Answer:
March through August
Step-by-step explanation:
Ok, in order to solve this problem, we must start by building an equation to solve. The original equation was:
[tex]S=56.9-40.7cos (\frac{\pi}{6}t)[/tex]
and we need to figure out the months when the sales exceed 7700 units. Since the equation is given in hundreds of units, we need to divide those 7700 units into one hundred to get 77 hundred units. So we can go ahead and substitute that value in the equation:
[tex]77=56.9-40.7cos (\frac{\pi}{6}t)[/tex]
if you wish you can rewrite the equation so the variable is on the left side of it but it's up to you. So you get:
[tex]56.9-40.7cos (\frac{\pi}{6}t)=77[/tex]
and now we solve for t
[tex]-40.7cos (\frac{\pi}{6}t)=77-56.9[/tex]
[tex]-40.7cos (\frac{\pi}{6}t)=20.1[/tex]
[tex]cos (\frac{\pi}{6}t)=\frac{20.1}{-40.7}[/tex]
[tex]cos (\frac{\pi}{6}t)=-0.4938[/tex]
[tex]\frac{\pi}{6}t=cos^{-1}(-0.4938)[/tex]
[tex]\frac{\pi}{6}t=2.087[/tex]
[tex]t=\frac{2.087(6)}{\pi}[/tex]
[tex]t=3.98 months[/tex]
but there is a second answer to this problem. Notice that the function cos can be 2.87 at [tex]2\pi-2.087=4.1962 rad[/tex] as well, so we repeat the process:
[tex]\frac{\pi}{6}t=4.1962[/tex]
[tex]t=\frac{4.1962(6)}{\pi}[/tex]
[tex]t=8.014 months[/tex]
So now we need to determine on which period of times the number of items sold exceed 77 hundred units so we build different intervals for us to test:
(1,3.98) (3.98,8.014) and (8,014, 13)
and find a test value for each of the intervals and test it.
(1,3.98) t=2
[tex]S=56.9-40.7cos (\frac{\pi}{6}(2))[/tex]
S=36.55
this is less than 77 so this is not our answer.
(3.98,8.014) t=5
[tex]S=56.9-40.7cos (\frac{\pi}{6}(5))[/tex]
S=92.15
this is more than 77 so this is our answer.
(8.014,13) t=10
[tex]S=56.9-40.7cos (\frac{\pi}{6}(10))[/tex]
S=36.55
this is less than 77 so this is not our answer.
so, since our answer is the interval (3.98,8.014)
this means that between the months of march and august we will be sellin more than 7700 units.
Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample. If the odds for E equal the odds against E', then P(E)P(F)=P(E∩F)
Correction:
Because F is not present in the statement, instead of working onP(E)P(F) = P(E∩F), I worked on
P(E∩E') = P(E)P(E').
Answer:
The case is not always true.
Step-by-step explanation:
Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.
And for any two mutually exclusive events, E and E',
P(E∩E') = 0
Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then
P(E)P(E') cannot be equal to zero.
So
P(E)P(E') ≠ 0
This makes P(E∩E') different from P(E)P(E')
Therefore,
P(E∩E') ≠ P(E)P(E') in this case.
Suppose that a random sample of 16 measures from a normally distributed population gives a sample mean of x=13.5 and a sample standard deviation of s=6. the null hypothesis is equal to 15 and the alternative hypothesis is not equal to 15. using hypothesis testing for t values do you reject the null hypothesis at alpha=.10 level of significance?
