3rd Grade Math Question

The 95% confidence interval for the effectiveness of the blood-pressure drug is given as follows:

[tex]22.6 < \mu < 24.4[/tex]

The mean, the standard deviation and the sample size for this problem, which are the three parameters, are given as follows:

[tex]\overline{x} = 23.5, \sigma = 12.2, n = 775[/tex]

Looking at the z-table, the critical value for a 95% confidence interval is given as follows:

z = 1.96.

The lower bound of the interval is then given as follows:

[tex]23.5 - 1.96 \times \frac{12.2}{\sqrt{775}} = 22.6[/tex]

The upper bound of the interval is then given as follows:

[tex]23.5 + 1.96 \times \frac{12.2}{\sqrt{775}} = 24.4[/tex]

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The correct total weight of the bags of granola is 8 1/4 pounds.

One thing that can be done to improve Roberto's reasoning is to ensure the accuracy of the calculations.

In his conclusion, Roberto added the weights of the bags of granola (2 1/2, 2 3/4, and 3) and claimed that the total weight was 8 1/4 pounds. However, the sum of these weights does not equal 8 1/4 pounds.

To address this, Roberto should recheck his calculations. Adding mixed numbers involves adding the whole numbers separately and then adding the fractions separately. In this case, 2 1/2 + 2 3/4 + 3 can be calculated as follows:

2 + 2 + 3 = 7 (sum of whole numbers)

1/2 + 3/4 = 2/4 + 3/4 = 5/4 = 1 1/4 (sum of fractions)

Thus, the correct sum is 7 + 1 1/4 = 8 1/4 pounds.

By double-checking the calculations and providing the accurate sum, Roberto's reasoning would be more precise, reliable, and free from errors.

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The probable question may be:

Roberto made a line plot to show the weight in pounds of the bags of granola in his store he concluded that the total weight of the granola was 2 1/2+2 3/4+3=8 1/4 pounds.

what is one thing that you could do to Roberto's Reasoning

The value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.

In the given table, Tasha observed a pattern in the powers of 4. When the exponent decreases by 1, the previous value is divided by 4. Using this pattern, she determined the values for 4 squared, 4 Superscript 1, 4 Superscript 0, 4 Superscript negative 1, and 4 Superscript negative 2.

To find the value of 4 Superscript negative 3, she divided the previous value (StartFraction 1 Over 16 EndFraction) by 4, resulting in StartFraction 1 Over 64 EndFraction.

Similarly, for 4 Superscript negative 4, she divided the previous value (StartFraction 1 Over 64 EndFraction) by 4, yielding StartFraction 1 Over 256 EndFraction.

Finally, to rewrite the value for 4 Superscript negative 4, she expressed it as negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.

Therefore, the value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction, which simplifies to StartFraction 1 Over 256 EndFraction

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Answer:

X=68m

Step-by-step explanation:

X²=40²+55²

X²=1600+3025

X²=4625

X=(4625)½

X=68m.

The equation of the line perpendicular to  y = 2 / 3 x - 4 and passes through (6, -2) is y = - 3 / 2x + 7.

The equation of a line can be represented in slope intercept form as follows:

y = mx + b

where

The slopes of perpendicular lines are negative reciprocals of one another.

Therefore, the slope of the line perpendicular to y = 2 / 3 x - 4 is - 3 / 2.

Hence, let's find the line as its passes through (6, -2).

Therefore,

y = - 3 / 2 x + b

-2 = - 3 / 2(6) + b

-2  = -9 + b

b = -2 + 9

b = 7

Therefore, the equation of the line is y = - 3 / 2x + 7.

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Foreign direct investment helps improve the economic situation of a recipient country by increasing employment opportunities in the country that the company invests in.

When foreign companies invest in a recipient country, they often establish or expand their operations, which requires hiring local workers. This leads to job creation and reduces unemployment rates in the recipient country.

Increased employment opportunities result in more individuals having access to income and improved standards of living.

Foreign direct investment also contributes to the transfer of technology, knowledge, and skills to the recipient country. Multinational companies often bring advanced technologies, production techniques, and management practices that may not have been available or widely adopted in the recipient country.

Furthermore, foreign direct investment stimulates domestic investment and encourages the growth of local businesses. When foreign companies invest in a recipient country, they often form partnerships or engage in supply chain relationships with local firms.

