a 1,402-kg car rounds an unbanked curve with a radius of 53 m at a speed of 9.9 m/s. what minimum coefficient of friction must exist between the road and tires to prevent the car from slipping?

The system that is more energy efficient is system A because it makes use of electricity to produce more results.

Energy efficiency is the use of less energy to perform the same task or produce the same result.

Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.

Energy efficiency has the following benefits:

According to this question, the following applies:

Based on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.

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Answer:

To make a simple model of the solar system that can be used to compare the time it would take for a spaceship to travel between different planets, the student must accurately represent the relative distances between the planets. This is because the time it would take for a spaceship to travel between two planets depends on the distance between those planets, so accurately representing the distances between the planets is essential for thinking about how long it would take for a spaceship to travel between them.

It is not necessary for the student to make sure that the model of each planet looks like the planet it represents, although this may help make the model more understandable. The most important thing is that the model accurately represents the relative distances between the planets.

In summary, the student must accurately represent the relative distances between the planets in order to think about how long it would take for a spaceship to travel between different planets in the solar system.

Answer:

Below

Explanation:

Normal force will be   mg cos 15° = 1.5*9.81 cos 15°   Newtons

Downplane force will be  mg sin 15° = 1.5 * 9.81  sin 15°    N

Acceleration

F = ma

F/m = a

1.5 ( 9.81) sin 15° / 1.5   m/s^2  = a

Answer:

24 A

Explanation:

Ohm's Law:  V = IR, so I = V/R

I = 120V/5Ω = 24 A

The time period of the small oscillations for the simple pendulum is found to be  3.14 seconds.

The pendulum is located in an elevator that is accelerating upwards with an acceleration of 6m/s² and length of the pendulum is 4m.

Because the elevator is accelerating in the upper direction the net acceleration of the pendulum will be (10 + 6)m/s².

The period of small accelerations for this pendulum will be given by the relation,

T = 2π(l/a)

Where,  l is the length of pendulum and a is the net acceleration.

Putting values,

T = 2π(4/16)

T = 2π(1/2)

T = π seconds.

T = 3.14 seconds.

So, the time period of this small oscillations for this pendulum is 3.14 second.

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The kinetic energy is 939.87 J.

Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.

A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.

Kinetic energy = 1/2mv²

Kinetic energy =  1/2×0.06×177²

Kinetic energy = 939.87 J.

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According to the given statement 16.7kg  is the mass of the sculpture.

The lowest frequency that could be produced by a particular instrument is known as the fundamental frequency. The fundamental frequency is also known as the instrument's first harmonic.

Use the string's tautness' fundamental frequency as a formula.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = The string's tension equals Mg.

M is a symbol for the substance's mass (sculpture)=?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= string length divided by mass gives the string's density.

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

95= 1/(2*0.9) √(T/0.0056)

171= √(T/0.0056)

Square both sides

29241= T/0.0056

T= 163.74 N

Recall that T =Mg

163.74= M * 9.8

M=163.74/9.8

M= 16.7kg

Consequently, the sculpture weighs 16.7kg.

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The magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.

Magnitude is a measure of the size or intensity of a physical quantity. It is usually defined as the absolute value of the numerical value of the physical quantity, and is often expressed in terms of a unit of measurement. Magnitude can refer to a variety of different physical quantities, such as size, intensity, brightness, or energy. Magnitude can also refer to the relative size or intensity of two or more physical quantities, when compared to each other.

The resultant force on the horizontal gate is equal to the sum of the hydrostatic forces acting on the gate.
Since the gate is horizontal, the hydrostatic forces acting on the gate will be equal to the pressure difference between the top and bottom of the gate.
This pressure difference is equal to the product of the fluid density, gravitational acceleration, and the gate width.
Therefore, the magnitude of the resultant force on the gate will be:
F = w * r * g
The location of the resultant force on the gate will be at the center of the gate, which is point A.
Therefore, the magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.

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The second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.

To determine the location of the second weight that will keep the meter stick balanced, we need to consider the principles of equilibrium.

The weight of the meter stick can be calculated as follows:

Weight of meter stick = mass * acceleration due to gravity

= 24 g * 9.8 m/s^2

= 235.2 N

The total weight of the two hanging weights is 96 g + 96 g = 192 g = 1.92 N.

The sum of the forces acting on the meter stick is equal to zero when:

235.2 N + 1.92 N = 0

This equation tells us that the sum of the forces acting on the meter stick is equal to zero when the total weight of the two hanging weights is equal to the weight of the meter stick.

