The value of the Decomposition equilibrium is 2-1 =1.
pV=nRT. n=m/Mr = 3.509 / 135 = 0.026 moles.
a) p=nRT/V=0.026 x 0.082 x 375/1 = 0.8 atm.
b) SO2Cl2 (g) ⇌ SO2 (g) + Cl2 (g).
1.43 - 0.8 = 63
2-1 =1.
0.63 x 0.026 = 0,01638. 0.026 -0,01638= 0.00962 moles of SO2CL2.
0.01638 moles of SO2 and 0.01638 moles of Cl2.
0.01638 + 0.01638 + 0.00962 = 0.04238 moles general.
1.43 x 0.01638 / 0.04238 = 0.5526 atm of SO2 and Cl2.
1.43 x 0.00962 / 0.04238 = 0.3246 atm of SO2CL2.
c) 0.01638 x 0.01638/ 0.00962=0,0278902703
d) Will react turn to the right
Decomposition is endothermic:- Yes all decomposition reactions are endothermic. Decomposition reactions involve the breaking of bonds that require energy. Due to this decomposition reactions are generally endothermic in nature.
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(a) The pressure in the atmosphere would be = 0.800 atm.
(b) Partial pressure of [tex]P_{SO_{2}Cl_{2} } =0.170 atm[/tex]
Partial pressure of [tex]P_{SO_{2}}=0.630atm[/tex]
Partial pressure of [tex]P_{Cl_{2}=0.630 atm[/tex]
(c) Equilibrium constant at 375 K is 2.33 atm.
(d) If the temperature were raised to 500K, the value of the equilibrium constant will increase.
(a) Mass of [tex]SO_{2}Cl_{2}[/tex] = 3.509 g
Molar mass of [tex]SO_{2}Cl_{2}[/tex] = 135.0 g/mol
Thus, moles of [tex]SO_{2}Cl_{2}[/tex] are-
Mole of [tex]SO_{2}Cl_{2}[/tex][tex]=\frac{3.500g}{135.0g/mol}[/tex] [tex]=0.026moles[/tex]
The initial pressure of the [tex]SO_{2}Cl_{2}[/tex] is calculated using the Ideal gas law-
[tex]P_{SO_{2}Cl_{2} } =\frac{nRT}{V} =\frac{(0.026moles)(0.082Latm/molK)(375K)}{1.00L}[/tex]
[tex]P_{SO_{2}Cl_{2} } = 0.800atm[/tex]
Thus, the Initial pressure of [tex]SO_{2}Cl_{2}[/tex]= 0.800 atm.
(b) Now,
[tex]P_{Total} =1.43atm[/tex]
At equilibrium,
[tex]P_{Total} =P_{SO_{2}Cl_{2} } +P_{SO_{2} } +P_{Cl_{2} }[/tex]
Thus, using the data from ICE table, solve for x-
1.43 = (0.800 - x) + x + x(1.43) = 1.43 - 0.800 = 0.630 atm
Hence, at equilibrium at 375 K, the partial pressure of each species present is-
[tex]P_{SO_{2}Cl_{2} } = 0.800-0.630 =0.170atm[/tex]
[tex]P_{{SO_{2} } } = x=0.630atm[/tex]
[tex]P_{{Cl_{2} } } = x=0.630atm[/tex]
(c) The expression of the equilibrium constant in terms of pressure for the decomposition of [tex]SO_{2}Cl_{2}[/tex] is written as-
[tex]K_{P} =\frac{P_{SO_{2} .}P_{Cl_{2} } }{P_{SO_{2}Cl_{2} } }[/tex]
Using the partial pressure values at 375 K , solve for [tex]K_{P}[/tex]-
[tex]K_{P} = \frac{(0.630atm)(0.630atm)}{0.170atm} =2.33atm[/tex]
Hence, the equilibrium constant at 375 K is 2.33 atm.
(d) As the decomposition of [tex]SO_{2}Cl_{2}[/tex] is endothermic, thus on increasing the temperature, more heat is added, so the reaction will go in a forward direction producing more products.
Thus, [tex]K_{500}[/tex] > [tex]K_{375}[/tex]
Hence, if the temperature were raised to 500K, the value of the equilibrium constant will increase.
