42. The number of decibels, d, produced by an audio


source can be modeled by the equation d = 10 log(K),


where I is the sound intensity of the audio source and


K is a constant. How many decibels are produced by an


audio source whose sound intensity is 1,000 times the


value of K?


F. 4


G. 30


H. 40


J. 100


K. 10,000

Answers

Answer 1
We are given that d = 10 log(K) where K is a constant and the sound intensity is 1000 times the value of K.

So, we can write I = 1000K

Substituting this value in the equation for d, we get:

d = 10 log(1000K)

d = 10 (log 1000 + log K)

d = 10 (3 + log K)

d = 30 + 10 log K

Since K is a constant, we can assume it to be 1.

Therefore, d = 30 + 10 log 1 = 30

So, an audio source whose sound intensity is 1000 times the value of K produces 30 decibels of sound.

Therefore, the answer is option G) 30.

Related Questions

Jeanette served 3/4 of a pizza to her friends each visitor was given 1/4 of the pizza

Answers

If Jeanette served 3/4 of a pizza to her friends, she has 1/4 of the pizza left.

To find out how many friends visited Jeanette, we can divide the amount of pizza she served (3/4) by the amount of pizza each friend was given (1/4):

(3/4) ÷ (1/4) = (3/4) x (4/1) = 3

So, Jeanette served 3/4 of a pizza to 3 friends.
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