7Which of the following terms describes how glaciers move?
A Quickly
B Gradually
C Aggressively
D Rapidly

Answers

Answer 1

Answer:

D is the answer  I think (0 w 0 )

Explanation:

Answer 2

The  glaciers move gradually. Hence, option (C) is correct.

What is glacier?

A glacier is a long-lasting mass of heavy ice that is perpetually moving. When the ablation of snow is greater than the accumulation over a long period of time, frequently centuries, a glacier forms.

As it slowly flows and deforms under forces brought on by its weight, it gains distinctive features like crevasses and seracs. Cirques, moraines, and fjords are the result of the erosion of rock and debris from its substrate as it travels.

The considerably thinner sea ice and lake ice that form on the surface of bodies of water are not the same as glaciers, which form only on land and may flow into water bodies.

The huge ice sheets, commonly referred to as "continental glaciers," in the polar areas of the planet contain 99 percent of the planet's glacial ice.

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Related Questions

Plz help this is so confusing

Answers

The correct answer is 5 km/h

Explanation:

The speed at which the duck travels can be found by using the equation that is given (speed= distance/ time). The first step to do this is to replace distance and time using the values given. Here is the process:

speed = distance / time

speed = 10 km / 2 hours

Now, solve this equation

speed = 10 km/ 2 hours

10 / 2 or 10 divided 2 = 5

Finally, use the units, in this case, the correct units are km/h

3.
What is a star? Why does the sun appear so big whereas the other stars do not?
Ans.​

Answers

The sun is a star,The sun appears larger since it’s only 91.4 million miles from earth which in the other hand the other stars are further way so it all has to do with the range of the stars

a student lifts a 15N mass through a distance of 1.5m. whats the works done ?

Answers

Answer:

10N/m

Explanation:

Calculating workdone=Force/Distance

Therefore=15N/1.5m

=10N/m

A 4 kg object moving to the left collides with and sticks to a 3 kg object moving to the right. Which of the following is true of the motion of the combined objects immediately after the collision?

a. They must be moving to the left.
b. They must be moving to the right.
c. They must be at rest.
d. The motion cannot be determined without knowing the speeds of the objects before the collision.

Answers

Answer:

D. The motion cannot be determined without knowing the speeds of the objects before the collision.

Explanation:

This question is tricky! We know the object moving to the left has a greater mass than the one moving to the right. We'd assume they would move to the left because the leftwards object has a greater mass, right?

Not. So. Fast.

We can solve for the objects' final velocity using the formula for momentum, m₁v₁ + m₂v₂ = (m₁ + m₂)v .

Now here's where the trap is sprung: we don't think about the equation. This shows that the final velocity of the objects and the direction depends on both the mass of the objects and their initial velocity.

Basically, what if the 3 kg object is moving at 1 m/s and the 4 kg object is moving at –0.5 m/s? The objects would move to the right after the collision!

Do we know the velocity of these objects? No, right?

That means we can't determine the direction of their motion unless we know their initial, pre-collision velocity. This question is tricky because we look at the 4 kg vs. 3 kg and automatically assume the 4 kg object would dictate the direction of motion. That's not true. It depends on velocity as well.

I hope this helps you! Have a great day!

Waves in the ocean are tearing apart the shoreline. Which of the following two Earth Systems are interacting with each other.

Answers

Answer:

the Indian Ocean on 26 December 2004. This event claimed 227,898 dead and missing from 14 countries. The difference in mortality rates between these tsunamis reflects, in part, the benefits of understanding how tsunami waves are generated and move, and educating citizens to make scientifically

sound and potentially life-saving decisions.

