Explanation:
= 5 cm = 0.05 m
T = 0.2 s
ω=2π/T=2π/0.2=10πrad/s
When displacement is y, then acceleration, a=−ω2y
Velocity, V=ωr2−y2
Case (a) When y=5cm=0.05m
a=−(10π)2×0.05=−5π2m/s2
V=10π×(0.05)2−(0.05)2=0
Case (b) When y=3cm=0.03m
a=−(10π)2×0.03=−3π2m/s2
V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s
Case (c) When y=0
a=−(10π)2×0=0
V=10π×(0.05)2−02=
hope it helps. pls follow and mark as brainliest
You slide a 15 kg box down a ramp with friction set to an angle of 38°. If the height of the ramp is 1.2 m, what's the frictional force on the box as it gets to the bottom of the ramp if the applied force down the ramp is 52 N?
Answer:
38.75N
Explanation:
According to Newton's second law
\sum Fx = ma
Fm-Ff = ma
Fm is the moving force
Fm = mgsin theta
Fm = 15(9.8)sin38
Fm = 90.5N
Ff is the frictional force
m is the mass = 15kg
a is two acceleration
Get the acceleration
a= F/m
a = 52/15
a ,= 3.45m/s²
Substitute the given values into the formula
90.5-Ff = 15(3.45)
90.5-Ff = 51.75
Ff = 90.5-51.75
Ff = 38.75N
Hence the frictional force on the box is 38.75N
A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls collide and stick together. What is their velocity immediately after the collision?
Answer:
8.3m/s
Explanation:
Given parameters:
mass of clay ball = 5kg
Speed of clay ball = 25m/s
mass of clay ball at rest = 10kg
speed of clay ball at rest = 0m/s
Unknown:
Velocity after collision = ?
Solution:
Since the balls stick together, this is an inelastic collision:
m1v1 + m2v2 = v(m1 + m2)
5(25) + 10(0) = v (5 + 10)
125 = 15v
v = 8.3m/s
HELLLPPPPPPPPPPPPPPPPPP
Answer:
If you going to ask a question ask it accurately.
Explanation:
Why does a concave lense always form a virtual image?
Answer:
Concave lens spreads out light rays that are then refracted through it.: A concave mirror or a converging lens will only produce a virtual image at a point if the image is located beyond the focal point. By the focal point, we define the point that is more than one focal length away.
define specific heat capacity
1. How much heat must be absorbed by 375 grams of water to raise its
temperature by 25° C?(Cp of water is 4.184)
Answer:
39225J
Explanation:
Given parameters:
Mass of water = 375grams of water
Change in temperature = 25°C
Specific heat capacity of water = 4.184J/g°C
Unknown:
Amount of heat absorbed = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the heat absorbed
m is the mass
c is the specific heat capacity
Ф is the change in temperature
Insert the parameters and solve;
H = 375 x 4.184 x (25) = 39225J
Jeff throws a ball straight up. For which situation is the vertical velocity zero?
a. on the way up
b. at the top
c. on the way back down
d. none of the above
Answer:
b. at the top
Explanation:
At the top of the climb, the vertical velocity of Jeff's throw has a value of zero.
Vertical velocity in this instance is acting against the acceleration due to gravity.
At the top of the thrown, the force of the throw becomes zero and the velocity also becomes zero. As the body finds it way downward, it begins to fall freely. The fall is due to the acceleration due to gravity which is experienced by every object on earth.Hello, what does the first condition mean?
Answer:
An object at rest is described by Newton's First Law of Motion. An object in static equilibrium has zero net force acting upon it. The First Condition of Equilibrium is that the vector sum of all the forces acting on a body vanishes.
Explanation:
Answer:
see below
Explanation:
the first condition means that the light ray inside the optically denser medium hits the surface of the optically less dense medium.
this in simple words means, light must be travelling from am optically denser medium to an optically less dense medium
hope this helps :)
What must happen to an object in order to accelerate it?
Answer:
For an object to accelerate, appropriate force must be applied to the object to cause it to change it’s velocity if it’s already in motion. However, to cause it to overcome static friction if it is at rest, and cause it to change it’s velocity
Explanation:
Which change of state takes place when a gas loses energy?
A. condensation
B. evaporation
C. molting
D. solidification
Answer:
Condensation (((((((((((((
The difference between temperature and thermal energy is that___________.
