3. A toy car is traveling with a velocity of 4 m/s and has a mass of 1120g. What is the car's
kinetic energy?

Answer:

<2 = 35degrees

<3 = 55degrees

Step-by-step explanation:

Find the diagram attached:

From the diagram:

<3 + <4 = 90

<3 + 35 = 90

<3 = 90 - 35

<3 = 55degrees

Also m<1 + m<2+ m<3 = 180 (sum of angles in a traingle)

90+<2+55=180

145+<2 = 180

<2 = 180 - 145

<2 = 35degrees

Answer:

c. Lower boundary = 0.50

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

An ecologist finds 220 yellow-flowered plants and 180 white-flowered plants.

220 out of 220 + 180 = 400. So

[tex]n = 400, \pi = \frac{220}{400} = 0.55[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.55 - 1.96\sqrt{\frac{0.55*0.45}{400}} = 0.5[/tex]

Thus the correct answer is given by option c.

Answer:

$1.65

Step-by-step explanation:

or

Missing from the question

Aletheia's speed is 0.6 miles per hour slower than Elvira's speed.

Answer:

[tex]s_E = 3.0[/tex]

[tex]s_A = 2.4[/tex]

Step-by-step explanation:

Given

[tex]d = 3.2m[/tex] -- distance

[tex]t_E = 1/2[/tex] --- Elvira time

[tex]t_A = 2/3[/tex] --- Aletheia time

[tex]s_E - s_A = 0.6[/tex] --- the relationship between their speeds

Required

Their walking speed

Distance (d) is calculated as:

[tex]d = speed * time[/tex]

For Elvira, we have:

[tex]d_E = s_E * 1/2[/tex]

For Aletheia, we have:

[tex]d_A = s_A * 2/3[/tex]

So, we have:

[tex]d_E + d_A = d[/tex] --- total distance

This gives:

[tex]s_E * 1/2 + s_A * 2/3 = 3.2[/tex]

Recall that:

[tex]s_E - s_A = 0.6[/tex]

Make sE the subject

[tex]s_E = 0.6+s_A[/tex]

Substitute [tex]s_E = 0.6+s_A[/tex] in [tex]s_E * 1/2 + s_A * 2/3 = 3.2[/tex]

[tex](0.6+s_A)* 1/2 + s_A * 2/3 = 3.2[/tex]

[tex]0.3+1/2s_A + 2/3s_A = 3.2[/tex]

Collect like terms

[tex]1/2s_A + 2/3s_A = 3.2-0.3[/tex]

[tex]1/2s_A + 2/3s_A = 2.9[/tex]

Express all as decimal

[tex]0.5s_A + 0.7s_A= 2.9[/tex]

[tex]1.2s_A= 2.9[/tex]

Divide both sides by 1.2

[tex]s_A = 2.4[/tex]

Recall that:

[tex]s_E = 0.6+s_A[/tex]

So, we have:

[tex]s_E = 0.6+2.4[/tex]

[tex]s_E = 3.0[/tex]  

If a is in the second quadrant, then cos(a) < 0 and sin(a) > 0.

Recall the double angle identity for cosine:

cos(2a) = 2 cos²(a) - 1 = 1 - 2 sin²(a)

It follows that

2 cos²(a) - 1 = -4/5   ==>   cos²(a) = 1/10   ==>   cos(a) = -1/√10

1 - 2 sin²(a) = -4/5   ==>   sin²(a) = 9/10   ==>   sin(a) = 3/√10

Then we find

1/cos(a) = sec(a) = -√10

1/sin(a) = csc(a) = √10/3

sin(a)/cos(a) = tan(a) = -3

1/tan(a) = cot(a) = -1/3

Answer:

C

Step-by-step explanation:

Vertical asymptotes are always in the form x = ?

