A 67 kg man stands at the front end of a uniform boat of mass 179 kg and of length, L = 2.5 m. Assume there is no friction or drag between the boat and water.
(a) What is the location of the center of mass of the system when the origin of our coordinate system (i) on the man's original location (ii) on the back end of the boat? [4 marks]
(b) If the man walks from the front end to the back end of the boat, by how much is the boat displaced? [3 marks]
(c) Now consider the man and his friend with identical mass of 67 kg are rowing the boat on a hot summer afternoon when they decide to go for a swim. The man jumps off the front of the boat at speed 3 m/s and his friend jumps off the back at speed 4 m/s. If the boat was moving forward at 1.5 m/s when they jumped, what is the speed of the boat after their jump?

Answers

Answer 1

Answer:

Explanation:

ai. com=(67*0+179*1.25)/(179+67)=0.91m

ii. com=(67*2.5+179*1.25)/(179+67)=1.59m

b. 0.91=(67(2.5-d)+179(1.25-d))/(179+67)

   d=0.68m

c. 1.5=(67*-3+67*-4+179*v)/(67+67+179)

    v=5.24m/s

Answer 2

The answers to your question are ;

A) Location of the center of the mass of system when origin of coordinate system is

i) On the original location of man = 0.91 m

ii) On back end of boat = 1.59 m

B) The boat is displaced by = 0.68 m

C) speed of boat after their jump ( V ) = 5.24 m/s

Given data :

mass of man = 67 kg

mass of boat = 179 kg

length of boat = 2.5 m

assumptions : No friction/drag force

Solutions

A) determine location of center of mass

i) On the man's original location = 0

= ( mass of man * 0 + mass * 1.25 ) / ( mass of boat + mass of man)

=  ( 0 + 179 * 1.25 ) /  ( 179 + 67 )

= ( 0 + 223.75 ) / ( 246 ) = 0.9096  ≈ 0.91 m

ii) On the back end of the boat

= ( mass of man * length of boat + mass of boat * 1.25 ) / ( mass of boat + mass of man )

= (  67 * 2.5 + 179 * 1.25 ) / ( 179 + 67 )

= ( 167.5 + 223.75 ) / ( 246 ) = 1.590 m

B) By How much is the boat displaced ( d )

0.91 ( location of center of mass from man's original location )

0.91  = (  67 *  (2.5 - d) +  179 (  1.25 - d ) ) / ( 179 + 67 )

        = ( 67 * ( 2.5 - d ) + 223.75 - 179d )) / ( 246 )

∴ d ≈ 0.68 m

C) Determine speed of boat after the jump

Initial speed of boat = 1.5 m/s

hence speed after the jump ( v )

speed of first man = 3 m/s

speed of second man = 4 m/s

1.5 m/s = ( 67 * -3 + 67 * -4 + 179 * v ) / ( 67 + 67 + 179 )

           = ( - 201 + -268 + 179v ) / ( 313 )

∴ v ≈ 5.24 m/s

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A 67 Kg Man Stands At The Front End Of A Uniform Boat Of Mass 179 Kg And Of Length, L = 2.5 M. Assume

Related Questions

1. A leftward force is used to pull a large wagon. In the wagon there is an unknown mass
that makes it very difficult to move, but a force applied is able to set the wagon into
constant motion. Let the force applied to the wagon and its unknown mass be 77.3 N. The
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Answer:

Wagon weight 366.41314(9.81) = 3,594.5129 = 3590 N

Load weight 349.9245(9.81) = 3,432.75982 = 3430 N

Explanation:

Let's assume the surface and the applied force are horizontal.

At constant motion, the friction force must balance the applied force

(from F = ma)

Ff = 77.3

μΝ = 77.3

μmg = 77.3

m = 77.3 / (0.011(9.81))

m = 716.3376... kg

Let M be the mass of the wagon

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M = 366.41314...kg

0.955 M = 349.9245... kg

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Answers

Explanation:

Time= Distance÷Velocity

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76 added to 129 is 215

Successive resonances/harmonics are observed to occur at 129, 215 and 301 Hz (Note: 129 Hz is not necessarily the fundamental frequency). the speed of sound is 76 added to 129 is 215

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The pitch of the sound is a major property where the frequency of sound occur by human ear within the range of human hearing.

It is higher than the frequency of the sound where the higher is its pitch and a lower frequency means a lower pitch.

The loudness of sound is another property which can be determined by amplitude of the sound is a measure of the magnitude of the maximum disturbance of sound.

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The boiling point of lauric acid is 298.9°C. Its melting point is 43.2°C. At room temperature (~25°C), lauric acid is in which state?
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Answers

Answer

A. solid

Explanation

We have that At room temperature (~25°C), lauric acid is in a

Solid state

Option A

From the question we are told that

The boiling point of lauric acid is 298.9°C. Its melting point is 43.2°C.

It is important to note that Room temperature is is at 25C

Generally

if lauric acid 298.9°C and melting point is 43.2°C

Therefore at room temperature low than Boiling and melting point  lauric acid is

Solid

in conclusion

At room temperature (~25°C), lauric acid is in a Solid state

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Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.

As stated in the article, the dog food manufacturing facility was shut down while the situation was looked into.

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Answers

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Explanation:

Hey there!

According to the question;

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Answers

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Answers

Answer:

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Answer:

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Explanation:

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