A balloon is going vertically upwards at a speed of 10 ms-1 . When it was 30 m above the ground, an object is dropped from it. How long does the object take to reach the ground? (g = 10 ms-1 )​

Answer:

D) 88 degrees

Step-by-step explanation:

Angle ABC is 1/2Arc AC (Inscribed angle theorem)

Answer:

3 + 2k

Step-by-step explanation:

Given:

1/5(15 + 10k)

= (1/5 * 15) + (1/5 * 10k)

= (1 * 15)/5 + (1 * 10k)/5

= 15/5 + 10k/5

= 3 + 2k

Therefore,

1/5(15 + 10k) = 3 + 2k

The equivalent expression is 3 + 2k

First, we need to set up our two equations. For the picture of this scenario, there is one length (L) and two widths (W) because the beach removes one of the lengths. We will have a perimeter equation and an area equation.

P = L + 2W

A = L * W

Now that we have our equations, we need to plug in what we know, which is the 40m of rope.

40 = L + 2W

A = L * W

Then, we need to solve for one of the variables in the perimeter equation. I will solve for L.

L = 40 - 2W

Now, we can substitute the value for L into L in the area equation and get a quadratic equation.

A = W(40 - 2W)

A = -2W^2 - 40W

The maximum area will occur where the derivative equals 0, or at the absolute value of the x-value of the vertex of the parabola.

V = -b/2a

V = 40/2(2) = 40/4 = 10

Derivative:

-4w - 40 = 0

-4w = 40

w = |-10| = 10

To find the other dimension, use the perimeter equation.

40 = L + 2(10)

40 = L + 20

L = 20m

Therefore, the dimensions of the area are 10m by 20m.

Hope this helps!

Answer:

Width: 10 m

Length: 20 m

Step-by-step explanation:

Hi there!

Let w be equal to the width of the enclosure.

Let l be equal to the length of the enclosure.

1) Construct equations

[tex]A=lw[/tex] ⇒ A represents the area of the enclosure.

[tex]40=2w+l[/tex] ⇒ This represents the perimeter of the enclosure. Normally, P=2w+2l, but because one side isn't going to use any rope (sandy beach), we remove one side from this equation.

2) Isolate one of the variables in the second equation

[tex]40=2w+l[/tex]

Let's isolate l. Subtract 2w from both sides.

[tex]40-2w=2w+l-2w\\40-2w=l[/tex]

3) Plug the second equation into the first

[tex]A=lw\\A=(40-2w)w\\A=40w-2w^2\\A=-2w^2+40w[/tex]

Great! Now that we have a quadratic equation, we can do the following:

4) Solve for w

[tex]A=-2w^2+40w[/tex]

Factor out -2w

[tex]A=-2w(w-20)[/tex]

For A to equal 0, w=0 or w=20.

The average of 0 and 20 is 10, so the width that will max the area is 10 m.

5) Solve for l

[tex]40=2w+l[/tex]

Plug in 10 as w

[tex]40=2(10)+l\\40=20+l\\l=20[/tex]

Therefore, the length of 20 m will max the area.

I hope this helps!

Answer:

x = [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

Given

[tex]\frac{4}{5}[/tex] x - [tex]\frac{1}{10}[/tex] = [tex]\frac{3}{10}[/tex]

Multiply through by 10 ( the LCM of 5 and 10 ) to clear the fractions

8x - 1 = 3 ( add 1 to both sides )

8x = 4 ( divide both sides by 8 )

x = [tex]\frac{4}{8}[/tex] = [tex]\frac{1}{2}[/tex]

Answer:

6

Step-by-step explanation:

A = π. r²

36π = π. r²

eliminate π, we get:

36=r²

r=√36

r = 6

Answer:

r = 6

Step-by-step explanation:

The area (A) of a circle is calculated as

A = πr² ( r is the radius )

Given A = 36π , then

πr² = 36π ( divide both sides by π )

r² = 36 ( take the square root of both sides )

r = [tex]\sqrt{36}[/tex] = 6

Answer:

200

Step-by-step explanation:

Substitute 15 for y

[tex] \frac{1}{5} x - \frac{2}{3} (15) = 30[/tex]

[tex] \frac{1}{5} x - 10 = 30[/tex]

[tex] \frac{1}{5} x = 40[/tex]

[tex]x = 200[/tex]

Answer:

Step-by-step explanation:

Equation for the total volume of the bucket has been given as,

V = 4 + 2t

Here V = Total volume

t = elapsed time

Table for the input-output values,

t        0         1         2        3        4

V       4         6        8        10      12

Therefore, line passing through the given points in the table will be the graph for the equation.

