9x^2+6x factorise fully

[tex]16 - 3 \times 5 {}^{2} \div 5[/tex]

[tex]16 - 3 \times 5 {}^{2} \div 5 {}^{1} [/tex]

[tex]16 - 3 \times 5 {}^{2} \div 5 {}^{ - 1} [/tex]

[tex]16 - 3 \times 5 {}^{2 - 1} [/tex]

[tex]16 - 3 \times 5 {}^{1} [/tex]

[tex]16 - 3 \times 5[/tex]

[tex]16 - 15[/tex]

[tex]1[/tex]

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Answer: P(4) - 4/12,1/3,33%,0.33

Step-by-step explanation:

My teacher went over the answers

Answer:

angle JKL is 21

Step-by-step explanation:

the angle of the two triangles are the same, so (2x + 1) = (3x - 9)

You would then find the x, which equals to 10.

Then replace x with ten with the equation.

9514 1404 393

Answer:

  80.67 fps

Step-by-step explanation:

1 mi/h = 22/15 ft/s

Multiplying this equation by 55, we get ...

  55 mi/h = 1210/15 ft/s = 80 2/3 ft/s ≈ 80.67 ft/s

Answer:

[tex]\frac{x-5}{x+1}[/tex], [tex]x\neq -1, x\neq -9[/tex]

Step-by-step explanation:

x^2 + 4x - 45

= (x+9)(x-5)

x^2 + 10x + 9

= (x+9)(x+1)

So the fraction goes to

[tex]\frac{(x+9)(x-5)}{(x+9)(x+1)}[/tex] which is [tex]\frac{x-5}{x+1}[/tex].

Since the denominator cannot be 0, x^2 + 10x + 9 cannot be equal to 0. Therefore x cannot be -1 or -9.

The area of figure will be;

⇒ 105.56 km²

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The figure is shown.

Now,

The area of figure is find as;

Total area = (12 × 7) + (π × 4² / 4) + (3 × 3)

               = 84 + 3.14 × 4 + 9

               = 93 + 12.56

               = 105.56 km²

Thus, The area of figure will be;

⇒ 105.56 km²

Learn more about the area visit:

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Answer: 22

Step-by-step explanation:

Solve for x

   1/2x + 7 = 18

Combine 1/2 and x.

  x/2+ 7 = 18

Move all terms not containing x to the right side of the equation.

Subtract 7 from both sides of the equation.

  x/2= 18 − 7

  x/2 = 11

Multiply both sides of the equation by 2.

  2 ⋅ x/2 = 2 ⋅ 11

Simplify both sides of the equation.

Cancel the common factor of 2.

  x = 2 ⋅ 11

Multiply 2 by 11.

  x = 22

What was the answer

Answer:D

Step-by-step explanation:

Answer:

Step-by-step explanation:

The are similar. That means that one could have its sides measured in miles and the other measured in a few inches. All three angles could be equal, but they are not congruent.

You need at least one properly placed side to make them congruent.

Answer:

Step-by-step explanation:

1/6 x 1/5 + 1/30

= 1/30 + 1/30

= 2/30

=1/15

Answer:

Proved all parts below.

Step-by-step explanation:

As given ,

|x| = [tex]\left \{ {{x , x\geq 0} \atop {-x, x< 0}} \right.[/tex]

To prove- a) For any real number x , | x | ≥ 0 . Moreover, | x | = 0 ⇒ x = 0

                 b) For any two real numbers x and y , | x | ⋅ | y | = | x y | .

                 c) For any two real numbers x and y , | x + y | ≤ | x | + | y | .

