A 0.82-in-diameter aluminum rod is 5.5 ft long and carries a load of 3000 lbf. Find the tensile stress, the total deformation, the unit strains, and the change in the rod diameter.

Answers

Answer 1

Answer:

Tensile stress = 0.1855Kpsi

Total deformation = 0.0012243 in

Unit strain =  1.855 *10^-5   or  18.55μ

Change in the rod diameter = 5.02 * 10^ -6 in

Explanation:

Data given: D= 0.82 in

                   L = 5.5 ft * 12 = 66 in

load (p) = 3000 (Ibf) /32.174 = 93.243 Ibm

Area = (π/4) D² = (π/4) 0.82²  = 0.502655 in²

∴ Tensile stress Rt = P/A = 93.243/0.502655 = 185.50099 pound/in²

                           Rt = 0.1855 Kpsi

∴ Total deformation = PL / AE = Rt * L/ Eal

                                 = 0.1855 * 10³  * 66 / 10000 * 10³

                                 = 0.0012243 in

∴the unit strains = total deformation / L = 0.0012243/ 66

                          =0.00001855 = 1.855 *10^-5

                         = 18.55μ

∴ Change in rod   Δd/ d = μ ΔL/L

                           = (0.33) 1.855 *10^-5 * 0.82

                           = 5.02 * 10^ -6 in


Related Questions

______ is not a type of digital signaling technique

Answers

Answer:

Data Rate Signaling

what the different methods to turn on thyrister and how can a thyrister turned off​

Answers

Answer:

forward voltage triggering

temperature triggering

dv/dt triggering

light triggering

gate triggering

Then turning off;

Turn off is accomplished by a "negative voltage" pulse between the gate and cathode terminals

Explanation:

hope it helps

A systems analyst is concerned that the current authentication system may not provide the appropriate level of security. The company has integrated WAYF within its federation system and implemented a mandatory two-step authentication system. Some accounts are still becoming compromised via phishing attacks that redirect users to a fake portal, which is automatically collecting and replaying the stolen credentials.
Which of the following is a technical solution that would BEST reduce the risk of similar compromises?
A. Security awareness training
B. Push-based authentication
C. Software-based TOPT
D. OAuth tokens
E. Shibboleth

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The answer in photo
Don't forget put heart ♥️

determine if the fluid is satisfied​

Answers

is there a picture or something?

On calculating which of the following quantities , does the body have an effect in simple projectile motion?​

Answers

Answer:

Force is a kinetic quantity. Force = m x a. Hence, the mass of the body has an effect on force calculation.

I want to explain what 2000 feet looks like to young children so that they can imagine it in class

Answers

Answer:

maybe take a really common toy kids play with or often see, find the average height for the toy and do the math to see how many of those toys stacked ontop of eachother would make up 2000 feet. For example (this isn't accurate btw just an idea of what it would sound like but) "Have you ever seen a barbie doll? well if you stack 400 barbie dolls ontop of their head it would be equal to 2000 feet."

Explanation:

sometimes taking common or beloved objects children have into your examples makes them have a better image of how small or how big something is.

Report of invertor to convert 12 volt to 220 volt.

Answers

Sorryyyy I need points

Which statement describes the relay between minerals and rocks ?

Answers

Answer:

•○●□■hey hi!■□●○•

Explanation:

Minerals and rocks are the same. Aggregates of minerals form rocks. Minerals determine the texture of a rock. Most rocks are made of a single mineral type.

☆♡hope this helps♡☆

When exchanging information with anyone involved in the collision, you should _____.

Answers

Try to be as relax as possible.

Provide names of all parties involved.

Provide vehicle information and identification details.

Provide full names, address, registration numbers and insurance company details.

Explanation:

After a collision one may be confused, afraid and have no attention about the details that what happened because all the collision event happens in a short interval of time. So the first thing one should do during information exchange is to sit back and relax and be calm so that one can remind the things at some extent. After that provide all the details about injured people and the involved vehicles.

When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point

Answers

The question is incomplete. The complete question is :

The solid rod shown is fixed to a wall, and a torque T = 85N?m is applied to the end of the rod. The diameter of the rod is 46mm .

When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point?

Solution :

Given data :

Diameter of the rod : 46 mm

Torque, T = 85 Nm

The polar moment of inertia of the shaft is given by :

[tex]$J=\frac{\pi}{32}d^4$[/tex]

[tex]$J=\frac{\pi}{32}\times (46)^4$[/tex]

J = 207.6 [tex]mm^4[/tex]

So the shear stress at point  A is :

[tex]$\tau_A =\frac{Tc_A}{J}$[/tex]

[tex]$\tau_A =\frac{85 \times 10^3\times 12 }{207.6}$[/tex]

[tex]$\tau_A = 4913.29 \ MPa$[/tex]

Therefore, the magnitude of the shear stress at point A is 4913.29 MPa.

State three types of maintenance.​

Answers

Answer:

Tradicionalmente, se han distinguido 5 tipos de mantenimiento, que se diferencian entre sí por el carácter de las tareas que incluyen:

Explanation:

Mantenimiento Correctivo: Es el conjunto de tareas destinadas a corregir los defectos que se van presentando en los distintos equipos y que son comunicados al departamento de mantenimiento por los usuarios de los mismos.

Mantenimiento Preventivo: Es el mantenimiento que tiene por misión mantener un nivel de servicio determinado en los equipos, programando las intervencions de sus puntos vulnerables en el momento más oportuno. Suele tener un carácter sistemático, es decir, se interviene aunque el equipo no haya dado ningún síntoma de tener un problema.

Mantenimiento Predictivo: Es el que persigue conocer e informar permanentemente del estado y operatividad de las instalaciones mediante el conocimiento de los valores de determinadas variables, representativas de tal estado y operatividad. Para aplicar este mantenimiento, es necesario identificar variables físicas (temperatura, vibración, consumo de energía, etc.) cuya variación sea indicativa de problemas que puedan estar apareciendo en el equipo. Es el tipo de mantenimiento más tecnológico, pues requiere de medios técnicos avanzados, y en ocasiones, de fuertes conocimientos matemáticos, físicos y/o técnicos.

Mantenimiento Cero Horas (Overhaul): Es el conjunto de tareas cuyo objetivo es revisar los equipos a intervalos programados bien antes de que aparezca ningún fallo, bien cuando la fiabilidad del equipo ha disminuido apreciablemente de manera que resulta arriesgado hacer previsiones sobre su capacidad productiva. Dicha revisión consiste en dejar el equipo a Cero horas de funcionamiento, es decir, como si el equipo fuera nuevo. En estas revisiones se sustituyen o se reparan todos los elementos sometidos a desgaste. Se pretende asegurar, con gran probabilidad un tiempo de buen funcionamiento fijado de antemano.

Mantenimiento En Uso: es el mantenimiento básico de un equipo realizado por los usuarios del mismo. Consiste en una serie de tareas elementales (tomas de datos, inspecciones visuales, limpieza, lubricación, reapriete de tornillos) para las que no es necesario una gran formación, sino tal solo un entrenamiento breve. Este tipo de mantenimiento es la base del TPM (Total Productive Maintenance, Mantenimiento Productivo Total).

A recessed luminaire bears no marking indicating that it is ""Identified for Through- Wiring."" Is it permitted to run branch-circuit conductors other than the conductors that supply the luminaire through the integral junction box on the luminaire?

Answers

Answer:

No it is not permitted

Explanation:

It is not permitted  because as per NEC 410.21 policy no other conductor is allowed to be passed through integral junction box luminaries unless such conductor supply recessed luminaries.

The marking will show that the Luminaries is of the right construction or right installation to ensure that the the conductors ( in the outer boxes ) will not be exposed to temperatures greater than the conductor rating, hence the lack of marking makes it not to be permitted.

Question in Statistics and Probability 2

Petrol samples were taken at three different stations along a national highway to determine whether the octane rating varied from one station to another. Six petrol specimens of the same category were randomly selected at each station in different days. We are interested to know if there is sufficient evidence to indicate a difference in the mean octane rating at the different stations.
 
