A bullet of mass m1 = 0.020 kg is fired with initial speed v1 into a block of mass m2 = 0.500 kg that is initially at rest. The bullet becomes embedded in the block and the pair slide along to the right a distance d= 0.35 m over a rough surface with uk = 0.25. the spring (with k = 450 N/m) is compressed by a distance of x = 0.075 m. work backwards and determine the initial velocity of the bullet.

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Answer 1
Bro this goes in physics

Related Questions

The perimeter of a square is 100 feet. What is the length of one of its​ sides? Explain your work.

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Answer:

25

Step-by-step explanation:

to find the perimeter you add up all the sides and since it's a square and squares have all four equal sides

you just divide 100/4=25

4 sides of a square. Each side of a square is equal. You said the perimeter is 100. So if we put it in an equation, lets say S = Side. 4s=100. Now we just divide. s=25

Each side is 25

Thank or brainliest if helpful :D

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