Answer:
Step-by-step explanation:
The summary of the statistics given include:
population mean [tex]\mu[/tex] = 15
sample mean [tex]\oerline x[/tex] = 13.5
sample size n = 16
standard deviation s = 6
The level of significance ∝ = 0.10
The null and the alternative hypothesis can be computed as follows:
[tex]\mathtt{H_o: \mu = 15} \\ \\ \mathtt{H_1 : \mu \neq 15}[/tex]
Since this test is two tailed, the t- test can be calculated by using the formula:
[tex]t = \dfrac{\overline x - \mu}{\dfrac{\sigma }{\sqrt{n}}}[/tex]
[tex]t = \dfrac{13.5 - 15}{\dfrac{6}{\sqrt{16}}}[/tex]
[tex]t = \dfrac{- 1.5}{\dfrac{6}{4}}[/tex]
[tex]t = \dfrac{- 1.5\times 4}{6}}[/tex]
[tex]t = \dfrac{- 6.0}{6}}[/tex]
t = - 1
degree of freedom = n - 1
degree of freedom = 16 - 1
degree of freedom = 15
From the standard normal t probability distribution table, the p value when t = -1 at 0.10 level of significance, the p - value = 0.3332
Decision Rule: We fail to reject the null hypothesis since the p-value is greater than the level of significance at 0.10
Conclusion: Therefore, we can conclude that there is insufficient evidence at the 0.10 level of significance to conclude that the population mean μ is different than 15.
If vectors i+j+2k, i+pj+5k and 5i+3j+4k are linearly dependent, the value of p is what?
Answer:
[tex]p = 2[/tex] if given vectors must be linearly independent.
Step-by-step explanation:
A linear combination is linearly dependent if and only if there is at least one coefficient equal to zero. If [tex]\vec u = (1,1,2)[/tex], [tex]\vec v = (1,p,5)[/tex] and [tex]\vec w = (5,3,4)[/tex], the linear combination is:
[tex]\alpha_{1}\cdot (1,1,2)+\alpha_{2}\cdot (1,p,5)+\alpha_{3}\cdot (5,3,4) =(0,0,0)[/tex]
In other words, the following system of equations must be satisfied:
[tex]\alpha_{1}+\alpha_{2}+5\cdot \alpha_{3}=0[/tex] (Eq. 1)
[tex]\alpha_{1}+p\cdot \alpha_{2}+3\cdot \alpha_{3}=0[/tex] (Eq. 2)
[tex]2\cdot \alpha_{1}+5\cdot \alpha_{2}+4\cdot \alpha_{3}=0[/tex] (Eq. 3)
By Eq. 1:
[tex]\alpha_{1} = -\alpha_{2}-5\cdot \alpha_{3}[/tex]
Eq. 1 in Eqs. 2-3:
[tex]-\alpha_{2}-5\cdot \alpha_{3}+p\cdot \alpha_{2}+3\cdot \alpha_{3}=0[/tex]
[tex]-2\cdot \alpha_{2}-10\cdot \alpha_{3}+5\cdot \alpha_{2}+4\cdot \alpha_{3}=0[/tex]
[tex](p-1)\cdot \alpha_{2}-2\cdot \alpha_{3}=0[/tex] (Eq. 2b)
[tex]3\cdot \alpha_{2}-6\cdot \alpha_{3} = 0[/tex] (Eq. 3b)
By Eq. 3b:
[tex]\alpha_{3} = \frac{1}{2}\cdot \alpha_{2}[/tex]
Eq. 3b in Eq. 2b:
[tex](p-2)\cdot \alpha_{2} = 0[/tex]
If [tex]p = 2[/tex] if given vectors must be linearly independent.
In the morning, Sophie goes to the church then goes to the school. In the afternoon she goes to school to home. The map shows the distance between school and home as 5 cm. If every 4 cm on the scale drawing equals 8 kilometers, how far apart are the school and home?
Answer:
10 km
Step-by-step explanation:
Distance = 5 cm
4 cm = 8 km
In km, how far apart is school and home?
