Answer:
25 mm = 0 deg C
200 mm = 100 deg C
200 - 25 = 175 = change in thread per 100 deg C
95 - 25 = 70 mm - change in thread from 0 deg C
70 / 175 * 100 = 40 deg C final temperature at 95 mm
For saving lives, what is the most important safety feature on a car? A. Air bag B. Safety Belt C. Anti-lock brakes
For saving lives the most important safety feature on a car is B. Safety Belt
What are safety features of a car ?Safety features of a car is a feature of a product designed to ensure or increase safety.
Air bag and Anti-lock brakes are the supplemental protection and designed to work best with combination with seat bells.
Air bag reduce the chance that upper body or head will strike the vehicle's interior during a crash alongside with belt that will also hold your upper body
so, the primary safety feature is seat belt and Air bag and Anti-lock brakes comes in secondary safety feature as they increases the safety and risk of getting an injury during any accident
correct answer is B. Safety Belt
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A force of 825N is required to push
a car across a lot.Tow students push the car 35m.How much work is done?
Answer:
the work done by the two students is 28,875 J
Explanation:
Given;
applied force, f = 825 N
distance through which the car is pushed, d = 35 m
The work done by the two students who pushed the 825 N across 35 m lot is calculated as follows;
Work done = force x distance
Work done = 825 N x 35 m
Work done = 28,875 Nm = 28,875 J
Therefore, the work done by the two students is 28,875 J
Photosynthesis is a process in which plants prepare food using carbon dioxide, chlorophyll, and water in the presence of sunlight.
I
What is the mass of a motorcycle that accelerates at a rate of 4 m/s?when a
325 N net force is applied?
Answer:
mass is 56.25 N
Explanation:
F=ma
325=4m
m=325/4
NEED HELP ASAP
Juan Soto of your Washington Nationals rounds the bases after another home run (Starts at home plate, runs to first base, to second base, to third base, and back to home plate). This time, the bases are exactly 44 meters apart (you do not need to convert).
When Juan reacher home plate what is bir displacement?
Explanation:
TEMPLE HINDUS MOSQUE MUSLIMS TEMPLE HINDUS MOSQUE MUSLIMS
HELP ASAP
A. 1.09 A
B. 1.20 A
C.0.910 A
D. 0.830 A
Answer:
The answer should be: 1.20 A
Explanation:
A rectangular coil of wire, 22.0 cm by 35.0 cm and carrying a current of 1.40 A, is oriented with the plane of its loop perpendicular to a uniform 1.50-T magnetic field pointing into the plane of the loop. Let the loop be in x-y Cartesian plane so that the long and short sides of the loop are parallel to x- and y-axis, respectively. The loop center is at the origin of x-y Cartesian plane. Note that the magnetic field is in the direction of the negative z-axis.a. Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the z-axis that the magnetic field exerts on the coil.b. The plane of the coil is now rotated through +30º from its initial orientation (the x-y plane of the Cartesian coordinate system that remains the same). Calculate: (i) the net force that the magnetic field exerts on the coil; (ii) the torque about the rotation axis that the magnetic field exerts on the coil.
Answer:
a) [tex]F_{net}=0[/tex]
b) [tex]T=0[/tex]
Explanation:
From the question we are told that:
Dimensions:
[tex]L*B=22.0*35.0cm[/tex]
Current [tex]I=1.40A[/tex]
Magnetic field [tex]B=1.40[/tex]
Therefore
[tex]Area=L*B[/tex]
[tex]A=22.0*35.0cm[/tex]
[tex]A=770cm=>770*0^{-4}[/tex]
a)
Generally Force on Looping gives
[tex]F_1-F_2[/tex]
[tex]F_3=F_4[/tex]
Therefore
[tex]F_{net}=0[/tex]
b)
Generally the equation for Torque is mathematically given by
[tex]T=i*Asin \theta[/tex]
Since A and B are on opposite direction
[tex]\theta=180[/tex]
Therefore
[tex]T=1.40*770*10^{-4}sin 180[/tex]
[tex]T=0[/tex]
Express the standard form: (i) radius of the earth= 6 400 000 m (ii) radius of hydrogen atom = 0.000 000 000 0529
Answer:
I) 6.4 × 10^(6) m
II) 5.29 × 10^(-11) m
Explanation:
Standard form is how we write very large number in such a way that it is easier to read.
