The molar mass of the unknown gas in the 500 mL flask at stp is 89.7 g/mol
We'll begin by calculating the number of mole of the gas that occupied 500 mL at stp.
Recall at stp:
22400 mL = 1 mole of the gas
Therefore,
500 mL = 500 / 22400 = 0.0223 mole of gas.
Finally, we shall determine the molar mass of the gas. This can be obtained as follow:
Mass of gas = 2 g
Mole of gas = 0.0223 mole
Molar mass of gas =?Molar mass = mass / mole
Molar mass of gas = 2 / 0.0223
Molar mass of gas = 89.7 g/molTherefore, the molar mass of the unknown gas is 89.7 g/mol
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Calculate the volume of a liquid with a density of 5.45 g/mL and a mass of 65 g.
Answer:
The answer is 11.93 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
[tex]volume = \frac{mass}{density} \\ [/tex]
From the question we have
[tex]volume = \frac{65}{5.45} \\ = 11.926605...[/tex]
We have the final answer as
11.93 mLHope this helps you
What is the volume in liters of 222 g of neon if neon has a density of 0.900 g/L?
Answer:
[tex]V=247L[/tex]
Explanation:
Hello there!
In this case, since the density is defined as the degree of compactness of a substance and is computed by diving the mass over the volume it occupies:
[tex]\rho =\frac{m}{V}[/tex]
Given the density and the mass of the neon, we can compute its density as shown below:
[tex]V=\frac{m}{\rho} =\frac{222g}{0.900g/L}\\\\V=247L[/tex]
Best regards!
The volume of neon in liters is 246.67 L.
To calculate the volume of neon, we use the formula below.
Formula:
D = m/V............... Equation 1Where:
D = Density of neonm = mass of neonV = Volume of neon.make V the subject of the equation.
V = m/D............... Equation 2From the question,
Given:
m = 222 gD = 0.900 g/LSubstitute these values into equation 2
V = 222/0.9V = 246.67 L.Hence, The volume of neon in liters is 246.67 L.
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Which letter? Thanks in advance!
Answer: b
Explanation:
please help 10 points asap
Answer:
opposite
Explanation:
Answer:
opposite
Explanation:
cu9c9ucoucucpucfpufupfpucupvpjvpucu
What are the products of photosynthesis
Answer:Glucose, Oxygen and Water
Explanation:
Answer:
Hello i have don this... : )
Explanation:
It is oxygen and glucose
Have a good day im 100% sure this is... i forgot but it is before or after the asexual and sexual lessons
I added a meme for no reason you will only get it if you have read heroes of Olympus
A scientist who collects and analyzes DNA from a crime scene is a
Answer:
forensic scientist
Explanation:
forensic science is the discipline in which professionals use scientific means to analyze physical crime evidence. this evidence is then presented in court in order to help determine the innocence or guilt of a specific suspect.
Answer:
Its a forensic scientist :D
Explanation:
I took a test and got it wrong but it showed the right answer and its a forensic scientist
(don't ask how i got it wrong i was rushing!!)
In the reaction of: ????2O4 (g) ⇌ 2????O2(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of ????2O4 = 0.0500 ????. What are the equilibrium concentrations of ????2O4 and ????O2 under these conditions?
Answer:
[N₂O₄] = 0.00411 M
[NO₂] = 0.0918 M
Explanation:
In the reaction of: N₂O₄(g) ⇌ 2 NO₂(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of N₂O₄ = 0.0500 M. What are the equilibrium concentrations of N₂O₄ and NO₂ under these conditions?
Step 1: Given data
Initial concentration of N₂O₄: 0.0500 M
Equilibrium constant (Kc): 0.513
Step 2: Make an ICE chart
N₂O₄(g) ⇌ 2 NO₂(g)
I 0.0500 0
C -x +2x
E 0.0500-x 2x
Step 3: Find the value of "x"
The equilibrium constant is:
Kc = [NO₂]² / [N₂O₄]
0.513 = (2x)² / (0.0500-x)
4x² + 0.513 x -0.02565
We solve for x and we get x₁ = 0.0458942 and x₂ = −0.558894 (neglected).
Step 4: Calculate the concentrations at equilibrium
[N₂O₄] = 0.0500-x = 0.00411 M
[NO₂] = 2x = 0.0918 M
Can someone help please
In addition to how much force Earth exerts on the object, which features of an object affect its weight? edginuity
Answer:A
Explanation:
A 7.28 g sample of chromium metal was heated to produce chromium oxide. The weight of the compound was 10.63 g. What is the percent chromium in this compound?
Answer:
68.48%
Explanation:
The percent mass of an element in a compound tells us about the amount of such element contributed to the total compound.
In this case, 7.28 g sample of chromium metal was heated to produce chromium oxide with weight of 10.63 g. The percent mass of chromium in chromium oxide can be calculated by using the formula:
%mass of Cr = mass of Cr/mass of Chromium oxide × 100%
%mass of Cr = 7.28/10.63 × 100
%mass of Cr = 0.6848 × 100
%mass of Cr = 68.48%
substance in which two or more atoms are bonded together.
molecule(s)
two or more atoms touching means they are connected as molecules which also make up compounds
how many molecules of HCI would react with 1 mol of MgO?
Answer:
C.
Explanation:
MoleculesHcl = (1 molMgO/1)(2molHCL/1molMGO)(6.02x10^23/1molHCL) = 1.204x10^24
A resistor is placed in a circuit. The voltage of the circuit is changed and the current is measured. The graph seen here shows the data that was collected. Determine the resistance of the resistor in this circuit.