Cross Multiply
[tex]\frac{4cm}{8km}[/tex] · [tex]\frac{5cm}{1}[/tex]
Cancel centimeters
[tex]\frac{40(km)(cm)}{4cm}[/tex]
Divide
= [tex]\frac{40km}{4}[/tex]
= 10 km
The Bay Area Online Institute (BAOI) has set a guideline of 60 hours for the time it should take to complete an independent study course. To see if the guideline needs to be changed and if the actual time taken to complete the course exceeds60 hours, 16 students are randomly chosen and the average time to complete the course was 68hours with a standard deviation of 20 hours. What inference can BAOI make about the time it takes to complete this course?
Answer:
At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 60 \ hr[/tex]
The sample size is [tex]n = 16[/tex]
The sample mean is [tex]\= x = 68 \ hr[/tex]
The standard deviation is [tex]\sigma = 20 \ hr[/tex]
The null hypothesis is [tex]H_o : \mu = 60[/tex]
The alternative [tex]H_a : \mu > 60[/tex]
Here we would assume the level of significance of this test to be
[tex]\alpha = 5\% = 0.05[/tex]
Next we will obtain the critical value of the level of significance from the normal distribution table, the value is [tex]Z_{0.05} = 1.645[/tex]
Generally the test statistics is mathematically represented as
[tex]t = \frac{ \= x - \mu}{ \frac{ \sigma }{\sqrt{n} } }[/tex]
substituting values
[tex]t = \frac{ 68 - 60 }{ \frac{ 20 }{\sqrt{16} } }[/tex]
[tex]t = 1.6[/tex]
Looking at the value of t and [tex]Z_{\alpha }[/tex] we see that [tex]t< Z_{\alpha }[/tex] hence we fail to reject the null hypothesis
This means that there no sufficient evidence to conclude that it takes more than 60 hours to complete the course
So
At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.
The mass of a species of mouse commonly found in houses is normally distributed with a mean of 20.2 grams with a standard deviation of 0.18 grams. Enter your responses as a decimal with 4 decimal places. (a) What is the probability that a randomly chosen mouse has a mass of less than 19.99 grams?
Answer:
12.1%
Step-by-step explanation:
Given that:
Mean (μ) = 20.2 grams and standard deviation (σ) = 0.18 grams.
The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean. A positive z score means that the raw score is above the mean and a negative z score means that the raw score is below the mean. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
a) For x < 19.99 g:
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{19.99-20.2}{0.18} \\\\z=-1.17[/tex]
From the normal distribution table, P(x < 19.99) = P(z < -1.17) = 0.1210 = 12.1%
The probability that a randomly chosen mouse has a mass of less than 19.99 grams is 12.1%
The weighted average of the possible values that a random variable X can assume, where the weights are the probabilities of occurrence of those values, is referred to as the:\
Answer: Expected value
Step-by-step explanation: The expected value of a random variable refers to a predicted variable which is obtained from the summation of the product of all possible values and the probability of occurrence of each value. The expected values gives the mean or average possible value over the cause of a certain experiment or scenario. It is thus the probability weighted average of all possible values or outcomes of an experiment.
The expected value could be represented mathematically as thus;
E(x) = [Σ(x * p(x)]
Where x = all possible values or outcomes of x;
p(x) = corresponding probability of each x value.
For the following polynomial, find P(a), P(-x) and P(x + h).
P(x) = 7x-6
Answer:
Step-by-step explanation:
Hello, please consider the following.
P(a) = 7 * a - 6
P(-x)= 7 *(-x) - 6 = -7x - 6
P(x+h) = 7 * (x+h) - 6 = 7x + 7h - 6
Hope this helps.
Thank you.
The values of the polynomial for the given expressions are:
P(a) = 7a - 6
P(-x) = -7x - 6
P(x + h) = 7x + 7h - 6
To find P(a), P(-x), and P(x + h) for the given polynomial P(x) = 7x - 6, we need to substitute the respective values of x into the polynomial expression.
