Answer:
Step-by-step explanation:
First of all, something is wrong with either the wording in the problem or the equation that you wrote; if the upward velocity is 18, we should see 18t in the equation, not 10t. I solved using 10t.
To find the max height of the ball and the time it took to get there, we need to complete the square on this quadratic and solve for the vertex. That will give us both of those answers in one!
To complete the square, set the quadratic equal to 0 and then move over the constant, like this:
[tex]-5t^2+10t=-35[/tex] The rule is that we have to have a 1 as the leading coefficient, and right now it's a -5, so we factor that out, leaving us with:
[tex]-5(t^2-2t)=-35[/tex] and now we are ready to begin the process to complete the square.
The rule is: take half the linear term, square it, and add it to both sides. Our linear term is a -2 (from the -2t); half of -2 is -1, and -1 squared is 1. We add in a one to both sides. BUT when we put the 1 into the set of parenthesis on the left, we didn't just add in a 1, we have that -5 out front that is a multiplier. That means that we actually added in a -5 after it's all said and done.
[tex]-5(t^2-2t+1)=-35-5[/tex] and we'll clean that up a bit. The right side is easy, that's a -40. The left side...not so much.
The reason we complete the square is to put this quadratic into vertex form. Completing the square creates a perfect square binomial on the left, which for us is, along with the simplification on the right:
[tex]-5(t-1)^2=-40[/tex]
Lastly, we move the -40 back over by adding and setting the quadratic back to equal y:
[tex]-5(t-1)^2+40=y[/tex] and we see that the vertex is (1, 40). That translates to a height of 40 meters at 1 second after launch. That's the vertex which, by definition, is the max or min of the parabola. Because our parabola is negative, the vertex for us is a max.
To find out how long it takes the ball to hit the ground, set the quadratic equal to 0 and factor however it is you are currently doing this in class. You can continue to factor from the vertex form we have the equation in if you'd like. Let's do that, since we are already most of the way there. Begin here:
[tex]-5(t-1)^2=-40[/tex] and divide both sides by -5 to get
[tex](t-1)^2=8[/tex] and take the square root of both sides to "undo" that squaring on the left:
t - 1 = ±√8. Now add 1 to both sides to isolate the t:
t = 1 ± √8. In decimal form:
t = 1 + √8 is 3.828 seconds and
t = 1 - √8 is -1.828 seconds.
Since we all know that time will NEVER be a negative value, the time it takes the ball to hit the ground is 3.828 seconds.
What’s the answers ?
hope this helps! feel free to clarify if unsure
HELPPP MEEEE OUTTTTTT ITS URGENTTTTT!!!!
Answer:
(x-12)^2+(y-2)^2=4
Step-by-step explanation:
Solve: -15/2 + 5y divided by 5/2
Answer:
- 3 + 2y
Step-by-step explanation:
[tex]\frac{-\frac{15}{2} +5y}{\frac{5}{2} }[/tex]
[tex]\frac{2}{5}( -\frac{15}{2} +5y} )[/tex]
[tex]-3+2y[/tex]
Step-by-step explanation:
Division by a fraction such as 5/2 is equivalent to multiplication by the reciprocal of the fraction (2/5).
Multiplying (-15/2 + 5y) by 2/5 yields:
-3 + 2y (answer)
Find the center and radius of the circle with equation (x+3)^2+(3+ 1)^2= 9. Then graph the circle.
Answer:
See graph
[tex](x +3)^{2}[/tex] + [tex](y + 1)^{2}[/tex] = 9
(-3 , -1) is the center.
[tex]\sqrt{9}[/tex] = 3 = radius
Step-by-step explanation:
[tex](x - h)^{2} + (y - k)^{2} = r^{2}[/tex]
center (h,k)
radius = r
which of the following is the x-coordinate of the solution to the system shown below
2x + y = 17
x - y = 4
———————————————
(1) x = 5
(2) x = 2
(3) x = 7
(4) x = 12
thank you in advance to ANYONE who answers this question:)))
Answer:
Step-by-step explanation:
The measure of an angle is 112.7º. What is the measure of its supplementary angle?
Answer:
67.3
Step-by-step explanation:
Let x = unknown angle
Supplementary angles add up to equal 180
Hence 112.7 + x = 180
Solve for x
112.7 + x = 180
Subtract 112.7 from both sides
x = 67.3
An angle supplementary to an angle with a measure of 112.7 degrees has a measure of 67.3
What is tanA?
Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 17, adjacent A C is 8, opposite B C is 15.
a.
StartFraction 15 Over 17 EndFraction
c.
StartFraction 8 Over 15 EndFraction
b.
StartFraction 8 Over 17 EndFraction
d.
StartFraction 15 Over 8 EndFraction
Answer:
D. [tex] \frac{15}{8} [/tex]
Step-by-step explanation:
Recall: SOH CAH TOA
Thus,
Tan A = Opposite/Adjacent
Reference angle (θ) = A
Length of side Opposite to <A = 15
Length of Adjacent side = 8
Plug in the known values
[tex] Tan(A) = \frac{15}{8} [/tex]
Please I need help who want to earn 13 points ..
Answer:
Triangle ISK
Step-by-step explanation:
Answer:
Triangle ISK
Step-by-step explanation:
if the angles and sides of one triangle are equal to the corresponding sides and angles of the other triangle, they are congruent.
∠Q = ∠I
∠R = ∠S
∠S = ∠K
Friends, i need help with this question.
Answer:
Step-by-step explanation:
The answer is 4.
Once you add 4, you get:
x^2 -2x + 4 = 7.
The left side is factorable:
(x-2)^2 = 7.
There is your perfect square.
In a survey of adults aged 57 through 85 years, it was found that 86.6% of them used at least one prescription medication. Complete parts (a) through (c) below.
a. How many of the 3149 subjects used at least one prescription medication?
(Round to the nearest integer as needed.)
b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication.
(Round to one decimal place as needed.)
Answer:
a) 272 used at least one prescription medication.
b) The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).
Step-by-step explanation:
Question a:
86.6% out of 3149, so:
0.866*3149 = 2727.
272 used at least one prescription medication.
Question b:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
For this problem, we have that:
[tex]n = 3149, \pi = 0.866[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 - 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.856[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.866 + 1.645\sqrt{\frac{0.866*0.134}{3149}} = 0.876[/tex]
For the percentage:
0.856*100% = 85.6%
0.876*100% = 87.6%.
The 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication is (85.6%, 87.6%).
The number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is: [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%
How to construct confidence interval for population proportion based on the sample proportion?Suppose that we have:
n = sample size[tex]\hat{p}[/tex] = sample proportion[tex]\alpha[/tex] = level of significance = 1 - confidence interval = 100 - confidence interval in percentageThen, we get:
[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]
where [tex]Z_{\alpha/2}[/tex] is the critical value of Z at specified level of significance and is obtainable from its critical value table(available online or in some books)
For this case, we have:
n = 3149confidence interval is of 90%[tex]\alpha[/tex] = level of significance = 100 - 90% = 10% = 0..10[tex]\hat{p}[/tex] = sample proportion = ratio of 86.6% of n to n (at the least)Part (a):
The number of subjects used at least one prescription medication is:
[tex]\dfrac{3149}{100} \times 86.6 \approx 2727[/tex]
Thus, the sample proportion we get is:
[tex]\hat{p} = \dfrac{2727}{3149} \approx 0.8659[/tex]
For level of significance 0.10, we get: [tex]Z_{\alpha/2} = 1.645[/tex]
Thus, the confidence interval needed is:
[tex]CI = \hat{p} \pm Z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\CI \approx 0.8659\pm 1.645 \times \sqrt{\dfrac{0.8659(1-0.8659)}{3149}}\\\\\\CI \approx 0.8659 \pm 0.0099[/tex]
Thus, CI is [0.8659 - 0.0099, 0.8659 + 0.0099] = [0.8560, 0.8758]
Thus, the number of subjects in the study who used at least one prescription medication is 2727 approx. The needed 90% confidence interval is: [0.8560, 0.8758] or in percentage as: 85.6% to 87.58%
Learn more about population proportion here:
https://brainly.com/question/7204089
Can someone help me I need it.
Answer:
C is the answer 3rd one...
1) 18,27 – 9,756 =
2) 6 – 2,407 =
3) 18 – 5,432 =
4) 10 – 7,602 =
5) 13,013 – 12,5 =
6) 972,5 – 247,451 =
7) 83,12 – 90,2 + 12,3 =
8) 46,75 – 60,13 + 32,50 =
9) 254,0187 – 29,34682 =
10)1.015,568 – 123,712 =
no entiendo me ayudan
Answer:
1) -7929
2) -2401
3)-5414
4) -7592
5) 12888
6)-237726
7) 7287
8)-4588
9)-394495
10) 891856
if -2 is a zero the polynomial 3x^2+2x+k, find the value of k
Answer:
value of K =16
I hope it's helps you
What is the measure of ∠
A. 60°
B. 6°
C. 42°
D. 49°
There are 5 more girls than boys in a class. The girls are 60 percent
a. How many pupils are in the class?
