2hr 57min+3hrs42min​

Answer:

[tex]\frac{12}{49}[/tex]

Step-by-step explanation:

[tex]\frac{4}{7} *\frac{3}{7} = \frac{12}{49}[/tex]

Hope this helps.

Answer:

[tex]f^{-1}(x) =\frac{x}{3} - 5[/tex]

The inverse function is to calculate the number of rides; given the amount paid

Step-by-step explanation:

Given

[tex]Admission = 15[/tex]

[tex]Ride = 3[/tex] per ride

Required

Explain the inverse function

First, we calculate the function

Let x represents the number of rides

So:

[tex]f(x) = Admission + Ride * x[/tex]

[tex]f(x) = 15 + 3 * x[/tex]

[tex]f(x) = 15 + 3x[/tex]

For the inverse function, we have:

[tex]y = 15 + 3x[/tex]

Swap x and y

[tex]x = 15 + 3y[/tex]

Make 3y the subject

[tex]3y = x - 15[/tex]

Make y the subject

[tex]y =\frac{x}{3} - 5[/tex]

Replace y with the inverse function

[tex]f^{-1}(x) =\frac{x}{3} - 5[/tex]

The above is to calculate the number of rides; given the amount paid

Area of a circle is pi x radius^2

Area = pi x 22 ^2

Area = pi x 484

Area = 1,519.8 mm^2

Answer:

1520.5mm²

Step-by-step explanation:

Area of a circle=πr²

π(22mm)²

π484mm²

1520.5308443374599mm²

to one decimal place

1520.5mm²

Answer:

They went over their goal for the last six months by 34 minutes per month.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the size of the data-set.

529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan.

The mean is:

[tex]M = \frac{529+499+651+652+1163+310}{6} = 634[/tex]

By how many minutes did they go over their goal in the last six months?

The mean was of 634 minutes, and they wanted to keep it below 600. So

634 - 600 = 34

They went over their goal for the last six months by 34 minutes per month.

Answer: $235.4

Step-by-step explanation:

Given

Price list on slacks is $22

Price list on jumpers is $37

Store ordered 30 pairs of slacks and 40 Jumpers

Total price becomes

[tex]\Rightarrow 22\times 30+37\times 40\\\Rightarrow \$2140[/tex]

for a discount of 11%

Trade discount is [tex]2140\times 11\%[/tex]

[tex]\Rightarrow 2140\times 0.11\\\Rightarrow \$235.4[/tex]

Answer:

The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)

Step-by-step explanation:

Hey there!

The probability of first getting a red marble is 1/3 since we have 1 red marble out of 2 + 1 = 3 total.

We put the marble back. The probability of then choosing a black marble is 2/3, since we have 2 black marbles out of 3 total.

So we get 1/3 * 2/3 = 2/9

The probability of picking a red marble first then replacing it and getting a black marble is 2/9. (The last option.)

Hope this helps, please mark brainliest if possible. Have a nice day. :)

9514 1404 393

Answer:

  -3840t^4

Step-by-step explanation:

The k-th term, counting from k=0, is ...

  C(5, k)·(4t)^(5-k)·(-3)^k

Here, we want k=1, so the term is ...

  C(5, 1)·(4t)^4·(-3)^1 = 5·256t^4·(-3) = -3840t^4

__

The program used in the attachment likes to list polynomials with the highest-degree term last. The t^4 term is next to last.

[tex]f'(4) = 43[/tex]

Explanation:

Given: [tex]f(x)=5x^2 + 3x + 3[/tex]

[tex]\displaystyle f'(x)= \lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h}[/tex]

Note that

[tex]f(x+h) = 5(x+h)^2 + 3(x+h) + 3[/tex]

[tex]\:\:\;\:\:\:\:= 5(x^2 + 2hx + h^2) + 3x + 3h +3[/tex]

[tex]\:\:\;\:\:\:\:= 5x^2 + 10hx + 5h^2 + 3x + 3h +3[/tex]

Substituting the above equation into the expression for f'(x), we can then write f'(x) as

[tex]\displaystyle f'(x) = \lim_{h \to 0} \dfrac{10hx + 3h + 5h^2}{h}[/tex]

[tex]\displaystyle\:\:\;\:\:\:\:= \lim_{h \to 0} (10x +3 +5h)[/tex]

[tex]\:\:\;\:\:\:\:= 10x + 3[/tex]

Therefore,

[tex]f'(4) = 10(4) + 3 = 43[/tex]

Answer:

5

Step-by-step explanation:

2/5 pickled peppers means that there are 2 pickled peppers out of 5 total peppers.

