20 POINTS!!!!!!!!!!!!!!!!

Answer:

First, you get both of them with same denominator:

3/7 and 2/3 => 9/21 and 14/21, however, there are only 4 rational numbers between 9/21 and 14/21.

The solution is that you can raise the denominator 2 times:

9/21 and 14/21 => 18/42 and 28/42

Now you can select : 19/42, 20/42, 21/42, 22/42, 23/42. They are a group of  5 rational numbers you are looking for.

Answer:

227 ft^2

Step-by-step explanation:

Here, we are tasked with calculating the roaming area that Fido has

Calculating this is same as calculating the area of circle that has a radius which is equal to the length of the leash

Mathematically, the area would be

A = π * r^2

A = 3.14 * 8.5^2

A = 226.865 ft^2

To the nearest square foot, this is 227 ft^2

Answer: 6

Step-by-step explanation:

in a 30 60 90 triangle the hypothenuse is [tex]2a[/tex], long side is [tex]a\sqrt{3}[/tex], and the short side is [tex]a[/tex]

Answer:

?

Step-by-step explanation:

1.add all numbers up.

2. put each number onto a fraction.

3. then the rest you should know

Answer: $2936.27

Step-by-step explanation:

Present value = $1663

Rate = 5.5%

Time(n) = 19years

Future value= PV(1+r)^n

= 1663(1+5.5%)^19

= 1663(1.055)^19

=1663 × 2.766

=4599.86

Interest = Future value - Present value

= $4599 - $1663

= 2936

Answer:

B:subtraction property

Step-by-step explanation:

[tex]\text{Simplify:}\\\\2(-n -3) - 7(5+2n)\\\\\text{Use the distributive property}\\\\-2n-6-35-14n\\\\\text{Combine like terms}\\\\-2n-6-35-14n\\\\-16n-6-35\\\\\boxed{-16n-41}[/tex]

Answer:

-9x + x = 17 – 1  

8x = 16

X = 16/8  

X=2

Answer:

Arc EPF is 240°

Step-by-step explanation:

Since the quadrilateral, EFGH is a trapezoid and EF is parallel to GH, we have;

∠HGF + ∠GFE = 180°

∠GHE + ∠GFE = 180°

∠HGF + ∠HEF = 180°

∴∠HEF = ∠GFE

In ΔHEF and ΔGFE

∠EHF = ∠EGF (Angles subtending the same segment)

With side EF common to both triangles and ∠HEF = ∠GFE , we have;

ΔHEF ≅ ΔGFE (Angle Angle Side rule)

Hence, side FG = EH

For cyclic trapezoid side FG = EH

The base angles subtended by GH = 70

Arc EH = x² - 2·x

Arc FG = 56 - 3·x

Therefore;

70 + x² - 2·x + 56 - 3·x + arc EPF = 360 .............(1)

Also since the equation of a circle is (x-h)² + (y-k)² = r², where the center of the circle is (h, k), then as EF is a displacement of say z from GH, then arc EH = FG which gives;

x² - 2·x = 56 - 3·x

x² - 2·x - 56 + 3·x = 0

x² + x - 56 = 0

(x - 7)(x + 8) = 0

Therefore, since x > 0 we have x = 7

Plugging in the value of x into the equation (1), we have

70 + 7² - 2·7 + 56 - 3·7 + arc EPF = 360 .............(1)

70 + 70 + arc EPF = 360

arc EPF = 360 - 140 = 240°.

Answer:

A B E

Step-by-step explanation:

A- w less-than-or-equal-to 3.6

B- The arrow points left.

E- There is a closed circle at 3.6.

Answer:

A B E

Step-by-step explanation:

Answer:

She would have $1,126.16 in 3 years.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.

In this question:

Invested 1000, which means that [tex]P = 1000[/tex].

Interest of 4%, so [tex]r = 0.04[/tex]

Semianually is twice a year, so [tex]n = 2[/tex]

How much money would she have in 3 years?

This is A(3).

[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]

[tex]A(3) = 1000(1 + \frac{0.04}{2})^{6} = 1,126.16[/tex]

She would have $1,126.16 in 3 years.

Answer:

Rocket A: The x-intercept= (0,0) and (7,0)

Maximum= (3.5, 220.5) *idk if your teacher wants x's or y's

Average Rate of Change over [0,2]= 90

Rocket B: The x-intercepts are=(0,0) and (4,0)

Maximum=(2,32)

Average Rate of Change over [0,2]= 16

Rocket A is faster

Step-by-step explanation:

Rocket A: graph on demos

when x is 2 y is 180 180/2=90

Rocket B: i graphed the points on demos and imagined maximun of the graph

(it also tell you the x-intercepts)

32/2=16

Hope this helps

Answer:

1/12 my guy

Step-by-step explanation:

There really isn't one

Answer:

Would be 0.08333 or 1/12

Step-by-step explanation:

Answer:

Step-by-step explanation:

Insufficient dimensions are given to compute an exact volume of each geometry, so we have to assume that the volume is proportional to the product of base area and height. Then the relative volumes will be ...

  bottle X: (6 in)(2 in)(1 in) = 12 in^3

  bottle Y: (4 in)(3 in)(1.5 in) = 18 in^3

  3rd bottle: (3 in)(6 in^2) = 18 in^3

That is, the relative volumes are ...