State the Null and the Alternative Hypotheses. 

Answers

I have this questions For a confidence level of 80% with a sample size of 21, find the critical t value answer key then u can help?

Write the different professions and human resources related to engineering and expalin any two of them?

Answers

Answer:

some of the professions and human resource related to engineering are:

Aerospace engineerAgricultural engineer Electrical engineer computer engineerproject Manger construction site engineer/supervisor

Aerospace engineering involves the study, design and development of spacecrafts using Core science principles.

Electrical engineering involves the study and application of core science principles especially physics and mathematics into providing Electrical related solutions

Explanation:

Engineering is a major branch of applied science. In general Engineering is concerned with the design and building of engines ( i.e. application of scientific/science facts   )

some of the professions and human resource related to engineering are:

Aerospace engineerAgricultural engineer Electrical engineer computer engineerproject Manger construction site engineer/supervisor

Aerospace engineering involves the study, design and development of spacecrafts using Core science principles.

Electrical engineering involves the study and application of core science principles especially physics and mathematics into providing Electrical related solutions

Plexiglas, polymethylmethacrylate (PMMA), is often used as display windows and cases in art galleries and museums. If its flame imparts 32 kW/m^2 to the surface when it burns estimate the energy release rate of a 3 m^2 square sheet (one side). Assume its vaporization temperature is 350°C. Calculate with units, provide work.

Answers

This question is incomplete, the complete question is;

Plexiglas, polymethylmethacrylate (PMMA), is often used as display windows and cases in art galleries and museums. If its flame imparts 32 kW/m^2 to the surface when it burns estimate the energy release rate of a 3 m^2 square sheet (one side). Assume its vaporization temperature is 350°C. Calculate with units, provide work.

a ⇒ [tex]q_{rad[/tex] = σT⁴, where σ = 5.67 × 10⁻¹¹ kW/m².K⁴

b ⇒ [tex]q"[/tex] = [tex]q_{flame[/tex] -  [tex]q_{rad[/tex]

c ⇒ [tex]m"[/tex] =  [tex]q"[/tex]/L, where L = 1.6 kJ/g

d ⇒ Q =  [tex]m"[/tex] × A × ΔHc, where ΔHc is 24.9 kJ/g

Answer:

a) [tex]q_{rad[/tex] = 8.54 kW/m²

b) [tex]q"[/tex] = 23.46 kW/m²

c) [tex]m"[/tex] = 14.6625 g/m²

d) Q = 1095.2888 kJ

Explanation:

Given the data in the question;

[tex]q_{flame[/tex] = 32 kW/m²

Area; A = 3m²

vaporization temperature; T = 350°C = ( 350 + 273 )K = 623 K

Now,

a) ⇒ [tex]q_{rad[/tex] = σT⁴, where σ = 5.67 × 10¹¹ kW/m².K⁴

we substitute

[tex]q_{rad[/tex] = ( 5.67 × 10⁻¹¹ kW/m².K⁴ ) × ( 623 K)⁴

[tex]q_{rad[/tex] = ( 5.67 × 10⁻¹¹ kW/m².K⁴ ) × 150644120641 K⁴

[tex]q_{rad[/tex] = 8.54 kW/m²

b) ⇒ [tex]q"[/tex] = [tex]q_{flame[/tex] - [tex]q_{rad[/tex]

we substitute

[tex]q"[/tex] = 32 kW/m² - 8.54 kW/m²

[tex]q"[/tex] = 23.46 kW/m²

c) ⇒ [tex]m"[/tex] =  [tex]q"[/tex]/L, where L = 1.6 kJ/g

we substitute

[tex]m"[/tex] =  23.46 / 1.6

[tex]m"[/tex] = 14.6625 g/m²

d) ⇒ Q =  [tex]m"[/tex] × A × ΔHc, where ΔHc is 24.9 kJ/g

we substitute

Q =  14.6625 × 3 × 24.9

Q = 1095.2888 kJ

If the constant is added to every observation of data then arithmatic mean obtained is

Answers

Answer:

Explanation:

Increased by the constant. Take a very simple case.