1. P(a):
P(a) = 7a - 6
2. P(-x):
P(-x) = 7(-x) - 6
P(-x) = -7x - 6
3. P(x + h):
P(x + h) = 7(x + h) - 6
P(x + h) = 7x + 7h - 6
To know more about polynomial:
https://brainly.com/question/2928026
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Karim has two investments, one in Company A, and another in Company B. Karim purchased 3,000 shares in company A at $2.65 per share. Since purchasing the shares, the price per share increased to $2.95 per share, after which point Karim decided to sell, realizing a profit. At the same time, Karim purchased 2,000 shares in Company B at $1.55 per share. Since purchasing the shares, the share price fell to $1.30 per share, after which Karim decided to sell the shares, suffering a loss. Karim is required to pay tax at a rate of 28% on the combined profit from both investments. Calculate how much tax Karim must pay.
Answer:
A:$2478
B:$728
Total:$3206
Step-by-step explanation:
2.95x3000=8850
1.30x2000=2600
8850x0.28=2478
2600x0.28=728
2478+728=3206
Carol owns a BBQ company that sells brisket for $11.75 per pound (after it is smoked for 10 hours). She buys the brisket for an AP$ of $4.72 per pound and they weigh 10.4 lbs each. Once they are done smoking, they weigh 6.24 lbs each.
What is the yield % of the briskets after Carol is done smoking them?
Answer: 60%
Step-by-step explanation:
Given, AP$ of Brisket = $4.72
Weight of each brisket on purchase : 10.4 lbs
Weight of each brisket after smoking : 6.24 lbs
Yield % of the briskets after Carol is done smoking them=[tex]\dfrac{\text{Weight after smoking}}{\text{Weight on purchase}}[/tex]
[tex]\dfrac{6.24}{10.4}\times100\\\\=60\%[/tex]
Hence, the yield % of the briskets after Carol is done smoking them = 60%
plzz answer this fasttttttttt
Answer:
37°
This is because the square indicates a right angle.
53 - 90 = 37
We have,
∠AOB = 53°∠BOC = x°∠A0C = 90°Now,
AOB + ∠BOC = ∠A0C
⇒ 53° + x° = 90°
⇒ x° = 90° - 53°
⇒ x° = 37°
Please give me the answer ASAP The average of 5 numbers is 7. If one of the five numbers is removed, the average of the four remaining numbers is 6. What is the value of the number that was removed Show Your Work
Answer:
The removed number is 11.
Step-by-step explanation:
Given that the average of 5 numbers is 7. So you have to find the total values of 5 numbers :
[tex]let \: x = total \: values[/tex]
[tex] \frac{x}{5} = 7[/tex]
[tex]x = 7 \times 5[/tex]
[tex]x = 35[/tex]
Assuming that the total values of 5 numbers is 35. Next, we have to find the removed number :
[tex]let \: y = removed \: number[/tex]
[tex] \frac{35 - y}{4} = 6[/tex]
[tex]35 - y = 6 \times 4[/tex]
[tex]35 - y = 24[/tex]
[tex]35 - 24 = y[/tex]
[tex]y = 11[/tex]
Okay, let's slightly generalize this
Average of [tex]n[/tex] numbers is [tex]a[/tex]
and then [tex]r[/tex] numbers are removed, and you're asked to find the sum of these [tex]r[/tex] numbers.
Solution:
If average of [tex]n[/tex] numbers is [tex]a[/tex] then the sum of all these numbers is [tex]n\cdot a[/tex]
Now we remove [tex]r[/tex] numbers, so we're left with [tex](n-r)[/tex] numbers. and their. average will be [tex]{\text{sum of these } (n-r) \text{ numbers} \over (n-r)}[/tex] let's call this new average [tex] a^{\prime}[/tex]
For simplicity, say, sum of these [tex]r[/tex] numbers, which are removed is denoted by [tex]x[/tex] .
so the new average is [tex]\frac{\text{Sum of } n \text{ numbers} - x}{n-r}=a^{\prime}[/tex]
or, [tex] \frac{n\cdot a -x}{n-r}=a^{\prime}[/tex]
Simplify the equation, and solve for [tex]x[/tex] to get,
[tex] x= n\cdot a -a^{\prime}(n-r)=n(a-a^{\prime})+ra^{\prime}[/tex]
Hope you understand it :)
Use DeMoivre's Theorem to find the indicated power of the complex number. Write the answer in rectangular form.
