A bulb is filled with Hą gas at a temperature T. The pressure is 756 mmHg. A portion of the gas is transferred to a flask and at 100 kPa, occupies 40.0 mL at the same temperature T. The pressure in the original bulb drops to 625 mmHg at temp. T. What is the volume of the bulb? (NOTE: 100 kPA = 750.0 mmHg)

Answer:

P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3

Explanation:

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.

A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.

Chemical equations must be balanced, which means that the atom types and numbers on both sides of the reaction arrow must match. Coefficients are the values added in front of formulas to balance equations; they multiply each atom in a formula.

Here the given equation is balanced as:

P₄ + 4NaOH + 2H₂O——> 2PH₃ + 2Na₂HPO₃

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Answer:

5–bromo–9–chlorodecane

Explanation:

To name the compound given above, the following must be obtained:

1. The longest continuous carbon chain. This gives the parent name of the compound.

2. The substituent group attached to the compound.

3. Position of the substituent group.

4. Combine the above to obtain the name.

Now, we shall determine the name of the compound as follow:

1. The longest continuous carbon chain is 10. Thus, the parent name of the compound is decane.

2. The substituent groups attached to the compound are:

I. Bromine (Br) => Bromo

II. Chlorine (Cl) => Chloro

3. The position of the substituent groups are:

I. Br => carbon 5

II. Cl => carbon 9

NOTE: numbering is done alphabetically.

4. Therefore, the name of the compound is:

5–bromo–9–chlorodecane

Answer:

A.

Explanation:

I chose this answer and it was correct ‍♀️

Answer:

Explanation:

From the graphical diagram attached below; we can see the relationship between the concentration of [tex]H_2O_2[/tex] which declines exponentially in relation to the time and it obeys the equation: [tex]\mathtt{y = 0.9951 e^{-8\times 10^{-4}x}}[/tex]

This relates to the 1st order reaction rate, whereby:

The integrated rate law[tex]\mathtt{ [A] = [A]_o e^{-kt}}[/tex]

here:

[A] = reactant concentration at time (t)

[A]_o = initial concentration for the reactant

k = rate constant

As such, the order of the reaction is the first order

Rate constant [tex]\mathtt{k = 8\times 10^{-4} {s^{-1}}}[/tex]

Rate law [tex]\mathtt{= k[H_2O_2]}[/tex]

The integrated rate law [tex]\mathtt{[H_2O_2] = [H_2O_2]_oe^{-(8*10^{-4})t}}[/tex]

From the given table:

the initial concentration of [tex]H_2O_2[/tex] = 1.00 M

∴

We can determine the concentration of the reactant at 4000s by using the formula:

[tex]\mathtt{[H_2O_2] = [H_2O_2]_oe^{-8*10^{-4}(t)}}[/tex]

[tex]\mathtt{[H_2O_2] = (1.00\ M)*e^{-8*10^{-4}(4000)\ s}}[/tex]

[tex]\mathtt{[H_2O_2] =0.0407 \ M}[/tex]

Finally, at 4000s: the average rate is:

[tex]\mathtt{= (8*10^{-4} \ s^{-1})(4000 \ s) }\\ \\ \mathtt{ = 3.256 \times 10^{-5} \ M/s}[/tex]

Answer:

he a real G

Explanation:

og tripple og

Answer:

C.

Explanation:

Also, please help me in my questions tab if you can! Thank you so much

Answer:

Equation 1 - nuclear fission

Equation 2 - nuclear fusion

Explanation:

Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.

Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.

In the first reaction, a neutron is released, and in the second a helium atom is released. The given two equations represent nuclear fission and fusion.

A nuclear reaction is a reaction that involves the nuclei of the atom and the absorption and release of energy. In the first reaction, a big nucleus is split by the neutron bombardment into smaller nuclei.

In the second reaction the process of nuclear fusion, two nuclei combine into a single larger nucleus that is shown as:

₁¹H+ ²₁H → ³₂He

Therefore, nuclear fission and fusion are represented by each of these equations.

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Answer:

71.1

Explanation:

Plato

Answer: 19

Explanation:

In order to write the Potassium electron configuration we first need to know the number of electrons for the K atom (there are 19 electrons). When we write the configuration we'll put all 19 electrons in orbitals around the nucleus of the Potassium atom.

Answer:

b. +3 and +6.