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when applied research is conducted in settings outside the laboratory, which of the following can be a problem?
when applied research is conducted in settings outside the laboratory, the focus on a specific real world problem can be a problem.
The configuration and contents of laboratories are determined by the diverse needs of the specialists that work inside. A laboratory might have a particle accelerator or a vacuum chamber, whereas a metallurgy lab might have tools for casting, refining, or evaluating the strength of metals. A psychologist would utilise a room with one-way mirrors and covert cameras to examine behaviour in their lab, whereas a biologist or chemist might employ a wet laboratory. In laboratories, such as those where computer scientists typically operate, computers (and occasionally supercomputers) are sometimes utilised for either simulations or data processing. Scientists in other professions will continue to use a variety of labs. In laboratories, engineers build, assemble, and test technical objects.
The complete question is:
when applied research is conducted in settings outside the laboratory, which of the following can be a problem?
a. examines the basic laws of human behavior
b. is just as likely to occur in the laboratory as in the field
c. focuses on a specific real world problem
d. has no connection with theory
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suppose of ammonium sulfate is dissolved in of a aqueous solution of sodium chromate. calculate the final molarity of ammonium cation in the solution. you can assume the volume of the solution doesn't change when the ammonium sulfate is dissolved in it. round your answer to significant digits.
The final molarity of the ammonium cation in the solution is 0.066M.
Firstly, we need to calculate the number of moles of ammonium sulfate:
No of moles = mass(g)/molar mass
No of moles = 2.57/132.14
No of moles = 0.0195 mol
When ammonium sulfate dissolves in sodium chromate, the following reaction will take place:
(NH₄)₂SO₄ + Na₂CrO₄ ------> (NH₄)₂CrO₄ + Na₂SO₄
No of Moles of sodium chromate = molarity x volume
= 66 x 0.200
No of moles of Sodium Chromate = 0.0132 mol
According to the reaction, 1 mol of sodium chromate produces 1 mol of ammonium chromate.
In this reaction, the sodium chromate amount is less than ammonium sulfate.
It can be concluded that Sodium chromate is a limiting reagent.
Therefore 0.0134 mol of ammonium cation is present in the resulting solution.
Molarity of ammonium cation = 0.0134 mol / 0.2 L
Molarity = 0.066 M
Therefore, 0.066M is the Molarity of the ammonium cation.
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At 25 °C, only 0.0140
mol of the generic salt AB is soluble in 1.00 L of water.
What is the sp
of the salt at 25 °C?
AB(s)↽−−⇀A+(aq)+B−(aq)
Correct task : At 25°C, only 0.0140 mol of the generic salt AB3 is soluble in 1.00 L of water. What is the Ksp of this salt at 25°C.
Solution:
When the salt dissolves, it dissociates as follows:
AB3 --> A3+ + 3B⁻
--S--------S-------3S--
The molar solubility (S) is the number of moles that can dissolve in 1 L of solution.
Molar solubility of salt is (0.0140 mol) / (1.00 L) = 0.0140 mol/L.
According to the dissociation equation:
Solubility of A3+ is 0.0140 mol/L and solubility of B⁻ is 3×0.0140 mol= 0.0420 mol/L.
[A3+] = 0.0140 mol/L.
[B⁻] = 0.0420 mol/L.
Ksp is the solubility product constant and calculated as follows:
Ksp(AB3) = [A3+] × [B⁻]3
Ksp(AB3) = [0.0140] × [0.0420]3
Ksp(AB3) = 10.37×10-7.
Ksp of this salt is 1.04×10-6.
Answer: 1.04×10-6 is the Ksp of this salt at 25°C.
Define the following: Renwable energy and non-Renwable energy.
A resource can be classified as renewable or nonrenewable based on whether it can replace itself at the rate it is used up or whether it has a finite supply.
What exactly is renewable energy?Energy obtained from natural resources that are renewed more quickly than they are used up is referred to as renewable energy. Such sources that are constantly replenished include the sun and the wind, for instance. Non-renewable energy comes from energy sources that will ultimately exhaust themselves or cannot be regenerated, not even after countless ages. Fossil fuels, such as petroleum, natural gas, and coal, are the non-renewable energy sources that are most often used.A resource can be classified as renewable or nonrenewable based on whether it can replace itself at the rate it is used up or whether it has a finite supply. Timber, wind, and solar power are examples of renewable resources, whereas coal and natural gas are examples of non-renewable resources.To learn more about Renewable energy refer to:
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cobalt- is radioactive and has a half life of years. how much of a sample would be left after years? round your answer to significant digits. also, be sure your answer has a unit symbol.
