A calorimeter has been filled with 75 mL of water. The density of water at 25 °C is
0.998 g/mL. How many grams of water do you have at 25°C?

Answer:

Each electrode attracts ions that are of the opposite charge. Positively charged ions, or cations, move toward the electron-providing cathode, which is negative; negatively charged ions, or anions, move toward the positive anode.

Answer:

jjjjjjjjj

Explanation:

hhhhhhhhhhh

Answer:

BF3

Explanation:

The octet rule describes atoms' preference and affinity for having eight (8) electrons in their valence shell. Whenever an atom is encircled by eight(8) electrons, it forms a stable configuration. This octet can be composed of its' own electrons as well as some shared electrons. In the periodic table, only the s-block and p-block electrons are considered for the octet rule.

However, out of the given option, only BF3 does not comply with the octet rule: This is because the Bromine contains 2 lone pairs of electrons and 3 other shared bonded pairs of electrons with Flourine making a total of 10 electrons in the valence shell and which does not conform with the octet rule.

Answer:

Melting-point apparatus

Answer:

Yes because same topic are long

Answer: At equilibrium, the partial pressure of [tex]PCl_{3}[/tex] is 0.0330 atm.

Explanation:

The partial pressure of [tex]PCl_{3}[/tex] is equal to the partial pressure of [tex]Cl_{2}[/tex]. Hence, let us assume that x quantity of [tex]PCl_{5}[/tex] is decomposed and gives x quantity of [tex]PCl_{3}[/tex] and x quantity of [tex]Cl_{2}[/tex].

Therefore, at equilibrium the species along with their partial pressures are as follows.

                         [tex]PCl_{5}(g) \rightarrow PCl_{3}(g) + Cl_{2}(g)\\[/tex]

At equilibrium:  0.123-x          x              x

Now, expression for [tex]K_{p}[/tex] of this reaction is as follows.

[tex]K_{p} = \frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}\\0.0121 = \frac{x \times x}{(0.123 - x)}\\x = 0.0330[/tex]

Thus, we can conclude that at equilibrium, the partial pressure of [tex]PCl_{3}[/tex] is 0.0330 atm.

Answer:

For 1: The product is phosphoric acid and the solution is acidic in nature.

For 2: The product is sodium hydroxide and the solution is basic in nature.

For 3: The product is nitric acid and the solution is acidic in nature.

Explanation:

For the given options:

(1): When diphosphorus pentoxide reacts with water, it leads to the formation of phosphoric acid, which makes the solution acidic in nature.

The chemical equation for the reaction follows:

[tex]P_4O_{10}+6H_2O(l)\rightarrow 4H_3PO_4(aq)[/tex]

(2): When disodium oxide reacts with water, it leads to the formation of sodium hydroxide, which makes the solution basic in nature.

The chemical equation for the reaction follows:

[tex]Na_2O+H_2O(l)\rightarrow 2NaOH(aq)[/tex]

(3): When dinitrogen pentoxide reacts with water, it leads to the formation of nitric acid, which makes the solution acidic in nature.

The chemical equation for the reaction follows:

[tex]3N_2O_5+3H_2O(l)\rightarrow 6HNO_3(aq)[/tex]

Sodium metal reacts rapidly with water to form a solution of sodium hydroxide (NaOH) and hydrogen gas (H2). This reaction is exothermic.

Equation:

2Na + 2H²0 --------}- 2NaOH + H²

hope it helps to everyone

Answer:

because atoms is just a chemical ahahahah

Explanation:

hope it helps ☺️

Dalton's hypothesis of atomic theory was given by John Dalton. The atoms of one element are the same as another and are not part of Dalton. Thus, option E is correct.

Dalton gave the atomic theory where atoms are the fundamental unit of the element of the periodic table. More than one element and atoms combine to form molecules and compounds.

The property of the atoms to get rearranged is the basis of the chemical reaction that results in the formation of the new product. This resulted in the formulation of chemical combinations. The atoms of the given element are said to be the same like the potassium contains the same atom.

The atoms of one element cannot be the same as another atom, like the atom of sodium and chloride are not the same. They are different in physical and chemical properties.

These atoms follow the law of conservation of mass. The atoms are composed of sub-atomic particles that have been constituted of neutrons, electrons, and protons.

Therefore, in option E. the atoms of two elements can never be the same.