A tsunami is a series of rapidly propagating, shallow-water ocean waves that develops when a submarine earthquake, landslide, or volcanic eruption displaces a large volume of water. Powerful earthquakes, with magnitudes of 9 or greater, caused both the 2004 and 2011 tsunamis. The earthquakes resulted from the movement of large tectonic plates. The 11 March 2011 earthquake occurred at 32 km (20

mi.) deep in Earth’s crust about 130 km (81 mi.) east of the city of Sendai. This location is on the boundary between two tectonic plates—the Pacific plate to the east and North American plate to the west. This

boundary fractured, releasing energy that was transmitted through the rocks and elevated portions of the

ocean floor. This drastic movement transmitted energy to the overlying ocean water, which generated

tsunami waves that radiated outward. The waves washed over the nearby coastlines and were felt around

the globe within hours (Figure 1.1).  

Explanation:

Answer:

I believe Geosphere (lithosphere) and Hydrosphere

Explanation:

I hope it's right if not please notify me.

PLEASE HELP!!!! WILL GIVE BRAINLIEST!!! WORTH 20 PTS!!!!!
Please write the processes and tectonic plate interactions that are causing the geological event to occur. Include an explanation of convection currents.

Answers

Answer:

Explanation:

These tectonic plates rest upon the convecting mantle, which causes them to move. The movements of these plates can account for noticeable geologic events such as earthquakes, volcanic eruptions, and more subtle yet sublime events, like the building of mountains.

Answer:

Tectonic plates recurring over and over again cause a rupture in the Earth's crust. This agitates the magma in volcanoes, causing the volcano to erupt.

Explanation:

Learning task 2: Using the information you gathered from Learning Task 1, make a concept web of the contributions of the following scientist in the DEVELOPMENT OF MAGNETIC THEORY
A. Andre- Marie Ampere
B. Michael Faraday
C. Heinrich Herts
D. James Clerk Maxwell
E. Hans Christian Oersted

Answers

Answer:

The contributions of the following scientist in the DEVELOPMENT OF MAGNETIC THEORY

James Clerk Maxwell Hans Christian Oersted

Explanation:

George Green was the first personality to formulate a mathematical principle of magnetism and electricity and his system created the framework for the work of different scientists such as William Thomson, James Clerk Maxwell, and others. Magnetism is the power exercised by magnets when they drag or deflect each other. Magnetism is produced by the movement of electric charges.

The contributions of James Clerk Maxwell  and Hans Christian Oersted, et al in the DEVELOPMENT OF MAGNETIC THEORY are as follows:

They discovered that the speed at which electromagnetic waves traveled was similar to that of lightThey proved that there was a proportional connection between electricity and magnetism

According to the given question, we are asked to show the contributions which the aforementioned scientists had in the development of the magnetic theory.

As a result of this, we can see that James Maxwell first developed this theory in the nineteenth century and the theory was modified by other scientists who made the framework for the electrical system and magnetism.

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What gases can CFC and HCFC refrigerants decompose into at high temperatures

Answers

Answer:

Hydrochloric and Hydrofluoric Acids.

A beaker with water resting on a scale weighs 40 N. A block
suspended on a hanging spring weighs 20 N. The spring scale
reads 15 N when a block is fully submerged in the water. What is
the reading of a scale on which the beaker with water rests, while
the block is submerged in the water after detached from the
hanging spring?
A. 25 N B. 60 N C. 55 N D. 45 N​

Answers

Answer:

D. 45 N​

Explanation:

The weight of the block is 20 N, when the block is fully immerged in water, it weighs 15 N. Hence the loss of weight = 20 N - 15 N = 5 N.

The loss of weight is as a result of the buoyant force. The buoyant force is the upward force exerted by a fluid when an object is fully or partially immersed in a fluid.

The buoyant force of 5 N acts in the upward direction, the weight of the beaker that would be read by the scale when the beaker is immersed in water = 40 N + 5 N = 45 N

How is the Moon thought to have formed

Answers

Omg I have the same question

Kieran caught 18 more Pokémon on Saturday than
Noah did. Kieran caught 53 Pokémon. Write and solve
an equation to find how many Pokémon, p, Noah
caught on Saturday.

Answers

Answer:

Noah caught 35 Noah on Satuday.