2(cos20∘+isin20∘))3=__________
Answer:
After solving the power:
[tex]\bold{2(cos60^\circ+isin60^\circ)}[/tex]
Rectangular form:
[tex]\bold{1+i\sqrt3}[/tex]
Step-by-step explanation:
Given the complex number:
[tex]2(cos20^\circ+isin20^\circ)^3[/tex]
To find:
The indicated power by using De Moivre's theorem.
The complex number in rectangular form.
Rectangular form of a complex number is given as [tex]a+ib[/tex] where a and b are real numbers.
Solution:
First of all, let us have a look at the De Moivre's theorem:
[tex](cos\theta+isin\theta )^n=cos(n\theta)+isin(n\theta )[/tex]
First of all, let us solve:
[tex](cos20^\circ+isin20^\circ)^3[/tex]
Let us apply the De Moivre's Theorem:
Here, n = 3
[tex](cos20^\circ+isin20^\circ)^3 = cos(3 \times 20)^\circ+isin(3 \times 20)^\circ\\\Rightarrow cos60^\circ+isin60^\circ[/tex]
Now, the given complex number becomes:
[tex]2(cos60^\circ+isin60^\circ)[/tex]
Let us put the values of [tex]cos60^\circ = \frac{1}{2}[/tex] and [tex]sin60^\circ = \frac{\sqrt3}{2}[/tex]
[tex]2(\dfrac{1}{2}+i\dfrac{\sqrt3}2)\\\Rightarrow (2 \times \dfrac{1}{2}+i\dfrac{\sqrt3}2\times 2)\\\Rightarrow \bold{1 +i\sqrt3 }[/tex]
So, the rectangular form of the given complex number is:
[tex]\bold{1+i\sqrt3}[/tex]
Shyla's research shows that 8 empty cans make 1/4 pound of aluminum. Shyla wants to know how many cans does it take to make 5 pounds of aluminum. How many cans are there per pound of aluminum?
Answer:
They will need 160 cans to make 5 lbs
32 cans for 1 lbs
Step-by-step explanation:
We can use ratios to solve
8 cans x cans
--------------- = ---------------
1/4 lbs 5 lbs
Using cross products
8 * 5 = 1/4x
40 = 1/4 x
Multiply each side by 4
4 * 40 = 1/4 x * 4
160 =x
They will need 160 cans to make 5 lbs
8 cans x cans
--------------- = ---------------
1/4 lbs 1 lbs
Using cross products
8 * 1 = 1/4x
Multiply each side by 4
8*4 = x
32 cans for 1 lbs
Answer:
32 cans per pound of aluminum
160 cans per 5 pounds of aluminum
Step-by-step explanation:
will make it short and simple.
8 empty cans can make 1/4 pound of aluminum.
therefore... 8 x 4 = 32 cans per pound of aluminum.
Number of cans to make 5 pounds of aluminum = 32 x 5
= 160 cans per 5 pounds of aluminum
Which is greater 9/20 or 60%
Answer:
60%
Step-by-step explanation:
9/20 is 45%
Answer:
60 %
Step-by-step explanation: If you divide 9/20, it equals to 0.45, makes it 45% and the number 45 in general is smaller than 60. Thus, 60% is greater than 9/20. I hope this helps.
The sum of two positive number is 6 times their difference. what is the reciprocal of the ratio of the larger number to the smaller?
let the numbers be a and b, a>b
a+b=6(a-b)
we need to find reciprocal of ratio of larger to smaller , which will be same as ratio of smaller to larger or b/a, let's call it x
divide the equation by a.
