Answer:
Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
Part B:
P''(-1, 0)
Q''(0, -1)
R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are not congruent
Step-by-step explanation:
The coordinates of triangle PQR are;
P(4, 0)
Q(0, 4)
R(-8, -4)
The coordinates of triangle P'Q'R' are;
P'(1, 0)
Q'(0, -1)
R'(-2, -1)
Part A:
The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' can be found from the ratio of the respective coordinates as follows;
The ratio of the x, and y coordinates of the points are;
P'/P = x'/x = 1/4, y'/y =0/0
R'/R = x'/x = -2/-8 = 1/4, y'/y =-1/-4 = 1/4
Therefore, the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' = 1/4
Part B: For reflection across the y-axis, we have;
Pre-image (x, y) becomes the image, (-x, y)
Therefore, we have;
Reflection of P'(1, 0) about the y-xis becomes P''(-1, 0)
Reflection of Q'(0, -1) about the y-xis becomes Q''(0, -1)
Reflection of R'(-2, -1) about the y-xis becomes R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are similar but they are not congruent as the dimensions of PQR are larger than the dimensions of the sides of triangle P''Q''R''.
(A) The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
(B) Coordinates of Δ P"Q"R"
P" (-1,0)
Q"(0,-1)
R"(2,-1)
(C) Triangles PQR and P"Q"R" are not congruent.
Given
ΔPQR is transformed into ΔP'Q'R'
Coordinates of P, Q, R are
P (4,0),
Q(0,-4)
R(-8,-4)
Coordinates of P'Q'R' are
P'(1,0)
Q'(0,-1)
R'(-2,-1)
(A) By Distance formula we can find the distance between P Q and P'Q'
Distance formula = [tex]D= \sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2 }[/tex]
Where D = Distance between two points [tex](X_1.Y_1) \; and\; (X_2.Y_2)[/tex]
from distance formula we can write that
[tex]PQ = \sqrt{(0-4)^2+ (-4-0)^2} }\\[/tex]
PQ = [tex]4\sqrt{2}[/tex]
Similarly
P'Q'= [tex]\sqrt{2}[/tex]
PQ /P'Q' = 4
hence the scale factor of dilation is 1/4 (Compression)
(B )The Coordinates of Reflection about y axis can be written for a point
[tex](x,y ) \; as \; (-x,y)[/tex]
So the Coordinated of Δ P"Q"R" can be written as
P" (-1,0)
Q"(0,-1)
R"(2,-1)
(C) ΔPQR and ΔP"Q"R" are similar triangles but they are not congruent because their sides are not equal in size.
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surface area of sphare
Surface area of sphere is what referred to as Total surface area or lateral surface area because here the surface is curved everywhere.
[tex] \large{ \boxed{ \rm{ \orange{Surface \: area \: of \: sphere = 4\pi {r}^{2} }}}}[/tex]
Total surface area of other 3-D shapes:
Cuboid = 2(lb + bh + hl)Cube = 4s²Cylinder = 2πr(r + h)Cone = πr(l + r)Hemisphere = 3πr²Lateral surface area of these shapes:
Cuboid = 2h(l + b)Cube = 6s²Cylinder = 2πrhCone = πrlHemisphere = 2πr²━━━━━━━━━━━━━━━━━━━━
In the figure shown, what is the measure of angle x? (5 points) 115 degrees 130 degrees 145 degrees 150 degrees
Answer:
x=115
Step-by-step explanation:
180 - (115) =65(triangle)
65 + x = 180(on a line)
x=180-65
x = 115
Answer:
115 degrees
Step-by-step explanation:
the person above me is right, but there is an easier way.
Just add 50 and 65 degrees and boom you have your answer.
A certain pole has a cylinder-like shape, where the base's radius is 10 centimeters and the height is 2 meters. What calculation will give us the estimated surface area of the pole in square centimeters?
Answer:
2 pi •10•210
Step-by-step explanation:
Khan academy
If you draw a rectangle that has a width of 12 centimeters and an area of 48 centimeters, what is the length of the rectangle?
Answer:
length=4 cm
Step-by-step explanation:
Area of rectangle= length * width
48=l*12
length=48/12
length=4 cm
The sum of the numerator and denominator of a
fraction is 12. If the denominator is increased by 3,
the fraction becomes 1/2.