Explanation:

Given that,

Kieran caught 53 Pokemon

Kieran caught 18 more Pokémon on Saturday than  Noah did.

Let Noah caught x Pokémon on Saturday.

ATQ,

18 + x = 53

Thie is the equation that can be used to find the value of x.

Subtract 18 from both sides.

18 + x -18 = 53 - 18

x = 35

Hence, Noah caught 35 Noah on Satuday.

The force of gravity acting on an object is directed through this
center of gravity and toward the center of the

Answers

Explanation:

Every object has a center of gravity. ... The force of gravity acting on an object is directed through this center of gravity and toward the center of the earth. The object's weight, W, can be represented by a vector directed down (along the line the object would fall if it were dropped).

It should be towards the center of the earth.

The following information should be considered:

Each and every object contains the center of gravity. The force of activity acted on an object that director via his gravity center & towards the center of the earth.

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In the picture shown below A represents a characteristic of only geocentric model, B represents a characteristic common to both geocentric and heliocentric models, C represents a characteristic of only heliocentric model, and D represents a characteristic which the geocentric and heliocentric models do not have.
Under which label will the characteristic, "The sun and planets revolve around a central moon in the solar system" fall?
A
B
C
D

Answers

I believe the correct answer is C

A student is drinking a cup of hot chocolate. This method of energy transfer is

Answers

Answer:

conduction I believe if not its convection

Answer: Conduction transfers energy from the spoon to the hot chocolate.

Explanation: Heated water molecules and steam rise in the beaker, carrying heat by convection.

Firemen are shooting a stream of water at a burning building. A high-pressure hose shoots out the water with a speed of 26.0 m/s as it leaves the hose nozzle. Once it leaves the hose, the water moves in projectile motion. The firemen adjust the angle of elevation of the hose until the water takes 3.00 to reach a building 41.0m away. You can ignore air resistance; assume that the end of the hose is at ground level.

Required:
a. Find the angle of elevation of the hose.
b. Find the speed in m/s of the water at the highest point in its trajectory.
c. Find the acceleration in m/s^2 of the water at the highest point in its trajectory.
d. How high above the ground in m does the water strike the building?
e. How fast is it moving in m/s just before it hits the building?

Answers

Answer:

a) θ = 58.3º

b) vfh = 13.7 m/s

c) g = -9.8 m/s2

d) h = 22.2 m

e) vfb = 15.5 m/s

Explanation:

a)

Assuming that gravity is the only influence that causes an acceleration to the water, due to it is always downward, since both directions are independent each other, in the horizontal direction, the water moves at a constant speed.Since the velocity vector has a magnitude of 26.0 m/s, we can find its horizontal component as follows:vₓ₀ = v * cos θ (1)where θ is the angle between the water and the horizontal axis (which we define as the x-axis, being positive to the right).Applying the definition of average velocity, taking the end of the hose like the origin, and making t₀ = 0, we can write the following expression:

        [tex]x_{f} = v_{ox} * t = v_{o} * cos \theta * t (2)[/tex]

Replacing by the givens of xf = 41.0m, t = 3.00 s, and v=26.0 m/s, we can solve for the angle of elevation θ, as follows:

        [tex]cos \theta = \frac{x_{f} }{v*t} = \frac{41.0m}{26.0m/s*3.00s} = 0.526 (3)[/tex]

⇒θ = cos⁻¹ (0.526) = 58.3º (4)

b)

At the highest point in its trajectory, just before starting to fall, the vertical component of the velocity is just zero.Since the horizontal component keeps constant during all the journey, we can conclude that the speed at this point is just v₀ₓ, that we can find easily from (1) replacing by the values of v and cos θ, as follows:vₓ₀ = v * cos θ = 26.0 m/s * 0.526 = 13.7 m/s. (5)

c)

At any point in the trajectory, the only acceleration present is due to the action of gravity, which accepted value is -9.8 m/s2 (taking the upward direction on the vertical y-axis as positive)

d)

