20 pts.





Which of the following statements is true?
O Electromagnets use electrlcity and magnets.
O Magnetic fields are strongest around the poles of a magnet.
O The south pole of a magnet will repel the south pole of another magnet.
O all of the above

In an open circuit like the picture the light bulb will be off. So, option (C) is correct.

Electric circuit is a way for current to flow through electricity. An electric circuit consists of a source of energy for the charged particles that make up the current, like a battery or generator; sources of current-using equipment, like lamps, electric motors, or computers; and the connecting wires or transmission lines.

Ohm's law and Kirchhoff's rules are two of the fundamental mathematical laws that define how electric circuits function.

In the given diagram, the circuit is open. So, no current passes through it and the light bulb will be off. Hence, option (C) is correct.

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Answer:

Answers at the bottom!!

Explanation:

For the first answer: Gamma ray

Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.

For the second answer: They both have technological uses.

In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.

Hope this helps!!

Happy Holidays and Season Greeting!!

ii Feliz Navidad a todos !!

Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.

"A gamma ray (g) is a packet of electromagnetic energy (photon) emitted by the nucleus of some radionuclides following radioactive decay." Gamma photons are the most energetic photons in the electromagnetic spectrum.

"An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation." Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz and energies in the range 145 eV to 124 keV.

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They both have technological uses.

Microwaves and x-rays have in common is all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other.

"The application of practical sciences to industry or commerce." The methods, theory, and practices governing such application. a highly developed technology.  The total knowledge and skills available to any human society for industry, art, science, etc.

Microwaves are used in spacecraft communication, and much of the world's data, TV, and telephone communications are transmitted long distances by microwaves between ground stations and communications satellites. Microwaves are also employed in microwave ovens and in radar technology.

They are used on such products as aircraft and rocket parts and structures, canned and packaged foods, electronics, semiconductors and microchips, thermal insulations, and automobile tires. Material processing technologies use X-ray systems to automatically control the density or thickness of layers of substances.

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[tex]{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}[/tex]

[tex]\longrightarrow[/tex] The rate of change of velocity per unit time is called acceleration.

[tex]\longrightarrow[/tex] Its SI unit is m/s².

[tex]\huge\boxed{\fcolorbox{blue}{red}{Thank you}} [/tex]

we have that from the Question"Which of the following is the cause of an acceleration?" it can be said that  

From the Question we are told

Which of the following is the cause of an acceleration?

Generally the equation for acceleration is mathematically given as

[tex]a=\frac{F}{m}\\\\or\\\\a=\frac{u-v}{dt}\\\\[/tex]

Therefore

So in the selection of the option consider these points of acceleration

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The power required by the car if a 1430 kg car speeds up from rest to 14.0 m/s in 7.00 s is 20020 Joules.

In science and engineering, power is the rate at which work is completed or energy is delivered. It can be expressed as the product of the work completed (W) or the energy transferred (E) divided by the time interval (t), or W/t.

A high-powered motor can complete a given amount of work quickly, or a low-powered motor can accomplish it slowly. Foot-pounds per minute, joules per second (or watts), and ergs per second are examples of units of power, which measure work (or energy) per unit of time.

Given:

A 1430 kg car speeds up from rest to 14.0 m/s in 7.00 s,

Calculate the acceleration and displacement as shown below,

[tex]v = u + at[/tex]

14 =  0 + a × 7

a = 2 m/s²

[tex]s = ut + 1/2at^2[/tex]

s = 0 + 1 / 2 × 2 × 7²

s = 49 m,

Calculate the power as shown below,

Power = 1430 × 2 × 49 / 7

Power = 20020 Joules

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Answer:

50 km/h

Explanation:

200 km = 4 hours

200/4=50

50km/h

Answer:

Yes, it is easier to climb a slanted slope than a vertical or more steep slope.

Explanation:

On a vertical slope, you are climbing higher instead of farther so on each step gravity weighs you down much more than on a gentle slope

Answer:

40N in either direction is the answer

Answer

100N on the left force

Explanation:

You have to subtract 250 - 100 and the reamaining would be 100 and that 100 would go to the left force since it was the higher number

Given :

A copper plate of mass 3.0g.

Atomic number, z = 29.

Atomic mass, M.M = 63.5 g/mol.

Avogadro's number, [tex]N_a = 6.02\times 10^{23}\ atoms[/tex].

Charge on electron, [tex]e = 1.6\times 10^{-19}\ C[/tex].

To Find :

The total charge of all the electrons.

Solution :

Moles of copper,

[tex]m = \dfrac{3}{63.5}\ moles\\\\m = 0.047 \ moles[/tex]

Number of atoms in 0.047 moles of copper :

[tex]n = 0.047\times 6.02\times 10^{23}\\\\n = 2.83\times 10^{22} \ atoms[/tex]

Since, there are 29 electrons on each atoms.

So, total charge is :

[tex]C = 2.83\times 10^{22}\times 29\times 1.6\times 10^{-19}\ C\\\\C = 131312\ C\\\\C = 1.31 \times 10^5\ C[/tex]

Hence, this is the required solution.

it would be the 3rd one. so C

Answer: Age

Explanation:

Physical fitness has to do with the effective and efficient working of the body system which allows individuals to be healthy.

