(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.

Answer:

Fluorometric emission scanning.

Explanation:

Fluorometric emission scanning is used to detect the presence of porphyrins. There are various types of porphyrins and they can be tested in a lab with either, urine or blood sample testing.

Explanation:

Answer

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Correct option is

A

Precipitation reaction

B

Double displacement reaction

Balanced equation for the reaction is:

KCl(s)+AgNO3(aq)→AgCl(s)+KNO3(aq)

It is a double displacement reaction as both reactants exchange ions to form new products. Also, it is a precipitation reaction as white precipitates of silver chloride(AgCl) are formed.

Answer:

3.2371 g

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the material was transferred to the flask

Since the bottle is unaltered, the mass of the material transferred to the flask is equal to the difference between the initial mass of the system and the final mass of the system.

m = 25.3658 g - 22.1287 g = 3.2371 g

Answer:

Explanation:

1 mol of anything is 6.02 * 10^23 (in this case molecules)

x mol  has 9.06 * 10^24 molecules of NaNO3

x * 6.02 * 10^23  = 9.06 * 10^24 * 1     Divide by 6.02 * 10^23

x = 9.06 * 10^24/6.02 * 10^23

x = 1.5 * 10

x = 15 mols of NaNO3

1 mol of NaNO3

Na = 23

N = 14

O3 = 48

Total = 85

1 mol of NaNO3 = 85 grams

15 mols = x                              Cross Multiply

x = 15 * 85

x = 1275 grams

Note: these numbers are approximate but they are very close. You have to use your own values from your periodic table to find the mass of NaNO3. Your answer will be very close to 85.

Answer: The answer is 0.52 grams.

2H2O->2H2+O2

So, we can say that,

2 moles of water= 16 gm of O2

Then

0.065 moles of water=16/2*0.065 gm

                                   =0.52 gm

Hope you understood:)

Answer:

neutral one with ph equal to 7

Answer:

1178J is the heat of the reaction

Explanation:

Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC

The heat of a reaction follows the equation:

Q = m*S*ΔT

Where Q is the heat of the reaction,

m is the mass:

61.2mL * (1.00g/mL) = 61.2g

S is specific heat = 4.184J/g°C

ΔT = 4.6°C

Replacing:

Q = 61.2g*4.184J/g°C*4.6°C

Q = 1178J is the heat of the reaction

Answer:

-11.13 Degree Celsius

Explanation:

Here

Kf for H20 is 1.86 C/m

Mass of ethylene glycol = 27.1/100 * 100 = 27.1 grams

Number of moles of ethylene in 30 grams of ethylene = 27.1 g/molar mass of ethylene glycol = 27.1/62.07 = 0.4366 mol

Mass of water = 100 – 27.1 = 72.9 grams

Molality  = Moles/Mass of water in Kg = 0.4366 /0.0729 = 5.989 m

Melting Point Depression = Kf * Molality = 1.86 *5.989 = 11.13 deg C

Melting point of solution = Melting point of water - Melting Point Depression

= 0 – 11.13 = -11.13 Degree Celsius

Answer:

The iron core, copper wire, and an electricity source.

Explanation: Me

Answer: hello your question is incomplete below is the complete question

Salt water contains n sodium ions (Na+) per cubic meter and n chloride ions (Cl−) per cubic meter. A battery is connected to metal rods that dip into a narrow pipe full of salt water. The cross sectional area of the pipe is A. The magnitude of the drift velocity of the sodium ions is VNa​ and the magnitude of the drift velocity of the chloride ions is VCl​.

What is the magnitude of the ammeter reading ?

answer :

| I | = neAVₙₐ  + neAV (Cl-)

Explanation:

Given that there are N sodium ions

Determine the Magnitude of the ammeter reading

| I | = current due to sodium ions + current due to (Cl-) ions

     = neAVₙₐ  + neAV (Cl-)

Answer:

[tex]m_{Al_2O_3}=118.27gAl_2O_3[/tex]

Explanation:

Hello there!

In this case, if we consider the following chemical reaction, whereby Al2O3 is produced from Al and FeO:

[tex]3FeO+2Al\rightarrow 3Fe+Al_2O_3[/tex]

Thus, since there is 3:1 mole ratio of FeO to Al2O3, it turns out feasible for us to use their molar masses, 71.844 g/mol and 101.96 g/mol respectively, to obtain the grams of the latter as follows:

[tex]m_{Al_2O_3}=250.gFeO*\frac{1molFeO}{71.844gFeO}*\frac{1molAl_2O_3}{3molFeO} *\frac{101.96gAl_2O_3}{1molAl_2O_3}\\\\m_{Al_2O_3}=118.27gAl_2O_3[/tex]

Regards!

Answer:

CH3CH2CH3

Explanation:

Dipole moment is the measure of the polarity of a chemical bond. It is the extent of charge separation in a molecule.

Dipole moment is the product of the magnitude of charge and the distance separating the charges from each other.

The molecule having the lowest dipole moment among the options is the molecule that has the least polarity. The least polar molecule among the options is CH3CH2CH3, it has no polar bonds in its structure.

We have that for the Question "Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN "

it can be said that

 From the question we are given

CH3CH2CH3

CH3OCH3

CH3CHO

CH3OH

CH3CN

Generally alkanes have the lowest dipole moment, they have C-H bond which are non polar.

Therefore,

[tex]CH_3CH_2CH_3[/tex] have the lowest dipole moment

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Answer:

Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature

Explanation:

Answer:

1    being or located on the outside; external  

2    further from the middle or central part

Explanation:

Answer:

If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.

Iodine always used in a solution excess KI is given to aid in the solubilization of free iodine, which would be insoluble in clean water during normal circumstances.