Cobalt-60 is radioactive and has a half life of 5.26 years . amount of 3.60 mg sample would be left after 5.20 years is 1.82 mg.
The half-life t1/2 = 5.26 years
the decay constant , k = 0.693 / t1/2
= 0.693 / 5.26
= 0.1317 / year
the expression is given as :
t = 2.303 / k log No/N
No = 3.60 mg
t = 5.20 yr
5.20 = 2.303 / 0.1317 log 3.60 / N
5.20 = 17.4 log 3.60 / N
log 3.60 / N = 0.2988
3.60 / N = 1.989
N = 1.82 mg
The question is incomplete , the complete question is :
cobalt- is radioactive and has a half life of years. how much of a sample would be left after years? round your answer to significant digits. also, be sure your answer has a unit symbol.
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which of the following is not a network solid? selected answer: correctc. co2(s) correct answer: correctc. co2(s)
We were aware that SiO2 is a network covalent solid and that CO2 is a molecular solid, but I'm not sure how I would go about determining that.
Each silicon and carbon have the same number of valence electrons, and they both contain two oxygen atoms. Because solid sulfur dioxide is a molecule and has covalent bonds, it is not a network solid even if it is a solid and has covalent bonds. An example of a network solid is diamond. One of the many forms of elemental carbon found in nature, diamond is an allotrope of carbon. On an atomic level, it resembles this. The carbon atoms are linked together by the lines.
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from each partial (valence level) orbital diagram, write the ground-state electron configuration and group number
The electron configuration and group number is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10
What is electron configuration?Electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. It describes the energy levels, orbitals, and the number of electrons in each of the atom's orbitals. Electron configuration provides an understanding of the atom's structure, reactivity, and the likelihood of chemical reactions to occur. It also serves as a predictor of the atom's physical and chemical properties. Electron configuration is determined by the number of protons in the nucleus and the principal quantum number of the electron.
This is the ground-state electron configuration for the element titanium, which is located in group 4 of the periodic table.
The 1s orbital is filled with two electrons, the 2s orbital is filled with two electrons, the 2p orbital is filled with six electrons, the 3s orbital is filled with two electrons, the 3p orbital is filled with six electrons, the 4s orbital is filled with two electrons, and the 3d orbital is filled with ten electrons. This configuration of electrons corresponds with titanium's position in group 4 of the periodic table, which contains elements with four valence electrons in the outermost energy level.
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The equilibrium constant for a particular reaction has been measured at different temperatures. The results are plotted below: n A I/T Determine the correct thermodynamic properties for this reaction:(Warning!: There is a maximum of 2 attempts for this question) O endothermic with Aso o O exothermic with ASo < 0 O exothermic with aso > 0 O endothermic with ASo o O more information is needed Submit AnswerIncorrect. Tries 1/2 Previous Tries
Therefore, option an is the best choice and the equilibrium constant is 0.32. The best choice is that.
The equilibrium constant's value falls as temperature rises. An rise in temperature increases the value of the equilibrium constant when the forward reaction is endothermic. As the temperature fluctuates, so does the equilibrium position. For elements in their standard condition, G0f G f 0 is taken into consideration as zero. As a result, the reaction's standard change in Gibb's free energy at 25 degrees Celsius is 98.746 kJ. Since there is no longer any free energy to fuel the process at equilibrium, G=0.
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curved arrows are used to illustrate the flow of electrons. follow the arrows to predict the intermediate and product of reaction nah
The arrows are used to illustrate the flow of electrons. follow the arrows to predict the intermediate and product of reaction , the product is :
CH₃ - C -CH₃ + H₂O + ⁻OCH₃
||
O
The reaction is in between the 2 methoxypropan-2-ol and the hydroxide ion. the OH⁻ ion is the strong nucleophile and contain the negative charged. the hydroxyl group acts as a proton of the compound is acidic because of the electronegativity difference. the hydroxyl ion takes protons and form the water.