The factors that are critical in developing good physical fitness include the environment, the behavior of the individual and heredity. To maintain physical fitness, one should exercise, eat healthy, avoid smoking etc. Age is not a factor in physical fitness.

Answer:

The disk covers a rotation of 90º after 3 seconds.

Explanation:

Since the disk rotates at constant angular speed, we can determine the change in angular position ([tex]\Delta \theta[/tex]), measured in sexagesimal degrees, by the following kinematic formula:

[tex]\Delta \theta = \omega\cdot \Delta t[/tex] (1)

Where:

[tex]\omega[/tex] - Angular velocity, measured in sexagesimal degrees per second.

[tex]\Delta t[/tex] - Time, measured in seconds.

If we know that [tex]\omega= 30\,\frac{\circ}{s}[/tex] and [tex]\Delta t = 3\,s[/tex], then the change in angular position is:

[tex]\Delta \theta = \left(30\,\frac{\circ}{s} \right)\cdot (3\,s)[/tex]

[tex]\Delta \theta = 90^{\circ}[/tex]

The disk covers a rotation of 90º after 3 seconds.

Answer:

-240

Explanation:

A motorcycle skids for a distance of 2.0 m on an icy road, then the change in kinetic energy for the motorcycle will be equal to -240 J.

The force which a moving object has is referred to as kinetic energy in physics. It is defined as the number of effort required to propel a person of a specific mass from still to a specific velocity.

Aside from slight fluctuations in speed, your body holds onto the kinetic energy it obtains during acceleration.

When the body slows down from its present level to a condition of rest, the same quantity of energy is used.

Formally, kinetic energy is any quantity that has a gradient concerning time in the Lagrangian of a system.

As per the given information in the question,

Distance, d = 2.0 m

Friction, f = 120 N

The angle between displacement and friction force, θ = 180°

Now, the change in kinetic energy for the motorcycle = Work done by the friction.

K.E = f × d(cos θ)

= 120 (2.0 m)(cos 180°)

Δ K.E = -240 J

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[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

Answer:

F = 6[N].

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.

[tex]P=m*v\\or\\P=F*t[/tex]

where:

P = impulse or lineal momentum [kg*m/s]

m = mass = 10 [kg]

v = velocity [m/s]

F = force [N]

t = time = 5 [s]

Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.

[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]

where:

m₁ = mass of the object = 10 [kg]

v₁ = velocity of the object before the impulse = 1 [m/s]

v₂ = velocity of the object after the impulse = 4 [m/s]

[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]

Answer:

An applied force, A resistive force

Explanation:

An applied force is an interaction of one object on another that causes the second object to change its velocity.

A resistive force passively resists motion and works in a direction opposite to that motion.

Answer:

The value is  [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

Explanation:

From the question we are told that

     The mass of the object is  [tex]m_1 = 5.0 \ g = 0.005 \ kg[/tex]

     The net charge is  [tex]q = 3.8 \mu C= 3.8 *10^{-6} \ C[/tex]

     The mass of the second object is   [tex]m_1 = 2.0 \ g = 0.002 \ kg[/tex]

Generally for the first object the potential energy gained at the end of its acceleration is equal to its  kinetic energy

i.e

            [tex]\frac{ 1}{ 2} * m_1 * v^2_1 = q_1 * \Delta V \ \ --- (1)[/tex]

Here [tex]v_1[/tex] is the velocity of the first object

        [tex]\Delta V[/tex] is the potential difference through which it is accelerated  

Generally for the second object the potential energy gained at the end of its acceleration is equal to its  kinetic energy

i.e

            [tex]\frac{ 1}{ 2} * m_2 * v^2_2 = q_2 * \Delta V[/tex]

Here [tex]v_2[/tex] is the velocity of the second object and from the question it is

        [tex]v_2 = 2 v_1[/tex]

        [tex]\Delta V[/tex] is the potential difference through which it is accelerated        

So

          [tex]\frac{ 1}{ 2} * m_2 * (2v)^2_1 = q_2 * \Delta V[/tex]

=>        [tex]m_2 * 2v^2_1 = q_2 * \Delta V \ \ ---(2)[/tex]

Generally dividing equation 2 by equation 1

            [tex]\frac{2m_2 v^2_1 }{ \frac{1}{2} * m_1 * v_1^2} = \frac{q_2 \Delta V }{ q_1 * \Delta V}[/tex]

=>         [tex]q_2 = \frac{4m_2 * q_1 }{m_1}[/tex]

=>         [tex]q_2 = \frac{4* 0.002 * 3.8 *10^{-6} }{0.005}[/tex]

=>         [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

=>         [tex]q_2 = 6.1 *10^{-6} \ C[/tex]

Answer:

a = 0.1 m/s²

Explanation:

       [tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]

       [tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]

        [tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]

Answer:

7.21m/s

Explanation:

Using the law of conservation of momentum expressed as;

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the mass of the man and the stone respectively

u1 and u2 are their respective initial velocities

v is their final common velocity

Given

m1 = 96kg

m2 = 75g = 0.075kg

u1 = ?

u2 = 0m/s (initial speed of the stone)

v = 7.2m/s

Substitute into the firmula and get u1

96u1 + 0.075(0) = (96 + 0.075)(7.2)

96u1 = 96.075(7.2)

u1 = 691.74/96

u1 = 7.21m/s

Hence the man acquired a speed of 7.21m/s