Since we know the time when the water strikes the building, it will be the same for the vertical movement, so, we can use the kinematic equation for vertical displacement, as follows:

       [tex]\Delta y = v_{oy} * t - \frac{1}{2} *g*t^{2} (6)[/tex]

Our only unknown remains v₀y, which can be obtained in the same way than the horizontal component:v₀y = v * sin θ = 26.0 m/s * 0.85 = 22.1 m/s (7)Replacing (7) in (6), we get:

       [tex]\Delta y = 22.1 m/s* 3.0s - \frac{1}{2} *9.8m/s2*(3.00s)^{2} = 22.2 m (8)[/tex]

e)

When the water hits the building the velocity vector, has two components, the horizontal vₓ and the vertical vy.The horizontal component, since it keeps constant, is just v₀x:v₀ₓ = 13.7 m/sThe vertical component can be found applying the definition of acceleration (g in this case), solving for the final velocity, as follows:

       [tex]v_{fy} = v_{oy} - g*t (9)[/tex]

Replacing by the time t (a given), g, and  v₀y from (7), we can solve (9) as follows:

       [tex]v_{fy} = 22.1 m/s - 9.8m/s2*3.00s = -7.3 m/s (10)[/tex]

Since we know the values of both components (perpendicular each other), we can find the magnitude of the velocity vector (the speed, i.e. how fast is it moving), applying the Pythagorean Theorem to v₀ₓ and v₀y, as follows:

       [tex]v_{f} = \sqrt{(13.7m/s)^{2} +(-7.3m/s)^{2}} = 15.5 m/s (11)[/tex]

Cecily is inflating her bicycle tyre with the pump below. When she pushes the plunger down, it is doing work against the gas. This means that the plunger is transferring what to the gas particles?

Answers

Energy is being transferred into the gas particles. Since temperature is also being increased due to the increased pressure. Temperature is a measure of the average kinetic energy of particles. Therefore energy transfers to the gas.

The plunger is transferring energy to the gas particles.

What the plunger is transferring to the gas particles?

When Cecily is applying pressure to the plunger, the gas inside is being compressed, and the speed of gas molecules increases.

When these air molecules enter the tire, adiabatically, the temperature of the gas rises.

It happens due to an increase in the average kinetic energy of the gas particles.

Thus, the gas particles receive energy from the plunger.

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Megan walks 1100\,\text m1100m1100, start text, m, end text to the left in 330\,\text s330s330, start text, s, end text. What was her average speed in \dfrac{\text m}{\text s} s m ​ start fraction, start text, m, end text, divided by, start text, s, end text, end fraction?

Answers

Answer:

v = 3.34 m/s

Explanation:

Given that,

Distance, d = 1100 m

Time, t = 330 s

We need to find the average speed of the Megan. It is equal to the total distance divided by total time taken.

[tex]v=\dfrac{1100\ m}{330\ s}\\\\v=3.34\ m/s[/tex]

So, the average speed of Megan is 3.34 m/s.

Answer:

33.3

Explanation:

How many joules does your 1600W electric hair dryer transfer if it takes 1 minutes to dry your hair?
____ joules

Answers

Answer:

96,000joules!!!

Explanation:

Hope this helps u

Small household electrical devices, such as vacuum cleaners, televisions, and floor lamps, each draw a different amount of current, but all require 120 volts to operate. Are the outlets in of a power-strip, then, wired in series or parallel

Answers

Answer:

the selected configuration is PARALLEL

Explanation:

There are two ways to connect electrical circuits.

In series in this type of circuit the equipment is connected to the same line, in this case the current of the circuit circulates through all the inputs is the same, but the voltage in each one is a part of the total voltage, this circuit has the problem that if an appliance is disconnected or damages the power and the entire circuit is interrupted

              V_total = ∑ V_i

In a parallel circuit the equipment is connected in two two cables, for which the current is divided in each branch, the voltage in all the branches is the same, this type of circuit has the advantage that if one equipment is damaged or disconnects the others they can continue working

            V_total = V

Therefore, in consequence of the above, the selected configuration is PARALLEL

A basketball of mass 0.23kg is thrown horizontally against a rigid vertical wall with a velocity of 20m/s. It rebounds with a velocity of 15m/s. Calculate the impulse of the force of the wall on the basketball.