Answer:

64.2 minutes

Step-by-step explanation:

We are given that

Shen set timer to run=93 minutes

He has finished his run=69%

We have to find total number of minutes have gone by.

69% of 93

=[tex]\frac{69}{100}\times 93[/tex]

By using

a%[tex]=\frac{a}{100}[/tex]

69% of 93=[tex]\frac{6417}{100}[/tex]

69% of 93=64.17 min

69% of 93[tex]\approx 64.2min[/tex]

Hence, 64.2 minutes have gone by.

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Answer:

  $2505.80

Step-by-step explanation:

After the first exchange, the tourist has ...

  $3000(12.90 R/$) = R38,700

After 7 days, she has ...

  R38,700 -7(R900) = R32,400

After the second exchange, she has ...

  R32,400 × ($1/R12.93) = $2505.80

She gets $2505.80 at the second exchange.

Answer:

where are you from Korea or not

Hope it helps you!

-miraculousfanx-

Answer:

√-2 ≈ 1.41i

Step-by-step explanation:

√-2 = i√2 = i × 1.414.. ≈ 1.41i

Answer:

Step-by-step explanation:

y=3√x

domain : all real values≥0

Answer:

6 kwh

Step-by-step explanation:

(51 - 21.9)/4.66 = 6.24 => 6 kwh

Answer:

Santino rented the canoe for 8 hours.

Step-by-step explanation:

The total bill is represented by the formula r(h) = $10 + ($7.50/hour)h,

where h is the number of hours over which the canoe is rented.

If the total bill is $70, then $70 = $10 +  ($7.50/hour)h.

Solve this for h.  Start by subtracting $10 from both sides, obtaining:

$60 =  ($7.50/hour)h.

Dividing both sides by ($7.50/hour), we get:

           $60

h = --------------------- = 8 hours

      ($7.50/hour)

Santino rented the canoe for 8 hours.

Answer:

Step-by-step explanation:

[tex]20 \frac{1}{4} =\frac{80+1}{4} =\frac{81}{4} \\\sqrt{\frac{81}{4} } =\frac{9}{2} =4.5[/tex]

Answer:

21 is the answer I think sike I lied ik its not im just trying get this over with

You can use this formula to work out the area of a triangle when you know two sides and the angle inbwtween them :

1/2 x a x b x sin(C)

where a and b are the two sides you know and C is the angle in between them.

So here a = 7, b = 14, C = 125.

Area = 1/2 x 7 x 14 x sin(125) = 40.138...

= 40.1 (nearest 10th)

Answer:

Answer is 42

Step-by-step explanation:

2^5 + 10

2*2*2*2*2 + 10

32 + 10

42

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Answer:

Step-by-step explanation:

The angle is in the 2nd quadrant, where the sine is positive and the cosine is negative.

tan^2(θ) +1 = sec^2(θ) = (-9/4)^2 +1 = 97/16   ⇒   sec = -(1/4)√97

cot(θ) = 1/tan(θ) = -4/9

csc^2(θ) = cot^2(θ) +1 = (-4/9)^2 +1 = 97/81   ⇒   csc = (1/9)√97

sin(θ) = 1/csc(θ) = (9√97)/97

cos(θ) = 1/sec(θ) = (-4√97)/97

Answer:

[tex]{ \tt{ w = 2hx - 11x}} \\ \\ { \bf{w = x(2h - 11)}} \\ \\ { \bf{x = \frac{w}{2h - 11} }}[/tex]

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: x = \frac{w}{(2h - 11)} }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]w = 2hx - 11x[/tex]

[tex]✒ \: w = x \: (2h - 11)[/tex]

[tex]✒ \: x = \frac{w}{(2h - 11)} [/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

Answer: Bottom left corner

=======================================================

Explanation:

There are only four possible outcomes here

Based on this so far, the answer is either the table in the bottom left corner or in the top right corner. It's not possible for X = 4 since we only flipped 3 coins.