Find the fraction.
plz answer step by step
[tex]x+y=12\\\dfrac{x}{y+3}=\dfrac{1}{2}\\\\x=12-y\\2x=y+3\\\\2(12-y)=y+3\\24-2y=y+3\\3y=21\\y=7\\\\x=12-7=5\\\\\dfrac{x}{y}=\dfrac{5}{7}[/tex]
Given: AB ∥ DC , m CB =62°, m∠DAB=104° Find: m∠DEA, m∠ADB
Answer: m∠DEA = _________, m∠ADB =_______
Answer:
The values of the angles are;
m∠DEA = 62°, m∠ADB = 45°
Step-by-step explanation:
Specify an arc or an angle three letters
Angle opposite an arc on the circumference
m DA ≅ m CB = 62° (Arc between parallel lines are congruent)
∠CAB = 1/2 × m CB = 1/2 × 62° = 31° (Angle at the center = 2 × Angle st the circumference)
∠DBA = 31° (Angle at the center m DA = 2 × Angle st the circumference)
m∠DAB = 104° (Given)
∠ADB = 180° - m∠DAB - ∠DBA = 180° - 104° - 31° = 45° (Interior angles of triangle ΔADB
m∠ADB = 45°
∠AEB = 180 - ∠CAB - ∠DBA = 180° - 31° - 31° = 118°
∠AEB ≅ ∠COD (Vertically opposite angles)
∠DEA ≅ ∠CEB (Vertically opposite angles)
∠AEB + ∠COD + ∠DEA + ∠CEB = 360° (Sum of angles at a point)
118° + 118° + ∠DEA + ∠CEB = 360°
∠DEA + ∠CEB = 360° - 118° - 118° = 124°
Given that ∠DEA = ∠CEB we have;
2 × ∠DEA = 124°
∠DEA = 124°/2 = 62°
m∠DEA = 62°.
What is the 1st mistake...
Answer:
[tex]\huge\boxed{Step \ 3}[/tex]
Step-by-step explanation:
In Step # 3, We need to divide rather than to subtract. So, the first mistake is done in step 3.
Answer:
[tex]\Large \boxed{\mathrm{Step \ 4}}[/tex]
Step-by-step explanation:
[tex]20 +20 \div 4-2[/tex]
Division should be performed first, not subtraction.
[tex]20+5-2[/tex]
What’s up guys, pls help 19b)
Thanks
Answer:
90°
Step-by-step explanation:
As given in the figure:
[tex]AC \perp CE\\
\therefore m\angle ACE = 90\degree \\ [/tex]
solve equation show all steps what is 2x-3x+5=18
Answer:
x = -13
Step-by-step explanation:
2x-3x+5=18
Combine like terms
-x +5 = 18
Subtract 5 from each side
-x +5-5 = 18-5
-x = 13
Multiply each side by -1
x = -13
Answer:
[tex]\huge \boxed{{x=-13}}[/tex]
Step-by-step explanation:
[tex]2x-3x+5=18[/tex]
[tex]\sf Combine \ like \ terms.[/tex]
[tex]-1x+5=18[/tex]
[tex]\sf Subtract \ 5 \ from \ both \ sides.[/tex]
[tex]-1x+5-5=18-5[/tex]
[tex]-1x=13[/tex]
[tex]\sf Multiply \ both \ sides \ by \ -1.[/tex]
[tex]-1x \times (-1)=13 \times (-1)[/tex]
[tex]x=-13[/tex]
The temperature in Anchorage, Alaska at 6:00 am was 2°C. If the temperature drops 2 degrees each hour, what is the temperature in degrees celsius at 2:00 pm
Answer:
-12°C
Step-by-step explanation:
6AM = 2°C
8AM= -2°C
10AM= -6°C
12AM= -8°C
2PM= -12°C
the temperature in degrees Celsius at 2:00 pm would be -14°C.
To find the temperature in degrees Celsius at 2:00 pm, we need to determine the number of hours that have passed from 6:00 am to 2:00 pm, and then calculate the temperature decrease accordingly.
From 6:00 am to 2:00 pm, a total of 8 hours have passed (6 hours from 6:00 am to 12:00 pm, and 2 hours from 12:00 pm to 2:00 pm).
Given that the temperature drops 2 degrees Celsius each hour, we can multiply the number of hours (8) by the rate of temperature decrease (2 degrees/hour):
Temperature decrease = 8 hours × 2 degrees/hour = 16 degrees
Starting with a temperature of 2°C at 6:00 am, if the temperature drops 16 degrees Celsius over 8 hours, we can subtract 16 from the initial temperature:
Temperature at 2:00 pm = 2°C - 16°C = -14°C
Therefore, the temperature in degrees Celsius at 2:00 pm would be -14°C.
Learn more about temperature here
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Bismah is building 5 raised garden beds in a community garden. Each raised garden bed will need 1 7 8 bags of soil. How many bags of soil will Bismah need for all 5 raised garden beds?
