4/ PLEASE HELP ME ON THIS. ASAP

Answer:

[tex]3 * 18= 54[/tex] and [tex]54/18 = 3[/tex]

Step-by-step explanation:

Given

[tex]Sections = 3[/tex]

[tex]Measurement=18[/tex] per section

[tex]Total\ Measurement=54[/tex]

Required

Model the scenario

The model of this scenario is:

[tex]Sections * Measurement = Total\ Measurements[/tex]

This gives:

[tex]3 * 18 = 54[/tex] -- This represents the multiplication model

Divide both sides by 18

[tex]3 * 18/18 = 54/18[/tex]

[tex]3 * 1 = 54/18[/tex]

[tex]3 = 54/18[/tex]

Reorder

[tex]54/18 = 3[/tex] -- This represents the division model

Answer:

121*5677*66766.546646

5

Step-by-step explanation:

Answer:

Step-by-step explanation:

Circumference = 2pi r

440 = 2 *22\7 *r

70 = r

Area= pi r^2

Area= 22\7 *70*70

Area =15400

Answer:

41

Step-by-step explanation:

101+38=139

180-139 = 41

Answer:

There is one solution and that answer is mixed number form  1 5/7 or exact form 12/7

Step-by-step explanation:

Answer:

Step-by-step explanation:

m * 2 = 38

Equation: 2m = 38

Solution:

2m = 38

 m = 38/2

m = 19

Malik's score = 19

Answer:

38 is the product of Malik's score and 2. Use the variable m to represent Malik's score

Marks scored by Malik

The equation will be

[tex] \frak{2m = 38}[/tex]

Total marks

[tex] \tt \: m \: = \dfrac{38}{2} [/tex]

[tex] \tt \: m \: = 19[/tex]

The marks scored by Malik is 19

Answer:

Statistic

Step-by-step explanation:

We are given four options

Parameter

Statistic

Sample

Population

In the given question the total number of students represents the population i.e population and the population size would be= N= 8000

The number of students selected represent a sample  the sample size would ben= 500

A statistic is used for a given sample e.g in the given question the mean of the sample represents the statistic.

A parameter is used for a population e.g in the given question the mean of the population would be a parameter. A parameter is computed from the entire population

The correct option is statistic.

Answer:

A.

Step-by-step explanation:

In a Linear Function, the changes between x and y should remain constant.

A: x increases by 2 while y increases by 2 steadily so it is a linear function.

B: x increases by 1 and then zooms up to increasing in double (2) while y increases by 2 and then zooms up to increasing to more than double (5) so B is not a linear function.

C: x increases by 3, then one-third of 3 (1), then two-third of 3 (2). y decreases by 6, then one-third of 6 (2), then one-third (2) again when it should have decreased by two-third of 6 (4). Notice that the last decrease was different from x.

D: x increases by 6, then one-third of 6 (2), then half of 6 (3). y decreases by 3, then one-third of 3 (1), then two-third of 3 (2) when it should have decreased by half of 3 (1.5). Notice the last decrease was different from x.

Answer:

pick the answer a

Step-by-step explanation:

Answer:

-4

Step-by-step explanation:

Answer:

The answer is -3

Step-by-step explanation:

First I subtracted 4 from -11 giving me the product of 5 and n before 4 was added which is -15

I then divided -15 by 5 giving me -3

Answer:

m=25

Step-by-step explanation:

100/4

Answer: x =3; y = -2

[tex]\left \{ {{5x+6y=3} \atop {2x-3y=12}} \right.\\\\<=>\left \{ {{x=\frac{3-6y}{5} } \atop {2x-3y=12}} \right.\\\\<=>\left \{ {{x=\frac{3-6y}{5} } \atop {2.\frac{3-6y}{5}-3y =12}} \right.\\\\<=>\left \{ {{x=\frac{3-6y}{5} } \atop {6-12y-15y=12.5}} \right.\\\\<=>\left \{ {{x=\frac{3-6y}{5} } \atop {17y=6-60=-54}} \right.\\\\<=>\left \{ {{x=\frac{3-6y}{5} } \atop {y=-54/27}} \right.\\\\\\ <=>\left \{ {{x=\frac{3-6y}{5} } \atop {y=-2}} \right.\\\\<=>\left \{ {{x=3} \atop {y=-2}} \right.[/tex]

Step-by-step explanation:

Answer:

x = 3, y = -2.

Step-by-step explanation:

5x + 6y = 3

2x - 3y = 12           Multiply this by 2:

4x - 6y = 24           Now add this to the first equation:

9x = 27

x = 3.

Substitute x = 3 in the second equation:

2(3) - 3y = 12

-3y = 12 - 6 = 6

y = 6 / -3

y = -2.

Answer: A 95% confidence interval for the true proportion (p) will be (0.4762136, 0.5637864).

Step-by-step explanation:

Let p = True proportion of people rent their residence.

