6x-27=-3x
solve for x:D
Answer:
6×-27=-3×
+3×
9/9×=27/9
×=3
Dan, Harry and Regan sell cars.
Dan sells x cars.
Harry sells 5 more cars than Dan.
Regan sells twice as many cars as Dan.
Write an expression, in terms of x, for the mean number of cars Dan, Harry and Regan sell.
Answer:
4X+5
Step-by-step explanation:
Dan : X
Harry: X+5
Regan: 2X
X+X+5+2X
Answer:
[tex]Mean = \frac{4x + 5}{3}[/tex]
Step-by-step explanation:
Given:
Dan sold = x
Harry sold 5 more than Dan, that is = x + 5
Regan sold twice as Dan = 2x
[tex]Mean = \frac{ Total \ cars \ sold}{number\ of \ them \ sold \ it }\\\\Mean = \frac{x + ( x+ 5) +2x }{3} = \frac{4x + 5}{3}[/tex]
Solve 2x + 6 > 20. OLA X> 18 B. X>7 O c. x
someone help por favor
Answer:
2x+6>20
2x>20-6
2x/2>14/2
x>7
So your answer would be B
What’s 1/2 + 1/3? Y’all please help me . And when or if you can give me the answer can you do step-by-step on how you did that so I can do it myself next time?
[tex]\longrightarrow{\green{\frac{5}{6}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] \frac{1}{2} + \frac{1}{3} [/tex]
Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.
The L. C. M for 2 and 3 is 6.
Now, multiply the L.C.M. with both numerator & denominator.
[tex] = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} [/tex]
[tex]= \frac{3}{6} + \frac{2}{6} [/tex]
Now that the denominators are equal, we can add them.
[tex]= \frac{3 + 2}{6} \\ \\ = \frac{5}{6} [/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]