Answer:
Tosh is correct.Swap the locations of points B and F on the track and gather speed data. If Mac is correct, the speed at F (closer to the start) should be lower. (It will not be, confirming Tosh's claim.)Explanation:
The total energy of the car is continuously being exchanged between potential energy and kinetic energy as the car moves along the track. Neglecting energy loss due to friction, the kinetic energy will be greatest when the potential energy is least, at the lowest point on the track. As a consequence we agree with Tosh that the speed will be greatest at F because it is the lowest point.
__
If the track were modified to move the lowest point nearer the start, say by interchanging points B and F, then data could be gathered to show whose theory is supported. The evidence needed is the speed of the car at the new location of point F. Tosh's argument is supported if the speed at the new point F is substantially the same.
Jeff throws a ball straight up. For which situation is the vertical velocity zero?
a. on the way up
b. at the top
c. on the way back down
d. none of the above
Answer:
b. at the top
Explanation:
At the top of the climb, the vertical velocity of Jeff's throw has a value of zero.
Vertical velocity in this instance is acting against the acceleration due to gravity.
At the top of the thrown, the force of the throw becomes zero and the velocity also becomes zero. As the body finds it way downward, it begins to fall freely. The fall is due to the acceleration due to gravity which is experienced by every object on earth.Intensitatea curentului electric a unui circuit este de 123A iar sarcina electrica este de 1,7C sa se afle intervalul de timp in care este transportata sarcina electrica
The intensity of the electric current of a circuit is 123A and the electric charge is 1.7C to find the time interval in which the electric charge is transported.
Given that,
Current, I = 123 A
Electric charge, q = 1.7 C
To find,
The time interval in which the charge is transported.
Solution,
The electric current is given by electric charge per unit time. So,
[tex]I=\dfrac{q}{t}\\\\t=\dfrac{q}{I}\\\\t=\dfrac{1.7}{123}\\\\t=0.0138\ s[/tex]
So, the required time is 0.0138 seconds.
The two blocks shown below have masses m1 = 400 g and m2 = 600 g. They are connected by a string and lie on a frictionless tabletop. A 3.5 N force is applied to block m2, pulling it to the right. Find the acceleration then find the tension force in the string between two objects
A dog starts at the origin and runs forward at 6m/s for 1.5s and then turns around to fetch the ball by running backward at 7m/s for 3s. If the dog runs back to the origin at 4m/s the how much time has elapsed between the start and when he returns with the ball
Answer:
Total time elapsed between the start and when he returns with the ball is 7.5s
Explanation:
From the question,
- The dog starts at the origin and runs forward at 6m/s for 1.5s. First, we will determine the distance covered while running forward.
From
Speed = Distance / Time
Distance = Speed × Time
Speed = 6m/s
Time = 1.5s
∴ Distance = 6m/s × 1.5s
Distance = 9m
That is, the dog covered a distance of 9m while running forward.
- The dog turns around and runs backward at 7m/s for 3s. Now, we will also determine the distance the dog covered backwards.
Distance = Speed × Time
Speed = 7m/s
Time = 3s
Distance = 7m/s × 3s
Distance = 21m
The dog's displacement from the origin is 21m - 9m = 12m
Now, to calculate how much time has elapsed between the start if the dog runs back to the origin at 4m/s, we will first determine the time the dog spent back to the origin and then add to the time spent for the first two distances.
To get back to the origin, the dog needs to cover 12m
From
Speed = Distance / Time
Time = Distance / Speed
Distance = 12m
Speed = 4m/s
∴ Time = (12m) / (4m/s)
Time = 3s
Therefore, the dog spent 3s to run back to the origin.
Hence, total time elapsed = 1.5s + 3s + 3s
Total time elapsed = 7.5s
The difference between temperature and thermal energy is that___________.
Answer:
Heat vs temperature - Energy Education The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.
Compare between Convex lens and concave lens
Answer:
A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.
If an oceanic plate and a continent plate converge, or push towards each other, which plate will sink under the other one?