  X : Y : 3rd = 12 : 18 : 18 = 1 : 1.5 : 1.5

The corresponding relative prices are ...

  X : Y : 3rd = 9.96 : 14.40 : 13:20 = 1 : 1.446 : 1.325

__

A. Bottle Y has 1.5 times as much lotion as Bottle X.

__

B. Bottle Y is a better buy than Bottle X. (The price relative to X is less than the volume relative to X.)

__

C. The 3rd bottle is the best buy. For the same volume, the price of the 3rd bottle is less than that of Bottle Y.

_____

Note that the relative volume and price ratios are found by dividing all the numbers in the ratio sequence by the first number:

  12 : 18 : 18 = (12/12) : (18/12) : (18/12)

  9.96 : 14.40 : 13.20 = (9.96/9.96) : (14.40/9.96) : (13.20/9.96)

Answer:

D

Step-by-step explanation:

If AB is a tangent, then angle A must be a right angle.

If angle A is a right angle, then triangle ABC is a right triangle and will work in the Pythagorean theorem formula.

a^2 + b^2 = c^2

8^2 + 16^2 = 20^2

64 + 256 = 400

320 = 400

Since 320 = 400 is false, angle A is not a right angle, and AB is not a tangent to circle C.

Answer: D

Answer:

h = V/lw and the height = 6cm

Step-by-step explanation:

h = V/lw

V= [tex]96cm^{3}[/tex]

l = 8 cm

w = 2cm

V/lw = 6

Thus, the height = 6cm

Answer:Yes

Step-by-step explanation:

Given

Triangle has sides

length [tex]a=5\ in.[/tex]

[tex]b=12\ in.[/tex]

[tex]c=13\ in.[/tex]

If the triangle is Right angled then it must satisfy the Pythagoras rule

[tex](\text{Perpendicular})^2+(\text{base})^2=(\text{Hypotenuse})^2[/tex]

[tex](a)^2+(b)^2=(c)^2[/tex]

[tex]5^2+12^2=13^2[/tex]

[tex]25+144=13^2[/tex]

[tex]169=13^2[/tex]

[tex]13^2=13^2[/tex]

Therefore The given triangle is right angled

Answer:

The product of (x + 1)(x² + 2x + 2) is

x³ + 3x² + 2x + 4

Step-by-step explanation:

The product of (x + 1)(x² + 2x + 2) is Given in the steps below.

(x + 1)(x² + 2x + 2) = x(x² + 2x + 2) + x² + 2x + 2

= x³ + 2x² + 2 + x² + 2x + 2

= x³ + 3x² + 2x + 4

Answer:

Area of Shaded Region = (25π - 24) cm²

Step-by-step explanation:

See attachment

From the attached, the following observations are made;

Radius, r = 5cm

Base of triangles = 6cm.

Required

Area of shaded region.

If the distance between the base of the triangle to the outline of the circle is 1cm then the height of the triangle is 1cm less than the radius

Height = 5cm - 1cm

Height = 4cm

To calculate the area of the shaded region, we first calculate the area of the circle.

Area = πr²

Substitute 5 for r

Area = π * 5²

Area = π * 25

Area = 25π cm²

Then we calculate the area of both triangles

Area of 1 triangle is calculated as follows.

Area = ½ * base * height

Substitute 4 for height and 6 for base.

Area = ½ * 4 * 6

Area = 2 * 6

Area = 12cm²

Since both triangles are equal.

Area of two triangles = 2 * Area of 1 triangle

Area = 2 * 12cm²

Area = 24cm²

Having calculated the area of the circle and that of both triangles.

Area of shaded region = Area of Circle - Area of Triangles

Area of Shaded Region = 25π cm² - 24 cm²

Area of Shaded Region = (25π - 24) cm²

Answer:

The third one

Step-by-step explanation:

Answer: No

Step-by-step explanation:

Because Mode is not the best centre of tendency use for statistical data. And mode cannot be used for average.

Mean should be used for average values

Answer:

da ba dee da ba doo im blue

Step-by-step explanation:

Grace made a dot plot showing the distances she ran each day for two weeks.

She says that she usually runs 7 miles each day because that is the distance that occurs most often.

Do you agree with Grace’s reasoning?

Use the drop-down menus to explain and show your answer.

Dot plot named as ALTDCDistances RunALTDC has number line from 1 to 7. 1 dot on 1, 3 dots on 2, 3 dots on 3, 3 dots on 4 and 4 dots on 7 are given.

The mode, which is (3,4, or 7) ,(is or is not) a typical distance for the data. The median, which is (3.5,4, or 7),(is or is not) a typical distance for the data. The mean, which is (3,4, or 7) ,(is or is not) a typical distance for the data. So, Grace’s reasoning(is or is not ) correct.