To determine the location of the second weight, we also need to consider the moments about the pivot point. The moment of a force is calculated as the product of the force and the distance from the pivot point. The moments about the pivot point are equal to zero when the sum of the moments of the forces on one side of the pivot point is equal to the sum of the moments of the forces on the other side of the pivot point.

The moment of the weight of the meter stick about the pivot point is calculated as follows:

Moment of the weight of meter stick = force * distance from pivot point

= 235.2 N * 0.4 m

= 94.08 N*m

The moment of the weight hanging from the 9 cm mark about the pivot point is calculated as follows:

Moment of weight hanging from 9 cm mark = force * distance from pivot point

= 1.92 N * 0.09 m

= 0.1728 N*m

To keep the meter stick balanced, the moment of the second weight must be equal in magnitude but opposite in direction to the moment of the weight hanging from the 9 cm mark. The moment of the second weight can be calculated as follows:

Moment of second weight = force * distance from pivot point

= 1.92 N * distance from pivot point

Substituting the value of the force and setting the moment equal to the negative of the moment of the weight hanging from the 9 cm mark, we get the following equation:

1.92 N * distance from pivot point = -0.1728 N*m

Solving for the distance from the pivot point, we find that the second weight must be located at a distance of 0.09 m from the pivot point, or 9 cm. This is the same distance from the pivot point as the weight hanging from the 9 cm mark.

Therefore, the second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.

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The fast is the height of the pile increasing when the pile is feet high 0.1989 ft/min.

Calculation:

Here given the rate of change in volume DV/DT = 40 actions and we need the rate of change in height when height h = 16.

Putting all values.

40 = π/4 x (16)² x DV/DT

= DV/DT= 40 x 4/ 1×16×16

0.1989 ft/min.

Rate of change in height when height is 16 H is equal to 0.1989 ft/min.

The goal is to get a text from as many modalities as possible so that models trained on The Pile have broader generalization capabilities. For stakes, experts believe it comes from the Latin word pira. Pila loosely translates to the ball. If you've ever seen inflamed hemorrhoid, you'll understand this moniker better. Many hemorrhoids actually look like small round spheres.

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W = -500 J is the work, which is why it's negative because a woman is doing it.

Briefing

The heat transfer into the system,

Q = 9500 J, makes it positive.

(a) Heat and work are added to determine the change in internal energy, which is:

ΔU = Q+W

We replace with:

ΔU = 9500 J-500 J

ΔU = 9000 J\s(b) (b) The quantity of useful work completed given a total energy supply is now what is generally referred to as an efficiency. From this, we may divide the woman's labour by the shift in internal energy, giving us

=  500 j / 9000 j.

We get:

ϵ = 0.0556~ 5.56%

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Mass of the fertilizer bag is 165.82 kg

According to Newton's law,

F = m*a

So, m= F/a

m= 131/0.790

m= 165.82 kg

Mass is the measure of matter of a body.

Newton has stated three laws of motion. The first law states that every object will remain at rest or in uniform motion in a straight line unless an external force compels it to change its state of action .

The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.

The third law states that every action has an equal and opposite reaction.

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Most photons that leave the sun's surface have a surface temperature of 6,000 K, which corresponds to the visible light region of the electromagnetic spectrum.

The electromagnetic spectrum is a continuous range of wavelengths and frequencies that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The wavelengths and frequencies of these different types of electromagnetic radiation are all different and correspond to different regions of the spectrum.

The visible light region of the electromagnetic spectrum is the portion of the spectrum that can be seen by the human eye. It ranges from about 400 nanometers (nm) to about 700 nm in wavelength, and corresponds to frequencies of about 7.5 x 10^14 Hz to about 4.3 x 10^14 Hz. Photons with wavelengths and frequencies in this range have enough energy to excite the photoreceptors in the human eye, allowing us to see them.

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The required values are a) T = 2.3 seconds, b)  f = 0.434 Hz, c) ω = 2.7 rd/s.

Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.

Given,

Time = 11.5 seconds to five complete vibrations.

a) Time period is time taken to complete one vibration,

So T = 11.5/5 = 2.3 seconds

b) Frequency(f) = 1/T

f = 1/2.3 = 0.434 second inverse.

c) By using formula of angular frequency ω = 2π/T

ω = 2π/2.3 = 2.7 hz

Thus, final values are a) T = 2.3 seconds, b)  f = 0.434 second inverse, c) ω = 2.7 rd/s.