The reaction is given as follows :
OH
|
CH₃ - C - OCH₃ + OH⁻ ----> CH₃ - C -CH₃ + H₂O + ⁻OCH₃
| ||
CH₃ O
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Design a synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons or fewer alcohols containing 4 carbons or fewer
The enolates are the anions from the ketones. synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons is :
butan - 1 - ol ------> 2-ethyl-2-hexenoic acid
The enolates ions will acts as a nucleophile in the SN² reaction . The alkyl group will replace the alpha hydrogen and then the carbon carbon new bond is formed . synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons is given as :
CH₃ - CH₂ - CH₂ - CH₂ - OH + PCC --- > CH₃ - CH₂ - CH₂ - C - H
||
O
+ NaOH ----> CH₃ - CH₂ - CH₂ - CH = C - C - H
| ||
C₂H₅ O
+ H₂CrO₄ -----> CH₃ - CH₂ - CH₂ - CH = C - C - OH
| ||
C₂H₅ O
2-ethyl-2-hexenoic acid
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a valid lewis structure of cannot be drawn without violating the octet rule. group of answer choices nf3 so42- pf3 sbf3 if3
A valid lewis structure of cannot be drawn without violating the octet rule is IF₃.
According to the octet rule the atoms will be more stable if the valence electrons in the valence are eight electrons.
a) NF₃ = in the lewis structure of NF₃ the atom will contains the eight valence electrons in the valence shell. thus it follows the octet rule.
b) SO₄²⁻ = SO₄²⁻ , lewis structure follows the octet rule . atoms contains the eight valence electrons.
c) PF₃ = phosphorus valence electrons is 5 and the fluorine valence electron is 7 and fulfil the octet rule.
d) IF₃ = in the lewis structure IF₃ , it does not follows the octet rule . it contains the more than eight electrons .
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Oil and methane hydrates are both physical ocean resources found beneath the seafloor. List two other similarities between oil and methane hydrates.
Crude oil is a mixture of nitrogen, sulphur, oxygen, and volatile hydrocarbons. Methane hydrate is a particular kind of clathrate made up of water and low molecular weight gases like methane.
Fossil deposits under the seafloor are what make up oil. It is an organic chemical that was created by the deposition of organisms on the seafloor. Additionally, methane hydrates are created after marine creatures deposit. Under the ocean's surface, one can find both oil and methane hydrates.
Similarities between both the Oil and methane hydrates are :
They both came from the ocean floor.They come from fossil fuels.They are created by decaying aquatic life.They are an energy source that is not renewable.They were mostly made of hydrogen and carbon.Both contribute to climate danger.Under high pressure and low temperature, they solidified.To learn more about Oil and methane hydrates refer here
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mechanism of action that will produce diuretic effect- increase the number of particles in the tubular fluid . True or False
True, mechanism of action that will produce diuretic effect- increase the number of particles in the tubular fluid.
When the kidneys filter too much body fluid, it is called diuresis. As a result, you produce more urine and need to use the restroom more frequently. Diuresis may be brought on by specific medical disorders or by taking drugs that boost urine production. This illness can also be caused by lifestyle choices. Water tablets or diuretics are drugs that assist the body in eliminating extra fluid. They are frequently prescribed for illnesses like high blood pressure, chronic renal disease, and heart failure.
The kidneys are told to expel more water and salt via diuretics. This lessens edema and improves blood circulation throughout the body.
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Radioisotopic dating estimates the age of objects based on the fact that the half-life of any radioactive isotope is _____.a fixed value
The time it takes for one-half of the radioactive parent isotope to decay into the daughter isotope is known as the half-life.
As a result, if we begin with 1 gram of the parent isotope, there will only be 0.5 gram of the parent isotope left after 1 half-life. The fundamental idea behind radiometric dating is that by comparing an isotope's presence in a sample to its abundance on Earth and its known half-life (rate of decay), you may determine the sample's age. A radiometric dating technique is radiocarbon dating, often known as carbon-14 dating. It determines the age of carbon-bearing by using the naturally occurring radioisotope carbon-14 (14C).