Answer:
890 if it’s 178 bags per garden bed
Step-by-step explanation:
since 1 raised garden bed is supposedly 178 bags, 5 would be 890 since it’s just 5x178. if it’s not 178 bags (which would make sense since 178 is a big number), just multiply 5 by that number and if it’s a decimal round up to the next whole number if it’s about how many bags Bismah needs to buy, since you can’t by 1/2 of a bag
Bismah will need a total of 890 bags of soil for all the 5 raised garden. beds.
What is Multiplication?.Multiplication is one of the basic operations in mathematics where a number is added repeatedly to itself up to the times as the value of the other number.
That is, if a number p is multiplied to another number q, p × q, implies that p is added repeatedly to itself q times or q is added repeatedly to itself up to p times.
Number of garden beds Bismah has raised = 5
Number of bags of soil needed for a garden bed = 178 bags
Number of bags of soil needed for 5 garden bed = 178 × 5 bags
= 890 bags
Hence Bismah would need 890 bags of soil for the 5 raised garden beds in the community garden.
To learn more about Multiplication, click on the link given below :
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someone help me really quick
Answer:
u^18
Step-by-step explanation:
(u^3)^6
=
u^(3*6)
=
u^18
Hope this helps!
Jake ran 4 1/4 miles on Monday and 2 2/3 miles on Tuesday. On Wednesday he ran 1 fewer miles then he ran on Monday. How many miles did he run in all? PLEASE SHOW YOUR WORK I WILL MARK YOU BRAINLIEST AND PLEASE EXPLAIN
Answer:
Jake ran 10 1/6 miles in total
Step-by-step explanation:
4 1/4 + 2 2/3 - (4 1/4-1).
v
6 11/12 + 3 1/4
v
6 11/12 + 3 3/12 = 10 1/6
Jake ran 10 1/6 miles in total (Mon, Tues, Wed).
Answer:
61/6 or 10.1666666667
Step-by-step explanation:
Monday = 4 1/4
Tuesday = 2 2/3
Wednesday = Monday - 1
=> Monday = 17/4 miles
=> Tuesday = 8/3 miles
=> Wednesday = 17/4 - 4/4 = 13/4 miles.
=> (17/4 + 13/4) + 8/3
=> 30/4 + 8/3
=> Take the LCM of the denominators.
=> LCM = 12
=> 90/12 + 32/12
=> 122/12
SImplify 122/12
=> 61/6 or 10.1666666667
What is 51⁄6 as an improper fraction? For Seneca Learning:
Answer:
Step-by-step explanation:
[tex]5\frac{1}{6}=\frac{(5*6)+1}{6}=\frac{31}{6}[/tex]
Answer:
31/6 (improper fraction).
Step-by-step explanation:
5 1/6 = (6 × 5) + 1/6 = 31/6
31/6 is the improper fraction.
A rectangular box with a square base contains 24 cubic feet. if the height of the box is 18 inches, how many feet are there in each side of the base?
Answer:
4
Step-by-step explanation:
V = Lwh
the volume (given) = 24 ft^3
the height (given) = 18" = 1.5'
24 = L*w*1.5
divide both sides by 1.5
16 = Lw
You need to find the number of feet in each side of the base
since the box has a square base
L = W
AND, found above, L*w = 16
so 4*4= 16
Answer - 4
NEED IN 10 MIN. WILL GIVE BRAINLEST Solve the triangle. B = 36°, a = 41, c = 17
Answer:
Yes this is a Triangle
36 degrees of any side then 41 would connct to 36 and 17 would connects to 36 and 41! If this is Khan Academy your asking out of its a Yes, it is a Triangle
HOPE IM THE BRANLIESS UwUAnswer:
It is a triangle:
Step-by-step explanation:
b² = a² + c² - 2(a)(c)cos(B)
b² = 41² + 20² - 2(41)(20)cos(36)
b² = 754.2121292
b = 27.46292281
b = 27.463
A = 41, B = 27.4, C = 17
If x =2.3,5x.3= DONT MAKE ANSWERS THAT DONT MAKE ANY SENSE OR YOU WILL GET REPORTED
Answer:
34.5
Step-by-step explanation:
5 times x(2.3) = 11.5.
11.5 times 3 is 34.5
you put 2.3 in place of x because x was the unknown value, but now that we know it is 2.33 we plug it in.
What is the tangent ratio of KJL? (Question and answers provided in picture.)
Answer:
Option (1)
Step-by-step explanation:
The given triangle JKL is an equilateral triangle.
Therefore, all three sides of this triangle will be equal in measure.
Side JK = JL = KL = 48 units
Perpendicular LM drawn to the base JK bisects the base in two equal parts JM and MK.
By applying tangent rule in ΔJML,
tan(∠KJL) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{\text{LM}}{\text{JM}}[/tex]
= [tex]\frac{\text{LM}}{24}[/tex]
Since, Sin(K) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
Sin(60)° = [tex]\frac{\text{LM}}{48}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\text{LM}}{48}[/tex]
LM = 24√3
Now, tan(∠KJL) = [tex]\frac{\text{LM}}{24}[/tex]
= [tex]\frac{24\sqrt{3} }{24}[/tex]
Therefore, Option (1) will be the answer.
Hunter is copying an angle. His work so far follows. Explain the importance of his next step, which is drawing a line through A and Y using a straightedge.
This is to check to make sure that A is in the right place, since it was drawn using the arcs.
Using a straightedge ensures that there is a line passes through A and Y.
Because a line was drawn through point L, a similar line should be drawn through the corresponding point on ∠AYZ.
This is the other ray that will make up the angle ∠AYZ and will complete the construction.
Answer:
This is the other ray that will make up the angle ∠AYZ and will complete the construction.
Step-by-step explanation:
The point of the construction is to copy the angle. That is, the end result must be an angle with identical measure to the original. The construction so far has no angle at Y. Drawing ray YA will complete the construction and create the desired angle. That is, YA ...
This is the other ray that will make up the angle ∠AYZ and will complete the construction.
Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle, M, O, N, equals, 8, x, minus, 13, degrees \qquad m \angle LOM = 7x - 17^\circm∠LOM=7x−17 ∘ m, angle, L, O, M, equals, 7, x, minus, 17, degrees Find m\angle MONm∠MONm, angle, M, O, N:
Answer:
[tex] \boxed{99°}[/tex]Step-by-step explanation:
m<MON = 8x - 13°
m<LOM = 7x - 17°
To find : m <MON
First, we have to find the value of x :
Create an equation
[tex] \mathrm{8x - 13 + 7x - 17 = 180}[/tex] ( sum of angle in straight line )
Collect like terms
[tex] \mathrm{15x - 13 - 17 = 180}[/tex]
Calculate
[tex] \mathrm{15x - 30 = 180}[/tex]
Move constant to R.H.S and change its sign
[tex] \mathrm{15x = 180 + 30}[/tex]
Calculate the sum
[tex] \mathrm{15x = 210}[/tex]
Divide both sides of the equation by 15
[tex] \mathrm{ \frac{15x}{15} = \frac{210}{15} }[/tex]
Calculate
[tex] \mathrm{x = 14}[/tex]
Now, let's find the value of m<MON
[tex] \mathrm{8x - 13}[/tex]
Plug the value of x
[tex] \mathrm{ = 8 \times 14 - 13}[/tex]
Calculate the product
[tex] \mathrm{ = 112 - 13}[/tex]
Calculate the difference
[tex] \mathrm{ = 99}[/tex] °
Hope I helped!
Best regards!
Answer:
48
Step-by-step explanation:
because i say so
Solve two-step equations. -5/2 a + 5 = 25
Answer:
a = -8
Step-by-step explanation:
-5/2 a + 5 = 25
Subtract 5 from each side
-5/2 a + 5-5 = 25-5
-5/2 a = 20
Multiply each side by -2/5
-2/5 *-5/2 a = 20*-2/5
a = -8
Jess receives a $15000 salary for working as an engineer. If Jess has to spend $6000 of her salary on expenses each year, then what percent of Jess's money does she have to spend? Round your answer to the nearest whole number if necessary.
Answer:
Jess will have to spend 40% of her salary
Step-by-step explanation:
Jess salary = $15,000
Jess expenses = $6,000
what percent of Jess's money does she have to spend
Percentage of Jess expenses = Jess expenses / Total salary × 100
= 6,000 / 15,000 × 100
= 0.4 × 100
= 40%
Jess will have to spend 40% of her salary
The Nguyen family and the Reed family each used their sprinklers last summer. The Nguyen family's sprinkler was used for 15 hours. The Reed family's sprinkler was used for 25 hours. There was a combined total output of 1175L of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour? Nguyenfamily'ssprinkler:Lperhour Reedfamily'ssprinkler:Lperhour
Answer:
Nguyen family's sprinkler: 20 L per hour Reed family's sprinkler: 35 L per hourStep-by-step explanation:
Let n and r represent the output in liters per hour of the Nguyen and Reed family sprinklers, respectively. Then we have ...
