85,58,72,85,46,93 mean,mode,range,median​

Answer:

y = x + 2

Step-by-step explanation:

Step 1: Find the slope

[tex]m=\frac{y2-y1}{x2-x1} = \frac{6-1}{4-(-1)}=\frac{6}{6} =1[/tex]

Step 2: Substitute the slope and a point in to find y intercept

(6)=(1)(4)+b

6 = 4 + b

b = 2

Step 3: Substitute all the information in

y = x + 2

Therefore the equation for a line that passes through (4,6) and (-1,1) is y = x + 2

Answer:

-0.4 or 2.3

Step-by-step explanation:

simple

each box is 0.1 unit

Answer:

Step-by-step explanation:

The answer is where the graph cuts the x-axis.

I can't see it very well but it looks like x = -0.4 and 2.3.

Answer:

3 / 19

Step-by-step explanation:

Given the following :

ratio of college graduates with a graduate degree to non-college graduates = 1:8

ratio of college graduates without a graduate degree to non-college graduates is 2:3

If college graduate with a degree = A

College graduate without a degree = B

Non-college graduate = C

College graduate to non college graduate = A:C

College graduate without degree to non college graduate = B:C

A:C = 1:8 - - - (1) ; B:C = 2:3 - - - (2)

Combining the two ratios :

To do so : the proportion of non college graduate should be the same in both ratios

To do this, multiply (1) by 3 and (2) by 8

A:C = 3 : 24

B:C = 16 : 24

combining both, we have :

A:B:C = 3:16:24

If one random college graduate is picked, what is the probability that they hold a graduate degree?

Total proportion of college graduate : (college graduates with degree + college graduates without degree)

A + B = (3 + 16) = 19

Proportion who hold a graduate degree = A = 3

Probability = require outcome / Total possible outcomes

Thus :

P = A / (A +B)

= 3/19

Answer:

a² + 2ab + b²

Step-by-step explanation:

Given

(a + b)²

= (a + b)(a + b)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a + b) + b(a + b) ← distribute both parenthesis

= a² + ab + ab + b² ← collect like terms

= a² + 2ab + b²

Answer:

Step-by-step explanation:

77; The formula to calculating the area of a trapezoid is (a+b)/2 * c. a+b are the 2 parallel lines, and c is the height or the altitude. So, it is (10+12)/2 * 7, which is 22/2 * 7 = 11*7=77 :)

Answer:

LM = 2(MP)

Step-by-step explanation:

The radius KN is perpendicular to LM meaning that the line is split in half at the crossing. Review properties of circles to see why this is true.

Since we know this, we can say LM = LP + MP. And LP = MP.

So we can say LM = 2(MP).

Cheers

Answer:

c^(8)

Step-by-step explanation:

(c^5)(c)(c^2)

When the bases are the same, we can add the exponents when multiplying

The implied exponent on c is c^1

c^( 5+1+2)

c^(8)

Answer:

x= 3.43

Step-by-step explanation:

First, use the distributive property and multiply 3 by x and 3 by 2:

3x + 6

next use the distributive property again and multiply 4 by x and -5:

4x - 20

Combine Like terms: 3x + 6 + 4x - 20

3x + 4x = 7x

6 - 20 = -14

Now Add 14 to both sides: 7x - 14 = 10

10 + 14 = 24

Now divide 7 by both sides: 7x = 24

24 / 7 = 3.428571429 = 3.43

Answer:

x=24/7 or 3 3/7

Step-by-step explanation:

3(x+2) + 4(x-5)=10   parenthesis first

3x+6+4x-20=10

7x-14=10               addition on both sides

7x-14+14=10+14

7x=24

x=24/7

check the answer:

3(x+2) + 4(x-5)=10

3(24/7+2)+4(24/7-5)=10

72/7+6+96/7-20=10

168/7-14=10

24-14=10

10=10 correct

Answer:

Ok, when we have an equality, like:

A = B

That says that A is the same as B.

Then if a multiply, divide, add or subtract (or do a lot of other operations) in both sides of the equality, the equality does not change.

I suppose that we start with something like:

(4/3)*x = 2

(i will work with this, because you did not post the actual equations)

the thing that Carrie did is:

She multiplies both sides by 3, and get:

3*(4/3)*x = 2*3

4*x = 6

Now she divides bot sides by 4

4*x/4 = 6/4

x = 6/4 = 3/2.

Now, a simpler step is considerin (4/3) as a number A, then we have:

A*x = 2

Now we divide both sides by A.