Answer:

What’s the third length?..

Step-by-step explanation:

Answer:

y = 1/3X - 6

Step-by-step explanation:

Answer:

The  area of triangle B is [tex]2.72cm ^{2}[/tex]

Step-by-step explanation:

We will use the principle of similar triangles to solve the problem.

Since triangle A is just a scale version of triangle B, we can say that the two triangles are similar.

The area scale factor is the square of the length scale factor.

Given the length scale factor as 3,

The area scale factor will be 3 X 3 = 9 sq. cm

(Area of triangle A / Area of triangle B) =  (length of side A / Length of side B) square

[tex]\frac{24.5}{ area of B}= 3^{2}[/tex]

[tex]\frac{24.5}{Area of B}= 9\\Area of B = \frac{24.5}{9}= 2.72 cm ^{2}[/tex]

The  area of triangle B is [tex]2.72cm ^{2}[/tex]

Answer:

4th option: 1953.08 mm

Step-by-step explanation:

circumference of circle= [tex]\pi d[/tex]

Thus, circumference of wheel

[tex] = 3.14(622) \\ = 1953.08mm[/tex]

Answer:

D.

Step-by-step explanation:

Answer:

1:2

Step-by-step explanation:

Let's say there are x males and y females in the class.

The sum of all male weights will be 72x, and the sum of all female weights will be 60y.

If we get a class mean weight, we have:

(72x + 60y) / (x+y) = 68

72x + 60y = 68x + 68y

4x = 8y

y / x = 4/8 = 1/2

So the ratio of females to males is the class is 1:2

Answer:

1

Step-by-step explanation:

-2x+9y=15

x+7=4 ​

Solve for X.

x +7=4

   -7.  -7

x = -3

Plug in X into the first equation

-2(-3) + 9y = 15

6 + 9y = 15

-6.           -6

9y = 9

Divide by 9 on both sides

9/9=1

Answer:

x = -3. | y = 1. | (-3,1)

Step-by-step explanation:

-2x+9y=15

x+7=4

-7. -7

x= -3

-2(-3) + 9y =15

6 + 9y= 15

-6. -6

9y = 9

÷9. ÷9

y = 1

Answer:

it would be 1/6 divided by 2, or the seond option.

Step-by-step explanation:

To split something equally, you'd divide it in half. In other words, you'd be dividing it by 2.

Therefore, it would be 1/6 divided by 2, or the seond option.

I hope this helped and have a good rest of your day!

Answer:

5x-(9x+14)=−4x−14

3(x+10)-2=3x+28

So, 3(x+10)-2 is greater than 5x-(9x+14)

Answer: C. Outside the circle.

Step-by-step explanation:

To find whether point M lies on the circle, first derive the equation of the circle from the radius and center given.

Equation of a circle:

[tex](x-h)^2 + (y-k)^2=r^2[/tex]

Substitute the coordinates (0, 0) for h and k, and 2 times the square root of 3 for r:

[tex]x^2 + y^2 = 12[/tex]

Now, substitute the points (-3, 2) for x and y:

[tex]9 + 4 = 12[/tex]

This equation is incorrect, as the (x, y) coordinates produce a greater value than the radius of the circle squared. When this occurs, the point given is outside of the circle.

(A point like (1, 1), when substituted into the equation and solved to get 1 + 1 = 12, would be inside the circle, as its (x, y) coordinates produce a smaller value than the radius of the circle squared.)

As such, the correct answer is C.

Answer:

5. 34°

6. 29.7

Step-by-step explanation:

5. Using sine law

25/sin(93) = 14/sin(C)

sin(C) = 0.5592325395

C = 34.00273934°

6. Using cosine law

AC² = 23.2² + 18.1² - 2(23.2)(18.1)cos(91)

AC² = 880.507229

AC = 29.67334206

Answer:

5. m∠C ≈ 34°

6. AC ≈ 29.7 metres

Step-by-step explanation:

5. We need to use the Law of Sines here, which says that for a triangle with sides a, b, and c and angles A, B, and C:

[tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]

Here, a = 25, ∠A = 93°, and c = 14, so we want to find ∠C:

[tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]

[tex]\frac{25}{sin93} =\frac{14}{sinC}[/tex]

sinC ≈ 0.56

∠C ≈ 34°

6. We need to use the Law of Cosines here, which says that for a triangle with sides a, b, and c and angles A, B, and C:

[tex]c^2=a^2+b^2-2abcosC[/tex]

[tex]b^2=a^2+c^2-2accosB[/tex]

[tex]a^2=b^2+c^2-2bccosA[/tex]

Here, a = 23.2, c = 18.1, ∠B = 91°, and b = x. We want to find b, so:

[tex]b^2=a^2+c^2-2accosB[/tex]

[tex]x^2=23.2^2+18.1^2-2*23.2*18.1*cos(91)[/tex] ≈ 880.5

x ≈ 29.7 metres