Proof -

a)

As given x is a real number

Also , by definition of absolute value of x , we get

| x | ≥ 0

Now,

if |x| = 0

⇒ x = 0 and -x = 0

⇒ x = 0 and x = 0

⇒ x = 0

∴ we get

| x | = 0 ⇒  x = 0

Hence proved.

b)

To prove - | x | ⋅ | y | = | x y |

As we have,

|x| = [tex]\left \{ {{x , x\geq 0} \atop {-x, x< 0}} \right.[/tex]

|y| = [tex]\left \{ {{y , y\geq 0} \atop {-y, y< 0}} \right.[/tex]

|xy| = [tex]\left \{ {{xy , x,y > 0 and x,y < 0} \atop {-xy, x > 0, y< 0 and x <0 , y > 0}} \right.[/tex]

We have 4 cases : i)  when x > 0 , y > 0

                              ii) when x > 0 , y < 0

                              iii) when x < 0, y > 0

                              iv) when x < 0, y < 0

For Case I - when x > 0 , y > 0

⇒ |x| = x, |y| = y

⇒|x|.|y| = xy

For Case Ii - when x > 0 , y < 0

⇒ |x| = x, |y| = -y

⇒|x|.|y| = -xy

For Case Iii - when x < 0 , y > 0

⇒ |x| = -x, |y| = y

⇒|x|.|y| = -xy

For Case IV - when x < 0 , y < 0

⇒ |x| = -x, |y| = -y

⇒|x|.|y| = (-x)(-y) = xy

∴ we get , from all 4 cases

| x | ⋅ | y | = | x y |

Hence Proved.

c)

To prove - | x + y | ≤ | x | + | y |

Let

|x| = |x + y - y|

    ≥ |x + y| - |y|     ( Triangle inequality)

⇒ |x| + |y| ≥ |x + y|

Hence Proved.

Answer:

[tex]\dfrac{w}{z}=\dfrac{2}{7}[/tex]

Step-by-step explanation:

Given that,

[tex]w=\dfrac{6}{7}[/tex]

z = 3

We need to find [tex]\dfrac{w}{z}[/tex].

Put w = 6/7 and z = 3 in the w/z

[tex]\dfrac{w}{z}=\dfrac{\dfrac{6}{7}}{3}\\\\=\dfrac{6}{7}\cdot\dfrac{1}{3}\\\\=\dfrac{2}{7}[/tex]

So, [tex]\dfrac{w}{z}=\dfrac{2}{7}[/tex]. Hence, the correct answer is 2/7.

Answer:

im taking a nap

Step-by-step explanation:

Answer: 829 3/4 or 829 75/100

Step-by-step explanation:

Answer:

don't know

.....................

Answer:

x = 12

Step-by-step explanation:

Consider three orthogonal triangles (see picture)

1. The smallest triangle

2. The medium triangle

3. The big triangle that holds both triangles.

All are orthogonal (or right triangles) so you can use Pythagoras Theorem:

"The area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides"

Use Pythagoras theorem on triangle 1.

[tex]a^{2} = 3^{2} + 6^{2} = 45[/tex]

Now user Pythagoras on triangle 2.

[tex]b^{2} = x^{2} + 6^{2} = x^{2} + 36[/tex]

Now use Pythagoras on triangle 3 (the big triangle).

[tex](3 + x )^{2} = a^{2} + b^{2}\\x^{2} + 6x + 9 = a^{2} + b^{2}[/tex]

Now replace the values for [tex]a^{2}[/tex] and [tex]b^{2}[/tex] from the two equations derived from triangle 1 and 2:

[tex]x^{2} + 6x + 9 = 45 + x^{2} + 36[/tex]

The two [tex]x^{2}[/tex] get cancelled out, so:

[tex]6x + 9 = 45 + 36\\x = 12[/tex]

TA DA!