A*x/A = 2/A

x = 2/A

and we have A = (4/3) then 1/A = (3/4)

x = 2*(3/4) = 3/2

Answer:

x≥5

Step-by-step explanation:

3(x+15)≤5(x+2)+15

3x+45≤5x+10+15

3x+35≤5x+25

3x-5x≤25-35

-2x≤-10

x≥5

{x:xEx:6,7,8,9,10....}

Hope this helps ;) ❤❤❤

Answer:

Step-by-step explanation:

y = -2/3x + 4

y = 2/3x

2/3x = -2/3x + 4

4/3x = 4

4x = 12

x = 3

y = 2/3(3)

y = 2

(3,2) one solution

option 3

Answer:

scale factor = [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Compare the ratio of corresponding sides, image to original.

scale factor = [tex]\frac{3}{9}[/tex] = [tex]\frac{1}{3}[/tex]

Answer:

3.

Step-by-step explanation:

3x3 =9

1.2 x3=9

Answer:

313/7

Step-by-step explanation:

Here, we are interested in turning the wordings of the statement to numeric values.

We take it one at a time.

Sum of 35 and 1/5(35) = 35 + 7 = 42

This is added to 1/7(11 + 8)

= 1/7(19) = 19/7

So we have;

42 + 19/7 = (294 + 19)/7 = 313/7

Answer:

Compression, stirring, and friction all increase heat

Step-by-step explanation:

I did a lesson on it and got it right

Answer:

-5

Step-by-step explanation:

The coefficient is the number attached to the variable.

Answer:

-3

Step-by-step explanation:

First we need to distribute the -4.

-6x+20+4x=26

-2x+20=26

subtract 20 on both sides

-2x=6

divide out -2

x=-3

Answer:

x = 5 , y = 15

Step-by-step explanation:

You can solve this using substitution.

Let the quantity of cheese wafers be denoted by x and the quantity of chocolate wafers denoted by y

2x + 1y = 25

x + y = 20

These two equations are the answer to part A, (remember to include the above prompt which says what x and y denote).

For part B I used substitution because it was more applicable to the question then addition or elimination.

ACTUAL WORK

Set 2x + 1y = 25 equal to x

x = 25 - y / 2

Replace x with y in the second equation

(25 - y / 2) + y = 20

And solve for y

y = 15

Since we know what y is we can replace y in the second equation and find what x is

x + 15 = 20

Solve for x

x = 5

Answer:

5 Cheese Wafers and 15 Chocolate Wafers

Step-by-step explanation:

Answer:

Step-by-step explanation:

(a+2,b)=(4,5)

Since the points are equal we can equate them to find a

Comparing a + 2 to 4

We have

a + 2 = 4

Send 2 to the right side of the equation

a = 4 - 2

We have the final answer as

Hope this helps you

Step-by-step explanation:

Here,

according to the question,

(a+2, b)=(4,5)

since, they are equal, equating with their corresponding elements we get,

(a+2)=4

or, a= 4-2

Therefore, the value of a is 2.

Also you can find value of b in same way,

b=5.

Therefore, the value of a abd b are 2 and 5 respectively.

Hope it helps...

Answer:

Step-by-step explanation:

Angle 1 and angle 4 are Alternative angles:

Alternative angles are pair of angles on the inner side of each of those two lines but on opposite sides.

∠2-∠2=180  ,∠2=180-62=118

∠4+118=180  ⇒∠4=180-118 ⇒∠4=62 degrees

  ∠1=∠4                  alternative angles        

When [tex]\theta[/tex] terminates in quadrant III, both [tex]\cos\theta[/tex] and [tex]\sin\theta[/tex] are negative, and

[tex]\sin^2\theta+\cos^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac{12}{13}[/tex]

When [tex]\varphi[/tex] terminates in quadrant II, [tex]\cos\varphi[/tex] is negative and [tex]\sin\varphi[/tex] is positive, so

[tex]1+\tan^2\varphi=\sec^2\varphi\implies\sec\varphi=-\dfrac{17}{15}[/tex]

which gives

[tex]\cos\varphi=\dfrac1{-\frac{17}{15}}=-\dfrac{15}{17}[/tex]

[tex]\tan\varphi=\dfrac{\sin\varphi}{\cos\varphi}=-\dfrac8{15}\implies\sin\varphi=\dfrac8{17}[/tex]

Now,

[tex]\sin(\theta+\varphi)=\sin\theta\cos\varphi+\cos\theta\sin\varphi=-\dfrac{21}{221}[/tex]

Answer:

y = 7 when x = -5

Step-by-step explanation:

First go to x = -5

Then go up to where you meet the green line

The y value is 7

y = 7 when x = -5

Answer:

x=o and y= -6

Step-by-step explanation:

12-2x = - 2(y-x)

or,12-2x = -2y + 2x

or, 12 = - 2y + 4x

or, 12/2= 2x - y

or, 2x - y = 6

• 2x -6= y.....eqn_1

-2x=-2y+2x -12

or,4x +2y= -12

or,4x + 2(2x-6)= -12

or, 4x+4x-12=-12

or, 8x= 0

• x= o

putting the value of x in eqn...3

o=(y-0)+6

or, o= y + 6

•y = -6

Answer:

[tex]\huge \boxed{430=2 \times 5 \times 43}[/tex]

Step-by-step explanation:

Using factor tree,

Answer:

[tex]\large\boxed{2, 5, 43}[/tex]

Step-by-step explanation:

                                                          430

                                                      /             \

                                                  215              2

The 2 cannot be factorized anymore, so I will put a small box around it.

