2/3 of a number is 20 less than the original number.find the number

Answer:

[tex]{18}[/tex]

Step-by-step explanation:

[tex] \sqrt{(2 - 5) {}^{2} + ( 2 - 5) {}^{2} } [/tex]

[tex] = \sqrt{( - 3) {}^{2} + ( - 3) {}^{2} } [/tex]

[tex] = \sqrt{9 + 9} [/tex]

[tex] = \sqrt{18}[/tex]

Answered by GAUTHMATH

Answer:

518

Step-by-step explanation:

solution:

=8^2^×1^+1+6^2^×1^-1

=8^3+6^1

=8^3+6

=8×8×8+6

=512+6

=518

Answer:

69.3

Step-by-step explanation:

if you put it into 2D, you get a right triangle with leg lengths 62 (vertical height) and 31 (1/2 the base's length). Using Pythagorean's Theorem you get sqrt((62^2)+(31^2))= 69.318. Rounding to the nearest tenth you get 69.3

Answer:

Just use a calculator and wite the square root value in it

Step-by-step explanation:

Atempt this method with all options at last u will have ur answer

Answer:

A

Step-by-step explanation:

A logarithmic function, log(x) has a domain x>0. For this logarithmic equation x+2>0, x>-2.

Answer:

y(x) = 2x+3

Step-by-step explanation:

the rule is y(x) = 2x+3

Answer:

12 minutes

Step-by-step explanation:

Given

[tex]s_1 = 10mi/h[/tex] --- walk speed

[tex]s_2 = 20mi/h[/tex] --- jog speed

[tex]d = 2\ miles[/tex] --- distance

Required

The time to walk the given distance

Time is calculated as:

[tex]Time = \frac{distance}{speed}[/tex]

In this case, the speed is the speed at which she walks.

So, we have:

[tex]Time = \frac{d}{s_1}[/tex]

Substitute known values

[tex]Time = \frac{2mi}{10mi/h}[/tex]

[tex]Time = 0.2hr[/tex]

Convert to minutes

[tex]Time = 0.2 * 60mins[/tex]

[tex]Time =12mins[/tex]

Answer:

x=0

x=6

x=-1

Step-by-step explanation:

x(x^2-5x-6)

x(x-6)(x+1)

x=0

x=6

x=-1

Answer:

40*8.5=340

6*90=540

total=880/2.5=352bags

Answer:

4w = -5-19

4w=-24

w=-6

hope that answers your question

good luck

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Short answer: to solve this problem, follow directions.

Let c and p represent numbers of cakes and pies produced daily. Then the constraints are ...

  2c +3p ≤ 108 . . . . . . . . available hours of preparation time

  1c +0.5p ≤ 20 . . . . . . . available hours of decoration time

  p ≥ 0, c ≥ 0 . . . . . . . . . negative numbers of cakes or pies cannot be produced

__

It works well to let a graphing calculator do this.

The feasible region is the doubly-shaded area with vertices ...

  (0, 0), (0, 36), (3, 34), (20, 0)

__

Profit is $25 per cake and $12 per pie, so is ...

  p = 25c +12p

__

The attached table shows the profit for the various mixes of cakes and pies in the feasible region. The most profit is had by production of cakes only.

The maximum profit is $500 per day for production of 20 cakes.

_____

Additional comment

We have used x for cakes and y for pies in the attachment, because those are variables that the Desmos calculator prefers.

As is sometimes the case, the production point giving maximum profit leaves one of the resources (preparation time) only partially utilized.

Answer:

70 days

Step-by-step explanation:

that is the procedure above

Answer:

(1,2) is ordered pair to (-4,2).

Step-by-step explanation:

(1,2)

hora khoi thaha vayena hai

-2a(a - d) + 2a(2a - 3d)

(-2a * a) + (-d * -2a) + (2a * 2a) + (2a * -3d)

-2a^2 + 2ad + 4a^2 - 6ad

(4a^2 - 2a^2) + (2ad - 6ad)

2a^2 - 4ad

---The above expression is simplified, though not fully. The below expression is fully simplified.

2a(a - 2d)

Hope this helps!

Answer:

The answer is 12

Step-by-step explanation:

You see its because.

Answer:

?=12

Step-by-step explanation:

Using the Thalès's theorem:

[tex]\dfrac{6}{6+4}=\dfrac{?}{20} \\\\?*10=6*20\ (cross\ products)\\\\?=\dfrac{6*20}{10} \ dividing\ by\ 10\\\\?=12[/tex]

Answer:

The answer is 7.5

Answer:

A. 45%

Step-by-step explanation:

34/75=45 = 45%

Answer:

Step-by-step explanation:

let the height of the room(h) = x

Length(l) = 3*x = 3x

length = 2 * breadth

breadth(b) = length /2 = 3x/2

Cost of whitewashing the 4  walls = ₹ 7200

Area of 4 walls = 7200 ÷ 50 = 144 m²   ------(I)

Area of walls = 2lh + 2bh

                      = 2*3x*x + 2  *[tex]\frac{3x}{2}[/tex] * x

                       = 6x² + 3x²

                        = 9x²

9x² = 144    {From (I)}

x²  = 144/9

x²  = 16

x = [tex]\sqrt{16}=\sqrt{4*4}[/tex]

x = 4 m

height = 4 m

length = 3*4 = 12m

Breadth = [tex]\frac{3}{2}*4=3*2=6 \ m[/tex]

Area of floor = l*b

                    = 12 * 6

                    = 72 m²

Cost of carpeting the floor = 72 * 325 = ₹ 23400

9514 1404 393

Answer:

  7.56 cm

Step-by-step explanation:

The volume is given by the formula ...