Thus;
I) radius of the earth = 6 400 000 m
What we will now have is;
6.4 × 10^(6) m
II) radius of hydrogen atom = 0.000 000 000 0529 m
What we will have is;
5.29 × 10^(-11) m
Answer:
i. 6.4 × 10⁶ m.
ii. 5.29 × 10⁻¹¹ m.
Explanation:
To express a number in standard form, we write it in the form a × 10ⁿ where 1 ≤ a < 10 and n is an integer.
(i) radius of the earth= 6 400 000 m
To express the radius of the earth = 6 400 000 m in standard form, we count the number of decimal places after the first digit. We have 6 decimal places after digit 6. So, we put a decimal point between digit 6 and 4. So, we have 6.4. Since we have 6 decimal places after the six digit, the exponent of our base which is 10 is 6.
So, writing 6 400 000 in the form in a × 10ⁿ, we have a = 6.4 and n = 6. So, in standard form we have 6.4 × 10⁶ m.
So, 6 400 000 = 6.4 × 10⁶ m in standard form.
(ii) radius of hydrogen atom = 0.000 000 000 0529 m
To express the radius of hydrogen atom = 0.000 000 000 0529 m in standard form, we count the number of decimal places after the decimal point including the first non-zero digit. We have 11 decimal places after the decimal point up to and including the first non-zero digit which is digit 5. So, we put a decimal point after the first non-zero digit,5. So, we have 5.29. Since we have 11 decimal places after the decimal point, the exponent of our base which is 10 is -11. The exponent is negative since the digit places are taken after the decimal point.
So, writing 0.000 000 000 0529 m in the form in a × 10ⁿ, we have a = 5.29 and n = -11. So, in standard form we have 5.29 × 10⁻¹¹ m.
So, 0.000 000 000 0529 m = 5.29 × 10⁻¹¹ m in standard form.
What symbol is a concentration be
[tex]Option \: (b)[/tex]
Explanation:
Second STATEMENT SAYS REGARDING TO THE CHEMICAL poison
The graph shows the motion of a car. Which segment
shows that the car is slowing down?
O A
OB
Ос
OD
Answer: its C
Explanation:
an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror should a screen be placed in order to obtain a shop image find the magnification size and nature of the image
Answer: Given: h₀=5cm
p=30cm
hi
f=45cm
require: q=?
hi=?
formulas:
1/f=1/p+1/q
hi/h₀=q/p
calculations:1/q=1/f-1/p
1/q=1/45-1/30
1/q=0.022=0.033
1/q= = -0.011
q=1/-0.011
q= -90.91cm
hi=p × h₀/q
hi=30ₓ5/-90.91
hi=150/-90.91
hi= -1.65cm
image is virtual , erect and diminished
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which of the following describes an action-reaction pair?
C. Your feet push down on the ground, and the ground pushes up on your feet.
When Your feet push down on the ground, and the ground pushes up on your feet. This is the correct example of action and reaction pair. The correct option is C.
What is Newton's third law of motion?Newton's third law of motion states that " for every action, there is an equal and opposite reaction".
This means that if object "1" exerts a force on object "2", then object "2" will exert an equal and opposite force on object "1".
In mathematical terms, the third law can be expressed as:
F₁₂ = - F₂₁
Where
F₁₂ = the force exerted by object "1" on object "2",
F₂₁ =the force exerted by object "2" on object "1".
The negative sign indicates that the two forces are equal in magnitude but opposite in direction.
This law applies to all objects in the universe, and it is essential for understanding how objects interact with each other. It explains how a rocket is propelled into space, how a person can walk on the ground, and how a bird can fly through the air.
For example: when a person walks on the ground, their foot exerts a force on the ground. According to Newton's third law, the ground will then exert an equal and opposite force on the foot, pushing the person forward. This allows the person to walk and move forward.
Similarly, when a bird flies through the air, the bird's wings exert a force on the air, and the air exerts an equal and opposite force on the bird, lifting it up and allowing it to fly.
Here in the question,
When you push down on the ground with your feet, the ground pushes up on your feet with an equal and opposite force. This pair of forces are equal in magnitude and opposite in direction, satisfying the conditions of Newton's third law of motion.
Whereas,
Option A describes two separate forces acting on you, but these are not action-reaction pairs because they are not equal in magnitude and opposite in direction.
Options B and D both describe forces acting in opposite directions, but they are not action-reaction pairs because they do not involve two objects interacting with each other.
Therefore, in option C Your feet push down on the ground, and the ground pushes up on your feet, which is the correct option.
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PLEASE ANSWER!!!
a ship sails a distance of 600 km at a speed of 20km/h.