                                                          430

                                                      /             \

                                                  215            [tex]\boxed{2}[/tex]

                                                  /  \                

                                             43     5

5 and 43 cannot be factorized any smaller.

                                                          430

                                                      /             \

                                                  215            [tex]\boxed{2}[/tex]

                                                  /  \                

                                             [tex]\boxed{43}[/tex]     [tex]\boxed{5}[/tex]

The prime factorization is the numbers in the boxes, which are 2, 5, and 43.

[tex]\large\boxed{2, 5, 43}[/tex]

Hope this helps :)

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If the formatting is not showing up correctly, please refer to the images of my answer below instead.

Answer:

1. Complex number.

2. Imaginary part of a complex number.

3. Real part of a complex number.

4. i

5. Multiplicative inverse.

6. Imaginary number.

7. Complex conjugate.

Step-by-step explanation:

1. Complex number: is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.

2. Imaginary part of a complex number: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.

3. Real part of a complex number: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.

4. i: a number defined with the property that 12 = -1.

5. Multiplicative inverse: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.

6. Imaginary number: any nonzero multiple of i; this is the same as the square root of any negative real number.

7. Complex conjugate: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.

Answer:

Complex number: is the sum of a real number and an imaginary number: a + bi, where a is a real number and b is the imaginary part.

2. Imaginary part of a complex number: the part of a complex that is multiplied by i; so, the imaginary part of the complex number a + bi is b; the imaginary part of a complex number is a real number.

3. Real part of a complex number: the part of a complex that is not multiplied by i. So, the real part of the complex number a + bi is a; the real part of a complex number is a real number.

4. i: a number defined with the property that 12 = -1.

5. Multiplicative inverse: the inverse of a complex number a + bi is a complex number c + di such that the product of these two numbers equals 1.

6. Imaginary number: any nonzero multiple of i; this is the same as the square root of any negative real number.

7. Complex conjugate: the conjugate of a complex number has the opposite imaginary part. So, the conjugate of a + bi is a - bi. Likewise, the conjugate of a - bi is a + bi. So, complex conjugates always occur in pairs.

Step-by-step explanation:

Answer:

(a) and (a)

Step-by-step explanation:

In both questions the denominator of the rational functions cannot be zero as this would make them undefined. Equating the denominators to zero and solving gives the values that x cannot be.

Given

[tex]\frac{x-3}{(3-x)(2+x)}[/tex]

solve (3 - x)(2 + x) = 0

Equate each factor to zero and solve for x

3 - x = 0 ⇒ x = 3

2 + x = 0 ⇒ x = - 2

x = 3 and x = - 2 are excluded values → (a)

------------------------------------------------------------------------

Given

[tex]\frac{-9x+3}{6x^2+10x-4}[/tex]

solve

6x² + 10x - 4 = 0 ← in standard form

(x+ 2)(6x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

6x - 2 = 0 ⇒ 6x = 2 ⇒ x = [tex]\frac{1}{3}[/tex]

x = [tex]\frac{1}{3}[/tex] and x = - 2 are excluded values → (a)

Answer:

933

Step-by-step explanation:

female : male

x : 1000

x : 4000

1000 x 4 = 4000

3732 : 4000

3732 ÷ 4 = 933

Answer:

1.0625

Step-by-step explanation:

Answer:

−5 < x < 10

Step-by-step explanation:

−6 < x − 1 < 9

Add 1 to all sides

−6+1 < x − 1+1 < 9+1

−5 < x < 10

Answer:

B

Step-by-step explanation:

Add one to everything

-5 < x < 10

Best of Luck!

Answer:

Step-by-step explanation:

Nala's marbles = n

Paul's marbles = 3n

nala loses 5 marbles

so nala's marbles = n - 5

paul buys 10 marbles

so paul's marbles = 3n + 10

Total marbles = 105

so,

n - 5 + 3n + 10 = 105

By transposing,

n + 3n = 105 - 10 + 5

4n = 100

n = 100 / 4

n = 25

Hope this helps

plz mark as brainliest!!!!!!!

Greetings from Brasil...

Real part with real part, complex part with complex part...

(-7 + 3i) - (2 - 6i)

(-7 + 3i) - (2 - 6i) = ((-7 - (+ 2)) + (3i - (- 6i))) = - 5

((-7 - 2) + (3i + 6i))