If you look at the dotted line, it lands on 2.  Because it's a vertical line, the asymptote is going to be x = 2

Answer:

its the second option

Step-by-step explanation:

hope this helps

Answer: 5x-130=15

Step-by-step explanation:

edmentum

Answer:

Step-by-step explanation:

1. Apply the Pythagoras theorem to determine the value of x, we have;

[tex]/Hyp/^{2}[/tex] = [tex]/Adj 1/^{2}[/tex] + [tex]/Adj 2/^{2}[/tex]

[tex]x^{2}[/tex] = [tex]15^{2}[/tex] + [tex]8^{2}[/tex]

   = 289

x = [tex]\sqrt{289}[/tex]

x = 17

2. Trigonometric ratios of <D.

i. Sin <D = [tex]\frac{opposite}{hypotenuse}[/tex]

              =  [tex]\frac{8}{17}[/tex]

ii. Cos <D = [tex]\frac{Adjacent}{Hypotenuse}[/tex]

                = [tex]\frac{15}{17}[/tex]

iii. Tan <D = [tex]\frac{Opposite}{Adjacent}[/tex]

                 = [tex]\frac{8}{15}[/tex]

3. Trigonometric ratios of <F.

i. Sin <F = [tex]\frac{opposite}{hypotenuse}[/tex]

             = [tex]\frac{15}{17}[/tex]

ii. Cos <F = [tex]\frac{Adjacent}{Hypotenuse}[/tex]

              =  [tex]\frac{8}{17}[/tex]

iii. Tan <F = [tex]\frac{Opposite}{Adjacent}[/tex]

               = [tex]\frac{15}{8}[/tex]

Answer:

FE→

Step-by-step explanation:

You start with the endpoint and go in the direction of the arrow

FE

It will have an arrow on top with an endpoint on the left and an arrow going in the same direction to indicate it is a ray→

Answer:

A. multi-way split.

Step-by-step explanation:

Multi way split consists of internal at decision tree branches. Gini index measures probability of impurity in the random variables chosen. Entropy is measure of uncertainty in the sample selected. Binary splitting is used to speed up numerical evaluation.

Answer:

19) The square root of 35 with one digit decimal accuracy is 5.9.

21) The sqrt. of 61 to the nearest integer is 8!

Step-by-step explanation:

take the square roots around 61.

the square root of 8 is 64,

the square root of 7 is 49.

61 is closer to 64.

Integers cannot be fractions, so the answer of 7.8 is rounded up to 8! (This Is For Number 21)am not really that sure about number 19

Using translation concepts, it is found that the function whose graph is given is:

A. y= cos(2x)

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The original cosine function has period of [tex]2\pi[/tex], and in this problem, the function has a period of [tex]\pi[/tex], hence the domain was multiplied by 2, which means that option A is correct.

More can be learned about translation concepts at https://brainly.com/question/4521517

#SPJ1

I need the help for this quick app anyone can help

Answer:

80 Seconds

I dont really want to type the whole thing out, just think about it again, or go to a tutor website, you should be able to get it, you have to use these, multiplication of three numbers, and multiplication and division by factorization of numbers.

Answer:

432x^13

Step-by-step explanation:

(4x^2)^2 • (3x^3)^3

We know that a^b^c = a^(b*c)

4^2 x^2^2  * 3^3 x^3^3

16 x^4  * 27 x^9

We know that a^b ^ a^c = a^(b+c)

16*27 x^(4+9)

432x^13

Answer:

432x¹³

Step-by-step explanation:

( 4x² ) ² • ( 3x³ ) ²

( 16x²)² • ( 27x³)²

[tex]16 x{}^{2 \times 2} \times 6 {}^{3 \times 3 } \\ 16x {}^{4} \times27 {}^{9} [/tex]

[tex](16 \times 27)x {}^{4 + 9} [/tex]

432x¹³

Answer:

0.713 = 71.3% probability that the county office will get more than 0 calls in a 15 minute period.

Step-by-step explanation:

We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

A county office gets an average of 10 calls in a 2 hour time period.

10 calls each 120 minutes, which means that the mean for n minutes is:

[tex]\mu = \frac{10n}{120} = \frac{n}{12}[/tex]

15 minute period:

This means that [tex]n = 15, \mu = \frac{15}{12} = 1.25[/tex]

What is the probability that the county office will get more than 0 calls in a 15 minute period?

This is:

[tex]P(X > 0) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.25}*1.25^{0}}{(0)!} = 0.287[/tex]

So

[tex]P(X > 0) = 1 - P(X = 0) = 1 - 0.287 = 0.713[/tex]

0.713 = 71.3% probability that the county office will get more than 0 calls in a 15 minute period.