A) for what amount of time was the ship sailing?
B) is this a scalar quantity or a vector quantity?
Answer:
A) 30h
B) Scalar quantity
Explanation:
Part A
[Note: v represents speed, d represents distance, and t represents time]
Given:
[tex]d = 600 km[/tex]
[tex]v = 20 km/h[/tex]
Required:
[tex]t = ?[/tex]
Analysis:
[tex]v = \frac{d}{t} \\t = \frac{d}{v}[/tex]
Solution:
[tex]t = \frac{d}{v} \\t = \frac{600 km}{20 km/h} \\t = 30 h[/tex]
Statement:
Therefore, the ship was sailing for 30 hours.
--------------------------------------------------------------------------------------------------------------
Part B
This is a scalar quantity because time only has magnitude and can never be given direction so it can never be a vector quantity.
how far should an object be from a converging mirror of radius 36cm to form a real image one - ninth of its size
Answer:
focal length :
[tex]{ \tt{f = \frac{r}{2} }} \\ focal \: length = \frac{36}{2} = 18 \: cm[/tex]
From linear magnification:
[tex]{ \tt{ \frac{1}{m} + 1 = \frac{u}{f} }} \\ \frac{1}{9} + 1 = \frac{u}{18} \\ \\ u = \frac{18 \times 10}{9} \\ u = 20 \: cm[/tex]
The object must be at 20 cm
A parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is connected in series to a 4.89 μF capacitor. This three‑capacitor combination is connected to a 15.5 V battery. Determine the charge on each capacitor.
Answer:
a. i. 35.96 μC b. i. 11.98 μC ii. 24.04 μC
Explanation:
We need to find the total capacitance of the system C.
The total capacitance of the parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor is C' = 1.47 μF + 2.95 μF = 4.42 μF.
C' = 4.42 μF is in series with the 4.89 μF capacitor and for a series combination of capacitors, we have the total capacitance, C from
1/C = 1/4.42 μF + 1/4.89 μF
1/C = (4.42 μF + 4.89 μF)/(4.42 μF × 4.89 μF)
1/C = 9.31 μF/21.6138 μF²
C = 21.6138/9.31 μF
C = 2.32 μF
So, the total charge in the circuit Q = CV where C = total capacitance = 2.32 μF and v = voltage = 15.5 V
So, Q = CV
Q = 2.32 μF × 15.5 V
Q = 35.96 μC
i. The charge on the 4.89 μF capacitor
Since the 4.89 μF is in series with C', the total charge flowing i the circuit is the total charge in the 4.89 μF capacitor. So, its charge Q = 35.96 μC
b. The charge in the 1.47 μF and 2.95 μF capacitors.
To find the charge in the 4.89 μF and 2.95 μF capacitors, we need to find the voltage across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor. The voltage, V' across the 4.89 μF capacitor, since Q = CV', V' = Q/C = 35.96 μC/4.89 μF = 7.35 V
So, the voltage V" across the combined parallel combination of a 1.47 μF capacitor and a 2.95 μF capacitor, C' is V" = 15.5 V - V' (since V' + V" = 15.5 V).
So, V" = 15.5 V - V'
V" = 15.5 V - 7.35 V
V" = 8.15 V
i. The charge on the 1.47 μF capacitor
Using Q' = CV" where Q' = charge across capacitor, C = 1.47 μF and V" = 8.15 V.
So, Q' = CV"
Q' = 1.47 μF × 8.15 V
Q' = 11.98 μC
ii. The charge on the 2.95 μF capacitor
Using Q" = CV" where Q' = charge across capacitor, C = 2.95 μF and V" = 8.15 V.
So, Q" = CV"
Q" = 2.95 μF × 8.15 V
Q" = 24.04 μC
Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
A. For large nuclei, the mass of the original nucleus is greater than the mass of the products.
B. For large nuclei, the mass of the original nucleus is less than the mass of the products.
C. For small nuclei, the binding energy of the lighter nuclei is greater than the binding energy of the heavier nucleus.
D. For small nuclei, the binding energy of the lighter nuclei is less than the binding energy of the heavier nucleus.
Answer:
A is the answer!
Explanation:
Edge 2021
Answer:
A
Explanation:
Edge
Which activity is best described as a scientific endeavor?
A. Designing devices astronauts can use to help them stay healthy
while in space
B. Developing a procedure for testing how extended stays in space
affect the human body
C. Performing tests on devices used by astronauts to ensure they
can be used safely
D. Creating a process for improving the design of equipment used to
monitor astronauts' health
Answer:
B
Explanation:
BECAUSE TO DO THE TESTS YOU NEED TO DO THE SCIENTIFIC METHOD.
FOR EXAMPLE: OBSERVATIONS AND EXPERIMENTS TO OBTAIN RESULTS.
ANYWAY I LEAVE YOU THE LINK:
https://gscourses.thinkific.com
What is the final step in the fourth stage of technological design, after a product has been improved abs approved
Answer:
Evaluate the solution.
Explanation:
A technological design is designed as the design and study of a solution that can be provided from the solution by identifying the root cause or problem and trying to solve by various means.
A good technological design requires the minimum effort and resources while meeting the requirement of the problem.
The steps involved in the technological design are :
1. search and identify the problem or need.
2. design a solution
3. Implement a solution.
4. Evaluate the solution.
Therefore, the final step or the fourth step in the process of a technological design is " evaluating or communicating the final design solution".
một vật m=1kg có động lượng bằng 10kg.m/s. động năng của vật là
1. A 5 cm3 balloon is filled by a gas at a pressure
of 1 x 105 Pa . When the balloon is filled by 20
cm3 of the gas, what is the new pressure of the
gas?
A 1.0 x 105 Pa B 4.0 x 104Pa
C 2.5 x 104Pa D 4 x 103 Pa
E 5x 103 Pa
2. A bubble of air is formed at the base of a lake.
At that moment, its volume is 30 cm3 and it
experiences a pressure of 190 of cm Hg. What
is the volume of the bubble when it reaches the
surface of the sea.
[ The atmospheric pressure =
76 cm of Hg ]
A 25 cm3 B 50 cm3
C 75 cm3 D 100 cm3
E 150 cm3
Answer:
1) C. 2.5 x 10⁴ Pa
2) C. 75 cm³
Explanation:
Question 1.
Given the following data;
Initial volume, V1 = 5 cm³Initial pressure, P1 = 1 * 10⁵ PaFinal volume, V2 = 20 cm³To find the final pressure, P2, we would use Boyle's law;
Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.
Mathematically, Boyles law is given by;
PV = K
P1V1 = P2V2
Making P2 the subject of formula, we have;
P2 = (P1V1)/V2
Substituting into the formula, we have;
P2 = (1 * 10⁵ * 5)/20
P2 = (500,000)/20
Final pressure, P2 = 25,000 Pa or 2.5 x 10⁴ Pa.
Question 2.
Given the following data;
Initial volume, V1 = 30 cm³Initial pressure, P1 = 190 of cm HgFinal pressure, P2 = 76 cm of HgTo find the final volume, we would use Boyle's law;
Mathematically, Boyles law is given by;
PV = K
P1V1 = P2V2
Making V2 the subject of formula, we have;
V2 = (P1V1)/P2
Substituting into the formula, we have;
V2 = (190 * 30)/76
V2 = 5700/76
Final volume, V2 = 75 cm³
if the pelican in item 3 was traveling at the same speed but was only 2.7m above the water, how far would the fish travel horizontally before hitting the water?
Answer:
5.66 m
Explanation:
From online sources, the speed in item 3 being referred to was discovered to be 7.62 m/s
Now, let's get the time of flight from one of Newton's equation of motion;
S = ut + ½gt²
Considering the vertical component, we have u = 0 m/s.
Thus;.
S = ½gt²
Plugging in the relevant values;
2.7 = ½ × 9.8 × t²
t² = 2.7/4.9
t = √(2.7/4.9)
t = 0.7423 s
Now, when we consider the horizontal component of the motion, we have;
S = vt
Where;
S is the distance the fish will travel horizontally before hitting the water.
v = 7.62 m/s
t = 0.7423
Thus
s = 7.62 × 0.7423
s ≈ 5.66 m
Two cubic meters of a gas at 303 K are heated at constant pressure until the volume is doubled. What is the final temperature of the gas?
Answer:
[tex]V_1 = {2 \: m}^{3} [/tex]
[tex]T_1 = 303 \: k[/tex]
[tex]V_2 = 2(V_1) = 2(2) = 4 \: {m}^{3} [/tex]
[tex]T_2 = ?[/tex]
Here, it's mentioned that the pressure is constant.