A chemical equation is shown:
Al + O2 A1203
According to the law of conservation of mass, how many atoms of oxygen exist in the products of this reaction?
6
5
3
2
Answer:
Well the answer of 1 and 3 is WRONG based on the 1 star review and the answer of 3 is wrong too I just took a test with this question.
Explanation:
Sorry...
Answer:
it's 6
Explanation:
I just took the test and got it right
Does water take up space (have volume)? Yes or no
Answer:
Yes
Explanation:
10 The rate of the reaction between hemoglobin (Hb)
and carbon monoxide (CO) was studied at 20°C.
The following data were collected with all
concentration units in u mol/L. (A hemoglobin
concentration of 2.21 u mol/L is equal to
2.21 x 10 mol/L.)
[Hblo [CO),
Initial Rate
(u mol/L) (u mol/L) (u mol/Ls)
2.21
1.00
0.619
4.42
1.00
1.24
4.42
3.00
3.71
(a) Determine the orders of this reaction with
respect to Hb and CO.
(b) Determine the rate law.
(c) Calculate the value of the rate constant.
(d) What would be the initial rate for an
experiment with [Hb]o =3.36 u mol/L
[CO] =2.40 4 mol/L?
Answer:cookie
Explanation:
20 POINTS
What is true about the Sun, light bulbs, and flames?
AThey are all made of fire.
BThey are all made by people.
CThey are all found in nature.
DThey are all sources of light energy.
Answer:
D
Explanation:
Light blubs are not made of fire.
The sun wasnt made by humans.
You cant find Light bulbs in nature.
Meaning it is D.
Please help I need a answer to both
Hi , I’m really sorry because I just have the first question... so here it is :
So it is 0.52 mol .
Have a nice day .
PLEASE HELP!! I WILL MARK THE 1st ONE BRAINLIEST!
Answer:
A is not true.
Blue waves have ~500 nm and Orange waves have ~625 nm
Solid nickel reacts with aqueous lead (II) nitrate to form solid lead. What is the net ionic equation for this reaction? • Hint: In this reaction, nickel exhibits its most common oxidation state of +2. • Be sure to include the charge for each ion in the net ionic equation. Provide your answer below: (s) + (aq) → *(n)
Answer:
Pb²⁺(aq) --> Ni²⁺(aq)
Explanation:
The equation of the reaction is given as;
Ni(s) + Pb(NO₃)₂(aq) --> Pb(s) + Ni(NO₃)₂(aq)
In writing the ionic equation, we break the aqueous compound into ions. The solid and liquid compounds are ignored.
We have;
Pb²⁺(aq) + NO₃²⁻(aq) --> Ni²⁺(aq) + NO₃²⁻(aq)
Canceling the spectator ions;
Pb²⁺(aq) --> Ni²⁺(aq)
Answer:
Ni(s)+Pb2+(aq)→Ni2+(aq)+Pb(s)
Explanation:
The complete ionic equation of this reaction is
Ni(s)+Pb2+(aq)+2 NO−3(aq)→Ni2+(aq)+2 NO−3(aq)+Pb(s)
The nitrate ions are spectator ions and can be removed from the equation, giving us
Ni(s)+Pb2+(aq)→Ni2+(aq)+Pb(s)
What type of compound is disulfur dichloride?
a. organic compound
b. acid (ionic compound)
c. covalent compound
d. ionic compound
Answer:
Covalent compound
Explanation:
It is formed by covalent bonds, in which the atoms share a pair of valence electrons
I need the answer to this multiple-choice
Which can not be chemically broken down into simpler substances
Student places the ends of the wires The piece of iron shown in the picture which Physical property of iron is being tested in this picture
A. Thermal conductivity
B. Ductility
C. Electrical conductivity
D. Magnetism
Answer: C
Explanation:
Electrical conductivity
A rock with a mass of 70 grams is dropped into a graduated cylinder with 30 mL of water in it. The water level rose to 35 mL calculate the density of the rock in g/mL
Answer:
14
Explanation:
70g/(35mL-30mL)=14g/mL
If a rock with a mass of 70 grams is dropped into a graduated cylinder with 30 milliliter of water in it. The water level rose to 35 milliliters, then the density of the rock in gram / milliliter would be 14 gram / milliliter.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
The mass of ṭhe rock = 70 grams
The volume of the rock = 35 milliliters - 30 milliliters
= 5 milliliters
The density of the rock = mass of the rock / volume of the rock
=70 grams / 5 milliliters
= 14 gram / milliliter
Thus, the density of the rock would be 14 gram / milliliter.
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How and why was the periodic table set up?
What are the REDOX and BALANCED EQUATION for:
Aluminum metal and aqueous hydrochloric acid (HCl) will form Aqueous aluminum chloride and hydrogen Gas
Hydrogen peroxide (H2O2) will decompose to hydrogen and oxygen gas
A mystery element "X” has two stable isotopes X-50 which occurs 40% of the time
and X-60 which occurs 60% of the time. What is the average mass of element "X"?
A-50 amu
B-54 amu
C-56 amu
D-60 amu
Answer:
probaly C
Explanation:
I'm not sure on this one...
how are ionic bonds and covalent bonds different
A sample from one of Earth's oceans has a salinity of 34. What is the concentration of dissolved salts in this sample of seawater when expressed in ppmppm
Answer:
Concentration of dissolved salts = 34,038.76 ppm
Explanation:
Given:
Salinity of ocean water = 34
Find:
Concentration of dissolved salts
Computation:
Salinity of ocean water = 34 g/l
1g/l = 1001.14 ppm
Concentration of dissolved salts = 1001.14 ppm x 34
Concentration of dissolved salts = 34,038.76 ppm
