2. Calculate the force needed to accelerate a ball of mass 200 g by 15 m/s?

Answers

Answer 1

Answer:

Force = 3 Newton

Explanation:

Given the following data;

Mass = 200 g to kilograms = 200/1000 = 0.2 kg

Acceleration = 15 m/s²

To find the force;

Force = mass * acceleration

Force = 0.2 * 15

Force = 3 Newton


Related Questions

a car traveles a distance of 800m in 40s , calculate its distance​

Answers

Answer:

DISTANCE=800M

TIME=40s

Speed=20m/s

Explanation:

Have a nice day

Answer:

the distance is 800m

Explanation:

but i think its velocity

formula = D÷T

now 800m÷40

velocity=20m/s

what is the meaning of physic​

Answers

the scientific study of natural forces such as light, sound, heat, electricity, pressure, etc.

A sample of nitrogen gas is inside a sealed container. The volume of the container decreases while the temperature is kept constant. This is a ________ process.

a) isothermal
b) constant-volume
c) adiabatic
d) isobaric

Answers

I guess it’s d) isobaric mate correct me if I am wrong :D

what do you mean by supplementary quantities and its unit?​

Answers

~Solution :-Supplementary Quantities are geometrical quantities of circle and sphere. Supplementary are the units not still classified either as base or derived.

$ \large\boxed{ \sf \red{More ~Info :}}$

The units of supplementary quantities are dimensionless units.

[tex] \\ [/tex]

Imagine using brainly LOL COULDNT BE ME XD

Answers

Answer:

LOL! couldnt be me either bestieeeee

Answer:

-_-

Explanation:

i dont know What was XD??

determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if period of oscillation is 6 seconds

Answers

Answer:

-0.383 m

Explanation:

Diameter of cylinder = 4m  therefore  r = 2

height of cylinder ( H ) = 4 m

specific gravity = 0.6 ( assumed )

depth of immersion = 'h'

Determine the metacentric height

weight of cylinder in water = water displaced

= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h

= 0.6 * 4 = h

∴ h = 2.4 m

hence the depth of center of buoyancy from free space = h /2 = 1.2 m

The metacentric height can be calculated using the formula below

Gm = Io / Vsubmerged  - BG

attached below is the remaining solution

1. How much heat energy ( Q ) is required to heat 2.0 kg of copper from 30.0 oC to 80.0 oC?

Answers

Answer:

Heat capacity, Q = 38500 Joules

Explanation:

Given the following data;

Mass = 2 kg

Initial temperature, T1 = 30°C

Final temperature, T2 = 80°C

Specific heat capacity of copper = 385 J/Kg°C

To find the quantity of heat required;

Mathematically, heat capacity is given by the formula;

[tex] Q = mcdt [/tex]

Where;

Q represents the heat capacity or quantity of heat.

M represents the mass of an object.

C represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 80 - 30

dt = 50°C

Substituting the values into the formula, we have;

[tex] Q = 2 * 385*50[/tex]

Heat capacity, Q = 38500 Joules

What is the difference between heat capacity and specific heat capacity? I want the meaning please.

Answers

Answer:

The heat capacity of a body is defined as the heat required to raise it's temperature by me degree or one kelvin.while specific heat capacity of a substance is defined as the heat required to the temperature of a unit mass of it through one degree or one kelvin.

I hope it helps

An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magnitude of the velocity?

Answers

Answer:

[tex]v=10^5\ m/s[/tex]

Explanation:

Given that,

Magnetic force acting on an electron, [tex]F=12.8\times 10^{-19}\ N[/tex]

The magnitude of the magnetic field,[tex]B=8\times 10^{-5}\ T[/tex]

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

[tex]F=qvB[/tex]

Where

v is the velocity

So,

[tex]v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s[/tex]

So, the magnitude of velocity is[tex]10^5\ m/s[/tex].

A vector points -43.0 units along the x axis, and 11.1 units along the y axis. Find the Direction of the vector.