Overall, foreign direct investment increases employment opportunities, fosters technology transfer, and stimulates domestic investment, all of which contribute to improving the economic situation of a recipient country.

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The expression to estimate the number of containers of salsa needed is: 48 × 3 × 9. none of the option is correct.

To estimate how many containers of salsa are needed for all the tables in one day, we need to consider the total number of tables and the number of salsa containers required for each table.

Given that there are 48 tables and each table has 3 different types of salsa, we can estimate the total number of containers needed by multiplying the number of tables by the number of salsa types.

However, we also need to account for the fact that there are 9 different sets of customers throughout the day. Each set of customers will use all the tables, so we need to multiply the estimated number of containers by the number of sets of customers to get an accurate estimation for the day.

Let's analyze the options provided:

A) 50 × 9: This option assumes there are 50 tables, which is incorrect based on the given information.

B) 16 × 3 × 9: This option assumes there are 16 tables, which is incorrect based on the given information.

C) 50 × 3 × 10: This option assumes there are 50 tables and 10 different sets of customers. Although the number of tables is incorrect, this option accounts for the number of salsa types and the number of sets of customers. However, it does not accurately represent the given scenario.

D) 40 × 5 × 5: This option assumes there are 40 tables and 5 different sets of customers. It also considers the number of salsa types. However, it does not accurately represent the given scenario as the number of tables is incorrect.

None of the options provided accurately represent the given scenario. The correct expression to estimate the number of containers of salsa needed for all the tables in one day would be:48 × 3 × 9

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Answer: Its going down by odd numbers

Step-by-step explanation:

5-2=3, 2-(-3)= 5, then it would go on 7, 9, 11, 13...

Answer:

The difference between the numbers does not follow a common pattern; hence, the sequence is not arithmetic.

Step-by-step explanation:

Let's take the 1st two digits, 5 and 2

The difference between the numbers, 5-2 = 3

Following this pattern,

2-(-3) = 5

-3-(-10) = 7 and,

-10-(-19) = 9.

We can see that the differences are 3, 5, 7 and 9 and therefore we can prove that there is no common difference between the numbers.

Hence the sequence does not follow an arithmetic pattern as there is no common difference

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Answer:

CD: 8.5

m<D: 20.6°

m<C: 69.4°

Step-by-step explanation:

CD:

The first thing it wants us to do is find the length of CD. Since the triangle shown is a right triangle, we can use Pythagorean theorem ([tex]a^{2}+b^{2}=c^{2}[/tex])  to solve for the missing length. It's important to remember that when using the Pythagorean theorem, c is the hypotenuse.

[tex]a^{2}+b^{2}=c^{2}\\3^{2}+8^{2}=c^{2}\\9 + 64 = c^{2}\\73 = c^{2}\\\sqrt{73} =c[/tex]

Since our answer is no an integer, we must turn it into a decimal.

[tex]\sqrt{73}[/tex] ≈ 8.544003745 ≈ 8.5

m<D:

Now, they want us to find the measure of <D. To do this, we will need to use trig functions (sine, cosine, tangent). To help us determine which trig function to use, we can remember the acronym SOH CAH TOA. This acronym tells us that sine is equal to opposite divided by hypotenuse, cosine is equal to adjacent divided by hypotenuse, and tangent is equal to opposite divided by adjacent. Since we do the hypotenuse and sides adjacent and opposite of <D, we can choose whichever trig function we want. For this problem, we will use tangent, so we can avoid using a rounded number, 8.5, as one of our sides.

Tan(D) = opposite / adjacent

Tan(D) = 3 / 8     [Take the tan inverse of both sides}

[tex]Tan^{-1}(Tan(D))=Tan^{-1}(3/8)[/tex]     [Simplify]

[tex]D=Tan^{-1}(3/8)[/tex]     [Solve]

D ≈ 20.55604522

D ≈ 20.6°

m<C:

Lastly, we must find the last unknown angle on the triangle. Since all angles on a triangle total 180°, if know that <C+<D+<E=180°. Let's solve this equation.

<C+<D+<E=180°

<C + 20.6 + 90 = 180     [Add]

<C + 110.6 = 180     [Subtract]

<C = 180 - 110.6     [Solve]

<C = 69.4°

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The rule used by the merchant is a function because it establishes a relationship between the cost of an item and its selling price

A function is simply described as a mathematical rule, law or expression that shows the relationship between two variables.

These two variables are known as;

From the information given, we have that;

Function assigns a unique selling price for every cost input

Input: cost

Output: selling price = cost + 10% of cost Formula: SP = C + 0.1C.

By following this rule, consistent selling prices can be determined efficiently based on cos

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The equation that shows the Pythagorean identity is true for θ = 270° and is in the form sin²θ + cos²θ = 1 is option  B. 0² + (-1)² = 1

The Pythagorean identity is a fundamental trigonometric identity that relates the sine and cosine functions. It states that for any angle θ, the sum of the squares of the sine and cosine of that angle is equal to 1: sin²θ + cos²θ = 1.

We are given θ = 270° and we need to select the equation that satisfies the Pythagorean identity in the given form.

Let's evaluate each option:

A. 0² + 1² = 1

In this case, sin²θ = 0² = 0 and cos²θ = 1² = 1. Adding them together, we get 0 + 1 = 1, which satisfies the Pythagorean identity.

B. 0² + (−1)² = 1

Here, sin²θ = 0² = 0 and cos²θ = (−1)² = 1. Adding them, we have 0 + 1 = 1, which satisfies the Pythagorean identity.

C. (−1)² + 0² - 1

In this equation, sin²θ = (−1)² = 1 and co

s²θ = 0² = 0. However, the equation does not satisfy the Pythagorean identity because 1 + 0 - 1 ≠ 1.

D. 1² + 0² = 1

For this option, sin²θ = 1² = 1 and cos²θ = 0² = 0. Adding them together, we get 1 + 0 = 1, which satisfies the Pythagorean identity.

Based on our evaluation, options A and B both satisfy the Pythagorean identity for θ = 270°. Therefore, either A or B can be selected as the correct equation.The correct answer is  b.

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The Question was Incomplete, Find the full content below :

Which equation shows that the Pythagorean identity is true for θ = 270°?

Select the equation that is in the form sin²θ+ cos²θ = 1.

A. 0² + 1² = 1

B. 0² + (−1)² = 1

C. (-1)² + 0² - 1

D. 1² + 0² = 1

The quadratic equation is x² + (k - 3)x + 4 = 0.

The values of k are 7 and -1.

Given: The quadratic equation is x² + (k - 3)x + 4 = 0.

Now, we can find the possible values of k.

To find the values of k, we will apply the discriminant formula of quadratic equation which is given by: [tex]$D=b^2-4ac$[/tex] ,where a,b and c are the coefficients of the quadratic equation: ax²+bx+c

Roots of the quadratic equation are given by:

[tex]$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

Now, let's apply these formulas to the given quadratic equation:

x² + (k - 3)x + 4 = 0

Comparing with the standard quadratic equation of the form ax² + bx + c = 0, we get:

[tex]a = 1, b = k - 3, and c = 4$\\D = b^2 - 4ac$= $(k - 3)^2 - 4(1)(4)$= $k^2 - 6k + 9 - 16$= $k^2 - 6k - 7$[/tex]

The roots of the given quadratic equation are given by:

[tex]$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$[/tex]

Substituting the values of a, b, c, and D, we get:

[tex]$x = \frac{-(k - 3) \pm \sqrt{(k - 3)^2 - 4(1)(4)}}{2(1)}$$x = \frac{3 - k \pm \sqrt{k^2 - 6k - 7}}{2}$[/tex]

Now, for the quadratic equation to have real and equal roots, the discriminant must be equal to zero, i.e., [tex]$D = 0$$\ therefore, k^2 - 6k - 7 = 0$.[/tex]

Factoring the quadratic equation, we get:

[tex]$k^2 - 7k + k - 7 = 0$$\\k(k - 7) + 1(k - 7) = 0$$\\(k - 7)(k + 1) = 0$[/tex]

So, the possible values of k are k = 7 and k = -1.

Hence, the values of k are 7 and -1.