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All galaxies outside the Local Group are moving away from us, and the farther away they are, the faster they're going.

We may learn a lot about the nature of the cosmos from Hubble's rule, which states essentially that a known universe velocity (or, as it is commonly displayed, its redshift) is precisely proportionate to its distance. The relationship between distance and speed should not exist if the cosmos is constant and unchanging.

The Hubble-Lemaître law, commonly referred to as Hubble's law, is the finding in astrophysics that planets are eloping from Earth at rates proportionate to their separation. In other words, they are travelling away from Earth more quickly the more away they are.

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Only a decreasing gravitational force that acts downward will apply on the ball that is tossed straight up from the surface of a small, spherical asteroid with no atmosphere.

Hence,

Only a decreasing gravitational force that acts downward will apply on the ball that is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid.

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The required force is F = 3240 N.

As a result,

1200 kg is the car's mass.

Initial speed of the vehicle, u = 0.

The car's final speed is 27 meters per second.

Thus we have to first calculate the acceleration and then substitutes its value in the force formula

Taking time, t = 10 s

F = m a, where a represents the vehicle's acceleration, is the formula for the required force.

a= v - u / t

thus a = 27 - 0/ 10

a = 27/ 10

F = 1200 X 27 / 10

F = 3240 N.

Therefore, this is the necessary solution.

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The kind of spring should be held constant so as to improve the validity of the experiment.

Hooke's law states that the force that acts on a spring is directly proportional to the extension of the spring as long as the elastic limit is not exceeded.

As such, we can now understand that we can only be able to talk about the Hooke's law if there is no way in which the material has passed the elastic limit of the material. In this case, we are told that the students just embarked on a kind of experiment and they want to be able to verify the validity of the Hooke's law.

We saw that the masses that were hanged were increased but the springs were also changed. This would not allow us to determine the force constant and the Hooke's law accurately.

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4.71 s long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot.

The average position of an object's weight is known as its center of gravity. Any object's travel through space may be entirely explained in terms of how its gravitational center moves from one location to another and, if it is free to spin, how it rotates around that center of gravity. Calculations combining gravitation and dynamics may be made much simpler by treating an object's mass as though it were concentrated at a single location.

T=2π√(l/g)

T=2π√(5.53/9.81)

T=4.71

T =4.71 s

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The speed of the bullet before it strikes the rod is 67 m/s. To determine the speed of the bullet before it strikes the rod, we need to consider the conservation of angular momentum.

The moment of inertia of a thin rod about its center is given by the following formula:

where I is the moment of inertia, m is the mass of the rod, and L is the length of the rod.

Substituting the values given in the problem, we find that the moment of inertia of the rod is

In this case, the bullet strikes the rod, transferring some of its linear momentum to the rod in the form of angular momentum. The change in angular momentum of the rod is equal to the angular momentum of the bullet.

We can use the conservation of angular momentum to write the following equation:

where I1 is the initial moment of inertia of the rod, w1 is the initial angular velocity of the rod, J is the angular momentum of the bullet, I2 is the final moment of inertia of the rod, and w2 is the final angular velocity of the rod.

Since the initial angular velocity of the rod is zero, we can simplify the equation as follows:

J = I2 * w2

Substituting the values given in the problem, we find that the angular momentum of the bullet is

To determine the speed of the bullet before it strikes the rod, we need to consider the bullet's mass and the angle at which it strikes the rod. The mass of the bullet is given as 3.0 grams, which is equivalent to 0.003 kg. The angle at which the bullet strikes the rod is given as 60 degrees.

We can use the following formula to calculate the speed of the bullet before it strikes the rod:

Substituting the values given in the problem, we find that the speed of the bullet before it strikes the rod is (6.7 kg*m^2/s / 0.003 kg) * sin(60 degrees) = 67 m/s. This is the final answer.

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Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.

What results from the triple-alpha procedure as the finished product?

The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.

Which statement concerning alpha particles in an atom is accurate?

Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.

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Answer:

Here is answer

Explanation:

a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.

b) The characteristics of the weight of solid 'S' are:

It acts in the downward direction.

It is a gravitational force that is exerted by the Earth on the solid 'S'.

