A bag contains 10 discs.
Each disc is labelled with a different number from 1 to 10
Adinis chosen from the bag at random
Write down the probability that the chosen disc is
(a) the number 3
(b) a number loss than four
(c) a square number
(d) a prime number
Help please !!!

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (x - 5)(x - 4) }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}[/tex]

[tex] {x}^{2} - 9x + 20[/tex]

[tex] = {x}^{2} - 4x - 5x + 20[/tex]

Taking "[tex]x[/tex]" as common from first two terms and "[tex]5[/tex]" from last two terms, we have

[tex] = x(x - 4) - 5(x - 4)[/tex]

Taking the factor [tex](x-4)[/tex] as common,

[tex] = (x - 5)(x - 4)[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Answer:

16

Step-by-step explanation:

a+bc

a+(b×c)

4+(6×2)

4+12

answer=16

Answer:

y=1/4x - 1

Step-by-step explanation:

going off of the picture, I'd say this is your answer

Answer:

Step-by-step explanation:

r = 1/2 unit

[tex]Volume= \frac{4}{3}\pi r^{3}\\\\=\frac{4}{3}\pi *\frac{1}{2}*\frac{1}{2}*\frac{1}{2}\\\\=\frac{1}{3}*\pi *\frac{1}{2}\\\\=\frac{1}{6}\pi[/tex]

Answer:

I'm acutally not too sure on this but give me a moment to solve this

Step-by-step explanation:

[tex]x= \pi[/tex]

Step-by-step explanation:

[tex]\cos^2x+\cos x+1=0[/tex]

Let [tex]u= \cos x[/tex]

Then [tex]u^2+2u+1=(u+1)^2=0[/tex]

or

[tex]\cos x = -1[/tex]

This gives us [tex]x= \pi[/tex] or all integer multiples of [tex]\pi (n \pi)[/tex]

Step-by-step explanation:

hear is your answer in attachment

Answer:

= 3.6

Step-by-step explanation:

Do you know how to find the volume of a cylinder? Like any prism, it's area of base x height, in this case the base is a circle of radius 1.2m.

Density is simply mass / volume (kg / m3 ).

clarify its 1.2 x 3 = 3.6

12400 / 3.6 = 3.444 occuring

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex](4 {x}^{2} + 4x + 6)(7x + 5)[/tex]

[tex] = \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)[/tex]

[tex] = \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30[/tex]

Combining like terms, we have

[tex] = \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30[/tex]

[tex] = \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

Answer:

0.4

Step-by-step explanation:

0.2+0.2+0.2=0.6

1.0-0.6=0.4

This isn't 0.2 like the others which is why it's a biased dice like it says.

Answer:

x = 1

y = 5

z = 2

Step-by-step explanation:

System of equations:

6x - 2y + z = -2

2x + 3y - 3z = 11

x + 6y = 31

Isolate one variable in any of the equations:

x + 6y = 31

x = 31 - 6y

Plug in this value for x in another equation:

6(31 - 6y) - 2y + z = -2

186 - 36y - 2y + z = -2

186 - 38y + z = -2

-38y + z = -188

z = -188 + 38y

Plug in these values in the remaining equation:

2(31 - 6y) + 3y - 3(-188 + 38y) = 11

62 - 12y + 3y + 564 - 114y = 11

626 - 12y + 3y - 114y = 11

626 - 9y - 114y = 11

626 - 123y = 11

-123y = -615

y = 5

Plug in value of y into our other answers to solve for x and z:

x = 31 - 6(5)

x = 31 - 30

x = 1

z = -188 + 38(5)

z = -188 + 190

z = 2

Check your work:

6x - 2y + z = -2

6(1) - 2(5) + 2 = -2

6 - 10 + 2 = -2

-4 + 2 = -2

-2 = -2

Correct!

*Note there are several ways to solve for these types of problems. I used substitution*

Answer:

90

Step-by-step explanation:

Let the whole number be x.

100% is to x as 70% is to 63

100/x = 70/63

10/x = 10/9

10x = 90 * 10

x = 90

Answer: 90

Step-by-step explanation:

0.7x = 63, x = 63/0.7 = 90

Answer:

a. $0.13 / Ib.