4  +  5 +  6 = 15

The mean is 5  (obtained by dividing the total (15) by the number of terms (3).

Now add a constant say 6

4 + 6 = 10

5 + 6 = 11

6 + 6 = 12

Total = 33/3 = 11

So the mean 5 is increased by the constant 6.

Now do the same thing more symbolically.

4 + c

5 + c

6 + c

Total = 15 + 3c

Divide by 3 you get 5 + c

If you want a more formal proof involving n terms, leave a note.

Consider CO at 500 K and 1000 kPa at an initial state that expands to a final pressure of 200 kPa in an isentropic manner. Report the final temperature in units of K and using three significant digits.

Answers

Answer:

[tex]T_2=315.69k[/tex]

Explanation:

Initial Temperature [tex]T_1=500K[/tex]

Initial Pressure [tex]P_1=1000kPa[/tex]

Final Pressure [tex]P_2=200kPa[/tex]

Generally the gas equation is mathematically given by

[tex]\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{n-1}{n}}[/tex]

Where

n for [tex]CO=1.4[/tex]

Therefore

[tex]\frac{T_2}{500}=\frac{200}{1000}^{\frac{1.4-1}{1.4}}[/tex]

[tex]T_2=315.69k[/tex]

Hãy trình bày các bộ phận chính trong một bộ điều khiển điện tử (ECU) dùng trên ô tô. Cho biết công dụng của từng thành phần.

Answers

Answer:

sorry but I can't understand this Language.

Explanation:

unable to answer sorry

The secondary coil of a step-up transformer provides the voltage that operates an electrostatic air filter. The turns ratio of the transformer is 41:1. The primary coil is plugged into a standard 120-V outlet. The current in the secondary coil is 1.2 x 10-3 A. Find the power consumed by the air filter.

Answers

Answer:

  5.9 watts

Explanation:

The secondary voltage is the primary voltage multiplied by the turns ratio:

  (120 V)(41) = 4920 V

The power is the product of voltage and current:

  (4920 V)(1.2·10^-3 A) = (4.92)(1.2) W = 5.904 W

The power consumed is about 5.9 watts.

A 40kg steel casting (Cp=0.5kJkg-1K-1) at a temperature of 4500C is quenched in 150kg of oil (Cp=2.5kJkg-1K-1) at 250C. If there are no heat losses, what is the change in entropy of?
(i) The casing.
(ii) The oil.
(iii) Both considered.

Answers

Of the oil I hope this help

Which of the following is not a category of electrical burns

Answers

Which of the following is NOT a category of electrical burns Answer: Shock

Question 1 of 8.
What should you do to drive safely in the station?
Turn on your hazard lights
Roll your windows down and turn off the radio
Maintain idle speed (below 5mph)
All of the above
Mark for follow up

Answers

Answer: all of the above

Explanation:

To drive safely in the station, the correct option is D. All of the above.

It should be noted that when a person is driving, it's essential for the person to drive carefully in a station.

One should not smoke in a station. Also, it's important that the driver should turn on their hazard lights

Furthermore, it's important for one to roll their windows down, turn off the radio and also maintain idle speed.

In conclusion, the correct option is D.

Read related link on:

https://brainly.com/question/18889428

8.50 nC of charge is uniformly distributed along a thin rod of length L = 9.20 cm, which is then bent into a semicircle. What is the magnitude of the electric field at the center of the circle​

Answers

The answer would be 8.65

once scientist has asked a question conducted an investigation and analyzed the data his or hwr goalis to​

Answers

Answer:

hola

Explanation:

Explanation:

so its an question?..........

The following laboratory test results for Atterberg limits and sieve-analysis were obtained for an inorganic soil. [6 points] Sieve analysis Sieve Size No. 4 (4.75 mm) No. 10 (2.00 mm) No. 40 (0.425 mm) No. 200 (0.075 mm) Percent passing by weight 80 60 30 10 Atterberg limits Liquid limit (LL) Plastic limit (PL 31 25
(a) Classify this soil according to USCS system, providing the group symbol for it. Show how you arrive at the final classification.
(b) According to USCS system, what is a group name for this soil?
(c) Is this a clean sand? If not, explain why.