It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).

c) The weight of solid 'S' can be represented by a vector as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

[/asy]

a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.

b) These forces can be represented by vectors as shown below:

[asy]

unitsize(1cm);

draw((0,0)--(0,15),Arrow(6));

label("$W$", (0,7.5), W);

draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));

label("$N$", (7.5sqrt(2),7.5), NE);

draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));

label("$F_f$", (-7.5sqrt(2),-7.5), SW);

[/asy]

c) The characteristics of these forces are:

The normal force acts perpendicular to the surface of the inclined plane.

The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.

The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.

The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.

a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.

b) The characteristics of the gravitational force are:

It acts in the downward direction.

It is a force that is exerted by the Earth on the solid 'S'.

Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):

[asy]

unitsize(1cm);

draw((0,0)--(0,-1.3),Arrow(6));

label("$W$", (0,-0.65), S);

[/asy]

The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.

The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.

A car travels down a road at a certain velocity, is Vcar.

Let the initial velocity of the car travel downward be -V car

It is also, given, that the driver slows down so that the car is traveling only half as fast as before.

Resulting velocity = -1/2 vcar

Therefore, the correct option is c. -1/2vcar.

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Relative to the observer in on the shore, the velocity of the boat is 6.5 m/s, NE.

What is relative velocity?

The velocity of an object in relation to another observer is known as its relative velocity.

We cay say that the relative velocity is equal to the vector difference between the velocities of two objects. The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.

The diagram below shows the calculation where AC is relative speed, AB is speed of the boat and BC is the speed of stream.

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Answer:

2515.7N

Explanation:

First step is to find the acceleration:

U = 0 and V =58.7 m/s

a = (V-U)/t

where, t = 3.5s

a = 58.7/3.5

so, in order to find the net force,

F= ma

= 150kg × 58.7/3.5

= 2515.7 N

(a) The normal force is 267.7 N and frictional force is 980 N.

(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.

(c) The direction of the contact force is 1016 N.

∈(t) = 0

N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )

N₂ = 267.7 N

(a) Normal force F(d) = N₂ = 267.7 N

Frictional force N = 800 + 180

                         N = 980 N

(b) The minimum coefficient of static friction,

F(d) = μ N₁

μ = F / N₁

μ = 267.7 / 980

μ = 0.27

(c) The direction of the contact force,

R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]

R = 1016 N

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Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N

The maximum height an object will reach if it is thrown vertically upwards at 24.0 m/s will be equal to 29.35 meters.

Kinetic energy is the term used in physics to describe the force that a moving item has.

It is described as the amount of effort necessary to accelerate anybody with a particular mass from rest to a given velocity. Except for variations in speed, the body retains the kinetic energy it gains during acceleration.

As per the given information in the question,

The formula of kinetic energy is,

K.E = 1/2 mv²   (i)

The formula of gravitational potential energy is,

u = mg     (ii)

Equate equations (i) and (ii)

1/2 mv² = mgh

h = 1/2 v²/g

h = 1/2 (24)²/9.81

= 576/19.62

h = 29.35 meters.

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The heater needs to provide 540 W of power just to make up for the heat lost through this one wall.

Styrofoam is a trademarked brand of foam insulation and craft material manufactured by the Dow Chemical Company. It is made from expanded polystyrene (EPS) beads that are fused together with steam and pressure. EPS is a lightweight and rigid material that is used for insulation, packaging, and soundproofing. Its properties make it an ideal material for crafting, floristry, model building, and other art projects. Styrofoam is stable in most environments and is resistant to water, oil, and most chemicals. It can be cut, shaped, and painted easily and is an excellent thermal insulator. In addition, it is also non-toxic and non-carcinogenic, making it a safe and economical choice for many applications.

Assuming that the wall is a perfect insulator, the heater will have to provide enough power to make up for the heat lost due to conduction and convection. The rate of heat loss per unit area is given by:

Q = λ*A*(T2 - T1)/d
Where:
λ = thermal conductivity of styrofoam (see table above)
A = Area of wall (3*3) = 9 m2
T2 = Temperature inside the house (25C)
T1 = Temperature outside the house (0C)
d = thickness of styrofoam insulation (2.5 cm)

Plugging in the values we get:
Q = 0.045*9*(25-0)/0.025 = 540 W
Therefore, the heater needs to provide 540 W of power just to make up for the heat lost through this one wall.

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Answer:

a

Explanation:

As you add thermal energy the particles spread apart and are moving faster ..... a certain volume of water produces a much larger volume of steam as energy is added.....that is how steam engines work !