1+x=6(1-x)
on solving, x=5/7
I need help with this math problem please (3x+2)(5x-7)
Answer:
Hey there!
Using the foil method: (3x+2)(5x-7)
15x^2+10x-21x-14
15x^2-11x-14
Let me know if this helps :)
Find the total amount in the compound interest account.
$10000 is compounded semiannually at a rate of 9% for 22 years.
(Round to the nearest cent.)
Answer:
$69,361.23
Step-by-step explanation:
[tex] A = P(1 + \dfrac{r}{n})^{nt} [/tex]
[tex] A = 10000(1 + \dfrac{0.09}{2})^{2 \times 22} [/tex]
[tex]A = 10000(1.045)^{44}[/tex]
[tex] A = 69361.23 [/tex]
Answer: $69,361.23
These figures are similar. The area of one is given. Find the area of the other. PLZ HELP
Answer: 6
Step-by-step explanation:
If P is the midpoint of XY, XP = 8x - 2 and PY = 12x - 30, find the
value of x.
Answer:
x=7
Step-by-step explanation:
If P is the midpoint of XY, then XP = PY:
8x - 2 = 12x - 3012x -8x = 30 -24x = 28x= 28/4x= 7Find the missing side or angle.
Round to the nearest tenth.
Answer:
a = 4.1Step-by-step explanation:
To find the missing side in the question, we use the cosine rule
That's
Since we are finding a we use the formula
a² = b² + c² - 2(b)(c) cos AFrom the question
b = 2
c = 4
A = 78°
Substitute the values into the above formula
We have
a² = 2² + 4² - 2(2)(4) cos 78
a² = 4 + 16 - 16 cos 78
a² = 20 - 16cos 78
a² = 16.67341
Find the square root of both sides
a = 4.0833
We have the final answer as
a = 4.1 to the nearest tenthHope this helps you
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0 (csc(x) − cot(x))
Answer:
0
Step-by-step explanation:
[tex]\lim_{x \to 0} (csc(x)-cot(x))\\= \lim_{x \to 0}(\frac{1}{sin x}-\frac{cos(x)}{sin (x)} )\\=\lim_{x \to 0}(\frac{1-cos x}{sin x} )\\=\lim_{x \to 0}(\frac {2 sin ^2 \frac{x}{2}}{2sin \frac{x}{2} cos\frac{x}{2} } )\\=\lim_{x \to 0}(tan \frac{x}{2} )\\=\lim_{x \to 0}\frac{tan \frac{x}{2} }{\frac{x}{2} } \times \frac{x}{2} \\=1 \times 0\\=0[/tex]
perform the following division (-2/3) ÷ (4/7)
Answer:
-7/6
Step-by-step explanation:
-2/3 x 7/4 = -14/12 = -7/6
Answer: -7/6
Step-by-step explanation: (-2/3) ÷ (4/7) can be rewritten as (-2/3) · (7/4).
Remember that dividing by a fraction is the same thing
as multiplying by the reciprocal of the fraction.
Before multiplying however, notice that we
can cross-cancel the 2 and 4 to 1 and 2.
So multiplying across the numerators and denominator and
remembering our negative in the first fraction, we have -7/6.
A study of 200 computer service firms revealed these incomes after taxes: Income After Taxes Number of Firms Under $1 million 102 $1 million up to $20 million 61 $20 million or more 37 What is the probability that a particular firm selected has $1 million or more in income after taxes
Answer:
The probability that a particular firm selected has $1 million or more in income after taxes is 49%.
Step-by-step explanation:
We are given a study of 200 computer service firms revealed these incomes after taxes below;
Income After Taxes Number of Firms
Under $1 million 102
$1 million up to $20 million 61
$20 million or more 37
Total 200
Now, the probability that a particular firm selected has $1 million or more in income after taxes is given by;
Total number of firms = 102 + 61 + 37 = 200
Number of firms having $1 million or more in income after taxes = 61 + 37 = 98 {here under $1 million data is not include}
So, the required probability = [tex]\frac{\text{Firms with \$1 million or more in income after taxes}}{\text{Total number of firms}}[/tex]
= [tex]\frac{98}{200}[/tex]
= 0.49 or 49%
The probability that a particular firm selected has $1 million or more in income after taxes is 0.49 or 49%.