Answer:
The oceanic plate will sink under
Explanation:
Due to erosion over time and the sudden shift, the continental plate will rise causing earthquakes, tsunami’s, etc..
Why does a concave lense always form a virtual image?
Answer:
Concave lens spreads out light rays that are then refracted through it.: A concave mirror or a converging lens will only produce a virtual image at a point if the image is located beyond the focal point. By the focal point, we define the point that is more than one focal length away.
Hello, what does the first condition mean?
Answer:
An object at rest is described by Newton's First Law of Motion. An object in static equilibrium has zero net force acting upon it. The First Condition of Equilibrium is that the vector sum of all the forces acting on a body vanishes.
Explanation:
Answer:
see below
Explanation:
the first condition means that the light ray inside the optically denser medium hits the surface of the optically less dense medium.
this in simple words means, light must be travelling from am optically denser medium to an optically less dense medium
hope this helps :)
Calculate the temperature change when 1000J of heat is supplied to 100g of water.
Please explain
Explanation:
Given
heat supplied (Q) = 1000 J
mass(m) = 100 g = 0.1 kg
specific heat capacity of water(s) = 4200 J/kg°C
change in Temperature (dt) = ?
We know we have the relation
Q = m * s * dt
Or, 1000 = 0.1 * 4200 * dt
Or, 1000 = 420 dt
Or, dt = 1000/ 420
Therefore dt = 2.38°
Hope it will help :)
The temperature changes when 1000J of heat is supplied to 100g of water is dt = 2.38°
What is temperature?The average kinetic energy of a system is measured by its temperature. The kinetic energy of a system starts to rise as the particle's velocity increases, which raises the system's temperature.
The energy that is transferred when two bodies with different surface temperatures come in touch is referred to as heat.
The change is when 1000J of heat is supplied to 100g of water.
Given that:
heat supplied (Q) = 1000 J
mass(m) = 100 g = 0.1 kg
specific heat capacity of water(s) = 4200 J/kg°C
Change in Temperature (dt) = ?
We know we have the relation
Q = m x s x dt
Or, 1000 = 0.1 x 4200 x dt
Or, 1000 = 420 dt
Or, dt = 1000/ 420
Therefore, the temperature changes when 1000J of heat is supplied to 100g of water is dt = 2.38°.
To learn more about temperature, refer to the link:
https://brainly.com/question/11464844
#SPJ2
A softball and a baseball are launched from 2 different pitching machines at the same time.
th
Softball
182 g
165 m/sec
Baseball
143 g
112 m/sec
Which of these BEST explains what factors give the baseball and softball different velocities?
O mass and speed
O mass and direction
O speed and direction
O size and mass
A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls collide and stick together. What is their velocity immediately after the collision?
Answer:
8.3m/s
Explanation:
Given parameters:
mass of clay ball = 5kg
Speed of clay ball = 25m/s
mass of clay ball at rest = 10kg
speed of clay ball at rest = 0m/s
Unknown:
Velocity after collision = ?
Solution:
Since the balls stick together, this is an inelastic collision:
m1v1 + m2v2 = v(m1 + m2)
5(25) + 10(0) = v (5 + 10)
125 = 15v
v = 8.3m/s
A friend tells you that objects with more mass fall faster because they
have a stronger gravitational pull to Earth. How can you show your friend
that this is not true?
Answer:
by throwing heavy mass and less mass in vacuum simultaneously.
How much potassium nitrate (KNO3) would dissolve in 50 milliliters of water at 45ºC given that 55g of KNO3 is dissolved in 150mL of water at 45°C.
A. 19.7g
B. 15.1g
C. 18.3g
D. 23.3g
what happens if I increase the height of a skater
Answer:
The higher the skater is the more potential energy he has. As his height decreases, his potential energy decreases and his kinetic energy increases.
