Answer:
well its -2*-3-3 so
-2*-3 is 6-3 is 3
Step-by-step explanation:
(2x+y)2-y2 if x=-3 y=4 and z=-5
2. A house costs $30,000. A buyer is given a 1/10 discount. How much money does the buyer save?
Answer:
3000
Step-by-step explanation:
Write a linear inequality for each graph (back page)
Answer:
I can't read that...........
Determine the rate of change between the points (-1,-1) and (1,-1).
Answer:
[tex]\displaystyle m = 0[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinate Planes
Coordinates (x, y)Slope Formula: [tex]\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]Step-by-step explanation:
*Note:
Rate of change is slope.
Step 1: Define
Identify.
Point (-1, -1)
Point (1, -1)
Step 2: Find slope m
Simply plug in the 2 coordinates into the slope formula to find slope m.
Substitute in points [Slope Formula]: [tex]\displaystyle m = \frac{-1 + 1}{1 + 1}[/tex][Order of Operations] Simplify: [tex]\displaystyle m = \frac{0}{2}[/tex]Simplify: [tex]\displaystyle m = 0[/tex]in triangle abc it is given that AB =9 cm Bc=6cm and Ca = 7.5 cm also
triangle def is given that ef =8 cm and triangle def similar to triangle abc then perimeter of triangle def is
Answer:
Make me as brain liest plz
The perimeter of triangle DEF is; 30 cm
Similar TrianglesWe are given dimensions of Triangle ABC as;
AB = 9 cmBC = 6 cmCA = 7.5 cmThus;
Perimeter of Triangle ABC = 9 + 6 + 7.5 = 22.5 cm
We are told that Triangle DEF is similar to Triangle ABC.
This means that the ratio of corresponding sides must be equal to the ratio of their perimeter.
Side EF corresponds to side BC. Thus;
Perimeter of Triangle DEF/22.5 = 8/6
Cross multiply to get;
Perimeter of Triangle DEF = (22.5 × 8)/6
Perimeter of Triangle DEF = 30 cm
Read more on similar triangles at; https://brainly.com/question/14285697
You plan on joining a gym. The joining fee is $30 and you must pay $12 a month fee. If you have $100, how many months can you use the gym? Write and solve an inequality to represent the solution.
I need the process for this otherwise I won't get credit for it!!
Answer:
Inequality: 30+12x < 100
x ≈ 5 months
Step-by-step explanation:
To solve, first create the inequality. In this problem, 30 dollars is the flat fee for joining the gym and thus a constant. Additionally, 12 is the monthly payment and thus the coefficient for a variable because it changes with the number of months. Finally, 100 is the most that can be spent (the max), so it should be on the other side of the inequality and the sign should be less than or equal to 100.
This makes the inequality: 30+12x < 100
To find the number of months solve the inequality for x.
30+12x<10012x<70x<5.8So, the inequality equals x<5.8. However, the question asks for the number of full months. And, no more than 100 dollars can be spent. So, while you would normally round up. In this case, you must round down to 5 months.
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
help me please !!!!
Answer:
graph X only
Step-by-step explanation:
because with the rate of change it makes a straight line
Today everything at a store is on sale the store offers a 20
% discount the regualr price of a t shirt is 18 what is the discount price
Answer:
$14.40 is the discount price.
Step-by-step explanation:
0.2 x 18 = 3.6
18 - 3.6 = 14.4
Andrew shovels snow for 4 %2 hours and makes
$27. How much did he make per hour?
And how much does he earn in 8 hours?
(20pts) I need to know who is incorect and why
Answer:
i thig it is hj
Step-by-step explanation:
jk
tony purchases a pair of jeans for 45.49 before tax the jeans were originally priced at 69.99 what was the percent discount a 35% B 20% C 65% and D 80% pls help
the book is think up
Answer:
your so funny for a annoying kid
Step-by-step explanation:
A convenience store purchased a magazine and marked it up 100% from the original cost of $2.30. A week later, the store placed the magazine on sale for 50% off. What was the discount price?
A two digit number is four times the sum and three times the product of its digit. Find the number.
Please help this is my fifth time asking this question please answer it correctly with explanation
Step-by-step explanation:
There are two attachments to this post. The first attachment shows the numbered angles formed through the intersection of the transversal, t, into the parallel lines, m and n, which will be used to determine how each angle relates to other angles.
First attachment:The corresponding angles in the first attachment are:
∠1 and ∠5
∠2 and ∠6
∠3 and ∠7
∠4 and ∠8
Corresponding angles have the same measure.
The same-side exterior angles are the pair of angles that are outside the parallel lines, and on the same side of the transversal. In the first attachment, the same-side exterior angles are:
∠1 and ∠8
∠2 and ∠7
These angles are supplements of each other, meaning that the sum of their measure equal 180°.
Second Attachment:
Given parallel lines, m and n that are cut by a transversal, t.
The angle that has a measure of ∠(10x + 5)° is a supplement of ∠(5x + 25)°. In order to solve for the value of x, we must establish the following equation:
m∠(10x + 5)° + m∠(5x + 25)° = 180°
10x° + 5° + 5x° + 25° = 180°
Combine like terms:
15x° + 30° = 180°
Subtract 30 from both sides:
15x° + 30° - 30° = 180° - 30°
15x° = 150°
Divide both sides by 15:
15x°/15 = 150°/15
x = 10°
Verify whether we have correct value for x by substituting its value into the established equation:
m∠(10x + 5)° + m∠(5x + 25)° = 180°
10(10)° + 5° + 5(10)° + 25° = 180°
100° + 5° + 50° + 25° = 180°
180° = 180° (True statement).