What is probability?Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.
A study of 200 computer service firms revealed these incomes after taxes:
Income After Taxes Number of Firms Under
$1 million 102
$1 million up to $20 million 61
$20 million or more 37.
Then the total event will be
Total event = 102 + 37 +61 = 200
The probability that a particular firm selected has $1 million or more in income after taxes will be
Favorable event = 37 + 61 = 98
Then the probability will be
[tex]\rm P = \dfrac{98}{200} \\\\P = 0.49 \ or \ 49 \%[/tex]
More about the probability link is given below.
https://brainly.com/question/795909
€16.800,00. What is this in US Currency?
Answer:
That would be written as $16,800.00, or as $19,811.90 if you convert it at the current rate of exchange.
Step-by-step explanation:
Periods are used in European numbers to split up each third placed number while commas are used in the U.S.
Answer:
= 19824 us dollars
Step-by-step explanation:
Today august 09 2020:
1€ = 1.18 us dollars
then:
16800€ = 16800*1.18 = 19824 us dollars
check to see whether 5 is a solution: 10 + 7g < 44
Answer:
Not a solution
Step-by-step explanation:
We want to check and see if 5 is a solution to the inequality. Therefore, we must substitute 5 into the inequality.
[tex]10+7g < 44[/tex]
Plug 5 in for g.
[tex]g=5[/tex]
[tex]10+7(5) < 44\\[/tex]
First, multiply 5 and 7.
[tex]10 + (7*5) < 44[/tex]
[tex]10 + 35 < 44[/tex]
Next, add 10 and 35.
[tex](10+35) < 44[/tex]
[tex]45 < 44[/tex]
This statement is not true. 45 is not less than 44. Therefore, 5 is not a solution.
Answer:
it is not a solution
Step-by-step explanation:
By replacing the letter g with a 5 the answer would be 45<44 which is not true
Marco purchased a large box of comic books for $300. He gave 15 of the comic books to his brother and then sold the rest on an internet website for $330 making a profit , making a profit of $1.50 on each one.how many comic books were in the box? what was the original price of each comic book (assuming they all cost the same amount)?
Answer: There are 75 books.
Price of each book = $4.
Step-by-step explanation:
Let x = Number of books in the box.
Then as per given,
Cost of x books = $300
Cost of one book = [tex]\$(\dfrac{300}x)[/tex]
Books left after giving 15 of them = x-15
Selling price of (x-15) books= $330
Selling price of one book = [tex]\$(\dfrac{330}{x-15})[/tex]
Profit on each book= $1.50
Profit = selling price - cost price
[tex]\Rightarrow 1.50=\dfrac{330}{x-15}-\dfrac{300}{x}\\\\\Rightarrow\ 1.50=\dfrac{330(x)-300(x-15)}{x(x-15)}\\\\\Rightarrow\ 1.50=\dfrac{330x-300x+4500}{x^2-15x}\\\\\Rightarrow\ 1.50(x^2-15x)=30x+4500\\\\\Rightarrow\ 1.50x^2-22.5x=30x+4500\\\\\Rightarrow\ 1.50x^2-52.5x-4500=0\\\\\Rightarrow\ 1.50x^2-52.5x-4500=0\\\\\Rightarrow\ x^2-25x-3000=0\ \ [\text{divide by 1.5}][/tex]
[tex]\Rightarrow (x+40)(x-75)=0\\\\\Rightarrow\ x=-40,75[/tex]
Number of books cannot be negative.
So, there are 75 books.