15n +25r = 1175 . . . . total sprinkler output
n + r = 55 . . . . . . . . . sum of two output rates
The second equation tells us we can substitute n = 55 -r into the first equation:
15(55 -r) +25r = 1175
10r = 1175 -825 . . . . . . subtract 825
r = 350/10 = 35 . . . . . . divide by 10
n - 55 -35 = 20 . . . . . . find n from r
Nguyen family's sprinkler: 20 L per hour
Reed family's sprinkler: 35 L per hour
55÷11[120÷2{4+(10+5-7)}]
Answer:
3600
Step-by-step explanation:
First, solve the innermost brackets first.
=> 55/11 [120 /2{4 + (10 + 5 - 7)}]
=> 55/11 [120 /2{4 + (8)}]
=> 55/11 [120 /2{4+8}]
=> 55/11 [120 /2{12}]
=> 55/11[ 60 x 12]
=> 55/11 [720]
=> 5 [720]
=> 3600
\large 6\cdot\frac{6+2^2}{6+2-6}
Answer:
30Step-by-step explanation:
Given the expression [tex]\large 6\cdot\frac{6+2^2}{6+2-6}[/tex], on simplification we have;
[tex]= \large 6\cdot\frac{6+2^2}{6+2-6}\\\\= \large 6\cdot\frac{6+4}{8-6}\\\\= \large 6\cdot\frac{10}{2}\\\\= 6* 5\\\\= 30[/tex]
Hence the equivalent value of the expression is 30
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):
[tex]Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds[/tex]
second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
[tex]\frac{200}{60} = \frac{10}{3} \approx 3.33[/tex] loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
[tex]\frac{200}{65} = \frac{40}{13} \approx 3.08[/tex] loops per minute
then the period is:
[tex]\frac{13}{40} =0.325\,\,\,minutes[/tex]
Therefore runner B has the smaller period
Quadrilateral ABCD is inscribed in a circle. m∠A is 64°, m∠B is (6x + 4)°, and m∠C is (9x − 1)°. What is m∠D?
Answer:
m∠D = 97.34°
Step-by-step explanation:
Concept used"
sum of all angles of Quadrilateral is 360 degrees.
If any Quadrilateral is inscribed in circles then sum of opposite angle of that Quadrilateral is 180 degrees
________________________________________________
Given
Quadrilateral ABCD is inscribed in a circle
thus,
pair of opposite angles will be
m∠A and m∠C
m∠B and m∠D
thus,
m∠B + m∠D = 180
Thus,
m∠A + m∠C = 180
64+ (9x - 1) = 180
9x = 180 - 63 + 1 = 118
x = 118/9 = 13.11
thus, value of
m∠B is (6x + 4)°
m∠B = (6*13.11 + 4)° = 82.66°
m∠B + m∠D = 180
82.66 + m∠D = 180
m∠D = 180 - 82.66 = 97.34°
Thus,
m∠D is 97.34°
Hello, a quick question which number is least to greatest 0.359, 0.35, 1
Answer:
0.35, 0.359, 1
Step-by-step explanation:
0.359 = 359 thousandths
0.35 = 0.350 = 350 thousandths
1 = 1.000 = 1000 thousandths
Since 350 < 359 < 1000, then from least to greatest you get
0.35, 0.359, 1
Which statement best explains why the sine of an acute angle is equal to the cosine of the angles complement
Answer:
Option (B)
Step-by-step explanation:
From the figure attached,
ΔABC is a right triangle.
Cosine and Sine ratios from the given triangle will be,
SinA = [tex]\frac{\text{Opposite side}}{Hypotenuse}[/tex]
= [tex]\frac{a}{c}[/tex]
CosB = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{a}{c}[/tex]
Therefore, both the ratios (Sine and Cosine) will be equal as [tex]\frac{a}{c}[/tex]
Option (B) will be the correct option.
Help? It hard I try my best on a Separate picese
============================================
Work Shown:
3 & 1/2 = 3 + 1/2 = 3 + 0.5 = 3.5
3.5% = 3.5/100 = 0.035
r = 0.035 is the decimal form of [tex]3\frac{1}{2}\%[/tex] which is used along with
P = 500 (principal deposit)n = 12 (compounding 12 times a year)t = 0.5 (6 months is half a year)to get the following
A = P*(1+r/n)^(nt)
A = 500*(1+0.035/12)^(12*0.5)
A = 508.81405074594
A = 508.81
Extra info: Gabe earned A-P = 508.81 - 500 = 8.81 dollars in interest.
