours.

The other two cases however, involves making comparison between the sample means of two different groups, this requires the use of a two independent sample t-test

For a one-sample t test:

(Sample mean - population mean) / standard error.

Sample mean = s

Population mean = p

Sample size = n

For a two sample t-test :

[(s2 - s1) - (p2 - p1)] ÷ √[(sd1^2/n1) + (sd2^2/n2)]

A sports club was formed in the month of May last year. The function below, M(t), models the number of club members for the first 10 months, where t represents the number of months since the club was formed in May. m(t)=t^2-6t+28 What was the minimum number of members during the first 10 months the club was open? A. 19 B. 28 C. 25 D. 30

Answers

Answer:

A: 19

Step-by-step explanation:

For this, we can complete the square. We first look at the first 2 terms,

t^2 and -6t.

We know that [tex](t-3)^2[/tex] will include terms.

[tex](t-3)^2 = t^2 - 6t + 9[/tex]

But [tex](t-3)^2[/tex] will also add 9, so we can subtract 9. Putting this into the equation, we get:

[tex]m(t) = (t-3)^2 - 9 +28[/tex]

[tex]m(t) = (t-3)^2 +19[/tex]

Using the trivial inequality, which states that a square of a real number must be positive, we can say that in order to have the minimum number of members, we need to make (t-3) = 0. Luckily, 3 months is in our domain, which means that the minimum amount of members is 19.

Factor quadratic plz 15x^2-4x-4=

Answers

Answer:

x = 2/3 or x = -2/5

Step-by-step explanation:

15x^2 - 4x - 4 = ?

factor the left side of the expression and set factors equal to zero:

(3x-2)(5x+2)=0

3x - 2 =0 or 5x + 2 =0

3x =2 or 5x = -2

x = 2/3 or x = -2/5

Janet has 12 more cookies than Cody. If Janet has 60 cookies, write and solve to determine the number of cookies Cody has.

Answers

Answer:

48

Step-by-step explanation:

Janet - 12 = Cody

60 - 12 = Cody

60 - 12 = 48

The answer to your question is Cody has 48

Which value is a solution to w∕18 ≥ –1?

Answers

Answer:

w ≥ -18

Step-by-step explanation:

Answer:

w is greater than or equal to-18

The lines shown below are parallel. If the green line has a slope of -2, what is the slope of the red line?



A.
2

B.
-2

C.


D.
-

Answers

Answer:

the slope of the read line is also -2

Step-by-step explanation:

Which describes the translation of f(x) to g(x)? translation of four units up translation of five units up translation of four units to the right translation of five units to the right

Answers

Answer:

Option (1)

Step-by-step explanation:

Given question is incomplete; find the picture of the graph in the attachment.

Parent function f(x) = [tex]\frac{1}{2^x}[/tex]

When function 'f' is translated by 4 units up which is evident form the graph, the translated function obtained is,

g(x) = f(x) + 4

g(x) = [tex]\frac{1}{2^x}+4[/tex]

Therefore, Option (1). [Translation of 4 units up] is defined by the graph attached.

Answer:

Option (1)

Step-by-step explanation:

Solve the inequality -3 < 3/2(2-x)<5

Answers

Answer:

Step-by-step explanation:

what are the like terms of the expression.
3x+8x+y+x+8

Answers

Answer:

the like terms are:

3x+8x+x+y+8

12x+y+8

Answer:

The like terms are

3x, 8x, x

Step-by-step explanation:

3x+8x+y+x+8

The like terms are

3x, 8x, x

They are the terms that are in terms of the first power of x

which was the last palindromic date?

Answers

Answer:

The previous palindrome date in all formats came 909 years ago on 11/11/1111. The next will come in 101 years on 12/12/2121 and after that there will not be another until 03/03/3030.

It depends how you format the date. If you do mm/dd/yyyy format

mm = month

dd = day

yyyy = year

then the last palindromic date was September 10th, 2019 since this would be written as 9/10/2019 in the mm/dd/yyyy format

Taking out the slash symbols, we have the number 9102019 which is the same when we reverse the digits.

The answer will be different if you have the date format as dd/mm/yyyy

a sample from a mummified bull was taken from a certain place. The sample shows that 71% of the carbon-14 still remains. how old is the sample

Answers

Answer:

Step-by-step explanation:

Decay of carbon - 14 is exponential in nature . It decays as follows .

[tex]N=N_0e^{-\lambda t}[/tex]  λ is called decay constant .

λ = .693 / T where T is half life .