Therefore, we have the correct value for x = 10°.
m∠(10x + 5)° = 105°
m∠(5x + 25)° = 75°
Identify the vertex of the parabola represented by the equation y=−2x2+8x−1.
(−4, −65)
(4, −1)
(2, 7)
(−2, −25)
Answer:
it is correct but -65 is not correct
Please Help!! Asap!!
A local club team is holding tryouts for six spots on the soccer team. Since there is not much time before a very important tournament they need to select the best players. Which method would be the best to ensure they select the "most talented" soccer players?
A. They watch the players during tryouts and then put them on a list in order from the most skilled to the least skilled and then select the top six from the list.
B. The first day of tryouts they select the first six that show up as they figure those are the most eager for a spot.
C. They place all of the names of the people trying out in a hat and then select six out of the hat. Those are the ones that are chosen.
D. They watch the players during tryouts and then put them on a list in order from the most skilled to the least skilled and then select the top three and the bottom three from the list.
Answer:
A because it's most likely to be like that at tryouts
Z=3 evaluar -[z-(-z)+z]Por favor alguien que me ayude
a number of students are standing in a circle. they are evenly spaced and the fith student is directly opposite the eleventh student. how many students are there all together
Answer:
There would be 12
Step-by-step explanation:
HURRY PLEASE! Do questions 4,5,6 on paper
This should be right , if any doubt please comment
does anyones know these ?
No I don't know your thing
Consider this function.
h(x) = (x - 2)^2+3
Which of the following domain restrictions would enable h(x) to have an inverse function?
a. x < 1
b. x ＞5
c. x < 3
d. x > 4
(Ps: all four answer and larger equal then or smaller equal then
Answer:
No inverse function: (a), (b), (c)
Inverse function exists: (d)
Step-by-step explanation:
The graph of h(x) = (x - 2)^2 + 3 is a parabola that opens upward and has vertex at (2, 3). If the entire graph is drawn, and the horizontal line test then applied, h(x) would not have an inverse, because the horizontal line would intersect the parabolic graph twice.
Note that if we restricted the domain to x ≥ 2, the resulting graph would pass the horizontal line test. This would also be true for x ≥ 3, x ≥ 4, and so on. Not so for (a) x < 1. False for x > -5. True for x < 3. True for x > 4.
No inverse function: (a), (b), (c)
Inverse function exists: (d)
Write the equation of the line with x-intercept 3 and passing through the point (5.4)
Answer: y=(1/5)m+3
Step-by-step explanation:
Start with the standard form of an equation of a straight line: y=mx+b, whre m is the slope and b the y-intercept (the value of y when x=0).
y=mx+b
We know b (3), so:
y=mx + 3
To find the slope, m, we can use the one given point, (5,4):
y=mx + 3 for (5,4) would be:
4 = m*5+3
1 = 5m
m = (1/5)
y=(1/5)m+3
Help me this question is so hard i fried up my brain yesterday working on it for so long!!!!
Hello there! (:
The answer is 9.
3^4=3*3*3*3 (81)
3^2=9
81:9=9
So the answer is 9.
Hope it helps! If you have any question or query, feel free to ask! (:
~An excited gal
[tex]SparklingFlower[/tex]
How many solutions can be found for the system of linear equations represented on the graph?
A) no solution
B) one solution
C) two solutions
D) infinitely many solutions
Answer:
A) No solution
Step-by-step explanation:
Given the systems of linear equations, y = 2x + 1 and y = 2x - 1:
Both equations in the system have the same slope, m = 2, thus forming parallel lines. Since their lines are parallel from each other, then it means that their lines will never intersect.
Therefore, the given systems of linear equation is an inconsistent system that has no solution.
Plsss help It due tmr plsss
Answer: 50
Step-by-step explanation:
exterior angles are supplement of interior angle therefore the 110 thing must be 70, also youre given 60 so 70+60=130
50 is missing from 180
Can someone help plz
-x+3y=0
x+3y=12
System of linear equation by elimination
Answer:
x=6
y=2
Step-by-step explanation:
-x+3y=0 (1)
x+3y=12 (2)
(1)+(2)<=> 6y=12
A car traveled 35 miles per hour. In how many hours did it travel 280 miles?
Answer:
8
Step-by-step explanation:
280/35=8
Answer:
8 hours.
Step-by-step explanation:
280/35 = 8
The greatest possible number whose digits are all even numbers from 1 to 9
Answer:
8642Step-by-step explanation:
Our even numbers from 1-9 are:
2,4,6,8The largest possible number using the even numbers once is 8642.
Hoped this helped
Please help. ASAP. Work out, giving your answer in its simplest form:
3 1/2 divided by 2 3/5
Answer:
26/35
Step-by-step explanation:
1. First to divide the 3 1/2 by 2 3/5 you have to turn them both into improper fractions
First take 3 1/2. You have to multiply the whole number (3) by the denominator (2) and you would get 6. Then you would add then you add the product (6) to the numerator (1) and get 7.
You keep the denominator the same so the improper fraction is 7/2
Do the same thing to 2 3/5 and the improper fraction is 13/5
2. Now we can divide 13/5 by 7/2 using "keep, change, flip"
Keep: 13/5
Change: division to multiplcation
Flip: 7/2 to make 2/7
Your new equation is 13/5 × 2/7. Multiplcation is easy so you just have to multiply staight across: 13 × 2 and 5 × 7 giving you 26/35
If you divide 35 by 26 you will get 1.34 and a bunch of other numbers but I usually stop at two decimal places
hope this helps :)