Explanation:

Zeff = Z - S

The Z denotes the no of protons i.e. atomic number

S denotes the non-valence electrons

For boron,

the electronic configuration is 1s₂ 2s₂ 2p₄

Now  

Z = 5, S = 2

So,  

Zeff = 5-2

= +3

For O, the electronic configuration is 1s₂ 2s₂ 2p₄

So,  

Z = 8, S = 2

= 8-2

= +6

Hence, the second option is correct

Answer:

48 molecules

Explanation:

From the given reaction:

[tex]\mathtt{P_4 + 6Cl_2\to 4PCl_3}[/tex]

i.e. 1 mole of Phosphorus react 6 moles of chlorine to yield 4 moles of PCl₃

This implies that for each P₄ molecule, we will require 6 molecules of Cl₂

We are provided with 15 molecules of P₄ and 42 molecules of Cl₂

Suppose we utilized the whole 15 molecules of P₄, we will require:

= 15 × 6 = 90 moles of Cl₂ which is not readily available except 42 are available.

If we utilized 42 molecules of Cl₂, we will require 42/6 = 7 molecules of P₄ which is readily available.

From this analysis, we can opine that Cl₂ serves as the limiting agent

∴

P₄ : Cl₂ : PCl₃ = 1 : 6 : 4 = 7 : 42 : 48

It implies that only 48 molecules of phosphorus trichloride will be formed.

Answer:

The solute is salt and the solvent is water

Explain:

Because salt is a component the dissolves in the solvent

Answer:

18.45 g of C

Explanation:

This is a problem of rules of three:

1 mol of C₃H₈ contains 3 moles of C and 8 moles of H

If 8 moles of H are contained in 1 mol of propane

4.10 moles of H are contained in (4.1 . 1) /8 = 0.5125 moles

Now, If 1 mol of propane contains 3 moles of C

0.5125 moles of propane may contain (0.5125 . 3) / 1 = 1.5375 moles of C

Let's convert the moles to mass:

1.5375 mol . 12 g /mol = 18.45 g

Answer:

□In field investigations, you are usually working with much larger animals than in the lab. In field investigations, it is much more difficult to separate your control and experimental groups.

There are many ways in which a field  experiment can differ form of a classroom or a laboratory experiment,  one of which can be the environmental condition.

 A field experiment Is an experiment  which is performed in practically Outside the classroom or a laboratory in live situtations .

Environmental factors may deter the results  of a field experiment or  may alter the physical conditions of the object, For example  an anhydrous substance may become  hygroscopic, Which may  Alter the result of the field experiment.

  Hence,  field experiment can differ from  a classroom or a laboratory experiment  due to environmental conditions .

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Answer:

did it give you answers to in blanks

Answer:

[tex]C_3H_7O_3[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer that the empirical formula of mannitol contains carbon, hydrogen and oxygen, so that the first step is to calculate the moles of C and H contained in the CO2 and H2O, respectively, as the only sources of these two elements in the formula:

[tex]n_C=1.993gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2} =0.0453molC\\\\n_H=0.9519gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O} =0.106molH[/tex]

Next, we calculate the grams and moles of O by subtracting the mass of C and H from the mass of the sample:

[tex]m_O=1.375g-0.0453molC*\frac{12gC}{1molC}-0.106molH*\frac{1.01gH}{1molH}=0.724gO\\\\n_O=0.724gO*\frac{1molO}{16.0gO} =0.0453molO[/tex]

Finally, we divide the moles of C, H and O by 0.0453 as the fewest moles of both C and O to find the mole ratios in the formula:

[tex]C:\frac{0.0453mol}{0.0453mol} =1\\\\H:\frac{0.106mol}{0.0453mol} =2.34\\\\O:\frac{0.0453mol}{0.0453mol} =1[/tex]

To get:

[tex]CH_{2.34}O[/tex]

Which must be multiplied by 3 to get whole numbers for all the subscripts, and therefore obtain:

[tex]C_3H_7O_3[/tex]

Regards!

Answer:

A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords.

HEY. HOPE THIS HELPS♡

Answer:

D

Explanation:

Explanation:

All atoms of one type were identical in mass and properties.

Answer:

The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:

CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)

Explanation:

Cobalt (ii) hydroxide is an inorganic compound consisting of cobalt (ii) ions, Co²+ and hydroxide ions, OH-. It is insoluble in water and the pure form known as the beta form is a pink-coloured solid. The impure form which incorporates other anions in its molecular structure is blue in colour and is ustable.

