Answer:
the order higher is 3p79g5t88=yv5379
"All data types are keywords but all keywords are not data types", justify this statement.
Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.
Hope This Helps You ❤️Based on how they are stored in the computer, the types produced by these keywords can be categorized into two families, integer types and floating-point types.
What is the relation between data and keyword?Bit, byte, and word are terminology that can be used to refer to either memory or data storage units in computers.
The main distinction between text fields and keyword fields is that text fields are examined during indexing, whereas keyword fields are not.
This means that while keyword fields are indexed exactly as is, text fields are split down into their constituent phrases at indexing to allow for partial matching.
A word or collection of words that an Internet user enters into a search engine or search bar to conduct a search is referred to as a keyword in the context of digital marketing.
Therefore, All data types are keywords, but all keywords are not data types.
Learn more about data and keywords here:
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Two steel plates are to be held together by means of 16-mm-diameter high-strength steel bolts fitting snugly inside cylindrical brass spacers. Knowing that the average normal stress must not exceed 210 MPa in the bolts and 145 MPa in the spacers, determine the outer diameter of the spacers that yields the most economical and safe design.
Answer:
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
Explanation:
For steel bolt
Stress = 210 MPa or 210 N/mm2
Pressure = Stress* Area
Pbolt = 210 N/mm2 * 16^2 *(pi)/4
Pbolt = 210 N/mm2 * 200.96 mm^2 = 42201.6 N
For Brass spacer
Pressure = 42201.6 N
Area of Brass spacer = Pressure/Stress
Area of Brass spacer = 42201.6 N/145 N/mm^2 = 291.044 mm^2
Area of Brass spacer = (pi) (d^2 - 16^2)/4 = 291.044 mm^2
d^2 - 16^2 = 291.044 mm^2* 4/(pi) = 370.758
d^2 = 370.758 + 16^2
d^2 = 626.758
d = 25.03 mm
The outer diameter of the spacers that yields the most economical and safe design is 25.03 mm
1.1.2
Energy
1.1.3
Mass
1.1.4
Temperature
Power
1.1.5
1.2 State Ohm's law
1.3 State Joule's law
1.5 Name four factors that9 determine the resistance of the material
1.6 What is the SI Unit for current?
QUESTION 2
Answer:
the energy is sgdrh35679
what is the difference between a series circuit and a parallel circuit?
Answer:
In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.
Explanation:
SN1 reactions usually proceed with ________. A) equal amounts of inversion and retention at the center undergoing substitution B) slightly more inversion than retention at the center undergoing substitution C) slightly more retention then inversion at the center undergoing substitution D) complete inversion at the center undergoing substitution E) complete retention at the center undergoing substitution complete retention at the center undergoing substitution slightly more retention then inversion at the center undergoing substitution complete inversion at the center undergoing substitution equal amounts of inversion and retention at the center undergoing substitution slightly more inversion than retention at the center undergoing substitution
Answer:
equal amounts of inversion and retention at the center undergoing substitution
Explanation:
In an SN1 reaction, the rate determining step is the formation of a carbonation which is flat and planar.
This means that both faces of the carbo cation are equally available for attack by the nucleophile.
Attack on either of the faces may occur equally thereby yielding a racemic mixture.
For automobile engines, identify the best choice of motor oil.
A. High viscosity for Maine in the winter and low viscosity for Florida in the summer.
B. Low viscosity for Maine in the winter and low viscosity for Florida in the summer.
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
D. High viscosity for Maine in the winter and high viscosity for Florida in the summer.
E. It does not matter what the rating is for the motor oil.
Answer:
C. Low viscosity for Maine in the winter and high viscosity for Florida in the summer.
Explanation:
The choice of motor oil or engine oil depends on the type of engine and also on the type of climate on which the engine runs.
In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.
But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.
Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.
Therefore, option (c) is correct.
Your new team is working hard, but they are all less experienced than you and don't complete their tasks as quickly.What would you be most and least likely to do? (A). Reach out to your manager to discuss the situation.Try to identify the best way to support the new associates. (B).Remind your coworkers of performance expectations and that they need to be working harder to complete tasks. (C). Offer to help others complete their tasks; observe their work process and provide some tips that might help them. (D). Give your coworkers more time to figure out how to do the task; they likely just need more practice with what they've already learned.
