Answer:
The value is [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m_1 = 5.0 \ g = 0.005 \ kg[/tex]
The net charge is [tex]q = 3.8 \mu C= 3.8 *10^{-6} \ C[/tex]
The mass of the second object is [tex]m_1 = 2.0 \ g = 0.002 \ kg[/tex]
Generally for the first object the potential energy gained at the end of its acceleration is equal to its kinetic energy
i.e
[tex]\frac{ 1}{ 2} * m_1 * v^2_1 = q_1 * \Delta V \ \ --- (1)[/tex]
Here [tex]v_1[/tex] is the velocity of the first object
[tex]\Delta V[/tex] is the potential difference through which it is accelerated
Generally for the second object the potential energy gained at the end of its acceleration is equal to its kinetic energy
i.e
[tex]\frac{ 1}{ 2} * m_2 * v^2_2 = q_2 * \Delta V[/tex]
Here [tex]v_2[/tex] is the velocity of the second object and from the question it is
[tex]v_2 = 2 v_1[/tex]
[tex]\Delta V[/tex] is the potential difference through which it is accelerated
So
[tex]\frac{ 1}{ 2} * m_2 * (2v)^2_1 = q_2 * \Delta V[/tex]
=> [tex]m_2 * 2v^2_1 = q_2 * \Delta V \ \ ---(2)[/tex]
Generally dividing equation 2 by equation 1
[tex]\frac{2m_2 v^2_1 }{ \frac{1}{2} * m_1 * v_1^2} = \frac{q_2 \Delta V }{ q_1 * \Delta V}[/tex]
=> [tex]q_2 = \frac{4m_2 * q_1 }{m_1}[/tex]
=> [tex]q_2 = \frac{4* 0.002 * 3.8 *10^{-6} }{0.005}[/tex]
=> [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
=> [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
Which of the following is the cause of an acceleration?
[tex]{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}[/tex]
[tex]\longrightarrow[/tex] The rate of change of velocity per unit time is called acceleration.
[tex]\longrightarrow[/tex] Its SI unit is m/s².
[tex]\huge\boxed{\fcolorbox{blue}{red}{Thank you}} [/tex]
we have that from the Question"Which of the following is the cause of an acceleration?" it can be said that
Acceleration cause bodies to move at an increasing rate after which a velocity or speed is maintained Force is a main cause of Acceleration andacceleration is seen at a change in velocityFrom the Question we are told
Which of the following is the cause of an acceleration?
Generally the equation for acceleration is mathematically given as
[tex]a=\frac{F}{m}\\\\or\\\\a=\frac{u-v}{dt}\\\\[/tex]
Therefore
Acceleration cause bodies to move at an increasing rate after with a velocity or speed is maintained Force is a main cause of Acceleration andacceleration is seen at a change in velocitySo in the selection of the option consider these points of acceleration
Acceleration cause bodies to move at an increasing rate after which a velocity or speed is maintained Force is a main cause of Acceleration andacceleration is seen at a change in velocityFor more information on this visit
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what two charactoristic are needed to describe a force
Answer:
An applied force, A resistive force
Explanation:
An applied force is an interaction of one object on another that causes the second object to change its velocity.
A resistive force passively resists motion and works in a direction opposite to that motion.
what is mean by combination reaction ?
[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]
Those reaction in which two or more substances combine to form a one new substance are called Combination reaction
In this reaction, We can add :
Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.[tex] \underline{\green{\large \sf For\: example :}} [/tex]
[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]
In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.
A 96 kg man lying on a surface of negligible friction shoves a 75 g stone away from himself, giving it a speed of 7.2 m/s. What speed does the man acquire as a result?
Answer:
7.21m/s
Explanation:
Using the law of conservation of momentum expressed as;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the mass of the man and the stone respectively
u1 and u2 are their respective initial velocities
v is their final common velocity
Given
m1 = 96kg
m2 = 75g = 0.075kg
u1 = ?
u2 = 0m/s (initial speed of the stone)
v = 7.2m/s
Substitute into the firmula and get u1
96u1 + 0.075(0) = (96 + 0.075)(7.2)
96u1 = 96.075(7.2)
u1 = 691.74/96
u1 = 7.21m/s
Hence the man acquired a speed of 7.21m/s
A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?
Answer:
50 km/h
Explanation:
200 km = 4 hours
200/4=50
50km/h
which property of an object is not changed by a force
it is easier to climb up a slanted slope than a vertical slope
Answer:
Yes, it is easier to climb a slanted slope than a vertical or more steep slope.
Explanation:
On a vertical slope, you are climbing higher instead of farther so on each step gravity weighs you down much more than on a gentle slope
A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kinetic frictional force is equal to 70 N. Calculate the acceleration of the piano for an applied force of 100 N.
Answer:
a = 0.1 m/s²
Explanation:
If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:[tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]
By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:[tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]
Solving for a:[tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]
TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”
In an open circuit like the picture
A. the light bulb will produce light
B. a resistor controls the flow of current
C. the light bulb will be off
D. current will flow
In an open circuit like the picture the light bulb will be off. So, option (C) is correct.
What is electric circuit?Electric circuit is a way for current to flow through electricity. An electric circuit consists of a source of energy for the charged particles that make up the current, like a battery or generator; sources of current-using equipment, like lamps, electric motors, or computers; and the connecting wires or transmission lines.
Ohm's law and Kirchhoff's rules are two of the fundamental mathematical laws that define how electric circuits function.
In the given diagram, the circuit is open. So, no current passes through it and the light bulb will be off. Hence, option (C) is correct.
Learn more about electric circuit here:
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WILL MARK BRAINLIEST JUST PLEASE HELP
Answer:
40N in either direction is the answer
calculate the net force
250N left force and right force is 150N
Answer
100N on the left force
Explanation:
You have to subtract 250 - 100 and the reamaining would be 100 and that 100 would go to the left force since it was the higher number
A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force
Answer:
F = 6[N].
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 10 [kg]
v = velocity [m/s]
F = force [N]
t = time = 5 [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 10 [kg]
v₁ = velocity of the object before the impulse = 1 [m/s]
v₂ = velocity of the object after the impulse = 4 [m/s]
[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]