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give the number of sigma bonds and pi bonds for the molecule below: 3 sigma bonds, 6 pi bonds 6 sigma bonds, 3 pi bonds 6 sigma bonds, 6 pi bonds 12 sigma bonds, 3 pi bonds
Benzene is a carbon and hydrogen compound with aromatic properties. The chemical formula for benzoene is C6H6.To determine the number of sigma bonds in this, we can create the skeletal structure using only sigma bond representations.
Let's show the structure of benzene.
As can be seen, there are six C-H bonds and six C-C bonds.
We may therefore say that benzene has a total of 12 sigma bonds in it.
When we look at the structure of benzene, we can see that it has three C=C bonds.
There are consequently 3 pi bonds and 12 sigma bonds. As a result, benzene contains 15 covalent bonds.
Since benzene has 12 and 3 sigma and pi bonds, respectively, the correct answer is that it does.
Additional
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What percentage is the smell from monomer on the Paper towel
Answer: It is the radiation of energy.
Explanation:
Which of the following cations is isoelectronic with argon? 1.potassium ion 2.calcium ion 3.scandium ion 4.All of these 5.None of these
Option 1 is correct because potassium ions in argon contain 18 electrons. Thus, there are 18 isoelectronic in all that are present in Ar for K+. The electrical arrangement of these two ions is the same as that of Ar.
K+ and Cl ions are hence isoelectronic with Ar. Argon is isoelectronic with potassium ions that have a positive charge. For an ion with a -1 charge to become isoelectronic with argon, it would only have needed to gain 1 electron. Chlorine must have been present there.
Similar to the previous element, the next one can create a monovalent cation by losing one electron and isoelectronizing with argon. These include the potassium cation, K+, the chloride anion, Cl, and the sulphide anion, S2. Isoelectronic ions are said to have the same number of protons and electrons.
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match each process of the nitrogen cycle with the form of nitrogen that is produced. labels may be used more than once.
Matching each process of the nitrogen cycle with the form of nitrogen that is produced is combustion: NO2; decomposition: NH4+; nitrogen fixation: NH4+; denitrification: N2; and nitrification: NO3-.
The nitrogen cycle refers to the biogeochemical cycle by which nitrogen is converted into multiple chemical forms as it moves among terrestrial, atmospheric, and marine ecosystems. It is a repeating cycle of processes during which nitrogen circulates through both living and non-living things: the atmosphere, soil, water, plants, animals, and bacteria. In order to move through the different parts of the cycle, nitrogen must change forms. The conversion of nitrogen can be carried out through both biological and physical processes. The nitrogen converts into NO2 through stationary combustion and into NH4+ through decomposition. Fixation converts nitrogen in the atmosphere into forms that plants produce i.e., NH4+. Denitrification is the process that converts nitrate to nitrogen gas, producing N2. Nitrification is the process that converts ammonia to nitrite and then to nitrate producing NO3-.
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Which of the following compounds are the same?
Compound 1 is composed of 67 g of H and 33 g of F.
Compound 2 is composed of 29 g of Na and 71 g of Br.
Compound 3 is composed of 39 g of Na and 61 g of Br.
Compound 4 is composed of 33 g of F and 67 g of H.
A. Compounds 1 and 4
B. Compounds 2 and 3
C. Compounds 1 and 2
D. Compounds 2 and 4
The option among the given compounds that are the same compound is: Compounds 2 and 3
Th correct option is B.
What are compounds?Compounds are substances that are composed of two or more elements chemically combined together.
Compounds can be formed by the combination of two non-metals or a metal and a non-metal.
Compounds formed from the combination of two non-metals are covalent compounds.
Compounds formed from the combination of a metal and a non-metal are called ionic compounds since they form oppositely-charged ions.
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in the dehydrohalogenation of 2-bromobutane which conformation below leads directly to thr formation of cis-2-butene
The conformation below in the dehydrohalogenation of 2-bromobutane results in the immediate production of cis-2-butene.
Dehydrohalogenation in chemistry is an elimination process that eliminates a hydrogen halide from a substrate. Although the reaction is frequently linked to the synthesis of alkenes, it has other uses as well.
A hydrogen halide is eliminated (removed) from a substrate during a dehydrohalogenation reaction. Although the reaction is frequently linked to the synthesis of alkenes, it has other uses as well.