The probability of case A happening is 1/8 since we have 1 scenario that's all tails (TTT) out of 8 items in the sample space. Similarly, the probability for case D is the same probability. We only have one HHH out of 8 total items.

The probabilities of cases B and C are the same. Both are 3/8. Note that for case B, we have HTT, THT, TTH which is three occurrences in which we get exactly 1 head. So that explains the 3/8.

Answer:

We want to find:

[tex]\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}[/tex]

Here we can use Stirling's approximation, which says that for large values of n, we get:

[tex]n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n[/tex]

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

[tex]\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}[/tex]

Now we can just simplify this, so we get:

[tex]\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\[/tex]

And we can rewrite it as:

[tex]\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}[/tex]

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

[tex]\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}[/tex]

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Answer:

  B. 8 and 24

Step-by-step explanation:

There are a number of approaches you can use here. One of them is to choose the only answer that makes any sense in the problem.

The problem tells you the numbers have a ratio of 3, so numbers like 8 and 25, 9 and 24, 9 and 25 cannot be the answer.

The only answer choice that makes any sense is B: 8 and 24.

__

If you want to work the problem, there are different ways you can do that. One of my favorite is to consider ratio units. The ratio of the two numbers is 3:1. The difference of the two numbers is 3-1 = 2 ratio units, which we are told is 16. Then each ratio unit represents 16/2 = 8. Then the numbers are ...

  3×8 and 1×8 = 24 and 8.

Or, you can let a variable represent one of the numbers. If x is the first number, then the other number is 1/3x, and their difference is ...

  x -1/3x = 16

  2/3x = 16

  x = 16(3/2) = 24

The numbers are 24 and 24/3 = 8.

__

Additional comment

You need to talk to your teacher about this question. The answer choices list the smaller number first, but the problem statement tells you the first number is 3 times the second number. The correct answer would be 24 and 8.

Answer:

[tex]y=\frac{5}{2}x-14[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the slope (m)

[tex]y=\frac{5}{2}x-10[/tex]

In the given equation, [tex]\frac{5}{2}[/tex] is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of [tex]\frac{5}{2}[/tex]. Plug this into [tex]y=mx+b[/tex]:

[tex]y=\frac{5}{2}x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=\frac{5}{2}x+b[/tex]

Plug in the given point (-6,-29) and solve for b

[tex]-29=\frac{5}{2}(-6)+b[/tex]

Simplify -6 and 2

[tex]-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b[/tex]

Add 15 to both sides to isolate b

[tex]-29+15=-15+b+15\\-14=b[/tex]

Therefore, the y-intercept is -14. Plug this back into [tex]y=\frac{5}{2}x+b[/tex]:

[tex]y=\frac{5}{2}x-14[/tex]

I hope this helps!

Answer:

[tex]Width = 59[/tex]

Step-by-step explanation:

Given

The above data

Required

The class width

To do this, we simply calculate the difference between the class limits of any one of the classes.

Taking 1187–1246 as a point of reference, the class width is:

[tex]Width = 1246 - 1187[/tex]

[tex]Width = 59[/tex]

Answer:

since it's the lhs we are concerned about, i. e., Y axis, so it must be either up or down. now look at the question, it says 8x2 - (1), it means one lower value of y i. e., 1 unit down

Answer:It is shifted 1 unit down.

Step-by-step explanation:

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Answer:

  True

Step-by-step explanation:

In a geometric sequence, the terms a[n+1] and a[n] are related by the common ratio. If the sequence is otherwise unspecified, two sequential terms may have any a relation you like.* Either could be larger or smaller than the other.

__

* If one is zero, the other must be as well. Multiplying 0 by any finite common ratio will give zero as the next term.