Answer:
Heat vs temperature - Energy Education The core difference is that heat deals with thermal energy, whereas temperature is more concerned with molecular kinetic energy. Heat is the transfer of thermal energy, whereas temperature is a property the object exhibits.
Starting from rest, a sprinter reaches his top velocity in 3 seconds. He runs a distance of 24m in 3 seconds. What is his acceleration? (Assume his acceleration is uniform)
Answer:
[tex]a=5.34\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity of a sprinter, u = 0
He runs a distance of 24m in 3 seconds.
We need to find his acceleration. Let a be his acceleration. Using second equation of kinematics to find it.
[tex]s=ut+\dfrac{1}{2}at^2\\\\24=0+\dfrac{1}{2}a(3)^2\\\\a=\dfrac{24\times 2}{9}\\\\a=5.34\ m/s^2[/tex]
So, the acceleration of the sprinter is [tex]5.34\ m/s^2[/tex].
The acceleration of the sprinter from rest to his top speed is 5.33m/s²,
Given the data in the question
Since the sprinter starts from rest,
Initial velocity; [tex]u = 0[/tex]Time taken; [tex]t = 3s[/tex]Distance covered; [tex]s = 24m[/tex]Acceleration; [tex]a = \ ?[/tex]
To determine the acceleration of the sprinter, we use the second equation of motion:
[tex]s = ut + \frac{1}{2}at^2[/tex]
Where s is distance covered, u is initial velocity, a is acceleration and t is time.
We substitute our given values into the equation
[tex]24m = [0 * 3s] + [\frac{1}{2} * a * (3s)^2]\\\\24m = \frac{1}{2} * a * 9s^2\\\\24m = a * 4.5s^2\\\\a = \frac{24m}{4.5s^2} \\\\a = 5.33m/s^2[/tex]
Therefore, the acceleration of the sprinter from rest to his top speed is 5.33m/s²
Learn more: https://brainly.com/question/18835025
A plane flew at a speed of 600 km/hr for a distance of 1500 km,
How long did take to get to its destination
Explanation:
600 ÷ 60 = 10
1500 ÷ 10 = 150 minutes
I don't know how you should express the answer in:
So it's either 150 minutes or 2 hours and 30 minutes.
(This is kind of like mathematics, not physics)
HELP PLEASE!
A 700 kg race car makes one lap around a track. It has a velocity of 20 m/s with a centripetal force of 5,600 N. What is the radius of the track?
A speed skater goes around a turn with a 25 m radius. The skater has a velocity of 15 m/s and experiences a centripetal force of 720 N. What is the mass of the skater?
A 900-kg car moving at 5 m/s takes a turn around a circle with a radius of 30 m. Determine the net force acting upon the car.
An 800 kg race car makes one lap around a track. It has a velocity of 40 m/s with a centripetal force of 16,000 N. What is the radius of the track?
PLEASE EXPLAIN AND SHOW WORK!
The centripetal force is the force that keeps a body moving in a circular path.
The centripetal force is given by; F = mv^2/r
1) We have;
F = 5,600 N
v = 20 m/s
r =?
m = 700 kg
Making r the subject of the formula;
r =mv^2/F
r = 700 × (20)^2/5,600
r = 50 m
2) F = mv^2/r
F = 900 × (5)^2/30
F = 750 N
3) Making r the subject of the formula;
r =mv^2/F
r = 800 × (40)^2/ 16,000
r = 80 m
Learn more: https://brainly.com/question/11324711
The eagles suck, so do the giants and the jets and jaguars are irrelevant
anyone wanna argue
Naw ur pretty accurate, heck collage is the only football worth watching most the time. Hook'um horns!
what happens if I increase the height of a skater
Answer:
The higher the skater is the more potential energy he has. As his height decreases, his potential energy decreases and his kinetic energy increases.
Explanation:
Make me BRAINLIST please
Answer:
The higher the skater is the more potential energy he has. As his height decreases, his potential energy decreases, and his kinetic energy increases. ... Explore how the skater's change in speed relates to the potential and kinetic energy of the skater.
Explanation:
(Via Uteach)
A flight attendant pulls her 70 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 41 N at an angle of 57° above the horizontal.
Complete question :
A flight attendant pulls her 70 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 41 N at an angle of 57° above the horizontal.
(a) Find the work she does on the flight bag.
(b) Find the work done by the force of friction on the flight bag.
(c) Find the coefficient of kinetic friction between the flight bag and the floor.