Step-by-step explanation:

Slope of a line:

Suppose we have two data-points in a line. The slope is given by the change in the output divided by the change in the output.

In this question:

Input: weight(in pounds)

Output: Weekly cost to feed.

A hamster weighs half a pound and costs $2 per week to feed, while a Labrador Retriever weighs 62.5 pounds and costs $10 per week to feed.

Inputs: 0.5, 62.5

Outputs: 2, 10

Change in the outputs: 10 - 2 = 8

Change in the inputs: 62.5 - 0.5 = 62

Slope: [tex]m = \frac{8}{62} = 0.13[/tex]

So the correct answer is given by option A.

Answer:

0.13

Step-by-step explanation:

Solution :

a). P(X = x)

     =   [tex]$p(1-p)^x$[/tex]  for x = 0, 1, 2, ....

   P(x ≤ 3) = 0.837

b). Expectation = [tex]$\frac{(1-p)}{p}$[/tex]

                        = 1.7397

  Variance = [tex]$\frac{(1-p)}{p^2}$[/tex]

                 = 4.7663726

  Standard deviation = 2.1832

 Therefore, mean + standard deviation

                  = 1.7397 + 2.1832

                  = 3.9229

[tex]$P(x > 3.9229) = 0.1626$[/tex]

So the required P = 2 x 0.1626

                             = 0.325

Answer:

b.    [tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Step-by-step explanation:

[tex] l = 14j + 3k [/tex]

Switch sides.

[tex] 14j + 3k = l [/tex]

Subtract 14j from both sides.

[tex] 3k = l - 14j [/tex]

Divide both sides by 3.

[tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Answer:

c. one-tailed test, with rejection region in the upper tail.

Step-by-step explanation:

One tailed test is statistical test in which critical area of distribution is one sided and greater or less than certain value. One tailed test can be left or right sided depending on the population distribution. Rejection region of the one tailed test will determine whether to accept or reject the null hypothesis.

Step-by-step explanation:

the answer is in the above image

Answer:

The amount that your loan balance will be when you pay off the car is $20,566.18.

Step-by-step explanation:

Step 1. Calculation of monthly payment

This can be calculated using the formula for calculating the present value of an ordinary annuity as follows:

PV = P * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)

Where;

PV = Present value or the cost of the new car = $55,000

P = Monthly payment = ?

r = Monthly nominal rate = Nominal rate / 12 = 6% / 12 = 0.06 / 12 = 0.005

n = number of months = 72

Substitute the values into equation (1) and solve for P, we have:

$55,000 = P * ((1 - (1 / (1 + 0.005))^72) / 0.005)

$55,000 = P * 60.3395139355201

P = $55,000 / 60.3395139355201 = $911.51

Step 2. Calculation of the loan amount balance when you pay off the car

This can be calculated using the ballon payment formula as follows:

P = (PV - (Ballon / (1 + r)^n)) * (r / (1 – (1 + r)^-n)) ...................... (1)

Where:

P = Monthly payment = $911.51

PV = Present value or the cost of the new car = $55,000

Ballon = Ballon payment or the loan amount balance when you pay off the car = ?

r = Monthly nominal rate = Nominal rate / 12 = 6% / 12 = 0.06 / 12 = 0.005

n = number months to pay off the loan amount balance = 48

Substituting the values into equation (1) and solve for Ballon, we have:

911.51 = (55,000 - (Ballon / (1 + 0.005)^48)) * (0.005 / (1 - (1 + 0.005)^-48))

911.51 = (55,000 - (Ballon / 1.27048916109538)) * 0.0234850290479363

911.51 / 0.0234850290479363 = 55,000 - (Ballon / 1.27048916109538)

38,812.39 = 55,000 - (Ballon / 1.27048916109538)

Ballon / 1.27048916109538 = 55,000 - 38,812.39

Ballon / 1.27048916109538 = 16,187.61

Ballon = 16,187.61 * 1.27048916109538

Ballon = $20,566.18

Therefore, the amount that your loan balance will be when you pay off the car is $20,566.18.

Answer:

Step-by-step explanation:

This is the permutation of 4:

[tex]\huge\qquad \mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}[/tex]

✶⊶⊷⊶⊷❍❁❥❀❥❁❍⊶⊷⊶⊷✶

Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different ways can the four students be arranged to take a picture

so we have to find the permutation of 4

.°. In 24 different ways can the four students be arranged to take a picture

Answer:

Number of black balls=2

Total number of balls=3

Probability =2/3

Answer:

-2.5 or - 2 1/2

Step-by-step explanation:

Writing out the expression Mathematically ;

1/3(-15÷1/2)1/4

Using PEMDAS :

Solving the bracket first

(-15 ÷ 1/2) = (-15 * 2/1) = - 30

We have :

1/3(-30)1/4 = - 10 * 1/4 = - 10 / 4 = - 2.5

-2.5 = - 2 1/2

Answer:

i dont know just study hard bro

Step-by-step explanation:

Answer:

A =36 ft^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 ( b1+b2)h where b1 and b2 are the lengths of the bases

A = 1/2 ( 13+5) *4

A = 1/2 ( 18)*4

A =36 ft^2

Answer:

[tex]Median = 15.80[/tex]

[tex]Mode = 15.20\ \&\ 15.25[/tex]

[tex]IQR = 2.35[/tex]

Step-by-step explanation:

Given

[tex]15.60,\ 18.75,\ 14.60,\ 15.80,\ 14.35,[/tex]

[tex]13.90,\ 17.50,\ 17.55,\ 13.80,\ 14.20,[/tex]

[tex]19.05,\ 15.35,\ 15.20,\ 19.45,\ 15.95,[/tex]

[tex]16.50,\ 16.30,\ 15.25,\ 15.05,\ 19.10,[/tex]

[tex]15.20,\ 16.22,\ 17.75,\ 18.40,\ 15.25.[/tex]

Solving (a): The median and the mode

First, we sort the data.

[tex]13.80,\ 13.90,\ 14.20,\ 14.35,\ 14.60,\ 15.05,\ 15.20,\ 15.20,\ 15.25,\ 15.25,[/tex]

[tex]15.35,\ 15.60,\ 15.80,\ 15.95,\ 16.22,\ 16.30,\ 16.50,\ 17.50,\ 17.55,\ 17.75,[/tex]

[tex]18.40,\ 18.75,\ 19.05,\ 19.10,\ 19.45.[/tex]

The median position is:

[tex]Median = \frac{n + 1}{2}th[/tex]

[tex]Median = \frac{25 + 1}{2}[/tex]

[tex]Median = \frac{26}{2}[/tex]

[tex]Median = 13th[/tex]

The 13th item is: 15.80

Hence:

[tex]Median = 15.80[/tex]

The modes are:

[tex]Mode = 15.20\ \&\ 15.25[/tex] --- they both have frequency of 2 while others occur once

Solving (b): The interquartile range

This is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

Since the median is at the 13th position, Q1 is:

[tex]Q_1 = \frac{1 + 13}{2}th[/tex]

[tex]Q_1 = \frac{14}{2}th[/tex]

[tex]Q_1 = 7th[/tex]

The 7th item is: 15.20

[tex]Q_1 = 15.20[/tex]

Similarly, Q3 is:

[tex]Q_3 = \frac{13+n}{2}[/tex]

[tex]Q_3 = \frac{13+25}{2}[/tex]

[tex]Q_3 = \frac{38}{2}[/tex]

[tex]Q_3 = 19th[/tex]

The 7th item is: 17.55

So:

[tex]Q_3 = 17.55[/tex]

Hence,

[tex]IQR = 17.55 - 15.20[/tex]

[tex]IQR = 2.35[/tex]

9514 1404 393

Answer:

  AC = 17

Step-by-step explanation:

The segment sum theorem tells you ...

  AB +BC = AC

Substituting the given expressions, we have ...

