A certain light bulb consumes 200J of electrical energy per second, but only emits 25J of light energy per second. Calculate the efficiency of this bulb.
Answers
Answer 1
Answer:
The answer is 12.5%
Explanation:
The efficiency of a light bulb is:
Light energy comes out of the bulb / Electrical energy that was put in
= 25J / 200J = 12.5%
Answer 2
12.5% it told me that it had to be 20 characters long to submit it so there