Answers
Related Questions
When a mass is suspended from a spring the latter extends over a distance of 10cm. What will be the period of oscillations of the same system if it is placed horizontal on a frictionless surface
Answers
Answer:
0.64 s
Explanation:
It's period of oscillation (T) can be determined by,
T = 2[tex]\pi[/tex][tex]\sqrt{\frac{l}{g} }[/tex]
Where l is the length (extension on the spring), and g the acceleration due to gravity.
But,
l = 10 cm = 0.1 m
g = 9.8 m/[tex]s^{2}[/tex]
Thus,
T = 2 x [tex]\frac{22}{7}[/tex] [tex]\sqrt{\frac{0.1}{9.8} }[/tex]
= 0.6350
T = 0.64 s
The period of oscillation would be 0.64 s.
A 45.7 kg woman starts from rest at the bottom of a flight of stairs that has
a total height of 2.54 meters. She reaches the top of the stairs
in 5.00 seconds. How much power does she generate if she is moving at
2.63 m/s at the top of the stairs? Use g = 9.8 m/s2, and only include 3
numbers in your answer.
Answers
Answer:
The power generated by the woman is 259 W
Explanation:
Given;
mass of the woman, m = 45.7 kg
initial velocity of the woman, u = 0
total height ascended by the woman, h = 2.54 m
time of the woman's motion, t = 5.0 s
final velocity of the woman, v = 2.63 m/s
acceleration due to gravity, g = 9.8 m/s²
The potential energy of the woman due to the height she ascended;
P.E = mgh
P.E = 45.7 x 9.8 x 2.54
P.E = 1137.564 J
The kinetic energy of the woman due to her final velocity;
K.E = ¹/₂mv²
K.E = ¹/₂ x 45.7 x (2.63)²
K.E = 158.051 J
The total mechanical energy of the woman at the top of the stairs;
M.E = P.E + K.E
M.E = 1137.564 J + 158.051 J
M.E = 1295.615 J
The power generated by the woman;
Power = Energy/time
Power = 1295.615 J / 5 s
Power = 259.123 W
Power = 259 W
Does gravity increase or decrease with greater mass???
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Answer:
Increase
As the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force.
As the mass of either object increases, the force of gravitational attraction between them also increases.
Answered by none other than the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO
HOPE THIS HELPED!!!
1. An atom that loses electrons has a ________________________ charge and an atom that gains
electrons has a ___________________________ charge.
Charged atoms are called ___________________.
2. What is an insulator? Give 4 examples.
3. What is a conductor? Give an example.
4. How can we move electrons from one place to another? What actually causes the electrons to
move?
5. Static electricity is ______________________________________________________________________
_______________________________________________________________________________________
6. Explain the attraction and repulsion of charges.
7. Why does a balloon stick to the wall?
8. Why does your hair stand up when you take off your hat?
9. Why do you get a shock when you walk across a carpet?
10. When is static electricity most noticeable and why?
11. State the Principle of Conservation of Charge.
12. The invisible electric force field around charged objects depends on __________________________,
__________________________, and _____________________________.
13. What is the relationship between the charges and the field strength?
What is the relationship between the field strength and the distance between the charges?
1. What is DC?
What is AC?
2. Name 3 ways to get DC.
3. What is an electrical circuit?
4. What is voltage?
What is current?
What is resistance?
What causes heat and light in a wire?
COPY THE TABLE comparing water in a hose-DC-units
5. Which electricity do we use in our homes?
CLICK ON ALTERNATING CURRENT
1. Explain AC.
2. Who invented the light bulb?
3. Who really invented AC?
4. Who discovered the advantages of AC over DC?
5. How is AC made?
6. What is the main advantage of AC over DC?
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1. Positive, negative, ions
Answer a few yourself and I’ll come back and help some more.
g A projectile of mass 3 kg is launched horizontally from an initial height 3 m with an initial velocity 10 m/s. This velocity in the x direction is preserved when you ignore air resistance. The projectile still accelerates in the vertical y direction toward the ground, but this is exactly the energy lost from potential energy. Energy is conserved as long as you use the total mechanical energy equation. What is the final kinetic energy as the projectile just reaches the ground
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Answer:
The kinetic energy at ground will be "238.2 J".
Explanation:
The given values are:
mass,
m = 3 kg
Initial height,
h = 3 m
Initial velocity,
v = 10 m/s
By using the conservation of energy at points A and B,
⇒ [tex]E_A=E_B[/tex]
⇒ [tex]mgh+\frac{1}{2}mv^2=k_B[/tex]
On substituting the values, we get
⇒ [tex]3\times 9.8\times 3+\frac{1}{2}\times 3\times (10)^2=k_B[/tex]
⇒ [tex]88.2+0.5\times 3\times 100=k_B[/tex]
⇒ [tex]88.2+150=k_B[/tex]
⇒ [tex]238.2 =k_B[/tex]
How do scientists know the continents were once closer than they are today? Explain your answer in 2-3 complete sentences.
Answers
Answer:
Continental drift describes one of the earliest ways geologists thought continents moved over time. Today, the theory of continental drift has been replaced by the science of plate tectonics.
The theory of continental drift is most associated with the scientist Alfred Wegener. In the early 20th century, Wegener published a paper explaining his theory that the continental landmasses were “drifting” across the Earth, sometimes plowing through oceans and into each other. He called this movement continental drift.
A.) A gemstone of mass 1.8 kg compresses a scale's spring by 2.6 cm.
Determine the spring constant.
B.) How much would the spring in the previous question compress if a 5.2 kg mass was placed on the scale?
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Explanation:
Given that,
Mass, m = 1.8 kg
Compression, x = 2.6 cm
We know that,
Force on spring = weight
So,
[tex]mg=kx[/tex]
Where
k is spring constant
[tex]k=\dfrac{mg}{x}\\\\k=\dfrac{1.8\times 9.8}{2.6\times 10^{-2}}\\\\k=678.46\ N/m[/tex]
(2) If m = 5.2 kg
[tex]x=\dfrac{mg}{k}\\\\x=\dfrac{1.8\times 9.8}{678.46}\\\\x=2.6 \ cm[/tex]
Hence, this is the required solution.