Answer:

Step-by-step explanation:

There are 10 common trig identities which I am aware of.

Some are in the image attached

The first image is known as b

Basic Identities

The second are known as Trigonometric / Pythagorean Identities .

The third : Co-function identities

and many more.

I'm only allowed to post five images so that's all I have.

Answer:

x = 0

Step-by-step explanation:

First, multiply 4 by x+1

4x + 4 = 3x + 4

Subtract 3x on both sides

x + 4 = 4

Subtract 4 from both sides

x =

this is x = 0, since x = nothing.

Answer:

x=0

Step-by-step explanation:

4(x+1)= 3x+4

Distribute

4x+4 = 3x+4

Subtract 3x from each side

4x-3x+4 =3x-3x+4

x+4 = 4

Subtract 4 from each side

x+4-4 = 4-4

x=0

Answer:

Step-by-step explanation:

-9 is greater than the value of -12 because -9 is to the right of -12 on the number line.

Answer:

All numbers have an equal chance of being landed on.

Answer:

[tex] = { \tt{50 - 2(32 + 1)}}[/tex]

Solve the bracket:

[tex] = { \tt{50 - 2(33)}}[/tex]

Open the bracket:

[tex]{ \tt{ = 50 - 66}}[/tex]

Subtract the expression:

[tex]{ \bf{ = - 16}}[/tex]

Step-by-step explanation:

Multiply 2 by 32 and 1

50-64-2

-14-2

-16 Answer

Answer:

Added

Step-by-step explanation:

For example, take the arithmetic sequence of 3, 5, 7, 9...

Here, the number that gets us from the first number to the second (from 3 to 5), is 2. Meaning, we need to add 2 to 3 in order to get 5. I believe that makes "addition" or "added" the answer. Please let me know if I misunderstood and I will change my answer! Thank you!

Answer:

added or subtracted

Step-by-step explanation:

The measure of the angle ∠R in the right-angle triangle will be 37°. Then the correct option is A.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180°.

We know that the radius of the circle and the tangent line of the circle will intersect at the right angle which is 90°.

And the angles of the triangle will be supplementary angles. Then the equation is given as,

∠P + ∠Q + ∠R = 180°

53 + 90° + ∠R = 180°

∠R = 37°

The measure of the angle ∠R in the right-angle triangle will be 37°. Then the correct option is A.

More about the triangle link is given below.

https://brainly.com/question/25813512

#SPJ7

Answer:

x =  20

Step-by-step explanation:

The consecutive angles in a parallelogram are supplementary, sum to 180°

5x + 4x = 180

9x = 180 ( divide both sides by 9 )

x = 20

Answer:

The value of x is 40⁰.

Step-by-step explanation:

5x + 4x = 360⁰

DUE TO THE SUM OF QUADRATIC ANGLE.

Answer:

<BCO​ = <BAO​ = 20degrees

Step-by-step explanation:

If <ABC measures 100 and is inscribed in a circle O. find <BAO and <BCO​

To get <BAO and <BCO​, we need to get <AOC first.

From the figure, it can be seen that triangle ABC is an isosceles trinagle. Hence;

<BAC + <BCA + 100 = 180

Since <BAC = <BCA

<BAC + <BAC = 180 - 100

2<BAC = 80

<BAC = 80/2

<BAC = 40

Also;

<BAO = <BCO​ and <BAO = <BAC/2

<BAO = 40/2 = <BCO​

Hence <BCO​ = <BAO​ = 20degrees

Answer:

(0, 170) (5, 150) (60, -170)

Step-by-step explanation:

Plug each x value into the equation. The point is located on the line if the y values match.