Answers

Answer: hello the complete question is attached below

answer:

A) Group symbol = SW

B) Group name = well graded sand , fine to coarse sand

C) It is not a clean sand given that ≤ 50% particles are retained on No 200

Explanation:

A) Classifying the soil according to USCS system

 ( using 2nd image attached below )

description of sand :

The soil is a coarse sand since  ≤ 50% particles are retained on No 200 sieve, also

The soil is a sand given that more than 50% particles passed from No 4 sieve

The soil can be a clean sand given that fines ≤ 12%

The soil can be said to be a well graded sand because the percentage of particles passing through decreases gradually over time

Group symbol as per the 2nd image attached below = SW

B) Group name = well graded sand , fine to coarse sand

C) It is not a clean sand given that ≤ 50% particles are retained on No 200

Tech A says that the voltage regulator controls the strength of the rotor s magnetic field. Tech B says that the voltage regulator is installed between the output terminal of the alternator and the positive terminal of the battery. Who is correct?

Answers

Answer:

Voltage Regulator

Technician A is correct.

Explanation:

Technician B is not correct.  The voltage regulator is not installed between the output terminal of the alternator and the positive terminal of the battery as claimed by Technician B.  Technician A's opinion that the voltage regulator controls the strength of the rotor's magnetic field is correct.  The computer can also be used to control the output of the alternator by controlling the field current.

1) (30 pts ) Oxygen (O2) flows through a pipe, entering at at 4 m/sec at 10000 kPa, 227oC. For a pipe inside diameter of 3.0 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas

Answers

Complete Question

Nitrogen (N2) flows through a pipe, entering at at 4 m/sec at 1000 kPa, 2270C. For a pipe inside diameter of 3 cm, find the volumetric flow rate (m3/sec) and the mass flow rate of the gas (kg/sec) assuming you have an ideal gas Then using your ideal gas mass flow rate find the rate at which enthalpy enters the pipe (kJ/sec) NO Cp, Cv, k permitted

Answer:

[tex]H=9.91kJ/sec[/tex]

Explanation:

From the question we are told that:

Velocity [tex]v=4 m/sec[/tex]

Pressure [tex]P=1000kPa[/tex]

Temperature [tex]T=227 \textdegree C[/tex]

Diameter [tex]d=3cm=>0.03m[/tex]

Generally the equation for volumetric Flow Rate is mathematically given by

[tex]V_r=(\frac{\pi*d^2}{4}v)[/tex]

[tex]V_r=(\frac{\pi*(0.03)^2}{4} *4)[/tex]

[tex]V_r=0.002827m^3/s[/tex]

Generally the equation for mass Flow Rate is mathematically given by

[tex]m_r=\frac{PV_r}{RT}[/tex]

[tex]m_r=\frac{1000*0.002827}{0.297*(227+273)}[/tex]

[tex]m_r=0.019kg/sec[/tex]

Generally the equation for mass Flow Rate is mathematically given by

Using gas Table for enthalpy Value

[tex]T=500K=>h=520.75kg[/tex]

Therefore

[tex]H=mh[/tex]

[tex]H=0.019*520.75[/tex]

[tex]H=9.91kJ/sec[/tex]

Flat plate collector can provide temperature upto_____​

Answers

Answer:

80⁰C

Explanation:

80°C.

Normal flat plate collectors can deliver heat at temperatures up to 80°C. Deficiency rates for normal flat plate collectors can be classified as visual losses, which produce with cumulative angles of the incident sunshine, and thermal losses, which upsurge fast with the working temperature intensities

State the factor that influence the frequency of the induced emf of an alternating quantity

Answers

Explanation:

conductor, flux, and movement of conductor in magnetic field are some of the factors that induce emf.

1025 steel wire is stretched with a stress of 70 MPa at room temperature 20 C. If th length is held constant, to what temperature in 'C and 'F must the wire be heated to reduce the stres to 17 MPa?

Answers

Check attached pictureCheck attached pictureCheck attached pictureCheck attached picture

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