Explanation:
Make me BRAINLIST please
Answer:
The higher the skater is the more potential energy he has. As his height decreases, his potential energy decreases, and his kinetic energy increases. ... Explore how the skater's change in speed relates to the potential and kinetic energy of the skater.
Explanation:
(Via Uteach)
Help me I got this photo please
Answer:
Carbon Sink- photosythesis, ocean absorption, fossilization
Carbon Source- combustion, respiration
Explanation:
Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?
element z are isotopes because number of netron are different and number of protons are same
Is work being done on a barbell when a weight lifter is holding the barbell
over his head?
Answer:
Because in order for work to be done on an object, the object must be moving. Why isn't work being done on a barbell when a weight lifter is holding the barbell over his head? Work is maximized when force is applied in the same direction that the object is moving. ... In order to do work faster, more_is required.
Starting from rest, a sprinter reaches his top velocity in 3 seconds. He runs a distance of 24m in 3 seconds. What is his acceleration? (Assume his acceleration is uniform)
Answer:
[tex]a=5.34\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity of a sprinter, u = 0
He runs a distance of 24m in 3 seconds.
We need to find his acceleration. Let a be his acceleration. Using second equation of kinematics to find it.
[tex]s=ut+\dfrac{1}{2}at^2\\\\24=0+\dfrac{1}{2}a(3)^2\\\\a=\dfrac{24\times 2}{9}\\\\a=5.34\ m/s^2[/tex]
So, the acceleration of the sprinter is [tex]5.34\ m/s^2[/tex].
The acceleration of the sprinter from rest to his top speed is 5.33m/s²,
Given the data in the question
Since the sprinter starts from rest,
Initial velocity; [tex]u = 0[/tex]Time taken; [tex]t = 3s[/tex]Distance covered; [tex]s = 24m[/tex]Acceleration; [tex]a = \ ?[/tex]
To determine the acceleration of the sprinter, we use the second equation of motion:
[tex]s = ut + \frac{1}{2}at^2[/tex]
Where s is distance covered, u is initial velocity, a is acceleration and t is time.
We substitute our given values into the equation
[tex]24m = [0 * 3s] + [\frac{1}{2} * a * (3s)^2]\\\\24m = \frac{1}{2} * a * 9s^2\\\\24m = a * 4.5s^2\\\\a = \frac{24m}{4.5s^2} \\\\a = 5.33m/s^2[/tex]
Therefore, the acceleration of the sprinter from rest to his top speed is 5.33m/s²
Learn more: https://brainly.com/question/18835025
find the cp of an article which is sold for rupees 4048 , thereby , making a profit of 15 percent
Answer:
4048 = 115x/100.
Explanation:
Profit P = (15/100) X x.
P= 15x/100.
15x/100 = 4048- x.
4048 = 15x/100 + x.
4048 = 115x/100.
I think this is physics?
A student wants to calculate the density of the two objects shown below:
A Metal Cube and a Small Statue.
Describe the methods that the student should use to calculate the densities of the two objects.
ASAP please this piece of work is already late XD
Answer:
Okay
Explanation:
First we should quickly remind ourselves of the equation for density:density= mass/ volumeTo calculate the density we need a method of measuring the mass of each object and another method for measuring the volume of each object. To measure the mass in both cases we can simply use a measuring balance. To measure the volume we will need to use 2 separate methods. For the cube we can simply measure the length, height and depth with a ruler, multiply our measurements and we obtain the volume. The statue is a little more tricky because it has an irregular shape so we can't use the ruler anymore. Instead we should use graduated tank/trough of water. First of all measure the amount of water in the tank before putting in the statue. Then submerge the statue in the water and take another measurement of the volume of water in the tank. The statue will displace the water in the tank giving a higher value. We finally subtract the initial volume from the final volume and we should obtain the volume of the statue.We now have all the measurements necessary to calculate the density of both objects!
A flight attendant pulls her 70 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 41 N at an angle of 57° above the horizontal.
Complete question :
A flight attendant pulls her 70 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 41 N at an angle of 57° above the horizontal.
(a) Find the work she does on the flight bag.
(b) Find the work done by the force of friction on the flight bag.
(c) Find the coefficient of kinetic friction between the flight bag and the floor.
Answer:
7107 J ; - 7107 J ; 0.55
Explanation:
Given that :
Distance, d = 318m
Applied force = 41 N
θ = 57°
A.) Workdone = Force exerted along direction of motion
Workdone = applied Force * distance * cosθ
Workdone = 41 * 318 * cos57 = 7101.0037
Workdone = 7,101 J
B.) Workdone by force of friction on flight bag:
- 7,101 J (since the body moves at constant velocity)
C.)
Coefficient of kinetic friction (μ) = Frictional force / normal reaction)
μ = F / N
Frictional force, F = Workdone by friction / distance
F = 6200 / 318
F = 19.47N ;
Ff = weight of Flight bag = 70 N
N = Ff - Fsinθ
N = 70 - applied Force sinθ
N = 70 - 41sin57
N = 70 - 34.385493
N = 35.614506
μ = 19.47 / 35.614506
μ = 0.5466873
What state of matter can easily be compressed (squeezed into a much smaller space)? *
gases
solids
solids, liquids, and gases
liquids
Answer:
gases.
Explanation:
gases have the highest volume. if you compress (increase pressure) a gas, the volume decreases and it will take up less space as a liquid, and if you compress more, the liquid will become a solid.
additionally info: this is generally true, but as you get into more difficult subjects, this rule does not hold. for example, some substances cannot obtain a certain phase of matter when they are a certain temperature and or pressure. but that could be way more out of this questions league.
Velocities of two bodies A and B are given in vectors notation as va =i+2j-3k and Vb=3i+2j-k what will be the relative velocity of b with respect to a?
Answer:
[tex]V_{B/A}=2i+2k[/tex]
Explanation:
The relative velocity can be calculated by means of the difference between vector B minus vector A.
[tex]V_{A}=i+2j-3k\\V_{B}=3i+2j-k\\V_{B}-V_{A}=(3-1)i + (2-2)j+(-1-(-3))k\\V_{B/A}=2i+2k[/tex]
HELLLPPPPPPPPPPPPPPPPPP
Answer:
If you going to ask a question ask it accurately.
Explanation:
A force of 2 kN is applied to an object to make it move 3.6 m in the direction of the force. Select the correct value of work done on the object.
Answers to choose from:
1.8J
7200J
7.2J
555.6J
Answer:
W= F × d
W= 2kn × 3.6
W= 7.2 J
Work is measured in Joules!
Why does Farm Bureau and other advocacy organization oppose any mandated labeling of biotech crops?
Answer:
I’m. Nog sure
Explanation:
Have you ever noticed that how much electrical energy is consumed by electrical appliances in your home. Make a chart of all of these appliances with their power in kW and an average use on daily, weekly, and monthly basis. Usually the electrical power is written on most of the appliances or on their packing. Calculate the total consumption of electrical energy in kWh in your home for December, 2020. Find the expected electricity bill for this month, if 1 kWh energy costs Rs 10. Which item consumed most energy during the month
Answer:
A. The expected electricity bill for this month is Rs 18,896.2
B. The item which consumed the most energy during the month is the electric cooker with a total consumption of 1,110Kw/Month
Explanation:
Step 1 - Identify electrical appliances
I only have 8 electrical appliances in my home.