The type of atoms or groups of atoms that leave the molecule serves as a frequent indicator of elimination reactions. Dehydrohalogenation, for instance, is the removal of a hydrogen atom along with a halogen atom; dehalogenation is the removal of two halogen atoms. Dehydration, on the other hand, is the removal of a water molecule, typically from alcohol.
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Which of the following is the correct Lewis structure for the molecule NH3?
Answer:
Option 3 represents correct Lewis structure for NH3
The decomposition of a single compound at 349 K has a rate constant of 4.10 x 10-3 M s1. If the initial
concentration of the reactant is 1.304 M, what is the concentration of the reactant after 90.45 seconds?
(the answer should be entered with 3 significant figures; do not enter units; give answer in normal
notation-examples include 1.23 and 12.3 and 120. and -123)
Selected Answer:
Correct Answer:
0.933
0.933 ±1%
Answer: To solve this problem, you can use the first-order rate equation, which is given by:
[reactant] = [reactant]0 * e^(-k*t)
where [reactant] is the concentration of the reactant at time t, [reactant]0 is the initial concentration of the reactant, k is the rate constant, and t is the time.
Plugging in the given values, we get:
[reactant] = 1.304 M * e^(-4.10 x 10^-3 M s^-1 * 90.45 s)
= 1.304 M * e^(-0.0366)
= 1.304 M * 0.933
= 1.21 M
To express the answer with 3 significant figures, you can round the answer to 1.21 M. Therefore, the concentration of the reactant after 90.45 seconds is 0.933 ± 1%.
The Cori cycle is a metabolic pathway that involves active muscles and the liver. fatty acids glucose → glucose glycolysis → ATP gluconeo- genesis ATP CO2 + H2O lactate lactate LIVER MUSCLE Complete the sentences about the Cori cycle. Muscles break down into , which undergoes glycolysis. The end product of glycolysis in active muscles is , which is transported in the blood. The liver uses energy from to drive The produced in the liver is transported to the muscle in the bloodstream. Answer Banklactate pyruvate fatty acid oxidation glycolysis glycogen gluconeogenesis glucose
The process of moving lactate from cells that are engaged in anaerobic metabolism to the liver, where it is used to deliver glucose back to the cells, is known as the Cori cycle.
It serves as an illustration of one of the vital functions of the liver in ensuring that the body has an adequate supply of glucose. Gluconeogenesis has examples like the Cori cycle. It is true that the Cori cycle uses the liver's gluconeogenesis to change the lactate that muscles create into glucose. To be utilized by other cells throughout the body, this freshly created glucose is discharged into the blood. The Cori cycle, which transforms lactic acid into Glycogen, which can be used as a source of energy, prevents the excessive accumulation of lactic acid.
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Water boils at 100 degrees Celsius. What is the boiling point for water on the Kelvin scale? K = °C + 273 and °C = K - 273
Answer:
the answer is 373
Explanation:
K=°C + 273
K=100+273=373
Balance the Equation
________Fe+ ______ Cl₂ → ________ FeCl₃
Answer:
2Fe+2Cl2____2FeCl3
Explanation:
Fe has positive ions and hence to balance you add two ions to each side of the equation.
Draw structural formulas for the product formed by treating each compound with propylmagnesium bromide followed by aqueous HCl.
(a) CH2O
(b) (c) (d)
The structural formulas for the product formed by treating each compound with propyl magnesium bromide followed by aqueous HCl is given as follows :
CH₃CH₂CH₂ - CH₂ - OH
butanol
The propyl magnesium bromide , the formula is given as follows :
CH₃CH₂CH₂ -MgBr
when it react with compound CH₂O , the product formed is the butan - 1 - ol. the structural formula is given as follows :
CH₃CH₂CH₂ - CH₂ - OH
butanol
The propyl magnesium bromide is acts as grinard reagent which react with CH₂O and will form the alcohol, that butanol. here the CH₂O is called as the formaldehyde.
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PLEASE HELP!!!
1. SEP Develop Models
Use the space to draw electron dot structures to model the bonding in calcium oxide (CaO), calcium chloride (CaCl₂), and potassium nitride (K₂N). As you develop your models, consider the following: Use the diagram for NaCl as a guide for your electron dot structures. After the bond is formed, each ion should have a complete outer electron shell, and the overall charge on the compound should be zero.