Answer:
25.
Step-by-step explanation:
Let the number of pupils be x, then:
there are 0.6x girls and 0.4x boys.
From the given information:
0.6x - 0.4x = 5
0.2x = 5
x = 5/0.2
= 50/2
= 25.
Log5 =0,699 find log 0,5
Answer:
-0.301
Step-by-step explanation:
Correct Question :-
If log 2 = 0.301 , find log 0.5
Solution :-
We are here given that the value of log 5 is 0.699 . Here the base of log is 10 .
[tex]\rm\implies log_{10}2= 0.301 [/tex]
And we are supposed to find out the value of log 0.5 . We can write it as ,
[tex]\rm\implies log_{10}(0.5) = log _{10}\bigg( \dfrac{5}{10}\bigg)[/tex]
Simplify ,
[tex]\rm\implies log _{10}\bigg( \dfrac{1}{2}\bigg)[/tex]
This can be written as ,
[tex]\rm\implies log_{10} ( 2^{-1})[/tex]
Use property of log ,
[tex]\rm\implies -1 \times log_{10}2 [/tex]
Put the value of log 2 ,
[tex]\rm\implies -1 \times 0.301 =\boxed{\blue{-0.301}} [/tex]
Hence the value of log (0.5) is -0.301 .
*Note -
Here here there was no use of log 5 in the calculation .
Kristi finds a shirt for $27.99 at the store.
The sign says that it is 25% off the
original price. Kristi must also pay the 8.5%
sales tax. What is the cost of the shirt
after the sales tax?
Answer:
Kristi will pay $22.77 for the shirt.
Step-by-step explanation:
First, determine the sales price of the shirt. If the full price is $27.99, a 25% reduction is $7. Subtract the discount from the full price to get a sales price of $20.99 for the shirt.
Next, determine the amount of tax Kristi will pay for the shirt. In her state, the sales tax is 8.5% (0.085). Multiply $20.99 by 0.085 and you will see that the sales tax is $1.78. Add the amount of the tax, $1.78, to the sales price of the shirt, $20.99, and you will get $22.77 as the cost of the shirt after the sales tax is added.
i am thinking of a number.l take away 5. the result is 14 . what number did i think
Step-by-step explanation:
First sentence
Let the number be X
second sentence
X-5
Third sentence
X-5=14
X=19
The number is 19
Hi there!
»»————- ★ ————-««
I believe your answer is:
19
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\text{"I am thinking of a number. l take away 5. The result is 14."}\\\\\text{5 taken away from 'said number' would be 14.}\\\\\boxed{n-5=14}\\\\\\\boxed{\text{Solving for 'n'...}} \\\\\rightarrow n - 5 + 5 = 14 + 5\\\\\rightarrow \boxed{n = 19}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
A line of best fit must pass through all data points of a graph.
True or False?
help me friends write in copy
20 pts so don't spam
Answer:
ii
Step-by-step explanation:
from what you've written in the comments I think this question requires you to find the equation that can be expressed in two variables,so the best way to do this is to solve the pairs as simultaneous equations and see the ones that will give you two answers x and y
if you solve the first pair you will have
x + y = 5
2x+2y=10
2(x + y =5)
1(2x+2y=10)
2x+2y=10
2x+2y=10--
now from this you will see that it cannot be expressed as two variables because the answer is just zero..
for the second equation it can be expressed as two variables
x - y = 8
3x-3y =16
3(x-y =8)
1(x-3y=16)
3x-3y=24
x - 3y=16
2x/2=8/2
x=4
x-y=8
4-y=8
-y=8-4
-y/-1=4/-1
y=-4...
so you see it can be expressed as two variables..
if you solve the third one it will also give you an answer which is zero so it can't be expressed as two variables.
and the fourth one also cannot.
I hope this helps and if you don't understand feel free to ask..and sorry if it's wrong
What the additional information fill in the blanks
Answer:
QXV=WXV
Step-by-step explanation:
Graph the first six terms of a sequence where a_1=4 and r=2
Step-by-step explanation: The standard formula for geometric sequence is an = a1 * r^(n-1) where r is the geometric factor and n is an integer. In this problem, upon substitution, an = 4*2^(n-1).
Calculate the next 3 terms and write the formula for the nth term for the following sequences. 24,11,-2
Answer:
next 3 terms are -15, -28, -41. The formula would be n= (n-1)-13 to get the nth term
Step-by-step explanation:
Find the missing length of the following trapezoid
Answer:
1) The length of [tex]DC[/tex] is 20.
2) The length of [tex]PS[/tex] is 17.
Step-by-step explanation:
1) If [tex]DR = RE[/tex] and [tex]CS = SB[/tex], then we can use the following proportionality ratio:
[tex]\frac{DE}{DR} = \frac{32 - x}{26 - x}[/tex] (1)
Where [tex]x[/tex] is the length of segment [tex]\overline{CD}[/tex].
If [tex]DE = 2\cdot DR[/tex], then the value of [tex]x[/tex] is:
[tex]2 = \frac{32-x}{26-x}[/tex]
[tex]52 - 2\cdot x = 32 - x[/tex]
[tex]20 = x[/tex]
The length of [tex]DC[/tex] is 20.
2) If [tex]QV = VP[/tex] and [tex]RW = WS[/tex], then we can use the following proportionality ratio:
[tex]\frac{QP}{QV} = \frac{x-7}{12-7}[/tex] (2)
Where [tex]x[/tex] is the length of segment [tex]\overline{PS}[/tex].
If [tex]QP = 2\cdot QV[/tex], then the value of [tex]x[/tex] is:
[tex]2 = \frac{x-7}{5}[/tex]
[tex]10 = x-7[/tex]
[tex]x = 17[/tex]
The length of [tex]PS[/tex] is 17.
Write the slope-intercept form of the equation of the line described. Through (-1,-1) parallel to y=6x-2
Answer:
[tex]\boxed {\boxed {\sf y= 6x+5}}[/tex]
Step-by-step explanation:
We are asked to find the slope-intercept equation of a line. Slope-intercept form is one way to write the equation of a line. It is:
[tex]y=mx+b[/tex]
Where m is the slope and b is the y-intercept.
We are given a point (-1, -1) and the line is parallel to the line y= 6x-2. Since the line is parallel to the other line, they have the same slope, which is 6. We have a point and a slope, so we should use the point-slope formula to find the equation of the line.
[tex]y-y_1= m (x-x_1)[/tex]
Here, m is the slope and (x₁, y₁) is the point. We know the slope is 6 and the point is (-1, -1). Therefore:
m= 6x₁= -1y₁= -1Substitute the values into the formula.
[tex]y- -1 = 6(x- -1) \\y+1= 6(x+1)[/tex]
Distribute the 6. Multiply each value inside the parentheses by 6.
[tex]y+1 = (6*x)+ (6*1) \\y+1= 6x+6[/tex]
Slope-intercept form requires y to be isolated. 1 is being added to y. The inverse of addition is subtraction. Subtract 1 from both sides.
[tex]y+1-1=6x+6-1 \\y= 6x+5[/tex]
The equation of the line in slope-intercept form is y=6x+5
A boardwalk game of chance costs 2 dollars to play. You have a 20% chance of winning 1 dollar, a 25% chance of winning back your entire 2 dollars, and a 35% chance to win 5 dollars. What is the expected value of playing the game if you lose your bet 20% of the time?
Answer:
For a give event with outcomes:
{x₁, x₂, ..., xₙ}
Each with probabilities:
{p₁, p₂, ..., pₙ}
The expected value is:
Ev = x₁*p₁ + ... + xₙ*pₙ
Here we have the outcomes and probabilities:
win $1, with a probability 20%/100% = 0.2
win $2, with a probability 25%/100% = 0.25
win $5, with a probability of 35%/100% = 0.35
do not win, with a probability of 20%/100% = 0.2
Then the expected value of the game is:
Ev = $1*0.2 + $2*0.25 + $5*0.35 + $0*0.2 = $2.45
And if we know that the game costs $2, then the expected value is:
Ev = $2.45 - $2 = $0.45
The expected value is $0.45
Decrease £180 by 12.5%
Answer:
£ 157.5
Step-by-step explanation:
12.5 × 180 = 22.5
100
180 - 22.5 = 157.5
I hope this helps.
Find the size of the angles marked by letters in the following diagram.
a=132°
b=20°
Answer:
Solution given:
a=132°[exterior angle of a cyclic quadrilateral is equal to the opposite interior angle]
again
In ∆ BCO is similar to ∆ BOE
so
b=20°[corresponding angle of similar triangle are equal]
Please help me anyone
Answer:
115
Step-by-step explanation:
When x = -11, x^2 = 121. y = 121 - 6 = 115.
Hope this helped,
~cloud
Answer:
115
Step-by-step explanation:
y = x^2 - 6
Let x = -11
y = (-11)^2 - 6
y = (121) -6
= 115
Find the circumference and area of a circle with a diameter of 12 cm. (Use the approximation of 3.14 for )