  (3x +4) +(4x -1) = (6x +5)

  x = 2 . . . . . . . . . . . . . . . . . . subtract 3+6x from both sides

  AC = 6x +5 = 6(2) +5

  AC = 17

_____

  AB = 10, BC = 7

Answer:

Letter C

Step-by-step explanation:

Given:

[tex]5a+18<-27[/tex]

Subtract 18 from both sides

[tex]5a<-45[/tex]

Divide 5 from both sides to get [tex]a[/tex] alone

[tex]a<-9[/tex]

Letter C is the correct answer choice because the dot is at -9, the arrow is facing to the left, and the dot is open indicating that it's not greater/less than ""or equal to"".

Hope this is helpful

Answer:

4033

Step-by-step explanation:

An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:

a^2 = 2017^4

a = 2017^2

b^2 = 2016^4

b = 2016^2

Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:

We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by [tex]\frac{2017^2+2016^2}{2017^2+2016^2}[/tex] which is just one, and will simplify the fraction to just:

2017^2 - 2016^2

This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:

(2017 + 2016)(2017 - 2016)

And, without using a calculator, this is easy to simplify:

(4033)(1)

4033

The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

The function is given as:

y = 6x^2 + x - 35

Expand the function

y = 6x^2 + 15x - 14x - 35

Factorize the function

y = (2x + 5) * (3x - 7)

Set the function to 0

(2x + 5) * (3x - 7) = 0

Split

2x + 5 = 0 or 3x - 7 = 0

Solve for x

x = -2.5 or x = 7/3

Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3

Read more about quadratic functions at:

https://brainly.com/question/1214333

#SPJ1

Answer:

0.2 amps

Step-by-step explanation:

Given data

The formula V=IR is the formula for ohms law

Which state that  the voltage is directly proportional to the current and the resistance in an electric circuit

Now

R= 15 ohms

V= 3volts

V= IR

3= I*15

I= 3/15

I= 0.2 amps

Hence he current flowing is 0.2 amps

Answer:

(a) [tex]A = A_0 * e^{kt}[/tex]

(b) There will be 1lb left after 14 hours

Step-by-step explanation:

Solving (a): The equation

Since the substance decomposes at a proportional rate, then it follows the following equation

[tex]A(t) = A_0 * e^{kt}[/tex]

Where

[tex]A_0 \to[/tex] Initial Amount

[tex]k \to[/tex] rate

[tex]t \to[/tex] time

[tex]A(t) \to[/tex] Amount at time t

Solving (b):

We have:

[tex]t = 4.6hr[/tex]

[tex]A_0 = 8[/tex]

[tex]A(4.6) = 4[/tex]

First, we calculate k using:

[tex]A(t) = A_0 * e^{kt}[/tex]

This gives:

[tex]A(4.6) = 8 * e^{k*4.6}[/tex]

Substitute: [tex]A(4.6) = 4[/tex]

[tex]4 = 8 * e^{k*4.6}[/tex]

Divide both sides by 4

[tex]0.5 = e^{k*4.6}[/tex]

Take natural logarithm of both sides

[tex]\ln(0.5) = \ln(e^{k*4.6})[/tex]

This gives:

[tex]-0.6931 = k*4.6[/tex]

Solve for k

[tex]k = \frac{-0.6931}{4.6}[/tex]

[tex]k = -0.1507[/tex]

So, we have:

[tex]A(t) = A_0 * e^{kt}[/tex]

[tex]A(t) = 8e^{-0.1507t}[/tex]

To calculate the time when 1 lb will remain, we have:

[tex]A(t) = 1[/tex]

So, the equation becomes

[tex]1= 8e^{-0.1507t}[/tex]

Divide both sides by 8

[tex]0.125= e^{-0.1507t}[/tex]

Take natural logarithm of both sides

[tex]\ln(0.125)= \ln(e^{-0.1507t})[/tex]

[tex]-2.0794= -0.1507t[/tex]

Solve for t

[tex]t = \frac{-2.0794}{-0.1507}[/tex]

[tex]t = 13.7983[/tex]

[tex]t = 14[/tex] --- approximated

Answer:

ok so if it is 30 dollars per hour so 30h plus 20 so

f=30h+20

Hope This Helps!!!