A 0.98 gram sample of a volatile liquid was heated to 348 k. the gas occupied 265 ml of space at a pressure of 0.95 atm. what is the molecular weight of this gas?

Answers

Answer 1

Answer:

The molecular weight is [tex]Z = 111.2 \ g/mol[/tex]

Explanation:

From the question we are told that

   The mass of the sample is  [tex]m = 0.98 \ g[/tex]

    The temperature is  [tex]T = 348 K[/tex]

    The volume which the gas occupied is  [tex]V = 265 \ ml = 265 *10^{-3} L[/tex]

     The pressure is  [tex]P = 0.95 \ atm[/tex]

Generally from the ideal gas equation we have that

       [tex]PV = n RT[/tex]

Here n is the number of moles of the gas while the R is the gas constant with value  [tex]R = 0.0821 \ atm \cdot L \cdot mol^{-1} \cdot K^{-1}[/tex]

        [tex]n = \frac{PV}{ RT}[/tex]

=>      [tex]n = \frac{ 0.95 * 265 *10^{-3} }{ 0.0821 * 348}[/tex]

=>      [tex]n = 0.00881 \ mol[/tex]

Generally the molecular weight is mathematically represented as

          [tex]Z = \frac{m}{n}[/tex]

=>      [tex]Z = \frac{0.98 }{0.00881}[/tex]

=>      [tex]Z = 111.2 \ g/mol[/tex]


Related Questions

what are 4 sources of electrical energy?

Answers

Answer:

Clean Energy. Learn more about energy from solar, wind, water, geothermal, biomass and nuclear. Fossil. Learn more about our fossil energy sources: coal, oil and natural gas.Electric Power. Learn more about how we use electricity as an energy source. Energy Storage. Hydrogen & Fuel Cells.

Explanation:

I hope this helps xD

Answer:

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A 25 cm sample of dilute sulfuric acid contains 0.025 moles of the acid.
What is the hydrogen ion concentration in the solution?
A. 0.2 mol/dm3
B. 0.05 mol/dm3
C. 1.00 mol/dm3
D. 2.00 mol/dm3

Answers

Answer:B. 0.05 mol/dm3

Explanation:

The hydrogen ion concentration in the solution is 2 mol/dm³

The correct answer to the question is Option D. 2 mol/dm³

We'll begin by calculating the molarity of the solution.

Volume = 25 cm³ = 25 / 1000 = 0.025 dm3

Mole of H₂SO₄ = 0.025 mol

Molarity of H₂SO₄ =?

Molarity = mole / Volume

Molarity of H₂SO₄ = 0.025 / 0.025

Molarity of H₂SO₄ = 1 mol/dm³

Finally, we shall determine the concentration of Hydrogen ion in the solution.

H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)

From the balanced equation above,

1 mole of H₂SO₄ contains 2 moles of H⁺.

Therefore,

1 mol/dm³ H₂SO₄ will also contain 2 mol/dm³ H⁺.

Thus, the concentration of Hydrogen ion in the solution is 2 mol/dm³

The correct answer to the question is Option D. 2 mol/dm³

Learn more: https://brainly.com/question/3655413

Calculate the amount of heat, in Joules, needed to raise 34.0g of water from 55.0°C to 76.0*C. The specific heat of water is 4.18 J/gºC.

Answers

Answer:

2984.52J

Explanation:

Using the formula: Q = m × c × ∆T

Where;

Q = amount of heat (in Joules)

m = mass (in grams)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Based on the information provided in the question;

m = 34.0g

c = 4.18 J/gºC.

Initial temperature = 55.0°C

Final temperature = 76.0°C

Hence, Q = m × c × ∆T

Q = 34 × 4.18 × (76 - 55)

Q = 142.12 × 21

Q = 2984.52J

Therefore, 2984.52J is the amount of heat, in Joules, needed to raise 34.0g of the water.

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