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Answer:

[tex]\huge\boxed{\sf 44\ boys}[/tex]

Step-by-step explanation:

= Length × Width

Length = 32 m

Width = 11 m

Area of school room:

= Length × Width

= 32 × 11

= 352 m²

= 352 / 8

[tex]\rule[225]{225}{2}[/tex]

Answer:

There are 40 tables.

Step-by-step explanation:

Since we know that there are 9 times as many chairs, then there are tables, all we have to do is divide the number of chairs by 9, and we get the answer 40.

The answer is 3.99 metric tons.

To calculate the difference in carbon dioxide emissions between a commuter who takes a bus and one who drives a car every day, we need to compare the emissions of each mode of transportation per person.

The car averages 22 miles per gallon, which means it emits 4.3 metric tons of carbon dioxide per year. However, we don't know the number of passengers in the car.

The passenger bus emits 9.2 metric tons of carbon dioxide per year and can carry 30 people at a time. To find the emissions per person, we divide the total emissions by the number of passengers. In this case, each person on the bus emits 9.2 / 30 = 0.3067 metric tons of carbon dioxide per year.

To determine the difference in emissions, we subtract the emissions per person for the bus from the emissions per person for the car. Therefore, the difference is 4.3 - 0.3067 = 3.9933 metric tons of carbon dioxide per year.

Rounding this value to two decimal places, we get 3.99 metric tons.

Therefore, the answer is 3.99 metric tons.

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The domain of the square root function is x greater-than-or-equal-to 0, since the function is defined for all non-negative x-values or x-values greater than or equal to zero.

The domain of the square root function graphed below can be determined by looking at the x-values of the points on the graph.

From the given information, we can see that the curve starts at (0, -1) and goes through (1, -2) and (4, -3).

The x-values of these points are 0, 1, and 4.

Since the square root function is defined for any non-negative x-values or x-values more than or equal to zero, its domain is x greater-than-or-equal-to 0.

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To find an equation for the temperature, D, in terms of t, we can use the properties of a sinusoidal function to model the temperature variation over the day.

Given:

High temperature: 80 degrees

Low temperature occurs at 5 AM (t = 5)

t is the number of hours since midnight

Let's assume a sinusoidal function of the form:

D = A * sin(B * t + C) + Dc

where:

A represents the amplitude (half the difference between the high and low temperatures)

B represents the frequency (how many cycles occur over a 24-hour period)

C represents the phase shift (how much the function is shifted horizontally)

Dc represents the vertical shift (the average temperature throughout the day)

We can determine the values of A, B, C, and Dc based on the given information.

Amplitude (A):

The amplitude is half the difference between the high and low temperatures:

A = (80 - 50) / 2

= 30 / 2

= 15 degrees

Frequency (B):

Since we want the temperature to complete one cycle over a 24-hour period, the frequency can be calculated as:

B = 2π / 24

Phase Shift (C):

Since the low temperature occurs at 5 AM (t = 5), the function should be shifted horizontally by 5 hours. To convert this to radians, we multiply by (2π / 24):

C = 5 * (2π / 24)

Vertical Shift (Dc):

The average temperature throughout the day is the midpoint between the high and low temperatures:

Dc = (80 + 50) / 2

= 130 / 2

= 65 degrees

Now we can put all the values together to obtain the equation for the temperature, D, in terms of t:

D = 15 * sin((2π / 24) * t + (5 * 2π / 24)) + 65

Simplifying further:

D = 15 * sin((π / 12) * t + (π / 12)) + 65

Therefore, the equation for the temperature, D, in terms of t is:

D = 15 * sin((π / 12) * t + (π / 12)) + 65.

Part A: Approximately 50% of newborn babies weigh more than 3000 grams. Part B: Approximately 84.13% of newborn babies weigh more than 2000 grams. Part C: Approximately 84.13% of newborn babies weigh less than 4000 grams. Part D: Approximately 68% of newborn babies weigh between 2000 and 4000 grams. Part E: The range of birth weights that would contain the middle 68% of newborn babies' weights is from 2500 grams to 3500 grams.

1: Calculate the Z-scores for the given weights using the formula: Z = (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation.

For Part A:

Z = (3000 - 3000) / 500 = 0

Using the Z-table, we find that the percentage of babies weighing more than 3000 grams is approximately 50%.

For Part B:

Z = (2000 - 3000) / 500 = -2

Using the Z-table, we find that the percentage of babies weighing more than 2000 grams is approximately 97.72%. Since we want the percentage of babies weighing more than 2000 grams, we subtract this value from 100% to get approximately 2.28%.

For Part C:

Z = (4000 - 3000) / 500 = 2

Using the Z-table, we find that the percentage of babies weighing less than 4000 grams is approximately 97.72%.

For Part D:

To find the percentage of babies weighing between 2000 and 4000 grams, we subtract the percentage of babies weighing more than 2000 grams from the percentage of babies weighing less than 4000 grams.

Approximately 97.72% - 2.28% = 95.44%

For Part E:

Since the Empirical Rule states that approximately 68% of the data falls within one standard deviation of the mean, we need to find the weights that correspond to the boundaries of this range.

The lower boundary would be the mean minus one standard deviation: 3000 - 500 = 2500 grams.

The upper boundary would be the mean plus one standard deviation: 3000 + 500 = 3500 grams.

Therefore, the range of birth weights that would contain the middle 68% of newborn babies' weights is from 2500 grams to 3500 grams.

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Answer:

  A.  p(t) = 16 -5t +2t²

Step-by-step explanation:

You want the interpolating polynomial for points (1, 13), (2, 14), and (3, 19).

The given system of equations can be solved by your favorite method to find ...

The interpolating polynomial is p(t) = 16 -5t +2t².

__

Additional comment

The points and the polynomial are graphed in the second attachment.

<95141404393>

The interpolating polynomial  is (a) p(t) = 13 - 2.5t +1.5t²

From the question, we have the following parameters that can be used in our computation:

Points =  (1, 13), (2, 14), and (3, 19).

Using the general form of the quadratic formula, we have

a + b + c = 12

4a + 2b + c = 14

9a + 3b + c = 19

Subtract the equations to eliminate c

So, we have

3a + b = 2

5a + b = 5

Subtract the equations to eliminate b

So, we have

2a = 3

So, we have

a = 1.5

Next, we have

3a + b = 2

3(1.5) + b = 2

Evaluate

b = -2.5

Lastly, we have

4a + 2b + c = 14

4(1.5) + 2(-2.5) + c = 14

Evaluate

c = 13

So, the equation is p(t) = 13 - 2.5t +1.5t²

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The measure of angle LOP is given as follows:

m < LOP = 52º.

The segment OP bisects the angle O of the rhombus into two smaller angles, which are NOP and LOP.

.

A bisection means that the larger angle is divided into two smaller angles of equal measure.

The measure of angle NOP is given as follows:

m < NOP = 52º.

Hence the measure of angle LOP is given as follows:

m < LOP = 52º.

The final sentence is to find the measure of angle LOP.

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Answer:

c

Step-by-step explanation:

it's a property of powers, when the base is the same (-5) , you need to

sum the powers when both terms are multiplyng

subtract the powers when both terms are dividing (numerator power minus denominator power, in that order)

The option that shows the missing angles in the triangle is:

Option C: m∠1 < m∠4

We know that the sum of angles in a triangle is 180 degrees.

Therefore looking at the given triangle, we can say that:

m∠1 + m∠2 + m∠3 = 180°

We also know that the sum of angles on a straight line is 180 degrees and as such we can say that:

m∠3 +  m∠4 = 180°

By substitution we can say that:

m∠4 = m∠1 + m∠2

Thus:

m∠1 < m∠4

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The missing options are:

m∠1 > m∠4

m∠2 > m∠4

m∠1 < m∠4

m∠3 = m∠4

Answer:

y = x^2 + 6x +7

y=-x+1

Step-by-step explanation:

To answer this question, we need to find the equation for the line and for the parabola. So, let's do just that!

Line:

The line has a slope of -1 and and y-intercept of 1. This means that the equation for the line is y=-x+1.

Parabola:

To find the vertex form of a parabola, we must first find the vertex form of a parabola. The vertex form of a parabola is y=a(x-h)^2+k, where the vertex is (h,k). Since the vertex of the parabola is (-3,-2), h=-3 and k=-2. Let's plug these values into the vertex form of a parabola.

y=a(x-h)^2+k

y=a(x-(-3))^2+(-2)

y=a(x+3)^2-2

We're not done yet, though, as we still need to find the value of a. To do this, we will take one of the points on the parabola and plug it into the equation. I will be using the point (-1,2).

y=a(x+3)^2-2     [Plug in x and y values]

2=a((-1)+3)^2-2     [Simplify]

2=a(2)^2-2     [Simplify]

2=4a-2     [Add 2 to both sides]

4=4a     [Divide both sides by 4]

a=1

Now, we know that the equation of our parabola in vertex form is y=(x+3)^2-2. This isn't what the problem is asking for, though. Instead, they want the standard form of the parabola. To do this, we will need to expand y=(x+3)^2-2.

y=(x+3)^2-2

y=x^2 + 6x + 9 -2

y = x^2 + 6x +7

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Answer: (-5, -7)

Step-by-step explanation: To find the intersection of two functions, you need to set them equal to each other and solve for x.

In this case, we have:

2x + 3 = -4x - 27

Adding 4x to both sides, we get:

6x + 3 = -27

Subtracting 3 from both sides, we get:

6x = -30

Dividing both sides by 6, we get:

x = -5

Now that we have the value of x, we can find the corresponding value of y by plugging it into either of the original equations. Let's use f(x) = 2x + 3:

f(-5) = 2(-5) + 3 = -7

Therefore, the intersection of the two functions is (-5, -7).

Answer:

2/9

Step-by-step explanation:

Coin

A coin has 1 side heads and 1 side tails.

total number of possible outcomes = 2

desired outcome: heads

number of desired outcomes = 1

p(event) = (number of desired outcomes)/(total number of possible outcomes)

p(heads) = 1/2

Spinner

The spinner has 9 sections of equal size.

possible outcomes: the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9

total number of possible outcomes = 9

desired outcome: even number

number of desired outcomes = 4

p(event) = (number of desired outcomes)/(total number of possible outcomes)

p(even number) = 4/9

Combined probability

The coin and spinner are independent events. The overall probability of independent events is the product of the individual probabilities.

p(heads then even) = 1/2 × 4/9 = 4/18 = 2/9

Answer: 2/9

The given pair of equations is y = 4x + 2 and y = x + 5, and we are to determine which of the given graphs represents their solution. The first equation is in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. Comparing this with the given equation, we see that its slope is 4 and y-intercept is 2.

The second equation is also in slope-intercept form, y = mx + b. Comparing it with the given equation, we see that its slope is 1 and y-intercept is 5.Since we have two lines, we need to find their point of intersection. Substituting y = 4x + 2 into y = x + 5, we have4x + 2 = x + 5Simplifying the equation, we get3x = 3, which gives x = 1.

Substituting this value of x into either of the equations, say y = 4x + 2, we have y = 4(1) + 2 = 6. Hence, the point of intersection is (1, 6). Now, let's examine the given graphs and see which one has (1, 6) as a point of intersection:

Graph 1: The line y = 4x + 2 passes through (0, 2) and has a slope of 4, which means it will be steeper than the line y = x + 5. The line y = x + 5 passes through (0, 5) and has a slope of 1, which means it will be flatter than the line y = 4x + 2. Hence, these two lines cannot intersect at (1, 6). Graph 1 is not the solution.

Graph 2: The line y = 4x + 2 passes through (-1, -2) and has a slope of 4, which means it will be steeper than the line y = x + 5. The line y = x + 5 passes through (0, 5) and has a slope of 1, which means it will be flatter than the line y = 4x + 2. Hence, these two lines cannot intersect at (1, 6). Graph 2 is not the solution.

Graph 3: The line y = 4x + 2 passes through (-1, -2) and has a slope of 4, which means it will be steeper than the line y = x + 5. The line y = x + 5 passes through (0, 5) and has a slope of 1, which means it will be flatter than the line y = 4x + 2.

Hence, these two lines cannot intersect at (1, 6). Graph 3 is not the solution.Graph 4: The line y = 4x + 2 passes through (0, 2) and has a slope of 4, which means it will be steeper than the line y = x + 5. The line y = x + 5 passes through (0, 5) and has a slope of 1, which means it will be flatter than the line y = 4x + 2. Hence, these two lines cannot intersect at (1, 6). Graph 4 is not the solution.

Therefore, none of the given graphs represents the solution to the pair of equations.

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