The answer is 4 because the frequency is the number of cycles completed in one interval. Typically, the interval given is 2π. Here, you can count the cycles and get 4.

Answer:

VW = 4.9

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 46°

Hypothenus = VU = 7

Adjacent = VW =?

The value of VW can be obtained by using the cosine ratio as illustrated below:

Cos θ = Adjacent / Hypothenus

Cos 46 = VW / 7

Cross multiply

VW = 7 × Cos 46

VW = 4.9

Therefore, the value of VW is 4.9

Answer:

A

Step-by-step explanation:

Because it’s correct, and explains the property correctly

Answer:

The center is (0,0) and the radius is 1/4

Step-by-step explanation:

The formula for a circle is

(x-h)^2 + (y-k)^2 = r^2  where (h,k) is the center and r is the radius

16x^2+16y^2=1

Divide  by 16

x^2+y^2=1/16

x^2 + y^2 = (1/4) ^2

(x-0)^2 + (y-0)^2 = (1/4) ^2

The center is (0,0) and the radius is 1/4

Answer:

s = 7√6.

Step-by-step explanation:

From the 30-60-90 triangle we know that cos 30 = √3/2.

cos 30 = s / 14√2

√3/2 =  s / 14√2

2s = 14√2√3

s = 14√2√3 / 2

s = 7√6.

Answer:

See Below.

Step-by-step explanation:

We are given that:

[tex]\displaystyle I = I_0 e^{-kt}[/tex]

Where I₀ and k are constants.

And we want to prove that:

[tex]\displaystyle \frac{dI}{dt}+kI=0[/tex]

From the original equation, take the derivative of both sides with respect to t. Hence:

[tex]\displaystyle \frac{d}{dt}\left[I\right] = \frac{d}{dt}\left[I_0e^{-kt}\right][/tex]

Differentiate. Since I₀ is a constant:

[tex]\displaystyle \frac{dI}{dt} = I_0\left(\frac{d}{dt}\left[ e^{-kt}\right]\right)[/tex]

Using the chain rule:

[tex]\displaystyle \frac{dI}{dt} = I_0\left(-ke^{-kt}\right) = -kI_0e^{-kt}[/tex]

We have:

[tex]\displaystyle \frac{dI}{dt}+kI=0[/tex]

Substitute:

[tex]\displaystyle \left(-kI_0e^{-kt}\right) + k\left(I_0e^{-kt}\right) = 0[/tex]

Distribute and simplify:

[tex]\displaystyle -kI_0e^{-kt} + kI_0e^{-kt} = 0 \stackrel{\checkmark}{=}0[/tex]

Hence proven.

Answer:

5 cases

10 additional units

Step-by-step explanation:

Given that :

Total number of units needed = 60 units

Total number of units per case = 14

Hence, the total number of cases required will be :

Number of units needed / number of units per case

Number of cases required = 60 / 14 = 4.285 (this means that 5 cases are required as 4 cases won't be up to 60 units)

With 5 cases, we have exceeded the required units needed :

Additional units will be : (14 * 5) - 60

Additional units = 70 - 60 = 10 units

An

Step-by-step explon:

Step-by-step explanation:

1. The inputs are the dice values. Since the cube is six sided, the possible. values are (1,2,3,4,5,6).

2. The outputs values are points if we roll the number. If we land in a special space, we must respect that rule so our outputs are

(2,2,8,5,6,8).

3. I cant show a mapping diagram on brainly. Draw a mapping diagram and make sure to connect the x values and y values of the following.Also make sure to start on square 1.

4. The domain of the function is the same as the input. The dice values, 1,2,3,4,5,6

5.The range are the. values that occur if we roll the number about square 1.