Learn more about Dalton's theory, here:

https://brainly.com/question/15507302

#SPJ2

Answer:

a. The student performed the splint test incorrectly. He should of observed a popping sound when the splint was placed in the test tube.

Explanation:

It is given that a student performed an experiment where he dropped a nickel metal in to HCl solution. He observed the reaction and performed a splint test in the test tube that is filled with a gas which is formed while Nickle is dropped into the solution of HCl.

But the experiment that the student performed was incorrect. He must have observed the popping sound when the splint was placed in the test tube.

When the splint was added to the gas splint flared up. The hydrogen gas pops out when exposed to the flame.

[tex]$Ni + HCl(aq) = NiCl + H_2$[/tex]

Thus the correct option is (a).

Answer:

i believe its A, potassium iodide in water

Explanation:

Answer:

Balance the following reactions and identify the species that have been oxidized and the species that have been reduced.

CL2 +I- -------------> I2 +CL-

WO2 + H2 ---------------> W + H2O

CA + H2O -----------------> H2 + CA(OH)2

AL+ O2 --------------------> AL2O3

Explanation:

Oxidation is the process where an atom loses electrons.

During oxidation, the oxidation number of the atom increases.

Reduction is the process where an atom gains electrons.

During reduction, the oxidation number of the atom decreases.

The balanced chemical equations for the given reactions are shown below:

[tex]Cl_2 +2I^- -> I_2 + 2Cl^-[/tex]

Iodine undergoes oxidation and chlorine undergoes reduction.

[tex]WO_2 +2 H_2 -> W+ 2 H_2O\\[/tex]

In this reaction, W (tungsten) undergoes reduction and hydrogen undergoes oxidation.

[tex]Ca+2 H_2O ->H_2+Ca(OH)_2\\[/tex]

Ca undergoes oxidation and hydrogen undergoes reduction.

[tex]4Al+3O_2->2Al_2O_3\\[/tex]

Al undergoes oxidation and oxygen undergoes reduction.

Answer:

Deductive reasoning

Answer:

See explanation and image attached

Explanation:

Let us recall that the reaction in question is expected to happen by SN2 mechanism. This is because, the reaction occurs at secondary carbon atom and the attacking nucleophile (N3^-) is a good nucleophile.

The reaction occurs via a backside attack of the N3^- ion on (R)-2-chloropentane. This backside attack leads to inversion of configuration at the reaction centre to yield (S)-CH3CH(N3)CH2CH2CH3.

The images of the alkyl halide and nucleophile are shown in the image attached to this answer.

The direction of heat flow is increased which means blocks temperature is higher and hotter than it was before

Answer:

answer = 22.5m

Explanation:

using

[tex]s = \frac{ {v}^{2} - {4}^{2} }{2a} [/tex]

s= (0²-21²)/2(-9.8)

s= -441/19.6

s= 22.5m

do consider marking as Brainliest if this helped!!

Answer:

See explanation

Explanation:

Liquids are known to have a definite volumes but not a definite shape. This means that a liquid takes on the volume of the container in which it is found.

Hence, when a liquid is transferred from one container to another, the volume of the liquid remains the same but the shape of the liquid changes.

This happens when the two containers do not possess the same shape.

Explanation:

[tex]here \: is \: your \: explanation : - \\ \\ given \: balanced \:equation \: = > \\ \\ 2 A=>C \: + \: 4D \\ \\ by \: this \: equation \: we \: get \: \\ \\ 2 \: moles \: of \: A \: produce \: 4 \: moles \: \\ \\ of \: D \\ \\ hence \: . \: 1 \: mole \: can \: produce \: = 4 \div 2 \\ \\ = > 2 \: moles \: \\ \\ so \: if \: 6 \: moles \: of \: A \: used \: then \: \\ \\ amount \: of \: D \: produced \: = (6 \times 2) \\ \\ = > 12 \: moles \: of \: D \\ \\ \mathcal\blue{ Hope \: it \: helps \: you \: (. ❛ ᴗ ❛.) }[/tex]

Answer:

1.30 m

Explanation:

First we calculate the number of moles of solute in the solution, using the definition of molarity:

Then we calculate the mass of solvent, using the given volume and density:

Now we calculate the molality of the solution:

Explanation:

Answer:

the molar mass of the element

Answer:

See explanation

Explanation:

All molecules possess the London dispersion forces. However London dispersion forces is the only kind of intermolecular interaction that exists in nonpolar substances.