Half life of carbon-14 is 5700 years

λ = .693 / T

= .693 / 5700

= 12.158 x 10⁻⁵ year⁻¹

[tex]N=N_0e^{-\lambda t}[/tex]

N = .71 N₀

[tex].71 N_0 =N_0e^{-\lambda t}[/tex]

[tex].71 =e^{-\lambda t}[/tex]

Taking ln on both sides

ln .71 = - λ t

ln .71 = - 12.158 x 10⁻⁵  t

-0.3425 =  - 12.158 x 10⁻⁵  t

t = .3425 / 12.158 x 10⁻⁵

2817  years .

convert 8 7/9 yard into in

Answers

Answer:

316.08 inches

Step-by-step explanation:

There are 3 feet in a yard, and there is 12 inches in 1 foot, so there are 36 inches in one yard. If there is 8 7/9 yards it is the same at 8.78 yards, and  8.78 x 36 = 316.08 inches. Therefore 8 7/9 yards = 316.08 inches.

Solve the following equation algebraically:
3x^2=12

a.+3
b. +2
C.+3.5
d. +1.5

Answers

3x^2=12
(3x)^2 =12
9x^2= 12
X= 1.5

Answer:

Step-by-step explanation:

answer is c just took test

How is the following decimal written using bar notation? 3.126666666666...
3. 126
3.126
0 3.126
03.126

Answers

Answer:

_

3.126

Step-by-step explanation:

Bar notation is a way in Mathematics to write decimal number that are repetiting or infinite.

Bar notation symbol is – is placed above the first decimal number that repeats itself. It is easier than writing the same repeating number and over again. It tells us that this particular number with the bar over it, is repeated continuously till infinity

From the above question, we were asked to write 3.126666666666... using Bar notation

_

3.126666666666... = 3.126

The bar is placed over the digit 6

Nala can spend no more than $150 per month on gasoline. She has already purchased $60 in gas this month. Which inequality can be used to find the maximum number of fill-ups she can purchase during the rest of the month, assuming each fill-up costs $30? 30n + 60 > 150 30n + 60 150

Answers

Answer:

150<60+30n

Step-by-step explanation:

150 is the maximum amount that she can spend on gas. (which is the total)

she already spend $60

each fill up (n) costs 30

Answer:

the answer is B)

Step-by-step explanation:

I NEED HELP ASAP PLEASE

Answers

Answer:

3 and 2

Step-by-step explanation:

I can't see your orginal equation. But it's probably 3 cos x . Which the amplitude is 3 then. Vertical translation would be how I move this graph up or down compared to the y axis. So if I were to add a +2 to the end of 3cos(x) I will move the graph up 2 spaces. So my final equation is 3cos (x)+2.

The hypotenuse of a right triangle is 14 in. If the base
of the triangle is 2 inches determine the
length of the remaining side.
14 in
Х
2 in
O A &
B. 318
O c. 8v3
OD. 112

Answers

Answer:

13.85

Step-by-step explanation:

U use the pythagorean theorem

So 2^2 + x^2 = 14^2

Simplify the equation: 4+x^2=196

--> x^2=192

--> x=13.85

-Hope this helps :)

9514 1404 393

Answer:

  c.  8√3

Step-by-step explanation:

The Pythagorean theorem applies.

  14² = s² + 2²

  s = √(14² -2²) = √192 = 8√3

The length of the remaining side is 8√3.

Which best describes the relationship between the line that passes through the points (–6, 5) and (–2, 7) and the line that passes through the points (4, 2) and (6, 6)?

Answers

Answer: intersecting lines

Step-by-step explanation:

Answer:

The relationship of the lines would be Parallel.

You’ve been contracted to wallpaper a wall 10 feet wide and 12 feet high with a square window with 3 foot sides. How many square feet of wallpaper do you need to cover the wall if you were to exclude the opening for the window? _____ square feet

Answers

Answer:

111 ft²

Step-by-step explanation:

wall: 10 x 12 = 120

window: 3 x 3 = 9

wall - window = area to wallpaper

120 - 9 = 111

111 ft²

Answer:

111 sq ft

Step-by-step explanation:

wall: 10 x 12 = 120

window: 3 x 3 = 9

wall - window = area to wallpaper

120 - 9 = 111

111 ft²

Officer Jacobi drove 180 miles in his patrol car during part of May. The distance represents 40% of May. How many miles did he drive all of May? a) 710 miles b) 420 miles c) 720 miles d) 450 miles Need Help on How to work this problem out, what formula would I use?