Answers

Answer:

[tex]8.1\:\mathrm{Ns}[/tex]

Explanation:

The impulse-momentum theorem gives the impulse on an object to be equal to the change in momentum of that object. Since mass is maintained, the change in momentum of the basketball is:

[tex]\Delta p = m\Delta v[/tex], where [tex]m[/tex] is the mass of the basketball and [tex]\Delta v[/tex] is the change in velocity.

Since the basketball is changing direction, its total change in velocity is:

[tex]\Delta v = 20-(-15)=35\:\mathrm{m/s}[/tex].

Therefore, the basketball's change in momentum is:

[tex]\Delta p = m\Delta v = 0.23\cdot 35= 8.05=8.1\:\mathrm{kg\cdot m/s}[/tex].

Thus, the impulse on the basketball is [tex]\fbox{$8.1\:\mathrm{Ns}$}[/tex] (two significant figures).

If the force of gravity suddenly stopped acting on planets, they would

A.) spiral slowly towards the sun

B.) continue to orbit the sun

C.) move in straight lines tangent to thier orbits

D.) spiral slowly away from the sun

E.) fly straight away from the sun

Answers

i believe it is C i am not sure

Kiara starts at 4, walks 6 blocks left and 2 blocks right. What is her displacement?

Answers

I think 0 because on a number line, left is negative. 4-6=-2. And -2+2 is 0

The chart below summarizes the forces applied to four different objects.
Which object will experience the greatest acceleration?
A. Z
B. X
C. Y
D. W

Answers

Answer:

C. Y

Explanation:

From Newton's second law of motion, we know that:

       Force = mass x acceleration

So;

      acceleration  = [tex]\frac{Force }{mass}[/tex]  

 Therefore, to have the highest acceleration at a constant force, the mass must be low. Acceleration is inversely proportional to mass.

 

Y has the least mass and it will have the highest acceleration

If 478 watts of power are used in 14 seconds,how much work was done

Answers

Answer:

6692J

Explanation:

Power is defined as the rate at which work is being done.

So,

    Power  = [tex]\frac{workdone}{time }[/tex]  

  Work done  = Power x time

Given parameters:

Power  = 478watts

Time  = 14s

So;

 Work done  = 478 x 14  = 6692J

A uniform disk with mass 35.2 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is stationary. The disk is initially at rest, and then a constant force 34.5 N is applied tangent to the rim of the disk.
a) What is the magnitude v of the tangential velocity of a point on the rim of the disk after the disk has turned through .200 revolution?
b) What is the magnitude a of the resultant acceleration of a point on the rim of the disk after the disk has turned through .200 evolution?

Answers

Answer:

a) v = 1.01 m/s

b) a = 5.6 m/s²

Explanation:

a)

If the disk is initially at rest, and it is applied a constant force tangential to the rim, we can apply the following expression (that resembles Newton's 2nd law, applying to rigid bodies instead of point masses) as follows:

       [tex]\tau = I * \alpha (1)[/tex]

Where τ is the external torque applied to the body, I is the rotational inertia of the body regarding the axis of rotation, and α is the angular acceleration as a consequence of the torque.Since the force is applied tangentially to the rim of the disk, it's perpendicular to the radius, so the torque can be calculated simply as follows:τ = F*r (2)For a solid uniform disk, the rotational inertia regarding an axle passing through its center  is just I = m*r²/2 (3).Replacing (2) and (3) in (1), we can solve for α, as follows:

       [tex]\alpha = \frac{2*F}{m*r} = \frac{2*34.5N}{35.2kg*0.2m} = 9.8 rad/s2 (4)[/tex]