Cobalt (ii) hydroxide is formed as precipitate when an alkaline metallic hydroxide such as sodium hydroxide is mixed with an aqueous cobalt (ii) salt such as cobalt (ii) sulfate. The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:

CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)

Being a basic hydroxide, cobalt (ii) hydroxide neutralizes acids to form cobalt (ii) salts and water. For example: Co(OH)₂ (s) + H₂SO₄ (aq) ---> CoSO₄ (aq) + H₂O

Thus, cobalt (ii) hydroxide is soluble in acids.

Cobalt(II) hydroxide is used mostly as a drying agent for paints, varnishes, and inks. It is also useful in the preparation of other cobalt compounds.

Where is ur question ⁉️

Answer: In order to increase the rate of reaction between hydrochloric acid and sugar increase the concentration of hydrochloric acid to 2 M because greater concentration results in more collision between the reactants.

Explanation:

More is the concentration of reactant molecules more will be the number of collisions between their molecules. As a result, more readily the products will be formed.

Hence, for the given reaction when concentration of HCl is increased then there will be increase in the number of collisions between reactants.

Thus, we can conclude that in order to increase the rate of reaction between hydrochloric acid and sugar increase the concentration of hydrochloric acid to 2 M because greater concentration results in more collision between the reactants.

Answer:

2

Explanation:

You write your answer with the same number of significant figures as the number with the smallest amount of figures, in this case, that number is 2.1 so your answer should be written with 2 significant figures.

Answer:LOL

42

Explanation:

The mass of a single potassium atom is 6.50×10⁻²³ grams potassium atoms would be in 114 milligrams of potassium 17.53 ×10⁻²³.

An atom is the most diminutive form of any chemical compound that takes part in the chemical reaction to form any product and it is equal to the one mole which is 2.303 ×10²³ moles of the Avogadros number.

To calculate the number of atoms we have,  6.50×10⁻²³ grams of potassium and the value of one particle is 2.303 ×10²³ moles,

           atoms =   6.50×10⁻²³  / 114 milligrams of potassium

          atoms of potassium = 17.53 ×10⁻²³. atoms.

Therefore, 17.53 ×10⁻²³.atoms are present if the mass of a single potassium atom is 6.50×10⁻²³ grams potassium atoms would there be in 114 milligrams of potassium.

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Answer:

[tex]molar \: mass \: of \: copper(ii)nitrate = 64 + (14 + 48) \times 3 \\ = 250 \: g \\ 64 \: g \: of \: copper \: produces \: 250 \: g \: of \: copper \: nitrate \\ 10.36 \: g \: of \: copper \: will \: produce \: ( \frac{10.36 \times 250}{64} ) \: g \\ = 40.7 \: g[/tex]

Explanation:

the enerfy of of one photon of this light is 4.85x10^-19 J

E= 4.85x10^-19 J

Answer:

Check the image above

explanation:

When naming organic compounds based on IUPAC; we take note of functional group, position of functional group.

In 2,3,4-trimethyl-3-heptanol, the functional group is hydroxyl group ( OH ). It is on position 3 (2,3,4-trimethyl-3-heptanol. Then we put it on the third carbon. Another functional group is methyl group, with three positions, 2, 3, and 4.

In 4-ethyl-4-octanol, the functional group is hydroxyl group ( OH ) which is in position 4 on the fourth carbon. Another functional group is ethyl group in position 4 on the fourth carbon. In this case, the functional groups that have same position, are put on that same carbon.

Answer:

i believe the answer is D: 18

Explanation:

Answer:

18

M shell can actually hold 18 electron as you move higher atomic number

Answer:

Br

Explanation:

because bromine is more reactive as reactivity increases on moving from left to right in p-block. hope this make sense :)

Answer: The mass of carbon dioxide required is 308 g

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of octane = 100.0 g

Molar mass of octane = 114.23 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of octane}=\frac{100.0g}{114.23g/mol}=0.875mol[/tex]

For the given chemical reaction:

[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]

By the stoichiometry of the reaction:

2 moles of octane produces 16 moles of carbon dioxide

So, 0.875 moles of octane will produce = [tex]\frac{16}{2}\times 0.875=7mol[/tex] of carbon dioxide

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

[tex]\text{Mass of carbon dioxide}=(7mol\times 44g/mol)=308g[/tex]

Hence, the mass of carbon dioxide required is 308 g

Answer:

Chromosomes and I think its too many

Explanation: