7th grade math help me pleaseeee

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[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]3 \: ( \: x + 2 \: )[/tex]

Plugging in the value [tex]x = 5[/tex] in the above expression, we have

[tex] = 3\:( \: 5 + 2 \: )[/tex]

[tex] = 3 \: ( \: 7 \: )[/tex]

[tex] = 3 \times 7[/tex]

[tex] = 21[/tex]

[tex]\sf\pink{PEMDAS\: rule.}[/tex]

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35☂}}}}}[/tex]

Answer: 5 Units

Step-by-step explanation:

Answer:

Sorry for the late response, I had to have lunch.

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Step-by-step explanation:

Have a great summer :)

Answer:

EQUATION: X - 12 = 7X. SOLUTION: X = - 2.

Step-by-step explanation:

First, we do not know the number. When the number is unknown, it is a variable. I chose the variable, "X."

12 less than signals that we subtract 12. So that would be X - 12.

A product of 7 AND that number means we multiply 7 by X. That can be notated as 7X.

12 less than X is EQUAL to the product of 7 and X. So X - 12 = 7X.

To find the solution, we want to know the value of X. Move X to one side of the equation.

X - 12 = 7X

-X           -X

_________

-12     =   6X

Divide both sides by 6 to get X by itself.

X = - 2.

The area of the shaded region is (area of the circle) - (area of the square) - (area of the triangle)

Option A is the correct answer

A triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

The shaded region consists of the area inside the circle but outside the square, as well as the area inside the equilateral triangle but outside the square.

Now,

The area of the circle is πr²

Since the square is inscribed in the circle, the diameter of the circle is equal to the diagonal of the square.

Let's say the side length of the square is s.

By the Pythagorean theorem,

s² + s² = (diameter)²

2s² = (2r)²

s² = r²

The area of the square is s² = r².

The area of an equilateral triangle with side length s is √(3)/4 x s².

Since the side length of the square is equal to the height of the equilateral triangle, the side length of the equilateral triangle is also equal to s.

The area of the shaded region.

= (area of the circle) - (area of the square) - (area of the triangle)

Thus,

The area of the shaded region is (area of the circle) - (area of the square) - (area of the triangle)

Learn more about triangles here:

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Answer:

Step-by-step explanation:

Area of rectangle:

Given:

The area is:

A = (2x - 7)(3x² + 4x) =

   2x(3x² + 4x) - 7(3x² + 4x) =

   6x³ + 8x² - 21x² - 28x =

   6x³ - 13x² - 28x

Answer:

Area of rectangle = 6 x ³ - 13 x ² + 28

step by step explanation

Given That :-

To Find :-

Area of rectangle = Length × Width

Using Formula

Area of rectangle = Length × Width

substitute the values.

Area of rectangle = ( 2 x - 7 ) × ( 3 x ² + 4 )

= 2 x ( 3 x ² + 4 ) - 7 ( 3 x ² + 4 )

= 6 x ³ + 8 x - 21 x ² + 28

= 6 x ³ - 13 x ² + 28

Answer:

105mm

Step-by-step explanation:

To find the rainfall during the month of April simply multiply the number of days in April times the average daily rainfall

Number of days in April: 30

Average daily rainfall: 3.5mm

Rainfall during the month = 30 * 3.5 = 105mm

Answer:

OA . -6

Step-by-step explanation:

correct me if I'm wrong

[tex]R_2[/tex]  is 3 ohms

In a circuit containing two resistors [tex]R_1[/tex] and [tex]R_2[/tex] connected together in parallel, the total resistance [tex]R_T[/tex] is given by;

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}[/tex]              ---------(i)

Make [tex]R_2[/tex] subject of the formula;

=> [tex]\frac{1}{R_2} = \frac{1}{R_T} - \frac{1}{R_1}[/tex]  

=> [tex]\frac{1}{R_2} = \frac{R_1 - R_T}{R_TR_1}[/tex]

=>   [tex]{R_2} = \frac{R_TR_1}{R_1 - R_T}[/tex]       ---------------(ii)

From the question,

[tex]R_1[/tex] = 6Ω

[tex]R_T[/tex] = 2Ω

Substitute these values into equation (ii) as follows;

=> [tex]{R_2} = \frac{2*6}{6 - 2}[/tex]

[tex]{R_2} = \frac{12}{4}[/tex]

[tex]R_2[/tex] = 3Ω

Therefore, the value of [tex]R_2[/tex] = 3 ohms or [tex]R_2[/tex] = 3Ω

Answer: is 3 ohms.

Explanation: edmentum/plato :)

Answer:

11b^3+14b^2+b+9

---------------------------

         b2

Step-by-step explanation:

Answer:

y = 1sin(3x)

Step-by-step explanation:

y = A sin( (2π/ω)x )

A is amplitude = 1

ω is period = 2π/3

------------------------------

y = 1sin( 2π / (2π/3) x)

y = 1sin(3x)

The equation for the graph with a sinusoidal wave, given an amplitude of 1, a period of 2π/3, and a phase shift of 0, is y = sin((2π/3)x).

The equation for a sinusoidal wave can be written as:

y = A * sin(ωx + φ)

In this case, we are given the values of amplitude (A = 1), period (ω = 2π/3), and phase shift (φ = 0).

The amplitude (A) represents the maximum displacement or height of the wave from the center line. In this case, it is 1.

The period (ω) represents the length of one complete cycle of the wave. The period is the reciprocal of the frequency, and in this case, it is 2π/3.

The phase shift (φ) represents any horizontal displacement of the wave. In this case, the phase shift is 0, indicating that the wave starts at its equilibrium position.

Using these values, the equation for the given graph would be:

y = 1 * sin((2π/3)x + 0)

Simplifying it further:

y = sin((2π/3)x)

To learn more about equation click on,

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Answer:

64

Step-by-step explanation:13+51=64

Answer:

its the 2nd one

hope that helps<3

Answer:

jhkkkhj

Step-by-step explanation:

jkjkjkjkj

Answer:

C/3rd one. (y=2x+4)

Step-by-step explanation:

In the equation y=mx+b, m=slope of the line and b=y-intercept. From the graph, we know the y-intercept is 4 so we can write y=mx+4. To find the slope: (0-4)/(-2-0) = (-4)/(-2) = 2. We can replace the m with 2 to get the final equation of y=2x+4 which is also the third answer.

Answer:

X=2, y=-1

Step-by-step explanation:

-4x +8y=-16 equation 1

4x +3y=5 equation 2

     11y=-11 add two equations to eliminate x

y=-1

solve for x by inputting y value into either equation

4x+3y=5

4x+3(-1)=5

4x-3=5

4x=8

x=2

Answer:

1 centimeter

Step-by-step explanation:

nope

Answer: 15

Step-by-step explanation: 5+9+11+12+13+14+17=81

Make an equation based on this and solve for the variable (x)

81+x/8=12

12*8=96

81+x=96

96-81=15

x=15

Answer:

[tex]\sqrt{x+6}[/tex]

Step-by-step explanation:

So, there are a few things we need to go over to graph a function,

When a number is outside of a root, it changes the y value. For example:

y=[tex]\sqrt{x}+6[/tex]

With the +6, y will always be 6 higher than normal.

If it was -6, then y will always be 6 lower than normal.

What if the number is inside the root? Well, it works a little differently.

Instead of changing the y value, it changes the x value. For example:

y=[tex]\sqrt{x+6}[/tex]

So if you put a number in for x, lets say -6, wht would you get?

You would get -6+6=0

The square root of 0 is 0, so when x=-6, y=0

Normally, x would have to equal 0 for the y value to be 0.

So basically, when we see the number isnide of the root, we can think the our x coordinate being subtracted by that number.

This makes since, because if we subtract the +6 from x:

x-(+6)= x-6, and -6 is our x coordinate.

If it was -6 at the start, this would also work:

x-(-6)= x+6. So our x coordinate would start at 6.

Now, lets look at our graph.

As we can see, the x values start at -6, and the y values starts at 0.

This eliminates A and D, since the +6 would change the y value, not the x.

Remember that x-6 would make x a postive 6.

x+6 however, would make x a negative 6.

So we need x+6 in a square root.

This eliminates B, since it has a x-6, making the x coordinate postive 6, not negative 6.

So c is our answer.

Hope this helps!

Answer:

2300 mm^2

Step-by-step explanation:

Answer:

Rate = 10.4%

Step-by-step explanation:

Given :

P = $30000

A = $42520

Interest earned = 42520 - 30000 = $12520

Time = 4years

Find R

     [tex]Interest = \frac{PRT}{100}[/tex]

        [tex]12520 = \frac{30000 \times R \times 4}{100}\\\\12520 = 300 \times 4 \times R\\\\12520 = 1200 \times R\\\\R = \frac{12520}{1200}\\\\R = 10.43 \%[/tex]

Round to 1 decimal place, Rate = 10.4%

Answer:

35 is correct

Step-by-step explanation:

hope this helps.

Answer:

35°

Step-by-step explanation:

Angle ACD is 70°. The little tick marks on the angle mean both sides of the split are the same amount. This means if you divide the angle in half, you will find out what both of them are equal to.

Answer:

116

Step-by-step explanation:

116 is parallel to y so that are the same its called corresponding angles

When a transversal cuts two parallel lines, the corresponding angles are equal.

In the given figure, the corresponding angles are 116° and y

So, they are equal

⇒   y = 116°

Answer:

x = 25

Step-by-step explanation:

Correct question

In a right triangle Sin (40-x)=cos(3x) what is the value of x

Since Sin theta = Cos(90-theta)

Sin (40-x) = Sin(90-3x)

40 - x = 90 - 3x

-x+3x = 90 - 40

2x = 50

x = 25

Hence the value of x is 25

Given the expression below:

[tex] \large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } }[/tex]

Use the following property:

[tex] \large \boxed{ {a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} } }[/tex]

Therefore:

[tex] \large{ \frac{ {7}^{ \frac{3}{2} } }{ {7}^{ \frac{1}{2} } } = \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } } \\ \large{ \frac{ \sqrt{ {7}^{3} } }{ \sqrt{7} } = \frac{ \sqrt{7 \times 7 \times 7} }{ \sqrt{7} } \longrightarrow \frac{7 \sqrt{7} }{ \sqrt{7} } } \\ \large{ \frac{7 \cancel{ \sqrt{7} }}{ \cancel{ \sqrt{7} }} = 7}[/tex]

Note that a¹ = a. Therefore, 7¹ = 7.

Answer

Answer:

What is your question for probabilities?