So, the only kind of intermolecular interaction that exists in dimethyl ether is London dispersion forces.

As for ethyl alcohol, the molecule is polar due to the presence of polar O-H bond. In addition to London dispersion forces, dipole-dipole interactions and specifically hydrogen bonding also occurs between the molecules.

Because ethyl alcohol is polar, it is more soluble in water than dimethyl ether.

Answer:

2.9 × 10²⁴ atoms Cu; 3.3 × 10²¹ atoms C; 1.44 × 10²⁵ atoms Hg; 9.63 × 10²² atoms Na

Explanation:

To convert moles to atoms, we need a conversion factor: Avogadro's number. There are 6.02 × 10²³ atoms in 1 mole of atoms.

4.9 mol Cu × 6.02 × 10²³ atoms Cu/1 mol Cu = 2.9 × 10²⁴ atoms Cu

5.4 × 10⁻³ mol C × 6.02 × 10²³ atoms C/1 mol C = 3.3 × 10²¹ atoms C

24.0 mol Hg × 6.02 × 10²³ atoms Hg/1 mol Hg = 1.44 × 10²⁵ atoms Hg

0.160 mol Na × 6.02 × 10²³ atoms Na/1 mol Na = 9.63 × 10²² atoms Na

Answer:

D: Increasing temperature

Explanation:

From collision theory, we know that the more the increase in collisions, the faster the rate of the chemical reaction.

Now, the amount of solid solute in a solvent will change with a corresponding change in temperature. What we mean is that, the higher the temperature increases, the higher the number of collisions between the solvent molecules as well as leading to an increase in the solute particles which will mean an increase in the amount of the solid solute dissolved. The correct answer is option D.

Answer:

Increasing temperature.

Explanation:

Answer:

[tex]T_F=1029\ºC[/tex]

Explanation:

¡Hola!

En este caso, dada la información, es posible determinar que la temperatura del sistema estará entre 560 °C y 1100 °C, por lo tanto, se hará necesario establecer la suma de la energía del cobre y del estaño como cero:

[tex]Q_{Cu}+Q_{Sn}=0[/tex]

Así, podremos escribir esta ecuación en términos de masas, calores específicos y temperaturas como sigue:

[tex]m_{Cu}C_{Cu}(T_F-T_{Cu})+m_{Sn}C_{Sn}(T_F-T_{Sn})=0[/tex]

Con el fin de resolver para la temperature final:

[tex]T_F=\frac{m_{Cu}C_{Cu}T_{Cu}+m_{Sn}C_{Sn}T_{Sn}}{m_{Cu}C_{Cu}+m_{Sn}C_{Sn}}[/tex]

Así, reemplazamos las variables conocidas como se muestra a continuación:

[tex]T_F=\frac{150g*0.093cal/g\ºC*1100\°C+35g*0.060cal/g\ºC*560\°C}{150g*0.093cal/g\ºC+35g*0.060cal/g\ºC}\\\\T_F=1029\ºC[/tex]

¡Saludos!

Answer:

100,000

Explanation:

Answer:

Explained below.

Explanation:

In order to extract lead from lead oxide, we need to add carbon from coke to the lead oxide.

We will need;

A bunsen burner

A test tube

Charcoal

First step is to heat charcoal in an oxygen free environment. The safety measure here to ensure an oxygen free environment is to add some zinc metal powder into the test tube in order to remove any atmospheric oxygen inside the container.

Secondly, we will now put charcoal inside the test tube and turn on the bunsen burner to heat it until coke is formed.

Thirdly, we now introduce lead oxide into the coke inside the test tube and the carbon in the coke reacts with the lead oxide to produce lead and carbon dioxide.

Throughout all this process, since we required an oxygen free environment inside the test tube, whenever the test tube is opened, its neck must immediately be warmed by heat with the tube placed in a horizontal direction or very close to being in that horizontal direction so that any movement of air moves outwards from the tube.

Answer:

Percentage of carbon:

[tex] { \tt{ = \frac{24}{30} \times 100\%}} \\ = 80\%[/tex]

Percentage of hydrogen:

[tex]{ \tt{ = \frac{6}{30} \times 100\%} } \\ = 20\%[/tex]