Answer:

70-25=45

45+25=70

Step-by-step explanation:

Answer:

17 units

Step-by-step explanation:

Use distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex], to find the distance between (-9, 5) and (8, 5):

Let,

[tex] (x_1, y_1) = (-9, 5) [/tex]

[tex] (x_2, y_2) = (8, 5) [/tex]

Plug in the values into the distance formula:

[tex] d = \sqrt{(8 - (-9))^2 + (5 - 5)^2} [/tex]

[tex] d = \sqrt{(17)^2 + (0)^2} [/tex]

[tex] d = \sqrt{(289 + 0)} [/tex]

[tex] d = \sqrt{289} [/tex]

[tex] d = 17 [/tex]

Step-by-step explanation:

[tex]x ^{1} = - 5 \\ y ^{1} = - 2 \\ x {}^{2} = - 2 \\ y {}^{2} = 1 \\ then \: you \: solve \: with \: that \: formula \: you \: know[/tex]

Answer:

15%

5%

24%

40%

32%

80%

32%

54%

60%

66%

9%

89%

Step-by-step explanation:

Answer:

yeah I would say deal #1 is better

Answer:

a)  f(5) = 24

b) The inverse of given function

              f⁻¹ ( x ) = √x+1

c)    f⁻¹ ( 8 ) = √9 =3

Step-by-step explanation:

Explanation:-

Given  f(x) = x² - 1

a)

      f(5) = 5² -1 = 25-1 =24

b)      

put y =  f(x) = x² - 1

   ⇒   y =  x² - 1

 ⇒     x² = y + 1

⇒     x = √y+1

⇒ f⁻¹ ( y ) = √y+1      ( ∵ f⁻¹ ( y) =x)

The inverse of given function

              f⁻¹ ( x ) = √x+1

c)   put x=8

             f⁻¹ ( 8 ) = √8+1 = √9 =3

Answer:

29.8÷3=9.93333333333

Step-by-step explanation:

*note* the 3 is a repeating number

Answer: The answer is -19.5

Step-by-step explanation: This is because 1/2 is .5 in decimal form. A negative PLUS a positive = is negative since the -20 is larger than .5

Answer:

the answer would be -19.5 :)

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

-3/4

Step-by-step explanation:

-1 1/4 = -5/4

1/2 = 2/4

-5 + 2 = -3

-3/4

Answer: The answer is -3/4

Step-by-step explanation: covert the mixed numbers to improper fractions, then find the LCD and combine.

Solution :

Days :              0           1        2         3         4          5        6         7

Probability : 0.68     0.05   0.07   0.08   0.05    0.04   0.01    0.02

This is a valid probability distribution.

In the question it is given that call for a response of Y for short of a sample of people aged between 19 years to 25 years.

Also the event that describes the value of call for response greater than 3 i.e. (Y < 3) is a randomly chosen people between the age 19 to 25 years old who has gone to fitness center or did exercise fewer than 3 days.

Valid probability models add up to 1

The probability is a valid probability model

The probability model is given as:

Days :              0           1        2         3         4          5        6         7

Probability : 0.68     0.05   0.07   0.08   0.05    0.04   0.01    0.02

To determine if the model is a valid probability model, or not

We make use of:

[tex]\mathbf{\sum P(x) = 1}[/tex]

So, we have:

[tex]\mathbf{0.68 + 0.05 + 0.07 + 0.08 + 0.05 + 0.04 + 0.01 + 0.02 = 1}[/tex]

Add the probabilities

[tex]\mathbf{ 1= 1}[/tex]

The above equations shows that:[tex]\mathbf{\sum P(x) = 1}[/tex]

Hence, the probability is a valid probability model

Read more about probability models at:

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Answer:

18/3 is 6

-18/3 is -6

-18/(-3) is 6

18/(-3) is -6

Answer:

1/6 of the tomatoes

Step-by-step explanation:

So first, after she uses 5/9 she has 1 - 5/9 = 4/9 of her tomatoes left. Then, she uses 5/8 of that 4/9 to make a salad, so she used 5/8 * 4/9 = 5/18 of her tomatoes overall.  That means that she has 4/9 - 5/18 = 8/18 - 5/18 = 3/18 = 1/6 of her tomatoes saved.

Answer:

2 and 21/32

Step-by-step explanation: