Answer:
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A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns
Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
things that affects the demand for electricity
Which of the following statements are true with regard to resistivity?
Resistivity is material property. It depends only on temperature. For the same material with different length and area, resistivity remains the same until temperature remains constant.
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Help ppl ..I don’t know nothing
You tie the loose end of a 0.1 kg yo-yo string to your finger and then release the yo-yo so that it spins down toward the ground (the yo-yo is released from rest and the end of the string tied to your finger remains motionless). After the yo-yo falls a distance of 0.9 m, it has a translational speed of 4 m/s and an angular speed of 180 rad/s. What is the moment of inertia of the yo-yo
Answer:
The answer is "[tex]5.06 \times 10^{-6} \ kg \ m^2[/tex]"
Explanation:
[tex]\to E_1=0..............(i)\\\\\to E_2= \frac{mV^2}{2} +\frac{Iw^2}{2} - mgh.............(ii)\\\\ \Delta E=0\\\\\to mgh= \frac{mV^2}{2} +\frac{Iw^2}{2} \\\\ \to 2 \ mgh= mV^2 +Iw^2\\\\ \to 2 \ mgh- mV^2 =Iw^2\\\\ \to m(2gh- V^2) =Iw^2\\\\ \to I= \frac{m(2gh- V^2)}{w^2}[/tex]
[tex]= 5.06 \times 10^{-6} \ kg \ m^2[/tex]
An artery with cross sectional area of 1 cm2 branches into 20 smaller arteries each with 0.5 cm2 cross sectional area. If the velocity of blood in the thicker artery is v, what is the velocity of the blood in the thinner arteries
Answer:
The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.
Explanation:
To find the velocity of the blood we need to use the continuity equation:
[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex] (1)
Where:
n: is the number of branches
A: is the cross-sectional area
v: is the velocity
For artery 1, we have:
n₁ = 1, A₁ = 1 cm², v₁ = v
For the 20 arteries (2), we have:
n₂ = 20, A₂ = 0.5 cm², v₂ =?
By using equation (1):
[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]
[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]
[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]
Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.
I hope it helps you!
How many bonds can antimony form?
Answer:
An antimony can form 3 bonds
Let me know if this helps
Thanks!
:)
Explanation:
An electron (restricted to one dimension) is trapped between two rigid walls 1.40 nm apart. The electron's energy is approximately 19 eV. (a) What is the quantum number n for the energy state that the electron occupies? (b) Based on the quantum number you found in part (a), calculate a more precise value for the electron's energy in eV), expressed to at least three significant figures. (Use any physical constants or unit conversions to at least four significant figures in your calculations.) _________ eV
Answer:
a) n = 9.9 b) E₁₀ = 19.25 eV
Explanation:
Solving the Scrodinger equation for the electronegative box we get
Eₙ = (h² / 8m L²2) n²
where l is the distance L = 1.40 nm = 1.40 10⁻⁹ m and n the quantum number
In this case En = 19 eV let us reduce to the SI system
En = 19 eV (1.6 10⁻¹⁹ J / 1 eV) = 30.4 10⁻¹⁹ J
n = √ (In 8 m L² / h²)
let's calculate
n = √ (8 9.1 10⁻³¹ (1.4 10⁻⁹)² 30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²
n = √ (98) n = 9.9
since n must be an integer, we approximate them to 10
b) We substitute for the calculation of energy
In = (h² / 8mL2² n²
In = (6.63 10⁻³⁴) 2 / (8 9.1 10⁻³¹ (1.4 10⁻⁹)² 10²
E₁₀ = 3.08 10⁻¹⁸ J
we reduce eV
E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)
E₁₀ = 1.925 101 eV
E₁₀ = 19.25 eV
the result with significant figures is
E₁₀ = 19.25 eV
21.Which of the following contain the molecules with the highest average speed?
C
L 나
G G
ico
cube
at -10°C
water
at roon
temperature
wood
at room
temperature
steam
at 110°C
1. A person weighs 155 lbs and is walking 3.1 miles per hour. How much kinetic energy does the person have? (Keep in mind, 1 kg is 2.2 lb, and 1 m/s is 2.24 mi/h.)2. What is the kinetic energy of a 5 g bullet travelling 400 m/s?
3. Is it possible to have a negative KE? Why or why not?
Answer:
Explanation:
Kinetic energy is expressed as;
KE =1/2 mv²
M is the mass
v is the velocity of the object
1) Given
Mass = 155lb
Velocity = 3.1mi/hr
Since 1kg = 2.2lb
x = 155lb
x= 155/2.2
x = 70.45kg
Also
1m/s = 2.24mi/hr
y = 3.1mi/hr
y = 3.1/2.24
y = 1.384m/s
KE = 1/2(70.45)(1.384)²
KE = 0.9577×70.45
KE = 67.47Joules
2) M = 5g =0.005kg
V = 400m/s
KE = 1/2(0.005)400²
KE = 80000×0.005
KE = 400Joules
3} Since a body decelerates (negative acceleration) this mean that the velocity of a body can be a negative value showing that it is possible for a moving body to possess negative kinetic energy.
Explain what forces act on human body in equilibrium.
A student is pouring equal amounts of water, maple syrup, and cooking oil into a glass beaker and looking at how the
layers settle. Which property of the liquids is the student MOST likely comparing?
A volume
B mass
temperature
D density
HELP PLEASE!!!! :( Does anyone have Lab: Conservation of Linear Momentum for online Physics class?? WILL GIVE YOU 80 PTS
Answer:
this is it
Explanation:
the control and experiemental groups i didnt know
A student builds an electromagnet using a battery, an iron nail, and some insulated wire. The wire is wrapped around the nail 50 times, then connected to the
battery. What changes could the student make to increase the strength of the electromagnet?
1. wrap more wire around the nail
2. increase the voltage of the battery
3. use a switch to turn the electromagnetic on and off
4. increase the size of the nail
A. 1 and 2
B. 2 and 4
C. 1,2 and 4
D. 1,2,and 3
Answer:
a
Explanation:
its right
To increase the electromagnet's strength, the student must enlarge the nail, wrap more wire around the nail, and increase the voltage of the battery. Option c is the correct answer.
How does an electromagnet work?The mechanics of an electromagnet are not overly complicated. It is accomplished by wrapping a length of conductive wire, usually copper, around a metal object.Until electricity is introduced, this appears to be nothing more than a jumbled collection of parts, similar to Frankenstein's monster. An electromagnet, on the other hand, does not require a storm to be activated. A current is introduced and flows through the wire, which can come from a battery or another source of power.As a result of the magnetic field created around the coiled wire, the metal is magnetized as if it were a permanent magnet. Electromagnets are useful because they can be activated and deactivated by closing and opening a circuit.To learn more about electromagnet, refer to
brainly.com/question/7382276
#SPJ2
Two ice skaters with masses of 40 kg and 60 kg stand together on frictionless ice. The first skater pushes against the second. When the first skater has moved a distance of 12 m, how far has the second skater moved? A12 mB 10 mC 8 mD Cannot determine without knowing the force of the push. E 0 m
Answer:
c.8
Explanation:
Full moon is located______
a. farthest from the Sun
b. at a 90 degree angle with the Sun and Earth
c. closest to the Sun
Answer:
Im going to take an educated guess and say its B.
Explanation:
A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
What is a Full moon?A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.
When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.
Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
To learn more about the Full moon, refer to the link:
https://brainly.com/question/15032553
#SPJ2
If you cannot exert enough force to loosen a bolt with a wrench, which of the following should you do?
Question 5 options:
1.) Tie a rope to the end of the wrench and pull on the rope.
2.) Use a wrench with a longer handle.
3.) You should exert a force on the wrench closer to the bolt.
4.) Use a wrench with a shorter handle.
Answer:
2.) Use a wrench with a longer handle.
Explanation:
It is suggested to use a wrench with longer handle if you cannot exert enough force to loosen a bolt with a wrench.
In doing this work, the torque which is the force that can turn the screw is not enough;
Torque = force x distance
If we increase the distance or the length of the handle, we can generate more torque to overcome the force needed.
b. Interpret Data Solution A has a pH of 1.6.
Solution B has a pH of 4. Which solution
has a greater concentration of hydrogen
ions? Explain.
Answer:
Solution A has a pH of 6 and solution B has a pH of 8. Which of the following is true regarding the concentration of hydrogen ions in each solution? A) A has 100 times greater H+ concentration than B. B) B has 100 times greater H+ concentration than A. C) A has 7/9 of the H+ concentration of B. D) A has 9/7 of the H+ concentration of B. E) none of these
Explanation:
Hey im super sorry if i get this wrong :)
A car drives 150 km SE and then 50 km due N. What is the car's displacement?
Answer:
If the car travels 150 kilometers to the Southeast, and then 50 kilometers to the North, it is understood that the car does not travel the same way out as it does back. Therefore, the car's displacement will be the sum of both distances traveled, that is, 150 + 50, which is equal to 200. Therefore, the car traveled about 200 kilometers from its starting point.
A 3.63.kgkg chihuahua charges at a speed of 3.3m/s3.3m/s. What is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s0.50s
Answer:
23.96 N
Explanation:
From the question given above, the following data were obtained:
Mass of Chihuahua (m) = 3.63 kg
Velocity (v) = 3.3m/s
Time (t) = 0.50 s
Force (F) =?
Next, we shall determine the acceleration of the Chihuahua. This can be obtained as follow:
Velocity (v) = 3.3m/s
Time (t) = 0.50 s
Acceleration (a) =?
a = v/t
a = 3.3/0.5
a = 6.6 m/s²
Thus, the acceleration of the Chihuahua is 6.6 m/s².
Finally, we shall determine the force need to stop the Chihuahua as shown below:
Mass of Chihuahua (m) = 3.63 kg
Acceleration (a) = 6.6 m/s².
Force (F) =?
F = ma
F = 3.63 × 6.6
F = 23.96 N
Therefore, a force of 23.96 N is needed to stop the Chihuahua.
Answer:
The magnitude of the average force needed to bring the chihuahua to a stop is 23.96 N
Explanation:
Newton's second law states that the acceleration of an object is inversely proportional to the mass of the object. The greater the mass of an object, the less its acceleration will be if a given net force is applied to it. In other words, mass is a property of objects that opposes acceleration when a force is applied.
In this way, Newton's second law says that the acceleration of a body is proportional to the resultant of forces on the acting and inversely proportional to its mass. This is expressed by the mathematical relationship:
F = m * a
where:
F = Force [N]
m = Mass [kg]
a = Acceleration [[tex]\frac{m}{s^{2} }[/tex]]
You know that 3.63 kg chihuahua charges at a speed of 3.3m/s and you need to bring the chihuahua to a stop in 0.50s.
A motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies by the same amount in each unit of time, so that the acceleration is constant. In this case the uniformly varied rectilinear motion is fulfilled. Being:
velocity (final) = velocity (initial) + acceleration * time
vf = vi + a * t
the acceleration is:
[tex]a=\frac{vf-vi}{t}[/tex]
In this case:
vf= 0 [tex]\frac{m}{s}[/tex] because the chihuahua stops.vi= 3.3 [tex]\frac{m}{s}[/tex]t=0.50 sReplacing:
[tex]a=\frac{0\frac{m}{s} -3.3 \frac{m}{s} }{0.50 s}[/tex]
Solving:
a= -6.6 [tex]\frac{m}{s^{2} }[/tex]
Then the magnitude of the average force can be calculated as:
F=m*a
F=3.63 kg* (-6.6[tex]\frac{m}{s^{2} }[/tex] )
Solving:
F= - 23.96 N
The magnitude of the average force needed to bring the chihuahua to a stop is 23.96 N
When electrons are gained, a ion is formed.
Answer:
Ions are formed when atoms lose or gain electrons in order to fulfill the octet rule and have full outer valence electron shells. When they lose electrons, they become positively charged and are named cations. When they gain electrons, they are negatively charged and are named anions.
Explanation: CAN I RECEIVE A BRAINLIEST PLEASE
Can someone please help me with this problem. I’ve tried but I can’t seem to figure it out.
Find an expression for the center of mass of a solid hemisphere, given as the distance R from the center of the flat part of the hemisphere. Express your answer in terms of R. Express the coefficients using three significant figures.
Answer:
z_c = ⅜R
Explanation:
If we assume that the hemisphere has uniform density, we can express the centre of mass as;
z_c = (ρ/M)∫∫∫ z•dV
We know that density(ρ) = mass(M)/volume(V)
Thus, Vρ = M
And volume of hemisphere = 2πr³/3
Thus;
2Vρπr³/3 = M
So;
z_c = (ρ/(2Vρπr³/3))∫∫∫ z•dV
Where r = R in this case.
ρ will cancel out to give;
z_c = (3/(2πr³))∫∫∫_V (z•dV)
In spherical coordinates,
r is radius
Φ = angle between the point and the z − axis
θ = azimuthal angle
Therefore, the integral becomes what it is in the attached image.
I've completed the explanation as well in the attachment.
if an object is moving with a velocity of 25m/s, an acceleration of 5m/s and has a travel time of 5s, what is the final velocity of the object?
V = at + V0
where v0 is the initial speed, a is the acceleration and t is the time.
So:
v = 5m/s^2*5s + 25m/s = 50 m/s
Moderate injuries are generally __________.
A.
life-threatening
B.
soft tissue injuries
C.
bumps and bruises
D.
too serious for first aid
Please select the best answer from the choices provided.
A
B
C
D
Answer:
B. soft tissue injuries
Explanation:
i took the test on edge and its really the only one that would make sense if you payed attention to the lesson :)
A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/s2 about an axis through the center of the shell. What is the rotational inertia of the shell about the axis of rotation
Answer:
[tex]I=182.97\ kg-m^2[/tex]
Explanation:
Given that,
Radius of a spherical shell, r = 0.7 m
Torque acting on the shell, [tex]\tau=860\ N[/tex]
Angular acceleration of the shell, [tex]\alpha =4.7\ m/s^2[/tex]
We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :
[tex]\tau=I\alpha[/tex]
I is the rotational inertia of the shell
[tex]I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2[/tex]
So, the rotational inertia of the shell is [tex]182.97\ kg-m^2[/tex].
What are the 6 basic machines, and what are they and what can the be, and look like.
Answer:
Pulleys, levers, inclined planes, wedges, screws, and wheel and axle.
Explanation:
What is the momentum of 100 kg running at 4m/s north?
How long would it take a 500. W electric motor to do 15010 J of work?
What is the mass of a bullet in free fall with a force of 300N?