Answer:
7107 J ; - 7107 J ; 0.55
Explanation:
Given that :
Distance, d = 318m
Applied force = 41 N
θ = 57°
A.) Workdone = Force exerted along direction of motion
Workdone = applied Force * distance * cosθ
Workdone = 41 * 318 * cos57 = 7101.0037
Workdone = 7,101 J
B.) Workdone by force of friction on flight bag:
- 7,101 J (since the body moves at constant velocity)
C.)
Coefficient of kinetic friction (μ) = Frictional force / normal reaction)
μ = F / N
Frictional force, F = Workdone by friction / distance
F = 6200 / 318
F = 19.47N ;
Ff = weight of Flight bag = 70 N
N = Ff - Fsinθ
N = 70 - applied Force sinθ
N = 70 - 41sin57
N = 70 - 34.385493
N = 35.614506
μ = 19.47 / 35.614506
μ = 0.5466873
A dog starts at the origin and runs forward at 6m/s for 1.5s and then turns around to fetch the ball by running backward at 7m/s for 3s. If the dog runs back to the origin at 4m/s the how much time has elapsed between the start and when he returns with the ball
Answer:
Total time elapsed between the start and when he returns with the ball is 7.5s
Explanation:
From the question,
- The dog starts at the origin and runs forward at 6m/s for 1.5s. First, we will determine the distance covered while running forward.
From
Speed = Distance / Time
Distance = Speed × Time
Speed = 6m/s
Time = 1.5s
∴ Distance = 6m/s × 1.5s
Distance = 9m
That is, the dog covered a distance of 9m while running forward.
- The dog turns around and runs backward at 7m/s for 3s. Now, we will also determine the distance the dog covered backwards.
Distance = Speed × Time
Speed = 7m/s
Time = 3s
Distance = 7m/s × 3s
Distance = 21m
The dog's displacement from the origin is 21m - 9m = 12m
Now, to calculate how much time has elapsed between the start if the dog runs back to the origin at 4m/s, we will first determine the time the dog spent back to the origin and then add to the time spent for the first two distances.
To get back to the origin, the dog needs to cover 12m
From
Speed = Distance / Time
Time = Distance / Speed
Distance = 12m
Speed = 4m/s
∴ Time = (12m) / (4m/s)
Time = 3s
Therefore, the dog spent 3s to run back to the origin.
Hence, total time elapsed = 1.5s + 3s + 3s
Total time elapsed = 7.5s
The two blocks shown below have masses m1 = 400 g and m2 = 600 g. They are connected by a string and lie on a frictionless tabletop. A 3.5 N force is applied to block m2, pulling it to the right. Find the acceleration then find the tension force in the string between two objects
Calculate the temperature change when 1000J of heat is supplied to 100g of water.
Please explain
Explanation:
Given
heat supplied (Q) = 1000 J
mass(m) = 100 g = 0.1 kg
specific heat capacity of water(s) = 4200 J/kg°C
change in Temperature (dt) = ?
We know we have the relation
Q = m * s * dt
Or, 1000 = 0.1 * 4200 * dt
Or, 1000 = 420 dt
Or, dt = 1000/ 420
Therefore dt = 2.38°
Hope it will help :)
The temperature changes when 1000J of heat is supplied to 100g of water is dt = 2.38°
What is temperature?The average kinetic energy of a system is measured by its temperature. The kinetic energy of a system starts to rise as the particle's velocity increases, which raises the system's temperature.
The energy that is transferred when two bodies with different surface temperatures come in touch is referred to as heat.
The change is when 1000J of heat is supplied to 100g of water.
Given that:
heat supplied (Q) = 1000 J
mass(m) = 100 g = 0.1 kg
specific heat capacity of water(s) = 4200 J/kg°C
Change in Temperature (dt) = ?
We know we have the relation
Q = m x s x dt
Or, 1000 = 0.1 x 4200 x dt
Or, 1000 = 420 dt
Or, dt = 1000/ 420
Therefore, the temperature changes when 1000J of heat is supplied to 100g of water is dt = 2.38°.
To learn more about temperature, refer to the link:
https://brainly.com/question/11464844
#SPJ2
How much potassium nitrate (KNO3) would dissolve in 50 milliliters of water at 45ºC given that 55g of KNO3 is dissolved in 150mL of water at 45°C.
A. 19.7g
B. 15.1g
C. 18.3g
D. 23.3g
Compare between Convex lens and concave lens
Answer:
A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.
Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees ?
Answer:
No work is done since no distance is given
Explanation:
Since no distance is given, the force is not doing any work
No work is done by the man since we do not know the distance or displacement.
Work is only said to be done when the force applied on an object moves it through a particular distance.
Work done = Force x distance.
Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.
What state of matter can easily be compressed (squeezed into a much smaller space)? *
gases
solids
solids, liquids, and gases
liquids
Answer:
gases.
Explanation:
gases have the highest volume. if you compress (increase pressure) a gas, the volume decreases and it will take up less space as a liquid, and if you compress more, the liquid will become a solid.
additionally info: this is generally true, but as you get into more difficult subjects, this rule does not hold. for example, some substances cannot obtain a certain phase of matter when they are a certain temperature and or pressure. but that could be way more out of this questions league.
Why does Farm Bureau and other advocacy organization oppose any mandated labeling of biotech crops?
Answer:
I’m. Nog sure
Explanation:
A 5.75 g bullet is fired with a velocity of 1.50 x 102 m/s toward a stationary solid block resting on a frictionless surface. The bullet embeds but the block does not move. 1. What is the change in momentum of the bullet if it embeds in the block? 2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?
Answer:
1. -0.863 kgm/s 2. -1.438 kgm/s
Explanation:
1. What is the change in momentum of the bullet if it embeds in the block?
Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s
Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).
So, ΔP = m(v - u)
= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)
= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)
= -8.625 × 10⁻¹ kgm/s
= -0.8625 kgm/s
≅ -0.863 kgm/s
2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?
If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.
So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s
So, ΔP = m(v - u)
= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)
= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)
= -14.375 × 10⁻¹ kgm/s
= -1.4375 kgm/s
≅ -1.438 kgm/s
A softball and a baseball are launched from 2 different pitching machines at the same time.
th
Softball
182 g
165 m/sec
Baseball
143 g
112 m/sec
Which of these BEST explains what factors give the baseball and softball different velocities?
O mass and speed
O mass and direction
O speed and direction
O size and mass
A solar panel gives our 250 Watts
of power in 2 seconds. How much
work did the solar panel do?
Look at the atoms below
a. Atom W: 9 protons and 9 neutrons
b. Atom X: 8 protons and 9 neutrons
c. Atom Y: 9 protons and 9 neutrons
d. Atom Z: 9 protons and 10 neutrons
Which ones below are isotopes of each other and why?
element z are isotopes because number of netron are different and number of protons are same
(97-R) Dos cargas puntuales iguales están separadas por una distancia d. A) ¿Es nulo el campo eléctrico total en algún punto? Si es así, ¿cuál es la posición de dicho punto? B) Repita el apartado anterior suponiendo que las cargas fueran de distinto signo.
Answer:
Explanation:
El campo eléctrico provocado por una carga puntal sobre determinado punto viene dado por la ecuación:
E = K * Q /r² en esa ecuación E es el campo eléctrico (un vector), K es una constante K = 1/4*π*ε₀ Q es la carga que origina el campo, y r la distancia entre la carga y el punto donde se quiere determinar el campo. La fuerza de origen eléctrico y el campo eléctrico van en la dirección de la recta de unión entre carga y punto ( es decir según r) y esta fuerza sera repulsiva o de atracción según que la carga que la origina sea positiva o negativa (respectivamente, ya que en la determinación de fuerza y campo, se asume que se coloca una carga de prueba positiva en el punto ).
Siendo así, si dos cargas elécticas son iguales y están separadas una distancia r ; en el punto medio (r/2) los campos producidos por cada una de las cargas serán de la misma magntud.
Carga Q₁ = Carga Q₂ = Q
E₁ = K * Q₁ / (r/2)² y E₂ = K * Q₂/(r/2)²
Y además tendran direcciones totalmente opuestas, por lo que se anularan
En el segundo caso las cargas son iguales en magntud pero de diferentes signos ( una positiva y la otra negativa ). En este caso los campos eléctricos continuaran siendo de la msma magnitud pero dado que la carga positiva repele la carga de muestra (teorica) y la negativa la atrae los dos campos coinciden en su dirección y resultará una campo de magnitud doble. La dirección del campo será en la tendencia de acercarse a la caga negativa, así si la carga negativa está a la derecha la fuerza de origen eléctrico y el campo van hacia la derecha y si la carga negativa está a la izquierda pues esa será la diercción del campo