Price of each book = [tex]\dfrac{300}{75}=\$4[/tex]
So price of each book = $4.
A researcher measures daily driving distance from college and weekly cost of gas for a group of commuting college students. What kind of correlation is likely to be obtained for these two variables?
Answer:
There is a positive correlation between these two variables.
Step-by-step explanation:
Positive correlation is an association amid two variables in which both variables change in the same direction.
A positive correlation occurs when one variable declines as the other variable declines, or one variable escalates while the other escalates.
As the distance covered by the vehicle increases the amount of gas consumed also increases. Thus, the weekly cost of gas will also increase.
Thus, there is a positive correlation between these two variables.
PLS HELPPPPPPPPPPP :p 8*10^3 is how many times larger that 4*10^2?
Answer:
20 times.
Step-by-step explanation:
To find out how many times larger a number is than another number, simply divide the two numbers, with the larger number being in the numerator.
For example, how many times larger is 6 than 2? The answer would be 6/2 or 3 times larger.
So, divide 8*(10^3) and 4*(10^2):
[tex]\frac{8\times10^3}{4\times10^2}[/tex]
Expand the expressions. This is the same as saying:
[tex]\frac{8\times10\times10\times10}{4\times10\times10}[/tex]
We can cancel two of the 10s since they are in both the numerator and the denominator. Thus, only one 10 is left in the numerator:
[tex]\frac{8\times10}{4}[/tex]
Simplify:
[tex]=\frac{80}{4} =20[/tex]
Therefore, 8*(10^3) (or 8000) is 20 times larger than 4*(10^2) (or 400).
Answer:
20 times
Step-by-step explanation:
hey,
so lets solve 8*10^3 first
so we use the order of operations
P
= Parentheses first
E
= Exponents (ie Powers and Square Roots, etc.)
MD
= Multiplication and Division (left-to-right)
AS
= Addition and Subtraction (left-to-right)
so after doing the exponents part 8*1000
we do the multiplication
=8000
SO THE FIRST NUMBER IS 8000
now lets solve 4*10^2
so we use the order of operations
P
= Parentheses first
E
= Exponents (ie Powers and Square Roots, etc.)
MD
= Multiplication and Division (left-to-right)
AS
= Addition and Subtraction (left-to-right)
so we do exponents first 4*100
then multiplication
=400
SO THE SECOND NUMBER IS 400
To find out how many times larger a number is than another number, simply divide the two numbers, with the larger number being in the numerator.
now we divide 8000 by 400
=20
so 8*10^3 is 20 times larger than 4*10^2
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
Repeated-measures and matched-subjects experiments Aa Aa Repeated-measures experiments measure the same set of research participants two or more times, while matched-subjects experiments study participants who are matched on one or more characteristics. Which of the following are true for both a repeated-measures experiment and a matched-subjects experiment when used to compare two treatment conditions? Check all that apply.
A. The researcher computes difference scores to compute a t statistic
B. If the researcher has n number of participants to use in the experiment, then the degrees of freedom will be the same in a repeated-measures experiment or in a matched-subjects experiment
C. The researcher must compute an estimated standard error for the mean difference score to compute a t statistic.
D. Participants in both types of experiments are all measured the same number of times
A matched-subjects experiment produced a t statistic with a df of 9. How many subjects participated in this study?
A. 20
B. 10
C. 18
D. 9
For a repeated-measures experiment comparing two treatment conditions, the t statistic has a df of 11. How many subjects participated in this study?
A. 12
B. 22
C. 24
D. 11
Answer:
1. C. The researcher must compute an estimated standard error for the mean difference score to compute a t statistics.
2. B. 10
3. A. 12
Step-by-step explanation:
The degrees of freedom is number of independent variable factors that affect the range of parameters. The degrees of freedom is the calculation of number values that are free to vary. The degrees of freedom is calculated by N-1. Standard error is the estimated deviation of standard deviation from its sample mean distribution.