Answer:
Calcium Oxide must be Ionic, as we have one metal and one non metal involved. the metal is Calcium and the non metal is Oxygen. Meaning Calcium must be the one that transfers (loses) electrons to Oxygen, and Oxygen gains these electrons. It would look something like this:
Because Calcium transfers 2 electrons, it now has 2 more positively charged protons than the total number of electrons, as two electrons are lost. this means Calcium is no longer an atom, as it's positive protons and negative electrons can't cancel and make it neutral, it is now an ion, and a positively charged one at that. Same thing applies for Oxygen, but the opposite. because it has 2 more negative electrons than it's total of positive protons, it is now also an ion, and a negative one at that. The diagrams provided show the charges of the ions.
Potassium Nitrate must also be Ionic, for the same reason as before. the metal is Potassium and the non metal is Nitrogen. However, because Potassium is in Group 1, it only has 1 electron it can transfer to Nitrogen, but Nitrogen needs 2 electrons for a full outer energy level, therefore, we must have two Potassium atoms in this equation. It would look something like this:
Because there are two Potassium ions, each with a +1 charge, this means the overall charge of the Potassium ions is 2+, and this cancels out with the 2- provided by one ion of Nitrogen
Which of the following equations represents a reaction for which the standard entropy change is positive?
a) 3 O₂(g) --> 2 O₃(g)
b) 2 H₂(g) + O₂(g) --> 2 H₂O(l)
c) CaCO₃(s) --> CaO(s) + CO₂(g)
d) I₂(g) + 2 K(s) --> 2KI(s)
The correct response is A) The change in gaseous moles n g must be largest, indicating the formation of more gaseous products, which enhances unpredictability and, hence, entropy positive.
Entropy increases as a substance transitions from a solid to a liquid to a gas, and by observing the phases of the reactants and products, you can determine if an entropy change is positive or negative. Entropy will rise once the number of gas moles increases. The environment's negative entropy change is significantly outweighed by the system's positive entropy change. We can see that the system's entropy change is positive.
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Suppose
17.0g
of potassium acetate is dissolved in
250.mL
of a
0.30M
aqueous solution of sodium chromate.
Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the potassium acetate is dissolved in it.
Be sure your answer has the correct number of significant digits.
17.0g of potassium acetate is dissolved in 250.mL of a 0.30M aqueous solution of sodium chromate. The final molarity of acetate anion in the solution is 0.59 M.
The term "molar concentration" refers to the amount of a substance in a solution represented as a percentage of its volume. It is also used to refer to molarity, quantity concentration, or substance concentration. The most common unit used in chemistry to express molarity is the number of moles per liter, represented by the unit sign mol/L or mol/dm3 in SI units. One molar, or 1 M, of a solution's concentration is defined as one mol/L. Molarity is a unit of concentration used to describe chemical solutions (M). It is the number of moles of the solute in one liter of solution. This is not the same as the liters of solvent, to be clear (a common mistake). Despite being a useful unit, molarity has one fundamental flaw. Because temperature affects a solution's volume, it does not remain constant when it varies. Because you cannot directly measure solute in moles, you usually convert grams of solute to moles and then divide this amount by liters of solution.
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Which of the following is an observation of a chemical property?
Ozinc reacts with hydrochloric acid
density of wood is 0.51 g/cm³
water boils at 100°C.
sand paper is roughly textured
The right answer to the previous question and the correct observation of a chemical property is that zinc reacts with hydrochloric acid.
ZnCl2 +H2 = Zn +2HCL
Balanced equation:
ZnCl2 + H2 Zn + 2HCL
Zinc is a chemical element, designated by the symbol Zn and the atomic number 30. When the oxidation is removed, zinc turns shiny-greyish and at room temperature turns into a somewhat brittle metal.
All living things, including people, animals, plants, and microorganisms, depend on the trace metal zinc. It is the trace metal that is present in people in the second-highest concentration after iron. Zinc is an essential nutrient for development and a key cofactor for various enzymes. A lack of zinc can lead to a variety of diseases. Deficiency can lead to diarrhoea, infection susceptibility, and slower growth.
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