A bag contains balls of five different colors. Two are red, three are blue, ten are white, four are green and three are black. Balls are taken from the bag without looking, and not returned. What is the smallest number of balls that should be taken from the bag to be sure that two balls of the same color have been taken? please explain with the answer ​

Answer:

b. Pure Imaginary Numbers.

Step-by-step explanation:

[tex] (i \sqrt{3})^2 = i^2 \times (\sqrt{3})^2 = -1 \times 3 = -3 [/tex]

-3 is an integer, a complex number, and a rational number.

Answer: b. Pure Imaginary Numbers.

Answer:

Step-by-step explanation:

Domain of a function is defined by the set of x-values (input values) and Range is the set of y-values (output values) of the function.

1). The range and domain of P = {(x, y)| y = 3}

Domain: Set of all real numbers

Range: {y: y=3}

2). The domain set of C = {(2, 5), (2, 6), (2, 7)}

 Domain: {2}

3). The range set of E = {(3, 3), (4, 4), (5, 5), (6, 6)}

  Range: {3, 4, 5, 6}

4). The range and domain set of F = {(x, y)| x + y = 10}

   Domain = Range = {All real numbers}

Answer:

(x, y) = (10, 290)

Step-by-step explanation:

From the table

Total fees = fixed + variable

Fixed:

When number of times Ahmed mowed, x = 0

y = 40

When x = 2, y = 65

Rate of change = y2 - y1

= 65 - 40

= 25

y = 40 + 25x

Where,

y = total fees charged

40 = fixed fee

25x = variable fee

Total amount Ahmed will make for mowing 10 times

when x = 10

y = 40 + 25x

y = 40 + 25(10)

= 40 + 250

= 290

y = 290

(x, y) = (10, 290)

Answer:

See below.

Step-by-step explanation:

No, a reasonable estimate is around 7 * 6 = 42.

Round $6.99 to $7 and multiply by the 6 family members.

Answer:

hypotenuse = 7.3

Step-by-step explanation:

here 7 and 2 are the legs og the right triangle .we should find hypotenuse.

let the legs of the right triangle be a nd b respectively . And c be hypotenuse

using pythagoras theorem to find hypotenuse

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.28 = c

7.3 =c

Answer:

7.3

Step-by-step explanation:

[tex]7^{2} + 2^{2} = x^{2} \\ 53 = x^{2}\\\sqrt{53} = \sqrt{x^{2}} \\x = 7.3[/tex]

Hope this help!!!

Have a nice day!!!!

Answer:

3h³k² + 18h³k + 27h³

Step-by-step explanation:

Given

3h³(k + 3)² ← expand factor using FOIL

= 3h³(k² + 6k + 9) ← distribute parenthesis

= 3h³k² + 18h³k + 27h³

Answer:

-5, -3

Step-by-step explanation:

Answer:

Sara can buy 2 notebooks with the money that she has and she will have a remainding 23.1

Step-by-step explanation:

93.1-35-35=23.1

Answer:

the last one is correct

Step-by-step explanation:

because 3000/12 = 250 and 3500/14 = 250 so they are porportional.

Answer:

i dont under stand but i will just ask for help to my father

Step-by-step explanation:

i dont wnow the answer!???

Answer:

Step-by-step explanation:

[tex]Florence \ washed \ 3\ cars \ and\ earned\ = \$ x\\\\[/tex]

[tex]Cost\ of \ washing \ one \ car = \frac{x}{3}[/tex]

[tex]Anona \ washed \ 5 \ cars \ and \ earned \ 16 \ more \ than \ Florence = x + 16[/tex]

[tex]Cost\ of \ washing \ one \ car \ by \ Anona = \frac{x +16}{5}[/tex]

 [tex]\frac{x}{3} = \frac{x + 16}{5}\\[/tex]                    [tex][ \ cross \ multiply \ ][/tex]

[tex]5 \times x = 3 \times( x + 16)\\\\5x = 3x + 48\\\\5x - 3x = 48\\\\2x = 48\\\\x = 24[/tex]

[tex]Cost \ of \ washing \ one \car = \frac{x}{3} = \frac{24}{3} = \$ 8[/tex]

Therefore ,

                 Florence earned $24

                 Anona earned 24 + 16 = $40  

                 Caragh Washed 4 cars, so Caragh earned = 8 x 4 = $32

===================================================

Work Shown:

A = probability of landing on an odd number

A = 5/9 because there are 5 odd numbers out of 9 total

B = probability of getting heads

B = 1/2

C = landing on 3 on the spinner

C = 1/9

Multiply the values of A,B,C

A*B*C = (5/9)*(1/2)*(1/9) = (5*1*1)/(9*2*9) = 5/162

Note: The fraction 5/162 converts to the approximate decimal 0.03086 which then converts to 3.086%, when rounding to the nearest tenth of a percent we get 3.1%

Answer:

14

Step-by-step explanation:

Triangle=180

180-90 (RA) = 90

90-41= 39

(2x+11)=39

2x=28

x=14

Answer:

c = 60°

Step-by-step explanation:

Since the measures are among a 90° angle, we need to subtract 30° from 90° which equals 60°

c = 60°

Answer:

Angle B is congruent to Angle E.

Step-by-step explanation:

Also, if youve read Romeo and Juliet, please help me! My essay is due tomorrow. I just need informal help, no specific lines or anything

In the diagram below, ΔABC ≅ ΔDEF. Therefore, by CPCT, ∠B = ∠E.

Corresponding parts of congruent triangles or CPCT is used to denote the relation between the sides and the angles of two congruent triangles.

Since, ΔABC ≅ ΔDEF,

AB = DE

BC = EF

AC = DF

∠A = ∠D

∠B = ∠E

∠C = ∠F

Learn more about CPCT here

https://brainly.com/question/21360865

#SPJ2

Answer:

$63.30

Step-by-step explanation:

Assuming the $60 is excluding taxes:

60 * 1.055 = $63.30

Answer:

a₂₅ = - 367

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = - 22 - (- 7) = - 37 - (- 22) = - 15

This indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 7 and d = - 15 , then

a₂₅ = - 7 + (24 × - 15) = - 7 - 360 = - 367

Answer:

c) 72

hope this helps!

please give brainiest<3

Answer:

72

Step-by-step explanation:

Substitution:

4^3 + 4 x 6 - 16

64+24-16=72

Answer:

[tex] \frac{15 \sqrt{209} }{209} [/tex]

Step-by-step explanation:

Objective: Understand and work with trig identies.

Recall multiple trig identies and manipulate them to get from cosecant to secant.

Given

[tex] \csc(a) = \frac{60}{16} [/tex]

Apply reciprocal identity csc a = 1/sin a.

[tex] \sin(a) = \frac{16}{60} [/tex]

Apply pythagorean identity to find cos a.

[tex]( \frac{16}{60}) {}^{2} + \cos(x) {}^{2} = 1[/tex]

[tex] \frac{256}{3600} + \cos(x) {}^{2} = 1[/tex]

[tex] \cos(x) {}^{2} = \frac{3600}{3600} - \frac{256}{3600} [/tex]

We can simplify both expression

[tex] \cos(x) {}^{2} = \frac{225}{225} - \frac{16}{225} [/tex]

[tex] \cos(x) = \frac{ \sqrt{209} }{15} [/tex]

Cosine is positve on quadrant 1 so that cos(a)

Apply reciprocal identity sec a= 1/ cos a.

The answer is

[tex] \sec(a) = \frac{15}{ \sqrt{209} } [/tex]

Rationalize the denominator.

[tex] \frac{15}{ \sqrt{209} } \times \frac{ \sqrt{209} }{ \sqrt{209} } = \frac{15 \sqrt{209} }{209} [/tex]

Answer:

8:6

Step-by-step explanation:

If 8 out of 14 students are boys then the remaining number of students must be girls

So

14-8= 6

There are 6 girls out of the 14

So as a ratio of boys to girls

8:6

Answer:

8 : 6 <or> 4 : 3

Step-by-step explanation:

8 : 6 <or> 4 : 3

Since there are 8 boys out of 14, if you minus them , the answer will be the number of girls out of 14.

Answer:

119.4

Step-by-step explanation:

The Area of the Rectangle : 132 cm

Area of the Circle : 12.6 cm

Shade=  MINUS - 132 cm  - 12.5 cm = 119.4!

Happy To Help! :)

Answer:

A

Step-by-step explanation:

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x    = 55

Divide each side by 11

11x/11 = 55/11

x = 5

Answer:

[tex]\huge\boxed{x=5}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}7x-4y=23\\x+y=8&|\text{subtract}\ x\ \text{from both sides}\end{array}\right\\\left\{\begin{array}{ccc}7x-4y=23&(1)\\y=8-x&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\7x-4(8-x)=23\qquad|\text{use the distributive property}\\\\7x+(-4)(8)+(-4)(-x)=23\\\\7x-32+4x=23\qquad|\text{combine like terms}\\\\(7x+4x)-32=23\qquad|\text{add 32 to both sides}\\\\11x-32+32=23+32\\\\11x=55\qquad|\text{divide both sides by 11}\\\\\dfrac{11x}{11}=\dfrac{55}{11}\\\\x=5[/tex]

Answer:

D

Step-by-step explanation:

x=16

y=4

4=16-12

4=4

Answer:

D

Step-by-step explanation:

Answer:

should be 3/7 I think that's right

Answer:

c

Step-by-step explanation:

i hope it helped ᘳ◕ᴥ◕ᘰ

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30

Answer:

[tex]S' = (-5,-5)[/tex]

[tex]Q"=(-5,-5)[/tex]

Step-by-step explanation:

Given

[tex]S = (5,-5)[/tex]

[tex]Q= (5,5)[/tex]

Solving (a): Reflect S across y-axis

The rule to reflect across y-axis is:

[tex](x,y) \to (-x,y)[/tex]

So, we have:

[tex]S(5,-5) \to S'(-5,-5)[/tex]

Hence:

[tex]S' = (-5,-5)[/tex]

Solving (b): Reflect Q across x and y-axis

The rule to reflect across x-axis is:

[tex](x,y) \to (x,-y)[/tex]

So:

[tex]Q(5,5) \to Q'(5,-5)[/tex]

The rule to reflect across y-axis is:

[tex](x,y) \to (-x,y)[/tex]

So:

[tex]Q'(5,-5) \to Q"(-5,-5)[/tex]

Hence:

[tex]Q"=(-5,-5)[/tex]

i dont get it either

Step-by-step explanation:

Answer:

if this was a equation you would first subtract 12 from the other number then divide it by 3

Answer:

3(x+4)

Step-by-step explanation:

Check 3(x+4), when you use the distributive property, you get 3x + 12, so this is correct. (sorry, I'm really bad at explaining...)

Answer:

p=1

Step-by-step explanation:

2/5 + p = 4/5 + 3/5p

Multiply each side by 5 to clear the fractions

5(2/5 + p) = 5(4/5 + 3/5p)

2 +5p = 4 + 3p

Subtract 3p from each side

2+5p-3p = 4+3p-3p

2+2p = 4

Subtract 2 from each side

2+2p -2 = 4-2

2p =2

Divide by 2

2p/2 = 2/2

p=1

[tex]\huge\mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}[/tex]