  V = 1/3b²h . . . . where b is the base edge length, and h is the height.

Here we have V = 144 cm³, and b = h. Filling in these values and solving for h, we get ...

  144 cm³ = 1/3h³

  432 cm³ = h³

  h = ∛432 cm ≈ 7.55953 cm

The height of the pyramid is about 7.56 cm.

Answer:

[tex]7.56cm[/tex]

Step-by-step explanation:

Given that,

base length = Height

so,

[tex]volume = \frac{1}{3} {b}^{2} h \\ [/tex]

We can also write this as( according to this question)

[tex]v = \frac{1}{3} \times {b}^{2} \times b \\ v = \frac{ {b}^{3} }{3} [/tex]

let's solve

[tex]v = \frac{ {b}^{3} }{3} \\ 144 = \frac{ {b}^{3} }{3} \\ 144 \times 3 = {b}^{3} \\43 2 = {b}^{3} \\ \sqrt[3]{432} = b \\ b = 7.55[/tex]

[tex]base = height = 7.55cm \\ [/tex]

= 7.56cm

Answer:

27, 18

Step-by-step explanation:

Here's why

Answer:

-2/5

Step-by-step explanation:

Let the cost of a lamp = x

6 lamps would cost 6x

He bought 3 lamps at 3x plus Thad 950 left.

3 lamps plus the 950

Would be the same amount as 6 lamps:

Set up an equation and solve for x:

3x + 950 = 6x

Subtract 3x from both sides:

950 = 3x

Divide both sides by 3:

X = 316.67

Each lamp was $316.67

Multiply the price of a lamp by 6:

316.67 x 6 = 1900

He had $1900

Answer: $1900

Step-by-step explanation:

Mr Lim had enough money to buy 6 similar lamps. However he only bought 3 such lamps. That means he had only spent half of his money (6-3=3).

So, if he take money remaining with him = x = $950

Amount of money he first had = 2x =$950×2 = $1900

Answer:

2.6

Step-by-step explanation:

We'll use the Pythagoras theorem to solve this, which states that in a right angle triangle:

h^2 = a^2 + b^2

4^2 = 3^2 +b^2

16= 9 +b^2

16-9= b^2

7= b^2

(take square root in both sides)

b= 2.65

round to nearest 10th = 2.6

answer by Gauthmath

Answer:

Missing side is 2.6

3^2 + x^2 = 4^2

9 + x^2 = 16

-9            -9

x^2 = 7

([tex]\sqrt{x}[/tex])^2 = [tex]\sqrt{7}[/tex]

x = 7

Find the approximation o the square root of 7 in fractions then carry out the long division.

Or

Approx. is 2 3/5 which equals 2 6/10 which equals 2.6

Answer:

Hello,

Step-by-step explanation:

[tex]g(-9)=2\Longrightarrow\ g^{-1}(2)=-9\\\\y=h(x)=3x-4\\x=3y-4\\\\y=\dfrac{x+4}{3} \\\\h^{-1}(x)=\dfrac{x+4}{3}\\\\h(h^{-1}(x))=(h^{-1}o\ h)(x)=1_\pi(x) \ (identical\ permutation\ of\ plane) \\\\h(h^{-1}(2))=2[/tex]

Answer:

Hello,

m=2

(0,-3) True

(1,-1) True

(1.5,0) True

(-2,-2) False

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}y&=&mx-6\\8x-4y&=&12\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&mx-6\\y&=&2x-3\\\end{array}\right.\\\\\\The\ slope\ must\ be\ the\ same:\ m=2\\\\\\\begin{array}{c|c}&y=2x-3\\---&--------\\x&y\\0&2*0-3=-3\\1&2*1-3=-1\\1.5&2*1.5-3=0\\-2&2*(-2)-3=-7\\\end{array}[/tex]

Answer:

1 hour 33 minutes

Step-by-step explanation:

distance/speed= time

d =800/600

d=1.33

The aeroplane takes 1.33 hours to traverse a distance of 800 km.

Speed is the rate at which an object's position changes, measured in meters per second. For example, if an object starts at the origin, and then moves three meters in three seconds, its speed is one meter per second. The equation for speed is simple: distance divided by time

Given here: An airplane flies a distance of 800 km with an average speed of 600 km/h

Thus the time taken by the aeroplane to cover that distance is

t=800/600

t=4/3

t=1.33 hours

Hence, The aeroplane takes 1.33 hours to traverse a distance of 800 km.

Learn more about the speed of an object here:

https://brainly.com/question/28224010

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