Physics Middle School

A bus has velocity of 20 m/s towards east and another bus has velocity of 15 m/s in west direction . if they start to move from a point simultaneously, what distance do they cover in 2 minutes ? what will be their seperation ?

Help plss!!

Answers

Answer 1

Answer:

3.8 km

Explanation:

Eastern Side Bus

Velocity = 20m/s

Covers distance in 2 min (120sec) = 20×120 = 2400m = 2 km

Western Side Bus

Velocity = 15m/s

Covers distance in 2 min (120sec) = 15×120 = 1800m = 1.8 km

Separation Distance = 2+1.8 = 3.8 km

Answer 2
3.8 kilometers or km

Related Questions

All of these are very important parts of studying physics EXCEPT

1. describing the organization of the universe
2. understanding natural laws
3. memorizing complicated explanations
4. deducing and applying natural laws

Answers

Answer:

4. deducing and applying natural laws

4 since i am right.

Why is it possible for railway tracks to buckle even though there are gaps in them?​

Answers

These gaps which are of the order of a few millimeters, are provided to allow room for the rails to expand the rise in temperature due to the atmospheric temperature as well as the friction caused by running of train. All materials expand when heated and contract when cooled. The extent of expansion and contraction is quite low to be noticed by people or make much difference in most situations. However, since each section of the rail is very long, the expansion due to heating is significant, and unless space is provided for expansion of rails, the rails will bend to accommodate the increased length. This will make the railway unfit for running of trains.

Answer: the tracks will buckle under the force.

Explanation: Heat-related expansion places a lot of stress on the ties, ballasts, and rail anchors that keep the tracks fixed to the ground.

Mahiya and Mrinmoy are in a relay around a square field with each side of length 60m. First, Mahiya runs at a speed of 6 ms−1 for 60m to pass a baton to Mrinmoy. Then Mrinmoy runs 120m at 4ms−1 while Mahiya runs through the field to reach the other corner. Then Mrinmoy passes the baton. But Mahiya is now tired since she has been constantly running. So, she only runs at 3ms−1 for the final 60m. What is the average speed of the baton in ms−1?

Answers

The average speed of the baton can be determined by dividing the total distance travelled by the total time taken for that travelling.

[tex]Average\ Time = \frac{Total\ Distance}{Total\ Time}[/tex]

First, we will find the total distance, by adding the distances travelled by both Mahiya and Mrinmoy, while carrying the baton.

[tex]Total\ Distance = Distance\ Travelled\ by\ Mahiya\ to\ pass\ the\ baton\ to\ Mrinmoy\ +\ Distance\ Travelled\ by\ Mrinmoy\ to\ pass\ the\ baton\ to\ Mahiya\ +\ Final\ Distance\ Travelled\ by\\ Mahiya[/tex]Total Distance = 60 m + 120 m + 60 m = 240 m

Now, we will find the total time taken for this travelling. To find out the total time we will divide each distance travelled by the speed of the traveller during that distance:

[tex]Total\ Time = \frac{60\ m}{6\ m/s}+\frac{120\ m}{4\ m/s}+\frac{60\ m}{3\ m/s}\\\\Total\ Time = 10\ s\ +\ 30\ s\ +\ 20\ s[/tex]

Total Time = 60 s

Now, we finally find the average speed of the baton by using the formula:

[tex]Average\ Time = \frac{Total\ Distance}{Total\ Time}\\\\Average\ Time = \frac{240\ m}{60\ s}[/tex]

Average Speed = 4 ms⁻¹

Learn more about average speed here:

https://brainly.com/question/12322912?referrer=searchResults

PLEASE help with this!!! i'll give brainliest if right!!

Answers

1: decreases, increases, increases, stays the same
2: decreases, increases, increases, stays the same
3: increases, decreases, decreases, stays the same
4: increases, decreases, decreases, stays the same
Decrease increase is all of the answers for the graph
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