6th grade science I mark as brainliest (can someone answer my other question like this?)

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

Answer:

Think of an object you have observed ... Work with your group to gather evidence that light carries energy, then answer the questions below. Shine the flashlight on the liquid crystal sheet.

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

Answer:2900

Explanation:

I think

Answer:

Please see below as the answer is self-explanatory.

Explanation:

Answer:

Explanation:

A mixture can usually be separated back into its original components. Some examples of mixtures are a tossed salad, salt water and a mixed bag of M&M's candy.

Answer:

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Answer:

True

Explanation:

If an object is at rest it will stay at rest unless a force acts on it.

Answer: Mohs Scale

Explanation: Mohs Scale of Hardness

hope this helped!!!!!!!!!!!

Answer:

2 m/s

Explanation:

The momentum of the colliding system is conserved . Therefore, the velocity of the ball B with the same mass as A is 0.52 m/s.

Momentum of a body is the ability to bring the applied force makes maximum displacement. it is the product of mass and velocity. For a collision, the sum of initial momentum of the two bodies is equal to the sum of their final momentum.

Thus, u be the initial velocity and v be the final velocity.

Then, m1 u1+ m2 u2 = m1 v1 + m1 v2

m1 =  0.17 kg

u1 = 4 m/s

m2 = 0.17 kg

u2 = 0

Then initial momentum = 0.17 × 4 m/s + 0 = 0.68 kg m/s

v1 = 3.5 m/s

0.68 kg m/s = (0.17 × 3.5 m/s ) +  (0.17 × v2)

then v2 = 0.52 m/s.

Therefore, the velocity of ball B after collision will be 0.52 m/s.

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Answer:

industrial revolution

Explanation:

Answer:

density is defined as the amount of mass contained in unit volume of a body .its si unit is kg/m*3

Answer:

Density is the amount of mass per unit volume of a substance.

Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"

Answer:

the magnitude of the normal force on the book is 25.78N

Explanation:

The computation of the magnitude of the normal force on the book is shown below

Normal force = N is

= mgcosβ

= 2.70 × 9.8 × cos13°

= 25.78N

hence, the magnitude of the normal force on the book is 25.78N

The above formula should be applied

Answer:

270 Kg e 130 kg

Explanation:

how many times is the number put together

Answer:

100

w=f*s

20*5=100....

100 Joules of work is done on the cart.

Work done by a force is defined as the product of the displacement and the component of the applied force on the object in the direction of displacement. When we push a block with some force, the body moves with some acceleration, so it is called work done.

Work done is expressed as W=Fd and its unit is joules which can be defined as the amount of work done by a force in Newton is applied to an object, as a result of which it is displaced in meter.

For above given information,

Force= 20 N

Distance= 5 m

So, work done= 20*5= 100 Joules

Thus, 100 Joules of work is done on the cart.

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Answer:

A negative slope results when an individual is moving away

Explanation:

Answer:

Explanation:

a )

We shall apply Wein's displacement law

λm x T = b where λm is wavelength of radiation having maximum intensity

T is absolute temperature of body , and b is  a constant

b = 2898 μm-K

T = 273 + 34 = 307 K

λm x 307 = 2898

λm = 9.44 μm

= 9440 nm

It is infrared radiation .

b )

We shall apply Stefan's law of radiation.

E = σA T⁴

E is emitted radiation by body acting as black body   , A is surface area , T is absolute temperature of body

σ = 5.67 x 10⁻⁸ J / m²T⁴

Surface area of a typical man's body A = 1.9 m²

T = 273 + 34 = 307 K

Assuming human body as black body

E = 5.67 x 10⁻⁸ x 1.9 x 307⁴ J/s

= 9.57 x 10² J/s

= 957 W .

c )

Radiation absorbed

E = 5.67 x 10⁻⁸ x 1.9 x ( 273 + 20 )⁴ J/s

= 794 W .

Answer:

c is the answer,................

Answer:

gravitational potential energy.

Explanation:

Gravitational potential energy (GPE) can be defined as an energy possessed by an object or body due to its position above the earth surface.

Mathematically, gravitational potential energy is given by the formula;

[tex] G.P.E = mgh[/tex]

Where,

G.P.E represents gravitational potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

This ultimately implies that, anytime there is height, the object must have gravitational potential energy.

Hence, an object possesses gravitational potential energy due to its height (position) and the earth's gravitational force.

Answer:

Explanation:

Let us calculate the average velocity .

Average velocity = total distance / total time

Time taken to drive first 15 mi

= 15 / 60 = .25 h

Time taken to drive next 15 mi

= 15 / 30 = .5 h

Total time = .25 + .5 = .75 h

Total distance = 30 mi

average speed = 30 / .75

= 40 mi / h

So average speed is 40 mph which is less than given velocity of 45 mph .

Hence if she travels at 45 mph , she will take less time .

For the three-point charges fixed in a right triangle, we have:

1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. The force does an angle of 21.68° with the x-axis.

First, let's denote the charges as is shown in the picture below:

The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:  

[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex]  (1)    

Where:  

We can calculate the electrical forces with Coulomb's law:

[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]

Where:

Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])

The forces in the x-component are given by:

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex]   (2)

Where:              

We can calculate the angle θ with the following trigonometric function:

[tex]sin(\theta) = \frac{y}{z}[/tex]

[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]

To find the distance x (d₂₃), we need to use Pythagoras:

[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]

After entering θ and x (d₂₃) into equation 2, we have:

[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]

[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]

Hence, the x-component of the force is -1.66 N.

Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])

The only force acting on the y-axis is the y-component of the force F₂₁, so:

[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]

The minus sign is because the vector is pointing in the negative y-direction (see the picture below).

[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]

Hence, the y-component of the force is -0.66 N.

Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):  

[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]                                  

Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.

According to the picture below, the angle of the force with respect to the x-axis is given by:  

[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]

[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]

Therefore, the force does an angle of 21.68° with the x-axis.

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Answer:

Explanation:

Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller

Answer:

Ti and O

Explanation:

It is what it is.

Answer:

B. Ti and O

Explanation:

A.P.E.X

[tex]\displaystyle U_s = 0.6 \ J[/tex]

Math

Pre-Algebra

Order of Operations: BPEMDAS

Physics

Energy

Elastic Potential Energy: [tex]\displaystyle U_s = \frac{1}{2} k \triangle x^2[/tex]

Step 1: Define

k  = 7.50 N/m

Δx = 0.40 m

Step 2: Find Potential Energy

Answer:

Power supplied to the pump is 980000 W or 980 KW

Note: The question is incomplete. The complete question is given below:

On a day with no wind, a fountain in Switzerland propels 30000 kg of water per minute to a height of 140 metres.

a)Calculate the power used in raising the water?

b)The efficiency of the pump which operates the fountain is 70%

calculate the power supplied to the pump?

Explanation:

Efficiency = Power output/Power input * 100%

Power output = work done/ time

where work done = mass * acceleration due to gravity (g) * height

time = 1 minute = 60 seconds

mass of water = 30000 kg, height = 140 meters, g = 9.8 m/s²

Then, work done = 30000 * 140 * 9.8 = 41160000 J

Power output then = 41160000 J / 60 s

Power output = 686000 W

The power input can then be derived from the formula of efficiency

Power input = (Power output * 100)/Efficiency

Power input = (100 * 686000) / 70

Power input = 980000 W

Therefore, power supplied to the pump is 980000 W or 980 KW

Answer:

convergence and trench

Explanation:

LOL

The train has covered 13,500 meters of track.

We don't know its position, because we don't know where it started from, and we don't know how straight the track is.