Answers

Answer:

D: 450 miles

Step-by-step explanation:

So we know that Officer Jacobi drove 180 miles, which represents 40% of the total distance driven. In other words, 40% of the total distance traveled is 180. Thus (let D be the total distance traveled):

[tex]0.4D=180[/tex]

This equation is basically saying that 40% (0.4) of the total distance driven is 180 miles. To solve for the total distance D, we can divide both sides by 0.4. Thus:

[tex]0.4D=180\\D=450[/tex]

So the answer is D or 450 miles.

Note that there isn't a specific formula you would use. These types of problems require you to write out an equation yourself.

Answer: 450 miles


Explanation: When doing percentages, we can use the proportion is/over=%/100.

If we apply this to your problem, we can say 180 miles “is” 40% “of” x (x is the total number of miles driven in May.

Plugging in numbers for is, of, and the % gives us 180/x=40/100

Solving with cross multiplying and dividing gives us 450 miles=x
Other Questions
What is the slope of the line between (3, 4) and (2, 1)? What is the argument of -1 + 3 i? 30 60 120 150 simplify the expression 10 divided by 5 times 3 GIVING 100 POINTS PLEASE ANSWER SOON When ponds freeze, they freeze at the surface first before freezing at the bottom. Which property of water explains why this might happen? Density Adhesion High boiling point High specific heat 5. List the democratic rights we enjoy today whose origins can be traced to theFrenchRevolution Dr. Potter provides vaccinations against polio and measles. Each polio vaccination consists of 6 doses, and each measles vaccination consists of 3 doses. Last year, Dr. Potter gave a total of 60 vaccinations that consisted of a total of 225 doses. How many more measles vaccines did Mr. Potter give than polio? Show All Work !! The weights of cars passing over a bridge have a mean of 3,550 pounds and standard deviation of 870 pounds. Assume that the weights of the cars passing over the bridge are normally distributed. Use a calculator to find the probability that the weight of a randomly-selected car passing over the bridge is less than 3,000 pounds. 600 units of blood were donated. Graph A shows the percentage of each blood type donated. Chart A shows the types of blood recipient can receive. A patient who has a O blood type needs a transfusion. How many units of the donated blood could be used on the patient? Help ASAP! Marking Brainliest ;if you answer and explain Historical documents, written accounts by first-hand witnesses, or objects that have survived from the past are called A bag of chocolates weighs 70 grams. If the weight of the bag increases by 25% find the new weight of the bag. Which statement about this function is true?O A.The value of a is positive, so the vertex is a minimum.OB.The value of a is negative, so the vertex is a minimum.OC.The value of a is negative, so the vertex is a maximum.ODThe value of a is positive, so the vertex is a maximum. Slow 'n Steady, Inc., has a stock price of , will pay a dividend next year of , and has expected dividend growth of per year. What is your estimate of Slow 'and Steady cost of equity capital Compare the New England, Middle and Southern colonies: economics, geography, society please and thank you Please answer this question now Simplify (x + 4)(x2 6x + 3). x3 14x2 + 3x + 12 x3 6x2 17x + 12 x3 10x2 27x + 12 x3 2x2 21x + 12 Write the phrase "the product of 19 and a number" as a mathematical expression.A 19 + xB) 19/xC) 19 x(D) 19 -x Drag each label to the correct location on the table. Each label can be used more than once.Identify the voice used in each sentence.SentencesVoicePhil went to a movie with his friends.The peanut butter is being addedto the cake by the chef.The blue dress had been put ondisplay by the store assistant.Karl gave a touching speech at hisgraduation ceremony.Jacob's party will be attended byeveryone in townFred played with a monkey duringhis first trip to a zooactivepassive should I get a Great Dane puppy or a German Shepred puppy Factor Company is planning to add a new product to its line. To manufacture this product, the company needs to buy a new machine at a $620,000 cost with an expected four-year life and a $34,000 salvage value. All sales are for cash, and all costs are out-of-pocket, except for depreciation on the new machine. Additional information includes the following. (PV of $1, FV of $1, PVA of $1, and FVA of $1) (Use appropriate factor(s) from the tables provided. Round PV factor value to 4 decimal places.) Expected annual sales of new product $ 2,190,000 Expected annual costs of new product Direct materials 494,000 Direct labor 686,000 Overhead (excluding straight-line depreciation on new machine) 476,000 Selling and administrative expenses 174,000 Income taxes 30 % Required: 1. Compute straight-line depreciation for each year of this new machines life. 2. Determine expected net income and net cash flow for each year of this machines life. 3. Compute this machines payback period, assuming that cash flows occur evenly throughout each year. 4. Compute this machines accounting rate of return, assuming that income is earned evenly throughout each year. 5. Compute the net present value for this machine using a discount rate of 4% and assuming that cash flows occur at each year-end. (Hint: Salvage value is a cash inflow at the end of the assets life.)