Given: n= 500

People rent their residence = 260

[tex]p=\dfrac{260}{500}=0.52[/tex]

z-value for 95% confidence level = 1.96

A 95% confidence interval for the true proportion will be :

[tex]p\pm z^*\sqrt{\dfrac{p(1-p)}{n}}[/tex]

[tex]0.52\pm (1.96)\sqrt{\dfrac{0.52(1-0.52)}{500}}\\\\=0.52\pm(1.96\sqrt{\dfrac{0.2496}{500}})\\\\=0.52\pm 1.96\sqrt{0.0004992}\\\\=0.52\pm (1.96)(0.02234)\\\\=0.52\pm0.0437864\\\\=(0.52-0.0437864,\ 0.52+0.0437864)\\\\=(0.4762136,\ 0.5637864)[/tex]

A 95% confidence interval for the true proportion (p) will be (0.4762136, 0.5637864).

Answer:

there are 34 green marbles

there are 91 total marbles

Step-by-step explanation:

57 - 23 = 34

57 + 34 = 91

Answer:

1 3/4

Step-by-step explanation:

Answer:

p

Step-by-step explanation:

Answer:

running a two year contract is the best i have to do with my life in this world and it has a great way to go through the

Answer:

The 2nd one

Step-by-step explanation:

Answer:

3/2, 0.75,-3/2, -24

Step-by-step explanation:

I think that's the answer

(A): 825

(B): 42,900

Step-by-step explanation:

So basically what you want to do is divide how much ounces of oats you need in total by the amount the spoon will hold.

Total amount of oats needed ÷ How much the spoon holds = ?

So now you just add your values:

26 ÷ 4 = ?

26 ÷ 4 = 6.5

6.5 IS greater than 1

So, your equation could be one of these two:

Total oats needed ÷ How many oats the spoon will hold = ?

OR

26 ÷ 4 = ?

Answer: If you were born in April you a amiable, and always ready to help others and a faithful lover.

Step-by-step explanation:

Answer:

1/26

Step-by-step explanation:

Answer:

The first answer

Step-by-step explanation:

Answer: X = 57.5

Step-by-step explanation:

3x - 65 + x + 15 = 180

4x - 50 = 180

4x = 230

x = 57.5

Answer:

3x-65 degrees

Step-by-step explanation:

Since the angles are vertical angles, y should equal the same value of the corresponding angle.

Answer:

Ok so

Step-by-step explanation:

1st one is Infinte

2nd one is one soultion

3rd one is not

4th one is Infinte

5ht one is no

Hewo :>

:>             2(x-5) = 2(x-5) is infinitely

:>              5(x+4) = 5(x-6) is no solution

:>             5(x+4) = 3(x-6) is one solution

:>             4(x-2)=4(x+2) is infinitely

:>             x+2(x-5)=3(x-2)-4 is no solution

Have a nice Kawaii day :>

Answer:

that = 8 and if you want to see more you can go on

Answer:

The domain of the vector function is :  ( -6, -2) ∪ ( -2, 6)

Step-by-step explanation:

The given vector function  can be correctly expressed as:

[tex]r(t) = \dfrac{t-2}{t+2}i + sin \ tj + In(36-t^2) k[/tex]

The domain of the given function can be determined by finding the domain of each respective component.

To start with [tex]\dfrac{t-2}{t+2}[/tex]

Not defined, t = -2

Thus, the domain of the first component of the vector = [tex]( - \infty , -2) \cup ( 2, \infty )[/tex]

The 2nd component = sin t

No restriction on t

The 3rd component of the function is ㏑(36 - t²)

Let recall that natural is defined for +ve numbers,

i.e.

36 - t² > 0

(6 + t) (6 - t) > 0

Thus, it satisfies the inequality  -6 < t < 6

The third domain = (-6,6)

Overall;

The domain of the vector function is :  ( -6, -2) ∪ ( -2, 6)

Domain of a function is the set all possible inputs for that function.The domain of the given vector function is,

[tex](-6, -2) \cap (-2,6)[/tex]

Domain of a function is the set all possible inputs for that function.

Given information-

The vector function given in the problem is,

[tex]r(t)=\dfrac{t-1}{t+2} \hat i++sin(t)\hat j+ln(49-t^2)\hat k[/tex]

To find the domain of the above vector function, we need to find the domain of each function of vector quantity.

Lets find the domain of [tex]\hat i[/tex] first which is given by,

[tex]\dfrac{t-2}{t+2}[/tex]

This function is defined at all values except, t equals to -2 as the function is not defined at,

[tex]t=-2[/tex]

Hence the domain of component [tex]\hat i[/tex] is,

[tex](-\infty, -2) \cap (\infty,2)\\[/tex]

Lets find the domain of [tex]\hat j[/tex] first which is given by,

[tex]\sin(t)[/tex]

Two trigonometry function sine and cosine defined for all real number.

This function is defined at all real numbers. Hence the domain of component [tex]\hat j[/tex] is

Lets find the domain of [tex]\hat k[/tex] first which is given by,

[tex]\ln(36-t^2)[/tex]

Set the above argument greater than zero to find where the expression is defined.Thus,

[tex](36-t^2)>0\\(6+t)(6-t)>0[/tex]

Therefore,

The domain of it should be [tex](-6,6)[/tex]

Hence the domain of the given vector function is,

[tex](-6, -2) \cap (-2,6)[/tex]

Learn more about the domain here;

https://brainly.com/question/10197594