20 things that can be found in the poultry farm for chicken​

Answers

Answer 1

Answer:

1. Chicken

2. Air

3. Floor

4. Walls

5. Roof

6. Eg

7. Free Real Estate

8. You

9. Atoms

10. ****

11. Stuff

12. Nothing

13. Depression

14. Hobo

15. Stranger selling you kidneys for your time.

16. A question

17. Portal to another dimension

18. Waste of Time

19. Memes

20. A chicken is you!

Explanation:

The world cannot be explained, silence youth.


Related Questions

Which is a characteristic of the PSAT?

A. If you earn a high enough score you do not need to take the SAT
B. It is made up of mostly multiple choice questions
C. You usually take it as a high-school freshman
D. You are eligible for scholarships if you take it as a high school sophomore

Answers

I believe it’s B, ive taken it a few times and it’s mostly multiple choice.
it’s either c or b...i took it as a freshman but it was also multiple choice.

Consider the table below and answer the probability question. Write your answer as a percentage rounded to 1 decimal.
Kroger Wal-Mart Trader Joe's Total
South side 50 102 34 186
North side 61 92 70 223
Total 111 194 104 409
What is the probability that someone shops at Trader Joe's?

Consider the table below and answer the probability question. Write your answer as a percentage rounded to 1 decimal.

Kroger Wal-Mart Trader Joe's Total
South side 50 102 34 186
North side 61 92 70 223
Total 111 194 104 409
What is the probability that someone shops at Trader Joe's and lives on the North side?


what the answer hurry help please give brainiest

Answers

Answer:

[tex]P(Joe) = 0.3[/tex]

[tex]P(Joe\ \&\ North\ Side) = 0.2[/tex]

Explanation:

Solving (a): P(Joe)

To get this probability, we simply add up the items in the column named Joe.

These items are:

Joe: 34 and 70

And the total is:

[tex]Joe = 34 + 70[/tex]

[tex]Joe = 104[/tex]

The overall population of the system is:

[tex]Total = 409[/tex]

So:

[tex]P(Joe) = \frac{Joe}{Total}[/tex]

[tex]P(Joe) = \frac{104}{409}[/tex]

[tex]P(Joe) = 0.3[/tex]

Solving (a): P(Joe and North Side)

To get this probability, we simply get the intersecting element of Joe column and North Side row.

From the table, the intersecting element is:

Joe and North Side: 70

The overall population of the system is:

[tex]Total = 409[/tex]

[tex]P(Joe\ \&\ North\ Side) = \frac{Joe\ \&\ North\ Side}{Total}[/tex]

[tex]P(Joe\ \&\ North\ Side) = \frac{70}{409}[/tex]

[tex]P(Joe\ \&\ North\ Side) = 0.2[/tex]

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