Electric Cooker. Its power rating 3000 Watts (that is 3Kw/h)Refrigerator. Its power rating is 150 Watts (that is 0.15Kw/h)Waterheater. Its power rating is 4000 Watts (that is 4Kw/h)Electric Iron. Its power rating is 1000 Watts (that is 1Kw/h)Led TV. Its power rating is 235 watts (that is 0.235Kw/h)13 Energy-saving Light bulbs at 60 watts which is a total of 780 watts (which is 0.78Kw)Electric Standing Fan. Its power rating is 55 watts (that is 0.055Kw)Washing machine. Its power rating 255 watts (that is 0.255Kw)Step 2 - Assign usage per hour and calculate wattage used /month
The Electric Cooker is used an average of 9 hours/day. This is 270hours/month. Total Kw used per month 3Kw * 270hours = 1,110Kw/MonthThe refrigerator is used 24 hours. That is 0.15Kw *24*30days= 108Kw/MonthThe water heater is used 1 hour every day. That is 4Kw *30days = 120Kw/MonthThe electric Iron is used for 20 Minutes every day.That is 1Kw * 0.34hr *30= 10Kw/MonthThe Led Tv is used for 12hours/day. That is 0.235Kw*12*30=84.6Kw/monthThe bulbs are used for about 18hours/day. That is 0.78kw*18*30= 421.2Kw/monthThe electric standing fan is used for about 18 hours/day. That is 0.055kw*18*30=29.7Kw/monthThe washing machine is used for about 6 hours/week. That is 0.255Kw*4*6=6.12Kw/month
Step 3 - Add up all the Kw used per month and multiply by the cost of 1 Kw
Total Kilowatt Consumed/Month = 1110 +108+120+10+84.6+421.2+29.7+6.12
= 1,889.62Kw/Month
Total cost of energy consumed per month = 1889.62 * Rs 10
= Rs 18,896.2
Cheers!
Jack and Jill decide to run a race. Jack weighs 90 kg and Jill weighs 50 kg. At the end of the race it was decided that Jack and Jill tied so they had the same speed. Which person had more momentum ?
Answer: Jack.
Explanation:
Momentum is defined as the quantity of motion.
For an object that has a mass M, and a velocity V, the momentum is written as:
P = M*V
For this problem, we know that Jack and Jill had the same speed (so they had the same velocity), let's say that this velocity is v.
Then the momentum of Jack will be:
P = 90kg*v
And the momentum of Jill will be:
P = 50kg*v
We can see that Jack will have a larger momentum, and this is because he has a larger mass than Jill, but the same velocity as her.
(97-R) Dos cargas puntuales iguales están separadas por una distancia d. A) ¿Es nulo el campo eléctrico total en algún punto? Si es así, ¿cuál es la posición de dicho punto? B) Repita el apartado anterior suponiendo que las cargas fueran de distinto signo.
Answer:
Explanation:
El campo eléctrico provocado por una carga puntal sobre determinado punto viene dado por la ecuación:
E = K * Q /r² en esa ecuación E es el campo eléctrico (un vector), K es una constante K = 1/4*π*ε₀ Q es la carga que origina el campo, y r la distancia entre la carga y el punto donde se quiere determinar el campo. La fuerza de origen eléctrico y el campo eléctrico van en la dirección de la recta de unión entre carga y punto ( es decir según r) y esta fuerza sera repulsiva o de atracción según que la carga que la origina sea positiva o negativa (respectivamente, ya que en la determinación de fuerza y campo, se asume que se coloca una carga de prueba positiva en el punto ).
Siendo así, si dos cargas elécticas son iguales y están separadas una distancia r ; en el punto medio (r/2) los campos producidos por cada una de las cargas serán de la misma magntud.
Carga Q₁ = Carga Q₂ = Q
E₁ = K * Q₁ / (r/2)² y E₂ = K * Q₂/(r/2)²
Y además tendran direcciones totalmente opuestas, por lo que se anularan
En el segundo caso las cargas son iguales en magntud pero de diferentes signos ( una positiva y la otra negativa ). En este caso los campos eléctricos continuaran siendo de la msma magnitud pero dado que la carga positiva repele la carga de muestra (teorica) y la negativa la atrae los dos campos coinciden en su dirección y resultará una campo de magnitud doble. La dirección del campo será en la tendencia de acercarse a la caga negativa, así si la carga negativa está a la derecha la fuerza de origen eléctrico y el campo van hacia la derecha y si la carga negativa está a la izquierda pues esa será la diercción del campo