By Charles law :[tex]\implies V \propto T \\ [/tex]
[tex]\implies \dfrac{V_1}{V_2} = \dfrac{T_1}{T_2} \\ [/tex]
[tex]\implies \dfrac{2}{4} = \dfrac{303}{T_2} [/tex]
[tex]\implies \dfrac{T_2}{4} = \dfrac{303}{2} [/tex]
[tex]\implies T_2 = \dfrac{303 \times 4}{2} [/tex]
[tex]\implies T_2 = \dfrac{1212}{2} [/tex]
[tex]\implies T_2 = 606 \: k [/tex]
what is projectile motion
[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]
[tex]\sf{\qquad{\qquad{\underline{\underline{ Projectile~motion }}}}}[/tex]
If an object is given an initial velocity in any direction and then allowed to travel freely under gravity only, it is called a projectile motion.
It is basically 3 types
horizontally projectile motion oblique projectile motion included plane projectile motionThe path followed by a projectile is called its trajectory.
Projectile motion is when an object moves in a bilaterally symmetrical, parabolic path.
The path that the object follows is called its trajectory.
Projectile motion only occurs when there is one force applied at the beginning, after which the only influence on the trajectory is that of gravity
A thunderclap sends a sound wave through the air and the ocean below. The
thunderclap sound wave has a constant frequency of 100 Hz. What is the
wavelength of the sound wave in water? (The equation for the speed of a
wave is v= f x 1.)
Water
Diamond
Glass
Air
1,493
12,000
5,640
346
Speed of
sound
(m/s)
A. 11.00 m
B. 12.00 m
C. 14.93 m
D. 3.46 m
Answer:
C. 14.93 m
Explanation:
The given frequency of the wave, f = 100 Hz
The given equation for the wave speed, v, is presented as follows;
v = f × λ
The speed of sound in water, v = 1,493 m/s
Therefore, we get;
The wavelength, λ = v/f
∴ λ = 1,493 m/s/(100 Hz) = 14.93 m
The wavelength, λ = 14.93 m.
Which of the following is evidence for continental drift?
Pls help asap!!
A bucket contains hot water at 95°c. A man wants to bath with water at 40°c. What is the ratio of the mass of hot water to the mass of cold water that he needs.
Answer:
55
Explanation:95-40=55
i hope i did the math right if i didnt please tell me
And Minister Juan Carlos, how much clean energy are we using today in proportion (percentages) to dirty energy?
Answer:
39%.
Explanation:
Spain produces electricity from wind energy was 18%, from hydropower is 14%, 5% from solar energy, and 2% from other renewable sources in the year 2016. About 39% of energy comes from renewable resources while on the other hand, 61% of energy comes from non-renewable resources such as petroleum. Spain has the capability to fulfill all its energy needs from renewable resources.
What is the relationship between electric field lines and equipotential lines that you observed in doing the lab
Answer:
Explained below
Explanation:
Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.
Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.
A pendulum of mass 18 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 17 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that a=98 m/s2
By the work-energy theorem, the total work done on the mass as it swings is
W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J
No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.
If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.
Now, if w is the amount of work done by friction/air resistance, then
(176.4 N) h - w = 153 J
If you know the starting height h, then you can solve for w.
The following are steps involved in transmission at the cholinergic synapse:
1. Chemically gated ion channels on the postsynaptic membrane are opened.
2. Calcium ions enter the axon terminal.
3. An action potential depolarizes the axon terminal at the presynaptic membrane.
4. Acetylcholine is released from storage vesicles by exocytosis.
5. Acetylcholine binds to receptors on the postsynaptic membrane
Answer:
3. Step 1; An action potential depolarizes the axon terminal at the presynaptic membrane
2. Step 2; Calcium ions enter the axon terminal
4. Step 3; Acetylcholine is released from storage vesicles by exocytosis
5. Step 4; Acetylcholine binds to receptors on the postsynaptic membrane
1. Step 5; Chemically gated ion channels on the postsynaptic membrane are opened
Explanation:
3. The cholinergic synapse starts at the point of arrival of an electrochemical impulse or action potentials at the synaptic knob of the axon terminal of a presynaptic neuron membrane
2. The arrival of the action potential at the axon terminal causes the calcium ion Ca²⁺ channels to open and Ca²⁺ enters into the synaptic knob, resulting in the fusion of the presynaptic membrane and synaptic vesicles
4. The fusion enables the release into the synaptic cleft of many acetylcholine (ACh) transmitter molecules by exocytosis
5. Some of the ACh are transported across the synaptic cleft and bind to postsynaptic neuron membrane embedded ACh receptors
1. The binding of the ACh neurotransmitter molecules to receptors on the membrane of the dendrites of a neuron it leads to the opening of ion channels