2,2,8,5,6,8

6. No, the player could have rolled 3 and landed on 8. The player also could have rolled 6.

7. Yes, every one x value corresponds with one y value.

Answer:

h = 6.2 units

Step-by-step explanation:

Given triangle ABC is a right triangle with the measures of the two sides,

BC = [tex]\frac{10}{2}[/tex] = 5 units

AC = 8 units

By applying Pythagoras theorem in the given triangle,

AC² = AB² + BC²

8² = AB² + 5²

AB² = 64 - 25

AB = √39

AB = 6.24 units

AB ≈ 6.2 units

From the test the person wants, and the sample data, we build the test hypothesis, find the test statistic,  and use this to reach a conclusion both using the critical value and the p-value.

Doing this, the conclusions are:

---------------------------------------------------------

Hypothesis:

A machine in a factory must be repaired if it produces more than 10% defectives in production.

At the null hypothesis, we test if it does not have to be repaired, that is,  the proportion is of at most 10%. So

[tex]H_0: p \leq 0.1[/tex]

At the alternative hypothesis, we test if it does have to be repaired, that is, the proportion is greater than 10%. So

[tex]H_1: p > 0.1[/tex]

------------------------------------------------------

Decision rule:

0.01 significance level, using a left-tailed test(testing if the mean is more than a value), which means that:

----------------------------------------------------------

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, is the value tested at the null hypothesis, is the standard deviation and n is the size of the sample.

0.1 is tested at the null hypothesis:

This means that [tex]\mu = 0.1, \sigma = \sqrt{0.1*0.9}[/tex]

A random sample of 100 items from a day's production contains 15 defectives.

This means that [tex]n = 100, X = \frac{15}{100} = 0.15[/tex]

Value of the test-statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{0.15 - 0.1}{\frac{\sqrt{0.1*0.9}}{\sqrt{100}}}[/tex]

[tex]z = 1.67[/tex]

----------------------------------------------

Decision: Critical region

The test statistic is [tex]z = 1.67 < z_c[/tex], meaning that there is not enough evidence to conclude that the proportion of defectives is above 10%, that is, it does not support his decision to repair at the 0.01 significance level.

Decision: p-value

The p-value of the test is the probability of finding a sample proportion above 0.15, which is 1 subtracted by the p-value of z = 1.67.

Looking at the z-table, z = 1.67 has a p-value of 0.9525.

1 - 0.9525 = 0.0475.

The p-value of the test is 0.0475 > 0.01, meaning that there is not enough evidence to conclude that the proportion of defectives is above 10%, that is, it does not support his decision to repair at the 0.01 significance level.

A similar problem is found at https://brainly.com/question/24326664

Answer:

Symmetric with respect to the x-axis

Symmetric with respect to the y-axis

Symmetric with respect to the origin

This question is incomplete, the complete question is;

Many people grab a granola bar for breakfast or for a snack to make it through the afternoon slump at work. A Kashi GoLean Crisp Chocolate Caramel bar weighs 45 grams. The mean amount of protein in each bar is 8 grams. Suppose the amount of protein in the bars have a normal distribution with a standard deviation of 0.32 grams and a random Kashi bar is selected.  

Suppose the amount of protein is at least 8.6 grams. What is the probability that it is more than 8.7 grams

Answer:

the required probability is 0.472

Step-by-step explanation:

Given the data in the question;

Let x represent the random variable that shows the protein in the bar.

{ normal distribution }

mean μ = 8

standard deviation σ =  0.32

Now, Suppose the amount of protein is at least 8.6 grams. What is the probability that it is more than 8.7 grams

first we get the z-score for x = 8.6

z = x - μ / σ

z = ( 8.6 - 8 ) / 0.32

z = 0.6 / 0.32

z = 1.875

so

P( x ≥ 8.6 ) = P( z ≥ 1.875 ) = 1 - 0.9696 = 0.0304

Also for, x = 8.7

z = x - μ / σ

z = ( 8.7 - 8 ) / 0.32

z = 0.7 / 0.32

z = 2.1875

so

P( x > 8.7 ∩ x ≥ 8.6 ) = P( x > 8.7 ) = P( z > 2.1875 ) = 1 - 0.98565 = 0.01435

Now, the required probability will be;

P( x > 8.7 | x ≥ 8.6 ) = [P( x > 8.7 ∩ x ≥ 8.6 )] / [ P( x ≥ 8.6 ) ]

= 0.01435 / 0.0304

= 0.472

Therefore, the required probability is 0.472