Answers

Answer:

Explanation:

The direction of the vector implies only its angle, not its magnitude. The direction of the vector is found in

[tex]tan^{-1}(\frac{y}{x})[/tex] so

[tex]tan^{-1}(\frac{11.1}{-43.0})=-14.5[/tex] but since we are in QII (where x is negative and y is positive) we have to add 180 to this number to get a direction of 165.5 degrees

newtons second law lab report link

Answers

Answer:

ghittu iihg उह्स उउह्स उग्य्किव जिक्ह्ब

Solve this question for 5 points

Answers

Answer:

M_b = 2M_a

Explanation:

From gravity equation, we know that;

g = GM/R²

Where;

g is acceleration due to gravity

G is the gravitational constant

M is mass

Thus, making mass(M) the subject, we have;

M = gR²/G

Since we want to find the mass of B so that value of g on B is half that of its value on A.

Thus;

> g_b = ½g_a

> g_b/g_a = ½

Also, we are told that;

> R_a = ½R_b

> R_b/R_a = 2

If M_a = g_a•R_a²/G

And M_b = g_b•R_b²/G

Thus;

M_b/M_a = (g_b•R_b²/G)/(g_a•R_a²/G)

G will cancel out to give;

M_b/M_a = (g_b•R_b²)/(g_a•R_a²)

Rearranging for ease of simplification, we have;

M_b/M_a = (g_b/g_a) × (R_b/R_a)²

Plugging in the relevant ratios gives;

M_b/M_a = ½ × 2²

M_b/M_a = 2

M_b = 2M_a

Find the magnetic force experienced by a proton moving with the speed of 4x10^5 m/s in the magnetic field B of magnetic 7x10^-5 T.

A- Fmagnetic = 24.8x10^-19 N

B- Fmagnetic = 34.8x10^-19 N

C- Fmagnetic = 44.8x10^-19 N

D- Fmagnetic = 54.8x10^-19 N

Answers

Answer:

F = q v B    where B is the component  of the field perpendicular to v.

F = 1.6E-19 * 4E5 * 7E-5 = 4.48* 10^-18  N = 44.8 * E-19 N

A convex mirror of radius of curvature 1.6 m has an object placed at a distance of 1.0 m from it. Find the position of image and the magnification.​

Answers

Answer:

The image is formed at 0.44 m in front of the mirror

magnification (M) = 0.44

Explanation:

Applying, mirror formular

1/f = (1/u)+(1/v).................... Equation 1

Where f = Focal length of the convex mirror, u = object distance, v = image distance.

Using the real is positive convection,

From the question,

Given: f = -1.6/2 = -0.8 m( The focal length of a convex mirror is vitual), u = 1.0 m

Substitute these values into equation 1

-1/0.8 = (1/v)+(1/1)

Solve for v

1/v = 1.25+1

1/v = 2.25

v = 1/2.25

v = 0.44 m

Hence the image is formed at 0.44 m in front of the mirror

Magnification (M) = v/u

m = 0.44/1

m = 0.44

A blackbody radiator was expected to give off energy of increasing frequency
as its temperature increased. Which of the following ideas provided an
important step toward understanding why this was not observed?
A. Light is quantized and must be absorbed as a unit.
B. Electrons can act as both waves and particles.
C. Matter is quantized and cannot be broken down.
D. Large objects can be viewed as acting as waves.

Answers

Answer:

B.

Explanation:

Makes more sense to me

The Indianapolis speedway consists of a 2.5 mile track having four turns, each 0.25 mile long and banked at 9 12'

Answers

Answer: Your question is missing below is the question

Question : What is the no-friction needed speed (in m/s ) for these turns?

answer:

20.1 m/s

Explanation:

2.5 mile track

number of turns = 4

length of each turn = 0.25 mile

banked at 9 12'

Determine the no-friction needed speed

First step : calculate the value of R

2πR / 4 =  πR / 2

note : πR / 2 = 0.25 mile

∴ R = ( 0.25 * 2 ) / π

      = 0.159 mile ≈ 256 m

Finally no-friction needed speed

tan θ = v^2 / gR

∴ v^2 = gR * tan θ

 v = √9.81 * 256 * tan(9.2°)  = 20.1 m/s

why does the green colour of iron (ii) chloride change to yellow when chlorine gas is bubbled into it

Answers

Answer:

FeCl2 has a high melting point.

Explanation:

Iron is seen to get oxidized by addition of chlorine 3 as the product is rust colored and on dissolving in water has a yellow orange color. This is characterized by the aquatic iron and is due to the monohydroxy

Cuando una persona sube y baja una escalera, Cuanto vale su desplazamiento y cual es la medida de su trayectoria.

Answers

Answer:

Primero, definimos el desplazamiento como la distancia entre la posición final y la posición inicial.

Así, si comenzamos abajo, luego subimos la escalera, y luego bajamos, la posición final y la posición inicial serán la misma

por lo que el desplazamiento es igual a cero.

La medida recorrida es el espacio total recorrido.

Es decir, si entre el principio y el final de la escalera hay una distancia D.

La persona que sube y baja, recorre esta distancia dos veces.

Entonces cuando una persona sube y baja la escalera, la medida de su trayectoria será 2*D.

Mike lives in the northern United States minnesota and nick lives in the southern United States Louisiana. When they both feel insulted by the same individual, nick will be more

Answers

Complete question is;

Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana). When they both feel insulted by the same individual, Nick will be more likely to have a(n) ________ cortisol response and show ________ levels of physical aggression.

Answer:

- A hyper cortisol response

- higher levels of physical aggression

Explanation:

In study of hormones in the human body, it has been discovered that cortisol is a stress inducing hormone. Now, if they are in the summer when it is hot, it has been proven that's when the cortisol hormone circulates in a very large manner in the blood. This leads to frustration and as well possibly physical aggression.

Nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.

What is cortisol?

Cortisol has been identified as a stress-inducing hormone in studies of hormones in the human body.

Mike lives in the northern United States (in Minnesota) and Nick lives in the southern United States (Louisiana).

When they both feel insulted by the same individual, Nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.

Cushing syndrome is a condition characterized by elevated cortisol levels. This disorder is caused by your body producing too much cortisol.

Similar symptoms can occur after large doses of corticosteroids, thus this should be cleared out before testing for crushing syndrome.

Cortisol has been identified as a stress-inducing hormone in studies of hormones in the human body. Now, if they are in the summer when it is hot.

It has been proved that the cortisol hormone circulates in the blood in a very significant amount. This causes irritation and, in some cases, physical aggressiveness.

Hence nick will be more likely to have a(n) hyper cortisol response and show higher levels of physical aggression.

To learn more about cortisol refer to the link

https://brainly.com/question/7519944

radiation is the main way of transferring heat in a vacuum b solid c gas d liquid​

Answers

Answer:

gas

................

Explanation:

hope it helps u

An upright image which reduced in size 10 times occurred in a mirror. If the radius of
curvature of the mirror is 2 m, bow far is the object from the mirror?​

Answers

Answer:

-10/9 m

Explanation:

Radius of curvature, R=2 m

Focal length of mirror, f=R/2=2/2=1 m

Let height of object=h

Height of image, h'=h-10h=-9h

We have to find the distance of object from the mirror.

Magnification, m= [tex]\frac{h'}{h}=-\frac{v}{u}[/tex]

[tex]m=\frac{-9h}{h}=-9[/tex]

Image is upright and small in size it means the mirror is convex.

Focal length of convex mirror is negative.

f=-1m

[tex]-9=-\frac{v}{u}[/tex]

[tex]v=9u[/tex]

Now, mirror formula

[tex]\frac{1}{v}+\frac{1}{u}=-\frac{1}{f}[/tex]

[tex]\frac{1}{9u}+\frac{1}{u}=\frac{1}{1}[/tex]

[tex]\frac{1+9}{9u}=-1[/tex]

[tex]10=-9u[/tex]

[tex]u=-\frac{10}{9} m[/tex]

Hence, the distance of object  from the mirror is -10/9 m

a.
[2]
A train covers 450 km in 5 hr. between Station A and Station B.
What is the average speed of train in km/h and m/s.

Answers

Answer:

90 km/h

50 m/s

Explanation:

Distance = 450 km

Time = 5hrs

Speed = Distance/Time

450/5 = 90 km/h

1 km = 1,000 m

1 hr = 60m = 60 x 60 = 3,600 sec

but since it's 5hrs = 60 x 300m = 18,000

90 x 1,000 = 90,000/18,000 = 50 m/s

Which group of people was most directly affected by the twenty sixth amendment

Answers

adults. 18years olds and older were affected because back then only 21 years olds and older could vote but the 26th amendment changed that
adults were the ones that were affected the most by the 26th amendment

If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?​

Answers

Answer:

[tex]g=25.92\ m/s^2[/tex]

Explanation:

Given that,

The mass of the Jupiter,[tex]M=1.9\times 10^{27}\ kg[/tex]

The radius of Jupiter,[tex]r=69,911\ km=69911\times 10^3 km[/tex]

We need to find the acceleration due to gravity on Jupiter. The formula is

[tex]g=G\dfrac{M}{r^2}[/tex]

Put all the values,

[tex]g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2[/tex]

So, the value of acceleration due to gravity on the Jupiter is [tex]25.92\ m/s^2[/tex].

2. A cinder block is sitting on a platform 20 m high. It weighs 16kg. The block has
_ joules of potential energy.

Answers

Answer:

3136 Joules

Explanation:

Applying,

P.E = mgh.............. Equation 1

Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.

From the question,

Given: m = 16 kg, h = 20 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E = 16(20)(9.8)

P.E = 3136 Joules

Hence the potential energy of the cinder block is 3136 Joules

A bullet from a gun at 30° to the horizontal remains in flight for 25s before touching the ground.Calculate the velocity of the projection.​

Answers

Answer: The velocity of the bullet will be more than half of its earlier velocity

Explanation: I did it on a test and it was right because i calculated 30 degrees within 25 seconds and it was half times the velocity

i hope this helps sorry if i got it wrong

A wire, 20m long, is heated from a temperature of 5°C to 55°C. If the change in length is 0.020m, calculate the linear expansivity of the wire.​

Answers

Answer:

0.01998⁰C;¹

Explanation:

you can see all steps in photo

A mother is pulling a sled at constant velocity by means of a rope at 37°. The tension on the rope is 120 N. Mass of children plus sled is 55 kg. The mother has a mass of 61 kg.
a) Draw FBD for the sled with the kids as one object
b) Draw FBD for the mother
c) Find the normal force on the sled and on the mother
d) Find the kinetic friction acting on the sled and the static friction acting on the mother
e) Find the coefficient of kinetic friction for the sled

Answers

Answer:

Please find the complete solution in the attached file.

Explanation:

A basketball is shot by a player at a height of 2.0 m. The initial angle
was 53° above horizontal. At the highest point the ball was travelling 6
m/s. If he scored (the ball went through the rim that is 3.00 m above the
ground), what was the player’s horizontal distance from the basket?

Answers

Answer:

The answer is "8.28 m".

Explanation:  

[tex]\to u \cos 53^{\circ}=6 \ \text{therefore the horizontal velocity is constant alaways}\\\\\therefore[/tex]

[tex]u= \frac{6 \times 5}{3}= \frac{30}{3}= 10\ \frac{m}{s}\\\\[/tex]

In the projectfile when vertical displacement is 1 then 5 m comes at farther sides

Using  

[tex]S=ut-\frac{1}{2} gt^2\\\\1=u\sin 53^{\circ}\times t-5t^2\\\\1=8t-5t^2\\\\5t^2-8t+1=0\\\\ t=\frac{8\pm \sqrt{64-20}}{10} \\\\=\frac{8\pm 2\sqrt{11}}{10} \\\\t_2=\frac{8+2\sqrt{11}}{10} \\\\[/tex]

[tex]Distance=u \cos 53^{\circ}\times t_2\\\\[/tex]

               [tex]=6 \times \frac{8\pm 2\sqrt{11}}{10} \\\\=\frac{24\pm 6\sqrt{11}}{5} \\\\= 8.28 \ m[/tex]

When 100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C, about how much thermal energy
is absorbed by the ethyl alcohol? (Assume the density of ethyl alcohol to be 0.790 g/mL.)

Answers

Answer:

Q = 194.34  J

Explanation:

Given that,

100.0 mL of ethyl alcohol is heated from 10.0 C to 35.0 C.

We need to find the amount of thermal energy  absorbed by the ethyl alcohol.

The density of ethyl alcohol is 0.790 g/mL.

The formula for heat absorbed is given by :

[tex]Q=mc\Delta T\\\\As, d=\dfrac{m}{V}\\\\So,\\Q=dVc\Delta T\\\\Q=0.79\times 100\times 2.46\\\\Q=194.34\ J[/tex]

So, 194.34  J of thermal energy is absorbed by the ethyl alcohol.

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