Ex. -4 (170) + 170 = -510 this point is not on the line

-4 (0) + 170 = 170 this point is on the line because it is a "true" statement

Answer:

(0, 170) (5, 150) (60, -170)

Step-by-step explanation:

Answer:

2×5×7+2×5×2+2×7×2

70+20+28

108cm^2

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

[tex]l = 5 \: cm \\ w = 2 \: cm \\ h = 7 \: cm[/tex]

The formula to find SA => 2lh + 2lw + 2hw

[tex]SA => 2lh + 2lw + 2hw \\ = 2 \times 5 \times 7 + 2 \times 5 \times 2 + 2 \times 7 \times 2 \\ = 70 + 20 + 28 \\ = 118 \: \: cm {}^{2} [/tex]

=> The surface area of the rectangular prism is 118 cm².

Answer:

Yes my son they do so yeah

Step-by-step explanation:

Cuz I know

Answer:

second one

Step-by-step explanation:

just read where the purple line finishes on the x axis, in this case it’s 5 so it’s greater than 5 or equal to it.

Answer:

DOMAIN

RANGE

Answer:

s + l > 300

40 * s + 90 * l > 1500

Step-by-step explanation:

Let's say the amount of small bags is equal to s and the amount of large bags is equal to l.

The total amount of bags is equal to the sum of the small bags and large bags, as there can only be small or large bags. Therefore, the total amount of bags is equal to s + l. As the total amount of bags is greater than 300, we can write

s + l > 300

Next, the total number of packets of crackers exceeds 1500. We can find the total number of packets based on the amount of small and large bags. Because each small bag holds 40 packets, we can say that the amount of packets in small bags is equal to 40 * s. Similarly, the total amount of packets in large bags is equal to 90 * l. Therefore, the total amount of packets is equal to

40 * s + 90 * l

and since the total number of packets is greater than 1500, we can say

40 * s + 90 * l > 1500

Answer:

C

Step-by-step explanation:

Answer:

2 units

Step-by-step explanation:

Using the given formula

P = 2(l + w)

  = 2([tex]\frac{2}{3}[/tex] + [tex]\frac{1}{3}[/tex] )

   = 2(1)

   = 2 units

Answer:

We should expect 818 chicks to hatch in 19 to 28 days

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 22 days and standard deviation of approximately 3 days.

This means that [tex]\mu = 22, \sigma = 3[/tex]

Proportion between 19 and 28 days:

p-value of Z when X = 28 subtracted by the p-value of Z when X = 19.

X = 28

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{28 - 22}{3}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a p-value of 0.977.

X = 19

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{19 - 22}{3}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a p-value of 0.159.

0.977 - 0.159 = 0.818

Out of 1000:

0.818*1000 = 818

We should expect 818 chicks to hatch in 19 to 28 days

Answer:

Step-by-step explanation:

If the 2 lines are parallel

then x = 70 cos ( alternate interior angle)

but if not sorry man I just in grade 9 its my best effort

Really sorry. <3

:(

Answer:

l

Step-by-step explanation:

Answer:

22x 28 x 25 x 30 = 462000

whats are the units.....cm or m

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{22(28)(25)(30)}\\\large\textsf{22(28) = \bf 616}\\\large\textsf{616(25)(30)}\\\large\textsf{616(25) = \bf 15,400}\\\large\textsf{15,400(30)}\\\large\textsf{ = \bf 462,000}\\\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 462,000}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The question is incomplete. The complete question is :

Small Manufacturing Company has a standard overhead rate of $42 per hour. The labor rate is $15 per hour. Overhead is applied based on direct labor hours. Jobs B-1 and B-2 were completed during the month of March. Small incurred 140 hours of indirect labor during the month. Job B-1 used 82 direct labor hours and $3650 worth of direct material used. Job B-2 used 130 direct labor hours and $2,900 worth of direct material. What is the total cost of job B-2? Round to closest whole dollar (no cents).

Solution :

Particulars                                                        Job B-2

Direct material used                                        $ 2,900

Add : Direct labor cost (130 hours x $15)       $ 1,950

Add : overhead cost (130 hours x $ 42)         $ 5,460  

Total Cost of Job B-2                                      $ 10,310

Therefore, the total cost of the Job B-2 is $ 10,310.

answer:

-4

Step-by-step explanation:

-3x>12

x<-4

the correct graph is graph b