Iodine is a kind of element which are mainly used in iodometry titration. It can be represented by I.

A solution would be a homogenous mixture of two components, usually a solute as well as a solvent.

Iodimetry would be a technique that uses a standard iodine solution as a titrant for such an oxidizable analyte. When an excessive amount of iodide is used to decrease a chemical while somehow producing iodine.

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Answer:

Tundra and desert ecosystem are different especially when talking about their climate. Tundra is situated in northern latitude and is very cold having a negative 34 degrees and has a permafrost while desert is often situated closer to equator and thus have hot climate yet they have a similar characteristic when it comes to vegetation or the plants as both experience a water scarcity thus plants are already adapted to live in water-barren environment.

Explanation:

Answer:

Explanation:

Speed of light = Frequency * Wavelength

Speed of light is 3*10^8 m/s

Wavelength = Speed / Frequency = 3*10^8 / 3.7*10^14

= 8.11*10^(-7) m

= 811 nanometer

The wavelength of light will be

The wavelength of such a periodic wave would be the interval in which the shape of the wave repeats.

Calculation of wavelength of light

It is given that,

frequency = 3.7 x [tex]10^{14}[/tex] Hz

Speed of light = 3 × [tex]10^{8}[/tex] m/s

frequency × wavelength = speed of light.

wavelength =  speed of light / frequency

wavelength =  3 × [tex]10^{8}[/tex] m/s / 3.7 x [tex]10^{14}[/tex] Hz

wavelength = 0.81 × [tex]10^{-7}[/tex] m

wavelength = 8.1 × [tex]10^{-7}[/tex]

Therefore, wavelength of light will be  8.1 × [tex]10^{-7}[/tex].

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Answer:

See explanation and image attached

Explanation:

Alkenes react with borane (BH3) as shown in the image attached. Borane is a good electrophile since it is an electron deficient compound.

It can attack the electron rich pi bond. The attack of borane on the pi bond occurs as shown and leads to an addition reaction. Hydrogen and BH2^- are added across the double bond as shown.

The product of this reaction is shown in the image attached.

Answer:

The correct answer is "+2.37 V".

Explanation:

Given that,

Concentration of [tex]Mg^{2+}[/tex]

= 1.00 M

[tex]E^0 \ Mg^{2+}/Mg[/tex],

= -2.37 V

[tex]E^0 \ \mu^+/H_2[/tex],

= 0.00V

When S.H.E as well as anode act as cathode, then

⇒ [tex]E^0 cell=E^cathode-E^0 anode[/tex]

By putting the values, we get

⇒            [tex]=0.00V-(-2.37 V)[/tex]

⇒            [tex]=+2.37 \ V[/tex]    

Answer:

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

Using an ionic chloride and Phosphoric acid

H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

Explanation:

Answer:

The mass of the flour required to prepare the cookies is 1.8 kg.

Explanation:

The flour required to prepare the cookies is 3.95 lb.

1 lb = 0.454 kg

So, 3.95 lb = 3.95 x 0.454 kg = 1.8 kg

So, the mass of the flour required to prepare the cookies is 1.8 kg.

Answer:

t(9.32% remaining) = 203 yrs (3 sig. figs.)

Explanation:

All radioactive decay follows a 1st order decay profile. This is defined by the expression ...

A =A₀e^-k·t

A = final activity = 9.32%

A₀ = initial activity = 100%

e = base of natural logs

k = rate constant = 0.693/t(1/2) = (0.693/30.2) yrs⁻¹ = 0.023 yrs⁻¹

t = time of decay = ln(A/A₀)/-k = ln(9.32%/100%)/-0.023 yrs⁻¹

 = 203.286637 yrs (calc. ans.)

 ≅ 203 yrs (3 sig. figs.)

Answer:

Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.

Explanation:

First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.

Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.

Hence the answer above.

Answer:

significant number of what

Answer:

0.605 M

Explanation:

What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr?

Step 1: Given data

Step 2: Calculate the moles corresponding to 54.0 g of KBr

The molar mass of KBr is 119.00 g/mol.

54.0 g × 1 mol/119.00 g = 0.454 mol

Step 3: Calculate the molarity of the solution

Molarity is equal to the moles of solute divided by the liters of solution.

M = 0.454 mol / 0.750 L = 0.605 M

The question is incomplete, the complete question is;

Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction? chemical equation A strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution. yes no A strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution.

Answer:

No

Yes

Explanation:

A single replacement reaction occurs when a metal that is higher in the electrochemical series is placed in a solution of the salt of a metal which is lower than it in the electrochemical series.

For instance, when a strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution, a reaction occurs as follows;

Fe(s) + Pb(NO3)2(aq) ---------> Fe(NO3)2(aq) + Pb(s)

However, when a strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution no reaction occurs because lead is lower than iron in the electrochemical series hence it can not displace iron from an aqueous solution of its salt.

Answer: 0.943 M of potassium hydroxide solution is required.

Explanation:

A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.

To calculate the molarity of potassium hydroxide, the equation used is:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]              ........(1)

where,

[tex]n_1, M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid that is [tex]H_2SO_4[/tex]

[tex]n_2, M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the base that is KOH

We are given:

[tex]n_1=2\\M_1=0.506M\\V_1=23.3mL\\n_2=1\\M_2=?M\\V_2=25.0mL[/tex]

Putting values in equation 1, we get:

[tex]2\times 0.506\times 23.3=1\times M_2\times 25.0\\\\M_2=\frac{2\times 0.506\times 23.3}{1\times 25.0}\\\\M_2=0.943M[/tex]

Hence, 0.943 M of potassium hydroxide solution is required.

Explanation:  hi go to hell