Since the angular acceleration is constant, we can use the following kinematic equation:

        [tex]\omega_{f}^{2} - \omega_{o}^{2} = 2*\Delta \theta * \alpha (5)[/tex]

Prior to solve it, we need to convert the angle rotated from revs to radians, as follows:

       [tex]0.2 rev*\frac{2*\pi rad}{1 rev} = 1.3 rad (6)[/tex]

Replacing (6) in (5), taking into account that ω₀ = 0 (due to the disk starts from rest), we can solve for ωf, as follows:

       [tex]\omega_{f} = \sqrt{2*\alpha *\Delta\theta} = \sqrt{2*1.3rad*9.8rad/s2} = 5.1 rad/sec (7)[/tex]

Now, we know that there exists a fixed relationship the tangential speed and the angular speed, as follows:

        [tex]v = \omega * r (8)[/tex]

where r is the radius of the circular movement. If we want to know the tangential speed of a point located on the rim of  the disk, r becomes the radius of the disk, 0.200 m.Replacing this value and (7) in (8), we get:

       [tex]v= 5.1 rad/sec* 0.2 m = 1.01 m/s (9)[/tex]

b)    

There exists a fixed relationship between the tangential and the angular acceleration in a circular movement, as follows:

       [tex]a_{t} = \alpha * r (9)[/tex]

where r is the radius of the circular movement. In this case the point is located on the rim of the disk, so r becomes the radius of the disk.Replacing this value and (4), in (9), we get:

       [tex]a_{t} = 9.8 rad/s2 * 0.200 m = 1.96 m/s2 (10)[/tex]

Now, the resultant acceleration of a point of the rim, in magnitude, is the vector sum of the tangential acceleration and the radial acceleration.The radial acceleration is just the centripetal acceleration, that can be expressed as follows:

       [tex]a_{c} = \omega^{2} * r (11)[/tex]

Since we are asked to get the acceleration after the disk has rotated 0.2 rev, and we have just got the value of the angular speed after rotating this same angle, we can replace (7) in (11).Since the point is located on the rim of the disk, r becomes simply the radius of the disk,, 0.200 m.Replacing this value and (7) in (11) we get:

       [tex]a_{c} = \omega^{2} * r = (5.1 rad/sec)^{2} * 0.200 m = 5.2 m/s2 (12)[/tex]

The magnitude of the resultant acceleration will be simply the vector sum of the tangential and the radial acceleration.Since both are perpendicular each other, we can find the resultant acceleration applying the Pythagorean Theorem to both perpendicular components, as follows:

       [tex]a = \sqrt{a_{t} ^{2} + a_{c} ^{2} } = \sqrt{(1.96m/s2)^{2} +(5.2m/s2)^{2} } = 5.6 m/s2 (13)[/tex]

A block of mass m = 4.4 kg slides from left to right across a frictionless surface with a speed vi= 8.4 m/s It collides in a perfectly elastic collision with a second block of mass M that is at rest. After the collision, the 4.4-kg block reverses direction, and its new speed is 2.5 m/s What is V, the speed of the second block after the collision?

Answers

Answer:

[tex]v_{2'}=8.1\:\mathrm{m/s}[/tex]

Explanation:

In a perfectly elastic collision, the total kinetic energy of the system is maintained. Therefore, we can set up the following equation:

[tex]\frac{1}{2}m_1{v_1}^2+\frac{1}{2}m_2{v_2}^2=\frac{1}{2}m_1{v_{1'}}^2+\frac{1}{2}m_2{v_{2'}}^2[/tex]

Since the second block was initially at rest, [tex]\frac{1}{2}m_2{v_2}^2=0[/tex].

Plugging in all given values, we have:

[tex]\frac{1}{2}m_1{v_1}^2=\frac{1}{2}m_1{v_{1'}}^2+\frac{1}{2}m_2{v_{2'}}^2,\\\\\frac{1}{2}\cdot4.4\cdot8.4^2=\frac{1}{2}\cdot 4.4 \cdot (-2.5)^2+\frac{1}{2}\cdot 4.4\cdot {v_{2'}}^2,\\\\{v_{2'}}=\sqrt{64.31},\\\\{v_{2'}}\approx\fbox{$8.1\:\mathrm{m/s}$}[/tex]..

I WILL GIVE YOU BRAINLIEST! PLEASE HELP


A daydreaming soccer player takes a 0.47 kg ball to the face experiencing an impact force of 1060.9 N. If the ball hit the
player's face with a speed of 14.5 m/s and bounces off in the opposite direction with the same speed, calculate the time of
impact. Note: The time of impact will be a fraction of a second so answer with at least 5 decimal places

Answers

Answer:

0.00547s

Explanation:

Step one:

given data

mass= 0.4kg

force= 1060.9N

velocity = 14.5m/s

Frome

Ft= mv

substitute

t= mv/F

t=0.4*14.5/1060.9

t=5.8/1060.9

t=0.00547s

what happens if we add a lump of ice to a tumbler containing water? how does heat flow?​

Answers

Answer:

The ice will melt

Heat flows from the water to the ice

Explanation:

If we add a lump of ice to a tumbler containing water, the ice lump will melt in the water.

This is a simple physical change of state from solid to liquid.

At the end both the solid ice and the original liquid maintains the liquid state.

The heat will flow from the ice to the water in the tumbler. Heat generally flows from a body at higher temperature to one with a lower temperature. The water has a higher temperature when compared to the ice. So, heat flows from the liquid water to the ice until thermal equilibrium is reached.

Two spherical objects with a mass of 3.17 kg each are placed at a distance of 2.96 m apart. How many electrons need to leave each object so that the net force between them becomes zero

Answers

Answer:

1.704 × 10¹⁹ electrons

Explanation:

The gravitational force due to the identical masses with mass, m = 3.17 kg at a distance r = 2.96 m from each other is F = Gm²/r².

Since equal number of electrons have to leave both masses, we have a charge q on each mass acting to oppose each other at distance r.

So, the electrical force of repulsion is thus

F'= kq²/r²

For the net force to be zero, the gravitational force of attraction must balance the electrical force of repulsion.

So, F = F'

So,  Gm²/r² = kq²/r²

Gm² = kq²

q² = Gm²/k

taking square root of both sides, we have

q = m√(G/k)

So, substituting the values of the variables into the equation, we have

q = m√(G/k)

= 3.17 kg√(6.67 × 10⁻¹¹ Nm²/kg²/9 × 10⁹ Nm²/C²)

= 3.17 kg√(0.741  × 10⁻²⁰ C²/kg²)

= 3.17 kg × 0.861 C/kg

= 2.73 C

Now, q = ne where n = number of electrons and e = electron charge = 1.602 × 10⁻¹⁹ C

n = q/e

= 2.73 C ÷ 1.602 × 10⁻¹⁹ C

= 1.704 × 10¹⁹ electrons

Consider a simple pendulum consisting of a massive bob suspended from a fixed point by a string. Let T denote the time (the period of the pendulum) that it takes the bob to complete one cycle of oscillation (the time it takes for the pendulum to swing back and forth one time). How does the period of the swing of the simple pendulum depend on the quantities that define the pendulum and the quantities that determine the motion

Answers

Answer:

The period of the swing depends on only the length of the string and not on the mass of the bob and the period of the pendulum depends on only the horizontal component of g.

Explanation:

The period of the swing depends on only the length of the string and not on the mass of the bob. Since the length of the string and the mass of the bob define the pendulum.

Also, the properties that define the motion are the component of the weight of the bob in the horizontal direction which determines the to and fro movement of the bob. So, the period of the pendulum depends on only the horizontal component of g.

So, T = 2π√(l/g) where l = length of pendulum and g = acceleration due to gravity.

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